I have a column with numbers with various lengths such as 50055, 1055,155 etc. How can I add a decimal before the last 2nd place of each so that it would be 500.55, 10.55, and 1.55?
I tried using replace by finding the last 2 numbers and replace it with .||last 2 number. That doesn't always work because of a possibility of multiple repetition of the same sequence in the same string.
replace(round(v_num/2),substr(round(v_num/2),-2),'.'||substr(round(v_num/2),-2))
You would divide by 100:
select v_num / 100
You can convert this into a string, if you want.
I want to extract the lines that contain numbers which exceed a specific Integer for example if I have the following code
INTEGER ( 16 )
INTEGER ( 16 )
INTEGER ( 6 )
INTEGER ( 18 )
I want to keep only the lines that contain INTEGER (n <= 16), so I want to have as an output
INTEGER ( 16 )
INTEGER ( 16 )
INTEGER ( 6 )
If you can be sure that there are always spaces before and after the digits, then you could use this awk:
awk '$3 <= 16' file
This simply checks whether the third field is less than or equal to 16.
However, it might be safer to use something like this:
awk -F'[^0-9]+' '/INTEGER *\( *[0-9]+ *\)/ && $2 <= 16' file
This sets the field separator to any number of non-digit characters, so the first field is empty and the second field contains the digits you're interested in. If the line matches the pattern (which is flexible with respect to spacing) and the digits are less than or equal to 16, the line is printed.
I'm a very new beginner to awk. I'm reading over a simple loop statement where by using the split() command I have defined the 'a' array before the beginning of the loop and the 'b' array in each iteration of the loop.
Can someone help me with the statement below? I put it in to perspective since I know what the splits and for loop are doing.
split($2,a,":");
for(i=1,i<length(a),i++){
split(a[i],b," ")
#I don't know what the statement below this line does.
#It appears to be creating a multidimensional thing?
x[b[1]]=b[2]
It looks like a single dimension array. Let's say if you had a text file with one line like this:
1|age 10:fname john:lname smith|12345
Assuming a delimiter of pipe symbol |, your $2 is going to be age 10:fname john:lname smith.
Split that by colon : will give 3 items: age 10, fname john and lname smith
for loops through these 3 items. It takes the first item age 10
It is split that up by space. b[1] is now age, b[2] is now 10
Array x['age'] is set to 10
Similarly, x['lname'] is set to smith and x['fname'] is set to 'john'
x[b[1]]=b[2]
It's not creating a multidementional array.
x is a array. it's assigning the value of array key b[z] to b[z]. z is a positive integer I just used here.
Please help revise the title and the post if needed, thanks.
In short, I would like to firstly group lines with a unique value in the first field and accumulate the occurrences of a specific value in the other field in the underlying group of lines. If the sum of occurrences doesn't meet the self-defined threshold, the lines in the group should be ignored.
Specifically, with input
111,1,P,1
111,1,P,1
111,1,P,0
111,1,M,1
222,1,M,1
222,1,M,0
333,1,P,0
333,1,P,1
444,1,M,1
444,1,M,1
444,0,M,0
555,1,P,1
666,1,P,0
the desired output should be
111,1,P,1
111,1,P,1
111,1,P,0
111,1,M,1
333,1,P,0
333,1,P,1
555,1,P,1
666,1,P,0
meaning that "because the unique values in the first field 222 and 444 don't have at least one (which can be any desired threshold) P in the third field, lines corresponding to 222 and 444 are ignored."
Furthermore, this should be done without editing the original file and have to be combined with the solved issue Split CSV to Multiple Files Containing a Set Number of Unique Field Values. By doing this, a few lines will not be involved in the resulted split files.
I believe this one-liner does what you want:
$ awk -F, '{a[$1,++c[$1]]=$0}$3=="P"{p[$1]}END{for(i in c)if(i in p)for(j=1;j<=c[i];++j)print a[i,j]}' file
111,1,P,1
111,1,P,1
111,1,P,0
111,1,M,1
333,1,P,0
333,1,P,1
555,1,P,1
666,1,P,0
Array a, keeps track of all the lines in the file, grouping them by the first field and a count c which we use later. If the third field contains a P, set a key in the p array.
After processing the entire file, loop through all the values of the first field. If a key has been set in p for the value, then print the lines from a.
You mention a threshold number of entries in your question. If by that, you mean that there must be N occurrences of "P" in order for the lines to be printed, you could change {p[$1]} to {++p[$1]}, then change if(i in p) to if(p[i]>=N) in the END block.
I am holding the number in character format in abap. Because I have to take the minus from right to left. So I have to put the number to character and shift or using function 'CLOI_PUT_SIGN_IN_FRONT' I'm moving minus character to left.
But after assigning number to character it doesn't hold the points. I mean my number is;
1.432- (as integer)
-1432 (as character)
I want;
-1.432 (as character)
is there a shortcut for this or should I append some string operations.
Edit:
Here is what I'm doing now.
data: mustbak_t(10) TYPE c,
mustbak like zsomething-menge.
select single menge from zsomething into mustbak where something eq something.
mustbak_t = mustbak.
CALL FUNCTION 'CLOI_PUT_SIGN_IN_FRONT'
CHANGING
VALUE = mustbak_t.
write: mustbak_t.
If you're on a recent release, you could use string templates - you'll have to add some black magic to use a country that confoirms to your decimal settings, though:
DATA: l_country TYPE t005x-land,
l_text TYPE c LENGTH 15,
l_num TYPE p LENGTH 6.
SELECT SINGLE land
INTO l_country
FROM t005x
WHERE xdezp = space.
l_num = '-123456'.
l_text = |{ l_num COUNTRY = l_country }|.
WRITE: / l_text.
In this case, you need a country code to pass to the COUNTRY parameter as described in the format options. The values of the individual fields, namely T005X-XDEZP are described in detail in the country-specific formats.
tl;dr = Find any country where they use "." as a thousands separator and "," as a decimal separator and use that country settings to format the number.
You could also use classic formatting templates, but they are hard to handle unless you have a fixed-length output value:
DATA: l_text TYPE c LENGTH 15,
l_num TYPE p LENGTH 6 DECIMALS 2.
l_num = '-1234.56'.
WRITE l_num TO l_text USING EDIT MASK 'RRV________.__'.
CONDENSE l_text NO-GAPS.
WRITE: / l_text.
Here's another way, which i finally got working:
DATA: characters(18) TYPE c,
ints TYPE i VALUE -222333444.
WRITE ints TO characters. "This is it... nothing more to say.
CALL FUNCTION 'CLOI_PUT_SIGN_IN_FRONT'
CHANGING
value = characters.
WRITE characters.
Since integers are automatically printed with the thousands separator, you can simply output them to a char data object directly using WRITE TO with no aditions..... lol
DATA: currency TYPE cdcurr,
characters(18) TYPE c,
ints TYPE i VALUE -200000.
currency = ints.
WRITE currency TO characters CURRENCY 'USD' DECIMALS 0.
CALL FUNCTION 'CLOI_PUT_SIGN_IN_FRONT'
CHANGING
value = characters.
.
WRITE: / 'example',characters.
This prints your integer as specified. Must be apparently converted to a currency during the process.