I have an excel file that looks like:
12123 51212
12123.5 45832
12124 37656
12124.5 32987
12125 42445
and so on, where column A is always 0.5 increasing and column B has a certain output.
Now I have a specific value in cell E2, say 12124,23 and I want a VBA code to return, in this case, that the best matching value is in cell A3, because I need this cell location in further code, I don't need the corresponding value in column B. I don't know how to start, however. The file can be up to 30000 rows big.
I'd only like to know first which method to use, then I will try to write the code myself of course :)
JV
You don't have to use VBA for your problem, Excel will do it perfectly fine!
Try this
=vlookup(E2;A:A;2;true)
and for what you are trying to do, you HAVE TO sort your A column in an ascending fashion, or else you will get an error!
And if you do need that in VBA,
a simple for+if structure with a test like this
Function pr24(ByVal Value_To_Match As Double) As Range
For i = 2 To ActiveSheet.Cells(Rows.Count, 1).End(xlUp).Row
If Cells(i, 1) > Value_To_Match Then
If Abs(Cells(i - 1, 1) - Value_To_Match) >= Abs(Cells(i, 1) - Value_To_Match) Then
pr24 = Range(Cells(i, 1))
Else
pr24 = Range(Cells(i - 1, 1))
End If
Exit For
Else
End If
Next i
End Function
or you can use the worksheet function Vlookup
Application.WorksheetFunction.VLOOKUP()
You could use VLOOKUP function for this:-
Application.WorksheetFunction.VLOOKUP(lookup_value, table_array, column_index, range_lookup)
Set your values as below:-
lookup_value = 12124.23
table_array = would be the range Ax:Bx containing your values
column_index = 2 (the second column of table_array)
range_lookup = true
Setting range_lookup to true means that if the vlookup doesn't find the exact value it will return the closest match.
Note this will only work if the values in column A are sorted in ascending order.
Hope this helps.
You need to sort your data in column A first (smallest to largest), and then you can use a simple lookup formula:
=LOOKUP(E2,A:A)
If you don't want to sort the data, then you can use a VBA loop like so - however this is very inefficient - you should always use worksheet formulas where you can:
Sub SO()
Dim resultCell As Excel.Range
Dim checkCell As Double
Dim bestDiff As Double
checkCell = Range("E2").Value
bestDiff = checkCell
For i = 1 To Range("A" & Rows.count).End(xlUp).Row
If Range("A" & i).Value <= checkCell Then
If (checkCell - Range("A" & i).Value) < bestDiff Then
bestDiff = checkCell - Range("A" & i)
Set resultCell = Range("A" & i)
End If
End If
Next i
MsgBox "Best match is in " & resultCell.Address
Set resultCell = Nothing
End Sub
You dont'need VBA, a call co VLOOKUP Excel function will do the trick; remember to set the last parameter to true, to find a non exact match with the searched value
It should be like something similar to:
= VLOOKUP(E2, A:B, 2, true)
Related
I'm trying to implement a macro that looks for the words "TRUE" and "FALSE" in a huge array of data - and then, when found, changes the color of the cells above it.
Specifically, I would like it to color not the TRUE/FALSE-cell, but the 30 cells directly above it. This is where things get tricky... I hope someone can help.
I've tried adapting the below code, but mostly I'm adding it as inspiration at this point.
Sub ChangeColor()
lRow = Range("C" & Rows.Count).End(xlUp).Row
Set MR = Range("C2:C" & lRow)
For Each cell In MR
Select Case cell.Value
Case "Yes"
cell_colour = 4
Case "y"
cell_colour = 4
Case Else
cell_colour = 3
End Select
cell.Interior.ColorIndex = cell_colour
Next
End Sub
Using a datafield array
Looping through a range is always time consuming; this should speed it up.
Caveat: Formatting single cells can maximize file size, so at least I reformat the whole column C to xlColorIndexNone.
Option Explicit
Public Sub Mark30CellsAbove()
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("MySheet")
Dim v As Variant
Dim i As Long, j As Long, n As Long, m As Long, r As Long
Dim Rng As Range
Dim t As Double
' stop watch
t = Timer
' get last row in column C
n = ws.Range("C" & ws.Rows.Count).End(xlUp).Row
' get values to one based 2dim array
v = ws.Range("C1:C" & n).Value
' clear existing colors over the WHOLE column to minimize file size
ws.Range("C:C").Interior.ColorIndex = xlColorIndexNone
' loop through C2:Cn and mark 30 rows before found condition
For i = 2 To n
' check condition, find string "true" or "false"
If InStr(".true.false.", "." & LCase(v(i, 1)) & ".") > 0 Then
' set range block - fixed rows count 30 above found cell
If i < 32 Then ' only in case of less than 30 rows
Set rng = ws.Range("C2:C" & (i - 1))
Else
Set rng = ws.Range("C" & (i - 30) & ":C" & (i - 1))
End If
rng.Interior.ColorIndex = 4
End If
Next i
MsgBox "Time needed: " & Format(Timer - t, "0.00") & " seconds."
End Sub
Of course you could also loop within If - EndIf, just to see this slower method:
If InStr(".true.false.", "." & LCase(v(i, 1)) & ".") > 0 Then
' Always avoid to loop through a range
' For j = i - 1 To i - 30 Step -1
' If j < 2 Then Exit For ' optional escape if one line under title row
' ws.Cells(j, 3).Interior.ColorIndex = 4
' Next
End If
The code that I posted should only highlight cells in column B whose value is different from the corresponding cell in column A. I tested it and it worked OK.
If you want to try conditional formatting:
Select column B, or the part of column B that you want to colour conditionally.
In the following, I will assume that B1 is the active cell within the selection.
On the Home tab of the ribbon, click Conditional Formatting > New Rule...
Select "Use a formula to determine which cells to format".
Enter the formula =B1<>A1
If the active cell is not in row 1, adjust the formula accordingly. For example, if the active cell within the selection is B3, use =B3<>A3
Click Format...
Activate the Fill tab.
Select the desired fill colour.
Click OK until all dialogs have closed.
Change some values in column A and/or B to see the result.
Refer - https://social.technet.microsoft.com/Forums/ie/en-US/2fffa4d8-bbba-473b-9346-5fce8f0728a8/using-vba-to-change-a-cell-colour-based-on-the-information-in-a-different-cell-excel-2010?forum=excel
First you need to check whether the row of the cell is higher than 30 and then it you can offset to change the color:
Thus instead of this line: cell.Interior.ColorIndex = cell_colour
write this:
If cell.Row > 30 Then cell.Offset(-30, 0).Interior.ColorIndex = cell_colour
This may be done without VBA. You should set up two conditional formatting with formulas. First:
=COUNTIF(OFFSET(INDIRECT(ADDRESS(ROW(), COLUMN())),1,0,29,1), "TRUE")>0
and the same for false. To highlight the cell you just need to use Highlight Cell Rules (the top option for CF).
I would do this with conditional formatting
Mark all your data and press "Conditional Formatting". Enter 2 rules with Use a formula...
First rule is for TRUE. Assuming that you start with Col A:
=COUNTIF(A2:A31;TRUE)
The second rule is similar, just exchange TRUE by FALSE. Below the formula, press the "Format" button to set the color.
Explanation:
I reverted the logic: Instead of searching for TRUE/FALSE and then format the cells above, I look for every cell if it has at least one entry TRUE resp. FALSE in the next 30 cells. However, I have to admit I don't know how fast Excel can handle such a large amount of data.
I don't understand syntax for range.
Why does this work:
For i = 1 To 10
Range("A" & i & ":D" & i).Copy
Next
But this doesn't work:
For i = 2 To lastRow
num = WorksheetFunction.Match(Cells(i, 1), Range("A" & lastRow), 0)
Next
Why do I need to use
For i = 2 To lastRow
'num = WorksheetFunction.Match(Cells(i, 1), Range("A1:A" & lastRow), 0)
Next
What A1:A mean? Why can't I use
Range("A" & lastRow), 0
There is nothing wrong with your syntax and your code should've work just fine.
The problem with using worksheet function like Match, Vlookup and other look up functions is that if the value being searched is not found, it throws up an error.
In your case, you are trying to search multiple values in just one cell.
So let us say your lastrow is 9. You're code will loop from Cell(2,1) to Cell(9,1) checking if it is within Range("A" & lastrow) or Range("A9").
If your values from Cell(2,1) through Cell(9,1) is the same as your value in Range("A9"), you won't get an error.
Now, if you use Range("A1:A" & lastrow), it will surely work cause you are trying to match every element of that said range to itself and surely a match will be found.
WorksheetFunction.Match(Cells(2,1), Range("A1:A9")) 'will return 2
WorksheetFunction.Match(Cells(3,1), Range("A1:A9")) 'will return 3
'
'
'And so on if all elements are unique
It doesn't matter if you use Range("A9") or Range("A1:A9").
What matters is that you handle the error in case you did not find a match.
One way is to use On Error Resume Next and On Error Goto 0 like this:
Sub ject()
Dim num As Variant
Dim i As Long, lastrow As Long: lastrow = 9
For i = 2 To lastrow
On Error Resume Next
num = WorksheetFunction.Match(Cells(i, 1), Range("A" & lastrow), 0)
If Err.Number <> 0 Then num = "Not Found"
On Error GoTo 0
Debug.Print num
Next
End Sub
Another way is to use Application.Match over WorksheetFunction.Match like this:
Sub ject()
Dim num As Variant
Dim i As Long, lastrow As Long: lastrow = 9
For i = 2 To lastrow
num = Application.Match(Cells(i, 1), Range("A" & lastrow), 0)
Debug.Print num
'If Not IsError(num) Then Debug.Print num Else Debug.Print "Not Found"
Next
End Sub
Application.Match works the same way but it doesn't error out when it returns #N/A. So you can assign it's value in a Variant variable and use it later in the code without any problem. Better yet, use IsError test to check if a value is not found as seen above in the commented lines.
In both cases above, I used a Variant type num variable.
Main reason is for it to handle any other value if in case no match is found.
As for the Range Syntax, don't be confused, it is fairly simple.
Refer to below examples.
Single Cell - All refer to A1
Cells(1,1) ' Using Cell property where you indicate row and column
Cells(1) ' Using cell property but using just the cell index
Range("A1") ' Omits the optional [Cell2] argument
Don't be confused with using cell index. It is like you are numbering all cells from left to right, top to bottom.
Cells(16385) ' refer to A2
Range of contiguous cell - All refer to A1:A10
Range("A1:A10") ' Classic
Range("A1", "A10") ' or below
Range(Cells(1, 1), Cells(10, 1))
Above uses the same syntax Range(Cell1,[Cell2]) wherein the first one, omits the optional argument [Cell2]. And because of that, below also works:
Range("A1:A5","A6:A10")
Range("A1", "A8:A10")
Range("A1:A2", "A10")
Non-Contiguous cells - All refer to A1, A3, A5, A7, A9
Range("A1,A3,A5,A7,A9") ' Classic
Without any specific details about the error, I assume that Match does not return the value you expect, but rather an #N/A error. Match has the syntax
=match(lookup_value, lookup_range, match_type)
The lookup_range typically consists of a range of several cells, either a column with several rows or a row with several columns.
In your formula, you have only one cell in the lookup_range. Let's say Lastrow is 10. The first three runs of the loop produce the formula
=Match(A2,A10,0)
=Match(A3,A10,0)
=Match(A4,A10,0)
It is a valid formula but in most cases the result won't be a match but an error. Whereas what you probably want is
=Match(A2,A1:A10,0)
Looking again at your code, stitch it together and find why you need A1:A as a string constant in your formula:
For i = 2 To lastRow
num = WorksheetFunction.Match(Cells(i, 1), Range("A1:A" & lastRow), 0)
Next
I'm working on a macro that is supposed to count the number of times the term "GM" appears in a column. I decided to use a countif statement, as I have before and it worked well. However, for some reason when I run my code it outputs 0 every time, which definitely is not correct. I've run this same code with other columns and strings and it has worked fine, but for some reason if I search this certain column for the term "GM" it fails. The only thing I can think of is maybe countif only works if the string you're searching for is the only string in a cell, because in all cases where this is true the code works fine. In this particular case the string I'm looking for is not the only string in the cell and the code is failing. I've tried to find more info on whether or not this is true but I can't find anything online. Here's the code if anyone would like to take a look:
Function OemRequest() As Long
Sheets("CS-CRM Raw Data").Select
Sheets("CS-CRM Raw Data").Unprotect
Dim oem As Long
Dim LastRow As Long
Dim LastColumn As Long
'Determines size of table in document
LastRow = Range("A" & Rows.Count).End(xlUp).row
LastColumn = Cells(1, Columns.Count).End(xlToLeft).Column
oem = Application.WorksheetFunction.CountIf(Range(2 & "2:" & 2 & LastRow), "gm")
OemRequest = oem
End Function
You are correct that the COUNTIF as written will only match cells where the whole content is "gm". The criteria in the COUNTIF function will also accept wildcards, so to match on cells that contain "gm" do:
.CountIf(Range(2 & "2:" & 2 & LastRow), "*gm*")
Update
As you noted there is also an issue with your Range call. As it is, the expression inside the parens will evaluate to "22:2<LastRow>" (where <LastRow> is the value of the LastRow variable).
The 2's in there should be a variable containing the column name you're interested in. Something like:
Dim col as String
col = "B"
... Range(col & "2:" & col & LastRow) ...
This will evaluate to "B2:B<LastRow>", which is what you want.
Another possibility:
oem = WorksheetFunction.CountIf(Columns(LastColumn).Cells(2).Resize(rowsize:=LastRow - 1), "gm")
This will count cells containing "gm" (use wilcards if needed) in the LAST column of the table, except the one in the first row. (It assumes the table upper left corner is in cell "A1")
Of course you can create a variable if you would like to count any other column:
Dim lngCol as Long
lngCol = ...
oem = WorksheetFunction.CountIf(Columns(lngCol).Cells(2).Resize(rowsize:=LastRow - 1), "gm")
I think in this way
Sub Main()
Application.ScreenUpdating = 0
Dim Count As Double
Range("C1").Activate 'Firs row in the column
Do While ActiveCell.Value <> ""
If InStr(ActiveCell.Value, "MyText") Then
Count = Count + 1
End If
ActiveCell.Offset(1, 0).Activate
Loop
Application.ScreenUpdating = 1
End Sub
This will work, only if the data cell is not empty, if there is an empty space in middle of the worksheet, do this:
Sub Main()
Application.ScreenUpdating = 0
Dim Count As Double
Range("C1").Activate
Do While ActiveCell.Row <> Rows.Count ' This wil evaluate all the rows in the 'C' Column
If InStr(ActiveCell.Value, "MyText") Then
Count = Count + 1
End If
ActiveCell.Offset(1, 0).Activate
Loop
Application.ScreenUpdating = 1
End Sub
Hope it's work for you.
So, I'm trying to figure out how to write an Excel macro to populate Column C with either 3 or a 4 depending on the amount of numbers contained in Column B.
I have searched up and down for the right wording to this, but I keep coming up short.
Basically, I need the macro to look at the number of digits in Column B. If there are 12 digits then the number is a UPC, and if there are 13 then the number is an EAN. I then need the macro to populate Column C with a 3 for UPCs and a 4 for EANs. This needs to be for the entire range of rows in the spreadsheet.
Does anyone have any ideas? Thanks a lot in advance!
You don't need to use a dirty old loop, try this (much faster if you have lots of rows):
Sub HTH()
With Sheet1.Range("B1", Cells(Rows.Count, "B").End(xlUp)).Offset(, 1)
.Formula = "=IF(LEN(TRIM(B1))=12,3,IF(LEN(TRIM(B1))=13,4,""""))"
.Value = .Value
End With
End Sub
Or use a user defined function, which has the advantage of changing when the data in column B is updated.
Better yet just use a formula, you don't really need VBA.
Alternative VBA Method (looping the fast way):
Sub HTH()
Dim vArray As Variant
Dim lCnt As Long
With Range("B1", Cells(Rows.Count, "B").End(xlUp))
vArray = .Value
For lCnt = 1 To UBound(vArray, 1)
Select Case Len(Trim(vArray(lCnt, 1)))
Case 12: vArray(lCnt, 1) = 3
Case 13: vArray(lCnt, 1) = 4
Case Else:
End Select
Next lCnt
.Offset(, 1).Value = vArray
End With
End Sub
You can get the length of a cell's value by using Len() like this Len(Range("A1")) for example.
Now you just need to loop through your column and look at each value. If you look for the last used cell and loop only through that range your loop will be faster.
Here is how I would do it:
sub TestUPC()
With ActiveSheet
LastRow = .Cells(.Rows.Count, "B").End(xlUp).Row
End With
Dim rRng As Range
Set rRng = Range("B1:B" & LastRow)
For Each cell In rRng.Cells
If Len(Trim(cell))=12 then
cell.Offset(0, 1).Value = 3
ElseIf Len(Trim(cell))=13 then
cell.Offset(0, 1).Value = 4
End If
Next
End Sub
An in cell equation could look like this:
=IF(LEN(B1)=12,3,IF(LEN(B1)=13,4," "))
As suggested in the comments you might want to test for spaces depending on your data:
=IF(LEN(TRIM(A1))=12,3,IF(LEN(TRIM(A1))=13,4," "))
This program is to convert a column of data from cumulative to non-cumulative. On my sheet I have A1, B1, and C1 with the text Non-Cumulative, Cumulative, and Converted, respectively. I have numbers 1 to 10 beneath A1, then them summed cumulatively beneath B1. C1 is where I want to convert column B back to non-cumulative.
The IsNumeric is used to make the first row of data in C equal to the first row of data in B. It should detect that the title is above the number it is evaluating, thus knowing that no calculations have to be performed. For the rest of them, it'll see that the number above the one it is evaluating is a number, and thus the calculation has to be done.
My problem is that it isn't working. I think the reason is because IsNumeric() keeps coming back as false. Is there a different function I should be using? Do cell references not work in IsNumeric?
Here's the program!
Option Explicit
Dim i As Variant
Sub Conversion()
Sheets("Test Sheet").Select
For i = 1 To 10
If IsNumeric("B" & i) = False Then
Range("C" & i + 1) = Range("B" & i + 1)
Else: Range("C" & i + 1) = Range("B" & i + 1) - Range("B" & i - 1)
End If
Next
End Sub
The way you wrote your code is logical, just a minor syntax changes you need initially. However,
It's also best to check if the range is empty first...
Then check on if the value is numeric.
Better even, if you set the Range into a Range object and use offset
Code:
Option Explicit '-- great that you use explicit declaration :)
Sub Conversion()
Dim i As Integer '-- integer is good enough
Dim rngRange as Range
'-- try not to select anything. And for a cleaner code
Set rngRange = Sheets("Test Sheet").Range("B1")
For i = 1 To 10
If (rangeRange.Offset(i,0).value) <> "" then '-- check for non-empty
If IsNumeric(rangeRange.Offset(i,0).value) = False Then
rangeRange.Offset(i+1,1) = rangeRange.Offset(i+1,0)
Else
rangeRange.Offset(i+1,1) = rangeRange.Offset(i+1,0) - rangeRange.Offset(i-1,0)
End If
End if
Next i '-- loop
End Sub
To make your code more dynamic:
Another suggestion, you may simply Application.WorkSheetFunction.Transpose() the entire B column range that you need to validate into a variant array
Process the array and Transpose back to the Range with column B and C.
By doing so, you may omit setting for loop size manually but setting it using Lower and Upper bound of the array ;)
You need to check if the range of B i is numeric, not the string "B" & i
and rather than selecting the sheet, simply using a parent identifier like:
sheets("sheet1").range("B" & i)
This will help you avoid errors in your code
For i = 1 To 10
If IsNumeric(sheets("test sheet").range("B" & i).value) = False Then
Range("C" & i + 1) = Range("B" & i + 1)
Else: Range("C" & i + 1) = Range("B" & i + 1) - Range("B" & i - 1)
End If
Next