load script from other file extension? - module

is it possible to load module from file with extension other than .lua?
require("grid.txt") results in:
module 'grid.txt' not found:
no field package.preload['grid.txt']
no file './grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt/init.lua'
no file '/usr/local/lib/lua/5.1/grid/txt.lua'
no file '/usr/local/lib/lua/5.1/grid/txt/init.lua'
no file './grid/txt.so'
no file '/usr/local/lib/lua/5.1/grid/txt.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
no file './grid.so'
no file '/usr/local/lib/lua/5.1/grid.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
I suspect that it's somehow possible to load the script into package.preaload['grid.txt'] (whatever that is) before calling require?

It depends on what you mean by load.
If you want to execute the code in a file named grid.txt in the current directory, then just do dofile"grid.txt". If grid.txt is in a different directory, give a path to it.
If you want to use the path search that require performs, then add a template for .txt in package.path, with the correct path and then do require"grid". Note the absence of suffix: require loads modules identified by names, not by paths.

If you want require("grid.txt") to work should someone try that then yes, you'll need to manually loadfile and run the script and put whatever it returns (or whatever require is documented to return when the module doesn't return anything) into package.loaded["grid.txt"].
Alternatively, you could write your own loader just for entries like this which you set into package.preload["grid.txt"] which finds and loads/runs the file or, more generically, you could write yourself a loader function, insert it into package.loaders, and then let it do its job whenever it sees a "*.txt" module come its way.

Related

is there a way to use the full file path in the command line without typing it?

For example, I want to open a PDF file in the browser from the command line (just because it's much faster and I need to open many files at once) and when I use the command start [file name] from its directory it try to open it as a executable, so I need to open the browser and type the full path of the file as an attribute, is there a way to call the full path without typing it?
what I exactly need is I need the full path of a file to convert it to string (for example in the browser)
Using tab completions may help. For example, if your target file is named thisPDFisTotallyBananas.pdf and you have another file in the same folder named thisOtherPDFisNot.pdf, you could type thisP then TAB to complete the file name in the command prompt without needing to type the whole filename.

IntelliJ - File watchers: wrong output of macros

I am trying to setup a file watcher for scss files which is working on files with a filename not starting with _.
But if I have a file named _file_name.scss the output of any macros that include the filename will be file.name.scss.
The first _ is removed and following ones are replaced by ..
Even though in the insert macros selection tool I can see that the output when you select a macro is correct.
Like $FilePathRelativeToProjectRoot$ will display mypath/_file_name.scss in the selection tool but then my command from this file watcher will output mypath/file.name.scss.
Am I missing a parameter here ?
Full configuration:
For me, existing file names are not changed when using similar file watcher. But files with names starting the _ are not prettified, the main .scss that includes them is processed instead.
To avoid this, try adding COMPILE_PARTIAL=true variable to your file watcher settings:
Also, make sure that Track only root files is off.
See the comments in https://youtrack.jetbrains.com/issue/WEB-13459

load file with csv extension in ssis

I have to load file with csv extension from one particular folder to data base in ssis. file name is not known but folder and extension is fixed.
To load the content of a file, the file name with folder path is required else the connection manager can not be validated and configured.
The easiest way is to get file name is using a For Each Loop container:
Select the option [Foreach File Enumerator]
Provide the Folder path and extension (like *.csv) you already have.
Get the File Name in a variable and use it within the Source of the data flow task within the For each Loop container.
Refer

BigQuery loading batch folders error

I'm trying to load group of folders files in one time with when
i set
sourceURI = 'gs://ybbi/bi_landing_zone/files_to_load/app/reports/app_network_analytics_report/201409011*'
all the folders that i'm want to load start with 20140911
but i get the error:
ERROR: Invalid path: gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/
20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0 is one of these folders(don't know why it's print the all folder name of this specific folder)
in some other folder tree cases it's works, but in this specific folder tree it's return the same error .
i know that cloud storage don't have real folders and it's part of the name of the object, but you understand what i mean.
is it bug?
Without more information, what it looks like is that you have a object file called gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/ that is not a csv/json file. Some tools may create these dummy files in order to simulate directories. BigQuery requires all objects that match the input glob path to be importable files.
One solution would be to change the glob path to include a narrower set of files. You can pass multiple paths if that makes things easier. For example, you could pass
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/*
and
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_some_other_path/*

How to compute destination path for a file in InnoSetup dynamicaly?

I need to compute destination path for a file before copying. If the path does not exist I won't copy the file during installation.
Is this possible?
For example, can I call some computepath.exe an store the result into a variable?
You do not need to call a external program for that. Almost any computation can be done using pascal script, and you can then use the FileOrDirExists() function to determine if the path exists.
If that is not enough, you can take a different approach: extract the file to a temporary directory and call a computepathandcopy.exe passing the temp file name as a parameter. The exe will compute the path, check if it exists and perform the file copy.