Same column name used in where clause in codeigniter - sql

i want to sql query like this
SELECT * FROM `tblName`
where `id`='007' and
`doj` != '2014-07-26' and
`doj` != '2014-08-04'
i want same column 'doj' used in where clause.
please help me?
Thanks in advance.

<?php
$dates = array(
'2014-07-26',
'2014-08-04'
);
$this->db->from('tblName');
$this->db->where('id','007');
// first variant
foreach($dates as $date){
$this->db->where('doj !=',$date);
}
// or second variant
$this->db->where_not_in('doj',$dates); // <- seems to be better
// finally get result
$result = $this->db->get();
if($result->num_rows()){
var_dump($result->result_array());
} else {
echo 'no rows found';
}
// check query
echo $this->db->last_query();
?>

Related

How to select data from table that not inserted on other table in codeigniter

I've two tables products, stock I want to select all rows from table products that not inserted on stock and i've 2 conditions
1: column products.s_compnay_id = users.u_company_id
2: cloumn stock.s_company_id =users.u_company_id
that's my model
<?php
Class UserProducts_m extends CI_Model{
function index(){
$session_data = $this->session->userdata('logged_in');
$name = $session_data['username'];
$this->db->select('u_company_id');
$this->db->from('users');
$this->db->where('u_username', $name);
$user_data = $query = $this->db->get();
if ($user_data->num_rows() > 0) {
foreach ($query->result_array() as $row_userdata) {
$usercompanyid[] = $row_userdata;
}
$usercompany=$usercompanyid[0]['u_company_id'];
}
$query="select products.* from products where !FIND_IN_SET(products.p_id,select stock.s_p_id from stock and stock.s_company_id=$usercompany and p_company_id=$usercompany)";
$this->db->query($query);
$result= $this->db->get();
if ($result->num_rows() > 0) {
foreach ($result->result_array() as $row_result) {
$product_data[] = $row_result;
}
}
//return $result=$query->result();
}
}
?>
And that's my controller
<?php
Class UserProducts extends CI_Controller {
function index(){
$this->load->model("UserProducts_m");
$this->load->model("user");
$this->load->view("userproducts_v",array(
'userdata'=>$this->user->userdata(),
'userproducts'=>$this->UserProducts_m->index()
));
}
}
?>
that's my errors
Error Number: 1064
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'select stock.s_p_id from stock and stock.s_company_id=1 and p_company_id=1)' at line 1
select products.* from products where !FIND_IN_SET(products.p_id,select stock.s_p_id from stock and stock.s_company_id=1 and p_company_id=1)
Filename: C:/xampp/htdocs/Elvan/system/database/DB_driver.php
Line Number: 691
I suggest you try putting curly braces around the vars in your query statement. Then it should resolve to array values properly.
$query="select products.* from products where
!find_in_set(products.p_id,select stock.s_p_id from stock and
stock.s_company_id = {$usercompanyid[0]['u_company_id']} and
p_company_id = {$usercompanyid[0]['u_company_id']})";
I see a couple other problems.
The line
$result= $this->db->get();
is not needed because $this->db->query($query); already returned a database result object. Do this
$result = $this->db->query($query);
if ($result->num_rows() > 0)
{ ...
Then you have this useless block of code (Pardon me for being blunt)
foreach ($result->result_array() as $row_result)
{
$product_data[] = $row_result;
}
This is useless because your code just copies array values from one array to another. You'll save a lot of code execution with the following which produces the same thing your foreach loop does.
$product_data = $result->result_array();
result->array() returns an array where each item is an array representing a table row.
You did the same thing earlier adding items to the $usercompanyid array. Do this.
if ($user_data->num_rows() > 0)
{
$usercompanyid = $query->result_array();
}
One last problem. It appears that UserProducts_m::index() does not return anything.
You can use the NOT IN sql query for this.
SELECT *
FROM products
WHERE product_id NOT IN (select field name form stock where clause);

update some rows in code igniter

i'm new to codeigniter.
i need some help to update some rows.
here is my model:
public function change()
{
$aa = $this->input->post('id');
$bb = $this->input->post('app');
$query = $this->db->query('select kodeunit from user where email = "hehe#gmail.com"');
foreach ($query->result() as $row)
{
$kode = $row->kodeunit;
}
for($i=0;$i<sizeof($aa);$i++)
{
$data = array(
'approval' => $bb[$i]
);
$this->db->where('id_team', $aa[$i]);
$this->db->where('kodeunit', $kode);
$this->db->update('detail_tim', $data);
}
}
when i tried to update only one row, it worked with this way. but when im trying to update some rows, it doesnt change at all.
please help me to fix this problem thanks
Don't use sizeof() in your for loop, instead use $aa directly if it's an integer or count($aa) if it's an array
for($i=0;$i<count($aa);$i++)
it'll be better if you make it to other variable
$max = count($aa);
for($i=0;$i<$max;$i++)

PDO row doesn't exist?

Below is my code:
<?php
$url = $_GET['url'];
$wordlist = array("Www.", "Http://", "Http://www.");
foreach ($wordlist as &$word) {
$word = '/\b' . preg_quote($word, '/') . '\b/';
}
$url = preg_replace($wordlist, '', $url);
?>
<?php
$oDB = new PDO('mysql:dbname=mcnsaoia_onsafe;host=localhost;charset=utf8', 'mcnsaoia_xx', 'PASSWORD');
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside AND godkendt=ja");
$hStmt->execute(array('hjemmside' => $url));
if( $row = $hStmt->fetch() ){
echo "EXIST";
}else{
echo "NOT EXIST";
}
?>
My problem is that it says NOT EXIST, because I know that there is a row which should be found with the following query:
SELECT * FROM users WHERE hjemmside = :hjemmside AND godkendt=ja
So why does it say not exist? I have absolutely no idea :(
Instead of
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside
AND godkendt=ja");
try
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside
AND godkendt='ja'");
The left is most likely a column and the right side is a string? I don't speak your language, but this is the first thing coming to my mind.
You should surround with quotes your not integer variable in your query
AND godkendt='ja'
Or maybe let pdo deal with it
$hStmt=$oDB->prepare("SELECT * FROM users WHERE hjemmside = :hjemmside AND godkendt = :ja");
$hStmt->execute(array(':hjemmside' => $url, ':ja' => 'ja'));
//^ i added : for placeholder here, you missed it
I would also rather check if rows are returned
if($hStmt->$eowVount() > 0){
$row = $hStmt->fetch()
echo "EXIST";
}else{
echo "NOT EXIST";
}

$data = $query->row(); returns only one row

Im trying to list the results of my sql query (picking up all the movies from a category), but I cannot figure out how to get all the rows instead of only one.
Here's the code :
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->row();
$this->response($data, 200);
I've tried :
while($row = mysql_fetch_assoc($query)){
$data = $query->row();
}
$this->response($data, 200);
And it doesn't work. Any suggestion ? Thank you !
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->result();
To traverse the $data array:
foreach($data AS $row)
{
//to retrieve the data from each row.
$col1 = $row->col1;
$col2 = $row->col2;
}
Use result() instead of row(). result() will return an array of objects that are your results. Alternatively, you can useresult_array() which will resturn an array of arrays keyed according to your columns. Please refer to here for a better outline of the result() and row() methods.
Do you have a database configuration file? the load->database() requires it. Where is $movies_category coming from? This will let you iterate over your results.
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
foreach ($query->result() as $row)
{
echo $row->column;
}
Where column corresponds with one of the values in the movies table.
I'm surprised nobody has mentioned the potential hazards of using variables (possibly user input) in your SQL. You should seriously consider using query bindings or the active record features of CodeIgniter to build safer queries.
Consider the following solution to your problem:
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = ?';
$query = $this->db->query($sql, array($movies_category));
// $data = $query->result(); // returns result as an array of objects
$data = $query->result_array(); // returns result as array
$this->response($data, 200);
I'm assuming this is for some sort of API? If so, consider using the result_array() method as it will probably be better suited for your needed output, and also really easy to convert into JSON:
$json_data = json_encode($data);
Hope that helps,
Cheers.
For your question row() return only one value its good for checking in ID and if you want get all the rows use result_array() or simple result()
You can try this code....
Model:
function get_movies($movies_category){
$this->db->where("category",$movies_category);
$query = $this->db->get("movies");
return $query->result_array();
}
Controller:
$this->data['movies'] = $this->'name of model'->get_movies('here is the movie categories');
View:
foreach($movies as $m){
print_r($m);
}
exit();
Note you can directly add the code in function in model to controller add this in your controller if you want directly...
$this->data['movies] = $this->db->get('movies')->result_array();

sql update codeigniter

I am using codeIgniter..
I want to update a table column is_close when id=$ticket_id of my table= tbl_tickets.
I am doing this :-
$data=array(
'is_close'=>1
);
$this->db->where('id',$title_id);
$this->db->update('tbl_tickets',$data);
and I have also done this :-
$sql = "UPDATE tbl_tickets SET is_close={1} WHERE id='$title_id'";
$this->db->query($sql);
both are not working,i.e., my table is not updating the value to 1 and also no error is being shown in the broswer. :(
Edited: Included my model part :
function setClosePost($title_id){
$sql = "UPDATE tbl_tickets SET is_close=0 WHERE id='$title_id'";
$this->db->query($sql);
// $data=array(
// 'is_close'=>1
// );
// $this->db->where('id',$title_id);
// $this->db->update('tbl_tickets',$data);
}
My controller :-
function closePost(){
$this->load->model('helpdesk_model');
$this->helpdesk_model->setClosePost($this->input->post('title_id'));
}
first of all use a get method to check if ticket_id is exist or not.
another thing is always use return in your functions in models so you can check them by if(function_name){...}else{...}
then if your get method returned data correctly try
Model Method
public function set_closed($ticket_id){
$this->db->set(array(
'is_close'=>1
)); // pass fields in array
$this->db->where('id',$ticket_id);
$this->db->update('tbl_tickets'); // table name
return true;
}
then check that in your controller
if($this->Ticket_model->set_closed($ticket_id) == true){
echo 'ticket set to closed correctly';
}else{
echo 'there is some error on updating database'.$this->db->error(); // to checkout db error .
}
First, check $title_id before passing:
var_dump($title_id);
Then, try do "select a row with this id" before updating and after.
$query = $this->db->get_where('tbl_tickets', array('id' => $id));
foreach ($query->result() as $row)
{
var_dump($row->is_close);
}
$data=array(
'is_close'=>1
);
$this->db->where('id',$title_id);
$this->db->update('tbl_tickets',$data);
$query = $this->db->get_where('tbl_tickets', array('id' => $id));
foreach ($query->result() as $row)
{
var_dump($row->is_close);
}
Then, give your table structure.
Just try like this
$sql = "UPDATE tbl_tickets SET is_close='1' WHERE id=".$title_id;
$this->db->query($sql);
just try like this
**function edit($close,$id) {
$sql = "UPDATE tbl_tickets SET is_close= ? WHERE id = ? ";
$this->db->query($sql, array($close,$id));
}**
To handle this type of errors, i mean if reflection is not happen in database, then use below steps to resolve this type of error.
1) use $this->db->last_query() function to print query, using this we can make sure our variable have correct value (should not null or undefined), using that we can make sure also SQL query is valid or not.
2) If SQL query is valid then open phpmyadmin & fire same query into phpmyadmin, it will return error if query columns or table names are invalid.
Use this way, its best way to cross check our SQL queries issues.
I hope it will work.
Thanks
You are trying to update integer(INT) type value, just cross check with your column datatype if that is varchar then you have to put value in a single or double quote.
Like this
$data=array('is_close'=> '1');