I need to compute destination path for a file before copying. If the path does not exist I won't copy the file during installation.
Is this possible?
For example, can I call some computepath.exe an store the result into a variable?
You do not need to call a external program for that. Almost any computation can be done using pascal script, and you can then use the FileOrDirExists() function to determine if the path exists.
If that is not enough, you can take a different approach: extract the file to a temporary directory and call a computepathandcopy.exe passing the temp file name as a parameter. The exe will compute the path, check if it exists and perform the file copy.
Related
I have to load file with csv extension from one particular folder to data base in ssis. file name is not known but folder and extension is fixed.
To load the content of a file, the file name with folder path is required else the connection manager can not be validated and configured.
The easiest way is to get file name is using a For Each Loop container:
Select the option [Foreach File Enumerator]
Provide the Folder path and extension (like *.csv) you already have.
Get the File Name in a variable and use it within the Source of the data flow task within the For each Loop container.
Refer
How can I find out (with Windows a batch command), if, for example, a variable starts with ABC?
I know that I can search for variables if I know the whole content (if "%variable%"=="abc"), but I want that it only looks after the beginning.
I also need it to find out where the batch file is located, so if there is a other command that reveals the file's location, please let me know.
Use the variable substring syntax:
IF "%variable:~0,3%"=="ABC" [...]
If you need the path to the batch file without the batch file name, you can use the variable:
%~dp0
Syntax for this is explained in the help for the for command, although this variable syntax extends beyond just the for command syntax.
to find batch file location use %0 (gives full patch to current batch file) or %CD% variable which gives local directory
is it possible to load module from file with extension other than .lua?
require("grid.txt") results in:
module 'grid.txt' not found:
no field package.preload['grid.txt']
no file './grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt/init.lua'
no file '/usr/local/lib/lua/5.1/grid/txt.lua'
no file '/usr/local/lib/lua/5.1/grid/txt/init.lua'
no file './grid/txt.so'
no file '/usr/local/lib/lua/5.1/grid/txt.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
no file './grid.so'
no file '/usr/local/lib/lua/5.1/grid.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
I suspect that it's somehow possible to load the script into package.preaload['grid.txt'] (whatever that is) before calling require?
It depends on what you mean by load.
If you want to execute the code in a file named grid.txt in the current directory, then just do dofile"grid.txt". If grid.txt is in a different directory, give a path to it.
If you want to use the path search that require performs, then add a template for .txt in package.path, with the correct path and then do require"grid". Note the absence of suffix: require loads modules identified by names, not by paths.
If you want require("grid.txt") to work should someone try that then yes, you'll need to manually loadfile and run the script and put whatever it returns (or whatever require is documented to return when the module doesn't return anything) into package.loaded["grid.txt"].
Alternatively, you could write your own loader just for entries like this which you set into package.preload["grid.txt"] which finds and loads/runs the file or, more generically, you could write yourself a loader function, insert it into package.loaders, and then let it do its job whenever it sees a "*.txt" module come its way.
I'm attempting to create a process to import data. I created the entire process and it works, but I'm having trouble creating the variable to find the file name of the csv i want to import automatically. Each time a new csv is uploaded to me it has a timestamp on it. I want to be able to grab that file no matter what the name is and do work to it.
So for example this week the file name would be
filename_4-14-2014.csv
And next week
filename_4_21_2014.csv
And so on into eternity. . .
Is there a way to create a variable that picks up the full file name even though its changing?
After doing some poking around, I've discovered the following...
You can use a file system task to perform the copy operation I was referring to. You can set the input file and the output file as variables. This way you can always know that the file you use for import is always named the same, and has the right data.
You just need to add the variables and a File System Task to your package.
Ok so to accomplish what I wanted I created a Foreach Loop Container. Using the foreach loop container I had it look for any files ending with .csv in my specified folder by using a wildcard [denoted by asterisk: *.csv] .
Within the Foreach Loop container is as follows.
Step 1: File System Task - rename file.
Step 2: Data Flow Task - Import data to sql
Step 3: File System Task - Copy the file to another folder, append datetime to filename
Step 4: File System Task - Delete source file.
I used variables to get all the file and folder names plus datetimes.
[Question] Does Session::RemoveFiles() remove files in sub directory of source directory? If not, how to implement this ability?
(Please do not ask me why I have the remote directory as /C/testTransfer/. The code just for testing purpose.)
I have a SFTP program using WinSCP .Net assembly. Program language is C++/CLI. It opens up a work file. The file contains many lines of FTP instructions.
One type of instruction I have to handle is to transfer *.txt from source directory. The source directory may contain sub directories which may contain .txt as well. Once transfer is successful, delete the source files.
I use Session::GetFiles() for the transfer. It correctly transfer all .txt files (/C/testTransfer/*.txt), even those in sub directories (/C/testTransfer/sub/*.txt), in the source to the destination.
transferOptions->FileMask = "*.txt";
session->GetFiles("/C/testTransfer", "C:\\temp\\win", false, transferOption);
Now to remove, I use session->RemoveFiles("/C/testTransfer/*.txt"). I only see *.txt in the source (/C/testTransfer/*.txt), but not in the sub directory (/C/testTransfer/sub/*.txt), are removed.
The Session::RemoveFiles can remove even files in subdirectories in general. But not this way with wildcard, because WinSCP will not descend to subdirectories that do not match the wildcard (*.txt). Also note that even if you do not need the wildcard, the Session::RemoveFiles would remove even the subdirectories themselves, what I'm not sure you want it to.
Though you have other (and better = more safe) options:
Use the remove parameter of the Session::GetFiles method to instruct it to remove source file after successful transfer.
If you need to delete source files transactionally (=only after download of all files succeed), iterate the TransferOperationResult::Transfers returned by Session::GetFiles and call the Session::RemoveFiles for each (unless the TransferEventArgs::Error is not null).
Use the TransferEventArgs::FileName to get a file path to pass to the Session::RemoveFiles. Use the RemotePath::EscapeFileMask to escape the file name before passing it to the Session::RemoveFiles.
There's a similar full example available for Moving local files to different location after successful upload.
To recursively delete files matching a wildcard in a standalone operation (not after downloading the same files), use the Session::EnumerateRemoteFiles. Pass your wildcard to its mask argument. Use the EnumerationOptions.AllDirectories option for recursion.
Call the Session::RemoveFiles for each returned file. Use the RemotePath::EscapeFileMask to escape the file name before passing it to the Session::RemoveFiles.