VBA countif statement only returns 0 - vba

I'm working on a macro that is supposed to count the number of times the term "GM" appears in a column. I decided to use a countif statement, as I have before and it worked well. However, for some reason when I run my code it outputs 0 every time, which definitely is not correct. I've run this same code with other columns and strings and it has worked fine, but for some reason if I search this certain column for the term "GM" it fails. The only thing I can think of is maybe countif only works if the string you're searching for is the only string in a cell, because in all cases where this is true the code works fine. In this particular case the string I'm looking for is not the only string in the cell and the code is failing. I've tried to find more info on whether or not this is true but I can't find anything online. Here's the code if anyone would like to take a look:
Function OemRequest() As Long
Sheets("CS-CRM Raw Data").Select
Sheets("CS-CRM Raw Data").Unprotect
Dim oem As Long
Dim LastRow As Long
Dim LastColumn As Long
'Determines size of table in document
LastRow = Range("A" & Rows.Count).End(xlUp).row
LastColumn = Cells(1, Columns.Count).End(xlToLeft).Column
oem = Application.WorksheetFunction.CountIf(Range(2 & "2:" & 2 & LastRow), "gm")
OemRequest = oem
End Function

You are correct that the COUNTIF as written will only match cells where the whole content is "gm". The criteria in the COUNTIF function will also accept wildcards, so to match on cells that contain "gm" do:
.CountIf(Range(2 & "2:" & 2 & LastRow), "*gm*")
Update
As you noted there is also an issue with your Range call. As it is, the expression inside the parens will evaluate to "22:2<LastRow>" (where <LastRow> is the value of the LastRow variable).
The 2's in there should be a variable containing the column name you're interested in. Something like:
Dim col as String
col = "B"
... Range(col & "2:" & col & LastRow) ...
This will evaluate to "B2:B<LastRow>", which is what you want.

Another possibility:
oem = WorksheetFunction.CountIf(Columns(LastColumn).Cells(2).Resize(rowsize:=LastRow - 1), "gm")
This will count cells containing "gm" (use wilcards if needed) in the LAST column of the table, except the one in the first row. (It assumes the table upper left corner is in cell "A1")
Of course you can create a variable if you would like to count any other column:
Dim lngCol as Long
lngCol = ...
oem = WorksheetFunction.CountIf(Columns(lngCol).Cells(2).Resize(rowsize:=LastRow - 1), "gm")

I think in this way
Sub Main()
Application.ScreenUpdating = 0
Dim Count As Double
Range("C1").Activate 'Firs row in the column
Do While ActiveCell.Value <> ""
If InStr(ActiveCell.Value, "MyText") Then
Count = Count + 1
End If
ActiveCell.Offset(1, 0).Activate
Loop
Application.ScreenUpdating = 1
End Sub
This will work, only if the data cell is not empty, if there is an empty space in middle of the worksheet, do this:
Sub Main()
Application.ScreenUpdating = 0
Dim Count As Double
Range("C1").Activate
Do While ActiveCell.Row <> Rows.Count ' This wil evaluate all the rows in the 'C' Column
If InStr(ActiveCell.Value, "MyText") Then
Count = Count + 1
End If
ActiveCell.Offset(1, 0).Activate
Loop
Application.ScreenUpdating = 1
End Sub
Hope it's work for you.

Related

Applying VBA RIGHT to an entire column - Infinite Loop Issue

I have data that I am working to Parse Out that I have imported from approval emails sent in Outlook. At this point I am just importing the CreationTime and the SubjectLine.
For the subject line I am able to use the Split function to separate out most of the data. I then am left with Job Codes in Column B and Position numbers in Column C which includes the text: "Job Codes: XXXX" and the four digit job code number and "PN XXXX" and either a four digit or 6 digit position number. I am trying to use the Right functionality to loop through the entire column and reformat the column just to show only the four digit job code number for Column B and either just the 4 digit or 6 digit position number (the actual numbers) for Column C
For Job Code Column B:
Currently my code works for Shortening the Job Codes but it involves adding a column, putting the RIGHT formula in that column for the shortened Job Code, then copying and pasting the formula as values back into the column and then deleting the original column.
The problem- Works but perhaps not the most efficient with a larger data set (currently 200 rows but will have 2000 or more)
Code:
Sub ShortenJobCodes()
Application.ScreenUpdating = False
Const R4Col = "=RIGHT(RC3,4)"
Dim oRng As Range
Dim LastRow As Long
Range("B1").EntireColumn.Insert
LastRow = Cells(Rows.Count, "A").End(xlUp).Row
Set oRng = Range("B:B")
Range(oRng, Cells(LastRow, "B")).FormulaR1C1 = R4Col
Set oRng = Nothing
Columns("B").Select
Selection.Copy
Selection.PasteSpecial Paste:=xlPasteValues
Range("C1").EntireColumn.Delete
Application.ScreenUpdating = True
End Sub
For Position Numbers Column C:
Currently I have mirrored the above code but added in an if statement using LEN to count if the characters are less than 8, if so then insert one RIGHT function if not insert the other RIGHT function. This also involves adding an additional column putting the RIGHT formula in that column for the shortened Position Number(Eliminating all but just the number), then copying and pasting the formula as values back into the column and then deleting the original column.
Problem - This works but seems to take forever to process and in fact looks like it is in an infinite loop. When I Esc out of it, it does add the column and then input the proper RIGHT formula (leaving just the numeric values) but the sub never seems to end, nor does it copy and paste the formulas as values or delete the original column. As noted above I realize this is likely a more efficient way to do this but I have tried a bunch of options without any luck.
I am realizing part of the loop might be due to the range itself being an entire column but I cannot find a way to stop that with the last row (even though I have a count in there).
Code:
Sub ShortenPositionNumbers()
Application.ScreenUpdating = False
Const R4Col = "=RIGHT(RC4,4)"
Const R6Col = "=RIGHT(RC4,6)"
Dim oRng As Range
Dim rVal As String
Dim y As Integer
Dim selCol As Range
Dim LastRow As Long
Range("C1").EntireColumn.Insert
LastRow = Cells(Rows.Count, "A").End(xlUp).Row
Set selCol = Range("D:D")
For Each oRng In selCol
oRng.Select
rVal = oRng.Value
If Len(oRng.Value) > 8 Then
oRng.Offset(0, -1).FormulaR1C1 = R6Col
Else
oRng.Offset(0, -1).FormulaR1C1 = R4Col
End If
Next
Set oRng = Nothing
Columns("C").Select
Selection.Copy
Selection.PasteSpecial Paste:=xlPasteValues
Range("D1").EntireColumn.Delete
Application.ScreenUpdating = True
End Sub
Major Question: Is there a way to use RIGHT/TRIM/LEN/LEFT functions to do this within a cell without having to add columns/delete columns and insert functions?
There are a few things you can do here to speed up your code. I'm only going to reference the second code block as you can apply similar logic to the first.
The first issue is that you create a LastRow variable but never reference it again. It looks like you meant to use this in the selCol range. You should change that line to Set selCol = Range("C1:C" & lastRow). This way, when you loop through the rows you only loop through the used rows.
Next, in the For-Each loop you Select every cell you loop through. There really isn't any reason to do this and takes substantially longer. You then create the variable rVal but never use it again. A better way to set up the loop is as follows.
For Each oRng in selCol
rVal = oRng.Value
If Len(rVal) > 8 Then
oRng.Value = Right(rVal, 6)
Else
oRng.Value = Right(rVal, 4)
End If
Next
This is much cleaner and no longer requires creating columns or copying and pasting.
Try this, it uses Evaluate and no loops or added columns.
Sub ShortenPositionNumbers()
Application.ScreenUpdating = False
Dim selCol As Range
Dim LastRow As Long
With ActiveSheet
LastRow = .Cells(Rows.Count, "A").End(xlUp).Row
Set selCol = .Range(.Cells(1, 3), .Cells(LastRow, 3))
selCol.Value = .Evaluate("INDEX(IF(LEN(" & selCol.Address(0, 0) & ")>8,RIGHT(" & selCol.Address(0, 0) & ",6),RIGHT(" & selCol.Address(0, 0) & ",4)),)")
End With
Application.ScreenUpdating = True
End Sub
Or work with arrays
Sub ShortenPositionNumbers()
Dim data As Variant
Dim i As Long
With Range("C3:C" & Cells(Rows.Count, "A").End(xlUp).Row)
data = Application.Transpose(.Value)
For i = LBound(data) to UBound(data)
If Len(data(i)) > 8 Then
data(i) = RIGHT(data(i),6)
Else
data(i) = RIGHT(data(i),4)
End If
Next
.Value = Application.Transpose(data)
End With
End Sub

VBA EXCEL Range syntax

I don't understand syntax for range.
Why does this work:
For i = 1 To 10
Range("A" & i & ":D" & i).Copy
Next
But this doesn't work:
For i = 2 To lastRow
num = WorksheetFunction.Match(Cells(i, 1), Range("A" & lastRow), 0)
Next
Why do I need to use
For i = 2 To lastRow
'num = WorksheetFunction.Match(Cells(i, 1), Range("A1:A" & lastRow), 0)
Next
What A1:A mean? Why can't I use
Range("A" & lastRow), 0
There is nothing wrong with your syntax and your code should've work just fine.
The problem with using worksheet function like Match, Vlookup and other look up functions is that if the value being searched is not found, it throws up an error.
In your case, you are trying to search multiple values in just one cell.
So let us say your lastrow is 9. You're code will loop from Cell(2,1) to Cell(9,1) checking if it is within Range("A" & lastrow) or Range("A9").
If your values from Cell(2,1) through Cell(9,1) is the same as your value in Range("A9"), you won't get an error.
Now, if you use Range("A1:A" & lastrow), it will surely work cause you are trying to match every element of that said range to itself and surely a match will be found.
WorksheetFunction.Match(Cells(2,1), Range("A1:A9")) 'will return 2
WorksheetFunction.Match(Cells(3,1), Range("A1:A9")) 'will return 3
'
'
'And so on if all elements are unique
It doesn't matter if you use Range("A9") or Range("A1:A9").
What matters is that you handle the error in case you did not find a match.
One way is to use On Error Resume Next and On Error Goto 0 like this:
Sub ject()
Dim num As Variant
Dim i As Long, lastrow As Long: lastrow = 9
For i = 2 To lastrow
On Error Resume Next
num = WorksheetFunction.Match(Cells(i, 1), Range("A" & lastrow), 0)
If Err.Number <> 0 Then num = "Not Found"
On Error GoTo 0
Debug.Print num
Next
End Sub
Another way is to use Application.Match over WorksheetFunction.Match like this:
Sub ject()
Dim num As Variant
Dim i As Long, lastrow As Long: lastrow = 9
For i = 2 To lastrow
num = Application.Match(Cells(i, 1), Range("A" & lastrow), 0)
Debug.Print num
'If Not IsError(num) Then Debug.Print num Else Debug.Print "Not Found"
Next
End Sub
Application.Match works the same way but it doesn't error out when it returns #N/A. So you can assign it's value in a Variant variable and use it later in the code without any problem. Better yet, use IsError test to check if a value is not found as seen above in the commented lines.
In both cases above, I used a Variant type num variable.
Main reason is for it to handle any other value if in case no match is found.
As for the Range Syntax, don't be confused, it is fairly simple.
Refer to below examples.
Single Cell - All refer to A1
Cells(1,1) ' Using Cell property where you indicate row and column
Cells(1) ' Using cell property but using just the cell index
Range("A1") ' Omits the optional [Cell2] argument
Don't be confused with using cell index. It is like you are numbering all cells from left to right, top to bottom.
Cells(16385) ' refer to A2
Range of contiguous cell - All refer to A1:A10
Range("A1:A10") ' Classic
Range("A1", "A10") ' or below
Range(Cells(1, 1), Cells(10, 1))
Above uses the same syntax Range(Cell1,[Cell2]) wherein the first one, omits the optional argument [Cell2]. And because of that, below also works:
Range("A1:A5","A6:A10")
Range("A1", "A8:A10")
Range("A1:A2", "A10")
Non-Contiguous cells - All refer to A1, A3, A5, A7, A9
Range("A1,A3,A5,A7,A9") ' Classic
Without any specific details about the error, I assume that Match does not return the value you expect, but rather an #N/A error. Match has the syntax
=match(lookup_value, lookup_range, match_type)
The lookup_range typically consists of a range of several cells, either a column with several rows or a row with several columns.
In your formula, you have only one cell in the lookup_range. Let's say Lastrow is 10. The first three runs of the loop produce the formula
=Match(A2,A10,0)
=Match(A3,A10,0)
=Match(A4,A10,0)
It is a valid formula but in most cases the result won't be a match but an error. Whereas what you probably want is
=Match(A2,A1:A10,0)
Looking again at your code, stitch it together and find why you need A1:A as a string constant in your formula:
For i = 2 To lastRow
num = WorksheetFunction.Match(Cells(i, 1), Range("A1:A" & lastRow), 0)
Next

VBA find cell of closest value

I have an excel file that looks like:
12123 51212
12123.5 45832
12124 37656
12124.5 32987
12125 42445
and so on, where column A is always 0.5 increasing and column B has a certain output.
Now I have a specific value in cell E2, say 12124,23 and I want a VBA code to return, in this case, that the best matching value is in cell A3, because I need this cell location in further code, I don't need the corresponding value in column B. I don't know how to start, however. The file can be up to 30000 rows big.
I'd only like to know first which method to use, then I will try to write the code myself of course :)
JV
You don't have to use VBA for your problem, Excel will do it perfectly fine!
Try this
=vlookup(E2;A:A;2;true)
and for what you are trying to do, you HAVE TO sort your A column in an ascending fashion, or else you will get an error!
And if you do need that in VBA,
a simple for+if structure with a test like this
Function pr24(ByVal Value_To_Match As Double) As Range
For i = 2 To ActiveSheet.Cells(Rows.Count, 1).End(xlUp).Row
If Cells(i, 1) > Value_To_Match Then
If Abs(Cells(i - 1, 1) - Value_To_Match) >= Abs(Cells(i, 1) - Value_To_Match) Then
pr24 = Range(Cells(i, 1))
Else
pr24 = Range(Cells(i - 1, 1))
End If
Exit For
Else
End If
Next i
End Function
or you can use the worksheet function Vlookup
Application.WorksheetFunction.VLOOKUP()
You could use VLOOKUP function for this:-
Application.WorksheetFunction.VLOOKUP(lookup_value, table_array, column_index, range_lookup)
Set your values as below:-
lookup_value = 12124.23
table_array = would be the range Ax:Bx containing your values
column_index = 2 (the second column of table_array)
range_lookup = true
Setting range_lookup to true means that if the vlookup doesn't find the exact value it will return the closest match.
Note this will only work if the values in column A are sorted in ascending order.
Hope this helps.
You need to sort your data in column A first (smallest to largest), and then you can use a simple lookup formula:
=LOOKUP(E2,A:A)
If you don't want to sort the data, then you can use a VBA loop like so - however this is very inefficient - you should always use worksheet formulas where you can:
Sub SO()
Dim resultCell As Excel.Range
Dim checkCell As Double
Dim bestDiff As Double
checkCell = Range("E2").Value
bestDiff = checkCell
For i = 1 To Range("A" & Rows.count).End(xlUp).Row
If Range("A" & i).Value <= checkCell Then
If (checkCell - Range("A" & i).Value) < bestDiff Then
bestDiff = checkCell - Range("A" & i)
Set resultCell = Range("A" & i)
End If
End If
Next i
MsgBox "Best match is in " & resultCell.Address
Set resultCell = Nothing
End Sub
You dont'need VBA, a call co VLOOKUP Excel function will do the trick; remember to set the last parameter to true, to find a non exact match with the searched value
It should be like something similar to:
= VLOOKUP(E2, A:B, 2, true)

Change a cell's format to boldface if the value is over 500

I am using Excel 2010 and trying to add a bunch of rows placing the sum of columns A and B in column C. If the sum is over 500 I would then like to boldface the number in column C. My code below works works mathematically but will not do the bold formatting. Can someone tell me what I am doing wrong? Thank you.
Public Sub addMyRows()
Dim row As Integer 'creates a variable called 'row'
row = 2 'sets row to 2 b/c first row is a title
Do
Cells(row, 3).Formula = "=A" & row & "+B" & row 'the 3 stands for column C.
If ActiveCell.Value > 500 Then Selection.Font.Bold = True
row = row + 1
'loops until it encounters an empty row
Loop Until Len(Cells(row, 1)) = 0
End Sub
Pure VBA approach:
Public Sub AddMyRows()
Dim LRow As Long
Dim Rng As Range, Cell As Range
LRow = Range("A" & Rows.Count).End(xlUp).Row
Set Rng = Range("C2:C" & LRow)
Rng.Formula = "=A2+B2"
For Each Cell In Rng
Cell.Font.Bold = (Cell.Value > 500)
Next Cell
End Sub
Screenshot:
An alternative is conditional formatting.
Hope this helps.
Note: The formula in the block has been edited to reflect #simoco's comment regarding a re-run of the code. This makes the code safer for the times when you need to re-run it. :)

400 Error Excel Macro

I'm trying to run a macro that will delete rows that don't contain a particular value in column B. Here's my code:
Sub deleteRows()
Dim count As Integer
count = Application.WorksheetFunction.CountA(Range("AF:AF"))
Dim i As Integer
i = 21
Do While i <= count
If (Application.WorksheetFunction.IsNumber(Application.WorksheetFunction.Search("OSR Platform", Range("B" & i))) = False) Then
If (Application.WorksheetFunction.IsNumber(Application.WorksheetFunction.Search("IAM", Range("B" & i))) = False) Then
Rows(i).EntireRow.Delete
i = i - 1
count = count - 1
End If
End If
i = i + 1
Loop
End Sub
Now what it SHOULD be doing is the following:
1.) Find the number of rows to go through and set that as count (this works)
2.) Start at row 21 and look for "OSR Platform" and "IAM" in column B [this kind of works (see below)]
3.) If it finds neither, delete the entire row and adjust the count and row number as necessary (this works)
For some reason, whenever the code gets to the first If statement, an error window with a red X pops up that just says "400." As far as I can tell, I have written everything syntactically soundly, but clearly there's something wrong.
You may want to start by looping the other way. When you delete a line, all the previous lines are shifted. You account for this, but a reverse loop is simpler (for me anyways) to understand than keeping track of when I've offset the current position within the loop:
For i = count To 21 Step -1
Also, you're relying too much on Application.WorksheetFunction:
(Application.WorksheetFunction.IsNumber(Application.WorksheetFunction.Search("OSR Platform", Range("B" & i))) = False)
to
InStr(Range("B" & i).value, "OSR Platform") > 0
Application.WorksheetFunction takes much more processing power, and depending on what you are trying to accomplish, this can take a significantly longer amount of time. Also for this suggested change, the code size is reduced and becomes easier to read without it.
Your count can also be obtained without A.WF:
Excel 2000/03: count = Range("AF65536").End(xlUp).Row
Excel 2007/10: count = Range("AF1048576").End(xlUp).Row
Version independent: count = Range("AF" & Rows.Count).End(xlUp).Row
One more thing is that you can do (and should do in this case) is combine your If statements into one.
Making these changes, you end up with:
Sub deleteRows()
Dim count As Integer
count = Range("AF" & Rows.Count).End(xlUp).Row
Dim i As Integer
For i = count To 21 Step -1
If Len(Range("B" & i).value) > 0 Then
If InStr(Range("B" & i).value, "OSR Platform") > 0 Or InStr(Range("B" & i).value, "IAM") > 0 Then
Range("B" & i).Interior.Color = RGB(255, 0, 0)
End If
End If
Next i
End Sub
If this does not help, then can you step through the code line by line. Add a breakpoint, and step through with F8. Highlight the variables in your code, right-click, choose "add Watch...", click "OK", (Here's an excellent resource to help you with your debugging in general) and note the following:
Which line hits the error?
What is the value of i and count when that happens? (add a watch on these variables to help)
This worked for me. It uses AutoFilter, does not require looping or worksheet functions.
Sub DeleteRows()
Dim currentSheet As Excel.Worksheet
Dim rngfilter As Excel.Range
Dim lastrow As Long, lastcolumn As Long
Set currentSheet = ActiveSheet
' get range
lastrow = currentSheet.Cells(Excel.Rows.Count, "AF").End(xlUp).Row
lastcolumn = currentSheet.Cells(1, Excel.Columns.Count).End(xlToLeft).Column
Set rngfilter = currentSheet.Range("A1", currentSheet.Cells(lastrow, lastcolumn))
' filter by column B criteria
rngfilter.AutoFilter Field:=2, Criteria1:="<>*OSR Platform*", Operator:= _
xlAnd, Criteria2:="<>*IAM*"
' delete any visible row greater than row 21 which does not meet above criteria
rngfilter.Offset(21).SpecialCells(xlCellTypeVisible).EntireRow.Delete
' remove autofilter arrows
currentSheet.AutoFilterMode = False
End Sub
This code applies AutoFilter to column B to see which rows contain neither "OSR Platform" nor "IAM" in column B. Then it simply deletes the remaining rows greater than 21. Test it on a copy of your workbook first.
With a huge nod to this OzGrid thread, because I can never remember the proper syntax for selecting visible cells after filtering.