Pivot SQL table - sql

Question

I have a table with a column "date" and "name".
Here you can find a sample of my table: http://sqlfiddle.com/#!2/eddede/1
What I need to do is to count how many rows a person has for every year. If the person doesn't have a value in year X, you must see 0. The order of the names must be on total count of current year DESC, so at the moment: 2014.
I can count for every year/name, but not sure I need this for the pivot table: http://sqlfiddle.com/#!2/eddede/3
I would like that the result should look like this:
NAME 2012 2013 2014 TOTAL
Person B 2 2 2 6
Person C 0 1 2 3
Person A 4 3 1 8
I've tried, but I get something like this (So I don't post the wrong SQL-query...)
2012 2013 2014
6 6 5

Answer 1

You can get the result using an aggregate function with some conditional logic like a CASE expression:
select
name,
sum(case when year(date) = 2012 then 1 else 0 end) [2012],
sum(case when year(date) = 2013 then 1 else 0 end) [2013],
sum(case when year(date) = 2014 then 1 else 0 end) [2014],
count(*) Total
from list
group by name;
See SQL Fiddle with Demo
Now, if the year values are unknown, then you will need to use dynamic SQL. This creates a string of the SQL that you need to execute:
DECLARE #cols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX),
#orderby nvarchar(max)
select #cols
= STUFF((SELECT ',' + QUOTENAME(year(date))
from list
group by year(date)
order by year(date)
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
select #orderby = 'ORDER BY ['+cast(year(getdate()) as varchar(4)) + '] desc'
set #query = 'SELECT name, ' + #cols + ', Total
from
(
select name, year(date) dt,
count(*) over(partition by name) Total
from list
) x
pivot
(
count(dt)
for dt in (' + #cols + ')
) p '+ #orderby
exec sp_executesql #query;
See SQL Fiddle with Demo

Answer 2

I think this is what you are looking for:
SELECT
name,
SUM(if(year(date) = 2012, 1, 0)) AS '2012',
SUM(if(year(date) = 2013, 1, 0)) AS '2013',
SUM(if(year(date) = 2014, 1, 0)) AS '2014'
FROM list
GROUP BY name;
and with total :)
SELECT
t.name,
t.`2012`,
t.`2013`,
t.`2014`,
t.`2012` + t.`2013` + t.`2014` as total
FROM
(
SELECT
name,
SUM(if(year(date) = 2012, 1, 0)) AS `2012`,
SUM(if(year(date) = 2013, 1, 0)) AS `2013`,
SUM(if(year(date) = 2014, 1, 0)) AS `2014`
FROM list
GROUP BY name
) as t