$data = $query->row(); returns only one row - sql

Im trying to list the results of my sql query (picking up all the movies from a category), but I cannot figure out how to get all the rows instead of only one.
Here's the code :
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->row();
$this->response($data, 200);
I've tried :
while($row = mysql_fetch_assoc($query)){
$data = $query->row();
}
$this->response($data, 200);
And it doesn't work. Any suggestion ? Thank you !

$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->result();
To traverse the $data array:
foreach($data AS $row)
{
//to retrieve the data from each row.
$col1 = $row->col1;
$col2 = $row->col2;
}
Use result() instead of row(). result() will return an array of objects that are your results. Alternatively, you can useresult_array() which will resturn an array of arrays keyed according to your columns. Please refer to here for a better outline of the result() and row() methods.

Do you have a database configuration file? the load->database() requires it. Where is $movies_category coming from? This will let you iterate over your results.
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
foreach ($query->result() as $row)
{
echo $row->column;
}
Where column corresponds with one of the values in the movies table.

I'm surprised nobody has mentioned the potential hazards of using variables (possibly user input) in your SQL. You should seriously consider using query bindings or the active record features of CodeIgniter to build safer queries.
Consider the following solution to your problem:
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = ?';
$query = $this->db->query($sql, array($movies_category));
// $data = $query->result(); // returns result as an array of objects
$data = $query->result_array(); // returns result as array
$this->response($data, 200);
I'm assuming this is for some sort of API? If so, consider using the result_array() method as it will probably be better suited for your needed output, and also really easy to convert into JSON:
$json_data = json_encode($data);
Hope that helps,
Cheers.

For your question row() return only one value its good for checking in ID and if you want get all the rows use result_array() or simple result()
You can try this code....
Model:
function get_movies($movies_category){
$this->db->where("category",$movies_category);
$query = $this->db->get("movies");
return $query->result_array();
}
Controller:
$this->data['movies'] = $this->'name of model'->get_movies('here is the movie categories');
View:
foreach($movies as $m){
print_r($m);
}
exit();
Note you can directly add the code in function in model to controller add this in your controller if you want directly...
$this->data['movies] = $this->db->get('movies')->result_array();

Related

update some rows in code igniter

i'm new to codeigniter.
i need some help to update some rows.
here is my model:
public function change()
{
$aa = $this->input->post('id');
$bb = $this->input->post('app');
$query = $this->db->query('select kodeunit from user where email = "hehe#gmail.com"');
foreach ($query->result() as $row)
{
$kode = $row->kodeunit;
}
for($i=0;$i<sizeof($aa);$i++)
{
$data = array(
'approval' => $bb[$i]
);
$this->db->where('id_team', $aa[$i]);
$this->db->where('kodeunit', $kode);
$this->db->update('detail_tim', $data);
}
}
when i tried to update only one row, it worked with this way. but when im trying to update some rows, it doesnt change at all.
please help me to fix this problem thanks
Don't use sizeof() in your for loop, instead use $aa directly if it's an integer or count($aa) if it's an array
for($i=0;$i<count($aa);$i++)
it'll be better if you make it to other variable
$max = count($aa);
for($i=0;$i<$max;$i++)

How to return a JSON array from sql table with PhalconPHP

I have several tables that have JSON arrays stored within fields.
Using PHP PDO I am able to retrieve this data without issue using:
$query1 = $database->prepare("SELECT * FROM module_settings
WHERE project_token = ? AND module_id = ? ORDER BY id DESC LIMIT 1");
$query1->execute(array($page["project_token"], 2));
$idx = $query1->fetch(PDO::FETCH_ASSOC);
$idx["settings"] = json_decode($idx["settings"]);
This returns a string like:
{"mid":"","module_id":"1","force_reg_enable":"1","force_reg_page_delay":"2"}
Attempting to gather the same data via PhalconPHP
$result = Modulesettings::findFirst( array(
'conditions' => 'project_token = "' . $token . '"' ,
'columns' => 'settings'
) );
var_dump($result);
Provides a result of
object(Phalcon\Mvc\Model\Row)#61 (1) { ["settings"]=> string(167) "{"text":"<\/a>
<\/a>
","class":""}" }
What do I need to do different in Phalcon to return the string as it is stored in the table?
Thank you.
You have 2 approach
First :
Get the settings with this structure :
$settings = $result->settings;
var_dump($settings);
Second :
First get array from resultset, then using the array element :
$res = $result->toArray();
var_dump($res['settings']);
Try it.
You can decode json right in your Modulesettings model declaration:
// handling result
function afterFetch() {
$this->settings = json_decode($this->settings);
}
// saving. Can use beforeCreate+beforeSave+beforeUpdate
// or write a Json filter.
function beforeValidation() {
$this->settings = json_encode($this->settings);
}

How to output JSON from recordset in Dreamweaver with minimal manual code? [duplicate]

I have a basic MySQL database table People with 3 columns (ID, Name, Distance)
I am trying to output this with PHP as a JSON so my web app can pick it up. I tried using the solution from another answer:
$sth = mysql_query($con,"SELECT * FROM People");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
$rows[] = $r;
}
print json_encode($rows);
However I am just returning a blank array of [].
Update: Changed to mysqli and added dumps:
$sth = mysqli_query("SELECT * FROM Events",$con);
$rows = array();
var_dump($sth);
while($r = mysqli_fetch_assoc($sth)) {
var_dump($rows);
$rows[] = $r;
}
print json_encode($rows);
Returns:
NULL []
Swap your query and connection in the mysql_query-statement:
$sth = mysql_query("SELECT * FROM People", $con);
Besides that, the mysql-library is deprecated. If you're writing new code consider using mysqli_ or PDO.
Why no mysql_connect ?
var_dump($sth); // check the return of mysql_query()
var_dump($rows); // check the array of mysql_fetch_assoc result
I would check if your query is returning any rows first.
<?php
$rows = array();
array_push($rows, array("name" => "John"));
array_push($rows, array("name" => "Jack"));
array_push($rows, array("name" => "Peter"));
print json_encode($rows);
?>
Produces this output.
[{"name":"John"},{"name":"Jack"},{"name":"Peter"}]
Solved using a combination of answer to get:
$sth = mysqli_query($con,"SELECT * FROM Events");
$datarray = array();
while($row = mysqli_fetch_assoc($sth)) {
$datarray[] = $row;
}
print_r(json_encode($datarray));

Yii: adding custom fields

Is there a simple way of adding custom fields to a model? Say I have a table "user" with 3 fields: id, name and surname. I want this:
$user = User::model()->findByPk(1);
$echo $user->fullName; // echoes name and surname
Please note: I want this custom field to be added via sql, smth like
$c = new CDbCriteria();
$c->select = 'CONCAT("user".name, "user".surname) as fullName';
$user = User::model()->find($c);
Problem is that fullName property is not set.
UPD:
here is the code for a little bit trickier problem -- custom field from another table. This is how it's done:
$model = Application::model();
$model->getMetaData()->columns = array_merge($model->getMetaData()->columns, array('fullName' => 'CONCAT("u".name, "u".surname)'));
$c = new CDbCriteria();
$c->select = 'CONCAT("u".name, "u".surname) as fullName';
$c->join = ' left join "user" "u" on "t".responsible_manager_id = "u".id';
$model->getDbCriteria()->mergeWith($c);
foreach ($model->findAll() as $o) {
echo '<pre>';
print_r($o->fullName);
echo '</pre>';
}
You can add a function to the User class:
public function getFullName() { return $this->name.' '.$this->surname; }
This will return the full name as if it were an attribute from the database. This is much easier than adding a calculated column to the SQL.
In model
public function getMetaData(){
$data = parent::getMetaData();
$data->columns['fullName'] = array('name' => 'fullName');
return $data;
}
Thus not recommended

how to get last inserted id - zend

I'm trying to get latest inserted id from a table using this code:
$id = $tbl->fetchAll (array('public=1'), 'id desc');
but it's always returning "1"
any ideas?
update: I've just discovered toArray();, which retrieves all the data from fetchAll. The problem is, I only need the ID. My current code looks like this:
$rowsetArray = $id->toArray();
$rowCount = 1;
foreach ($rowsetArray as $rowArray) {
foreach ($rowArray as $column => $value) {
if ($column="id") {$myid[$brr] = $value;}
//echo"\n$myid[$brr]";
}
++$rowCount;
++$brr;
}
Obviously, I've got the if ($column="id") {$myid[$brr] = $value;} thing wrong.
Can anyone point me in the right direction?
An aternative would be to filter ID's from fetchAll. Is that possible?
Think you can use:
$id = $tbl->lastInsertId();
Aren't you trying to get last INSERT id from SELECT query?
Use lastInsertId() or the value returned by insert: $id = $db->insert();
Why are you using fetchAll() to retrieve the last inserted ID? fetchAll() will return a rowset of results (multiple records) as an object (not an array, but can be converted into an array using the toArray() method). However, if you are trying to reuse a rowset you already have, and you know the last record is the first record in the rowset, you can do this:
$select = $table->select()
->where('public = 1')
->order('id DESC');
$rows = $table->fetchAll($select);
$firstRow = $rows->current();
$lastId = $firstRow->id;
If you were to use fetchRow(), it would return a single row, so you wouldn't have to call current() on the result:
$select = $table->select()
->where('public = 1')
->order('id DESC');
$row = $table->fetchRow($select);
$lastId = $row->id;
It sounds like it's returning true rather than the actual value. Check the return value for the function fetchAll