How to get duplicate values in all rows filtering by one column - sql

Question

Here is what my table looks like.
Person Date Entry
Person1 05-20-14 142
Person2 05-20-14 443
Person1 05-21-14 248
Person1 05-21-14 142
I need two things.
First the number of times a Person made an entry for the first time.
I tried doing it with these queries. But the problem is I need this information per day.
That is if I query for 05/21, I need to see output
"Person1 1"
142 wont be included because it already exists.
In my query, I am filtering by date already, so I am not sure how to go out and search in the rest of the dates values. Here is what I have.
SELECT PERSON, Count(distinct Entry)
from [table]
where date >= 05/21/2014
and date < 05/22/2014
group by person
order by person.
This gives me
Person1 2
Both 248 and 142 are considered here. How do I look for 142 was an entry already made in previous dates. I am not very good at nested queries.
Thanks for looking.

Answer 1

Will this solve your problem or give you an idea how inner query should be?
SELECT PERSON, Count(distinct Entry)
from [table]
where date >= 05/21/2014
and date < 05/22/2014
and Entry not in (select distinct entry from [table] where date <> 05/21/2014)
group by person
order by person.
in the above query i have just added an inner query to get the distinct entry from other dates
select distinct entry from [table] where date <> 05/21/2014
and i have added the where condition that the current result should not consider those entries by
and Entry not in (select distinct entry from [table] where date <> 05/21/2014)
hope this helps you.

Answer 2

For the first query, it sounds like you need something like this:
SELECT Person
FROM sample
GROUP BY date, person
HAVING date = '05-21-2014'
See http://sqlfiddle.com/#!3/4653d/1
This might also help:
SELECT Person, date
FROM sample
GROUP BY date, person
ORDER BY date
Hopefully that helps, let me know if I am misunderstanding something..