I am writing a query with a where clause which needs to return the final day of the previous month in the previous year. So if I ran it today (18/06/2014), it would return 31/05/2013. If I ran it next month on 19/07/2014 it would return 30/06/2013 and so on.
I can use
select DATEADD(day,-1,DATEadd(MONTH,datediff(month,0,GETDATE()),0))
which returns the final date of last month but I can't work out how to adapt this to give me the date a year previously.
I can add - 365 to the end of the above code which does what I want but wouldn't account for leap years. Although I don't expect my reports to be in use for long enough for this to necessarily matter it would be good to find a solution that works nicely (and to think that they might be).
Any solutions greatly appreciated.
Just add another dateadd(YY, -1, {your code}) around your getdate() to roll the year back first, then look to previous month (per comments below).
select DATEADD(day,-1,DATEadd(MONTH,datediff(month,0,DATEADD(YY,-1,GETDATE())),0))
Related
Need help with this sql code, I would like to roll back start day of new month if last day of pervious month has values.
Thanks
I would suggest nesting EOMONTH() in an IF statement.
Not sure what table(s) you're working with, but general layout would be:
IF(MAX(date_column) = EOMONTH(MAX(date_column), MAX(date_column), new_date)
Reference for EOMONTH():
https://www.sqlservertutorial.net/sql-server-date-functions/sql-server-eomonth-function/
I work for a company where everyday I modify a query by changing the date of the day before, because the report is always from the previous day.
I want to automate the date change. I have made a table with two columns, one with all dates from this year and another with bits where if 0 is a working day and 1 if is a holiday.
I have successfully automated a little bit by telling if the day before is a working day then subtract 1 from the date (This is what happens everyday). But the problem is, that if is Monday appears as Friday, because Saturday and Sunday are not billable. And let's also say, that if today is Thursday and Wednesday and Tuesday we're holidays, then the report will run on Monday. I will leave you a picture, that shows how the table is made with dates.
Remembering, that if there is no holidays in the middle of the week, always will be subtract one.
The way to do this sort of thing is close to what you have done, but just extend it further. Create a BusinessDate table that has every date, and then every rule you have implemented inside it. You can go so far as to include a column such as ReportDate which will return,for every date, what date the report should be run for.
Do this once, and it will work forever more. You may have to update for future holidays once a year, but better than once a day!
It will also allow you to update things specific for your business, like quarter dates, company holidays, etc.
If you want to know more on the subject, look up topics around creating a date dimension in a data warehouse. Its the same general issue you are facing.
Too complicated for a comment and it involves a lot of guessing.
So everyday, your process starts by first determining if "today" is a work day. So you would do something like:
if exists (select * from <calendar> where date = cast (getdate() as date) and IsWorkday = 1")
begin
<do stuff>
end;
The "do stuff" section would then run a report or your query (or something that isn't very clear) using the most recent work day prior to the current date. You find that date using something like:
declare #targetdate date;
set #targetdate = (select max(date) from <calendar>
where date < cast (getdate() as date)
and IsWorkday = 1);
if #targetdate is not null
<run your query using #targetdate>
That can be condensed into less code but it is easier to understand when the logic is written step-by-step.
I need a WHERE statement where the date of the record is the previous day. I have the below code which will do this
WHERE DOC_DATE = dateadd(day,datediff(day,1,GETDATE()),0)
However I need this statement to get Friday's record when the current day is Monday. I have the below code but it will not work for me. No errors come back on SQL although no records results come back either. I have the below code for this
WHERE DOC_DATE = DATEADD(day, CASE WHEN datepart(dw,(GETDATE())) IN (2) then -3 ELSE -1 END ,0)
Important to add that this needs to be in a WHERE clause. This is for a Docuware administrative view I am creating. I have no control on how to write the SELECT statement, I only have access to edit the WHERE clause:
Here's a slightly "magical" way to compute the value that doesn't depend on any particular server settings such as datefirst. It's probably not immediately obvious how it works:
WHERE DOC_DATE = dateadd(day,datediff(day,'20150316',getdate()),
CASE WHEN DATEPART(weekday,getdate()) = DATEPART(weekday,'20150330')
THEN '20150313'
ELSE '20150315' END)
In the first line, we're computing the number of days which have elapsed since some arbitrary date. I picked a day in March 2015 to use as my base date.
The second line asks what today's day of the week is and if it's the same as some arbitrary "Known good" Monday. Just taking one value and comparing it to 2 depends on what your DATEFIRST setting is so I prefer not to write that.
In the third line, we decide what to do if it's a monday - I give a date that is 3 days before my arbitrary date above. If it wasn't a monday, we pick the day before.
Adding it all together, when we add the days difference from the arbitrary date back to one of these two dates from lines 3 and 4, it has the effect of shifting the date backwards 1 or 3 days.
It's can be an odd structure to see if you're not familiar with it - but combining dateadd/datediff and exploiting relationships between an arbitrary date and other dates computed from it can be useful for performing all kinds of calculations. A similar structure can be used for computing e.g. the last day of the month 15 months ago using just dateadd/datediff, an arbitrary date and another date with the right offset from the first:
SELECT DATEADD(month,DATEDIFF(month,'20010101',GETDATE()),'19991031')
As I said in a comment though, usually doing this sort of thing is only a short step away from needing to properly model your organisation's business days, at which point you'd typically want to introduce a calendar table. At one row per day, 20 years worth of pre-calculated calendar (adjusted as necessary as the business changes) is still less than 10000 rows.
You can try this.
WHERE DOC_DATE = DATEADD(DAY, CASE WHEN datepart(dw, GETDATE()) = 2 THEN -3 ELSE -1 END, CAST(GETDATE() AS DATE))
So what I'm looking to do is create a report that shows how many sales a company had on a weekly basis.
So we have a time field called created that looks like this:
2016-04-06 20:58:06 UTC
This field represents when the sale takes place.
Now lets say I wanted to create a report that gives you how many sales you had on a weekly basis. So the above example will fall into something like Week of 2016-04-03 (it doesn't have to exactly say that, I'm just going for the simplest way to do this)
Anyone have any advice? I imagine it involves using the UTEC_TO_xxxxxx functions.
The documentation advises to use standard SQL functions, like DATE_TRUNC():
SELECT DATE_TRUNC(DATE '2019-12-25', WEEK) as week;
you can use WEEK() function - it gives you week number
SELECT WEEK('2016-04-06 20:58:06 UTC')
if you need first day of the week - you can try something like
STRFTIME_UTC_USEC((UTC_USEC_TO_WEEK(TIMESTAMP_TO_USEC(TIMESTAMP('2016-05-02 20:58:06 UTC')), 0)),'%Y-%m-%d')
I had to add parentheses:
SELECT DATE_TRUNC(DATE('2016-04-06 20:58:06 UTC'), WEEK) as week;
This is quite an old question and things have moved on since.
In my case, I found that the old WEEK function is no longer recognised, so I had to instead use the EXTRACT function. The doc for it can be found here.
For me it was enough to just extract the ISOWEEK from the timestamp, which results in the week of the year (the ISOYEAR) as a number.
ISOWEEK: Returns the ISO 8601 week number of the datetime_expression. ISOWEEKs begin on Monday. Return values are in the range [1, 53]. The first ISOWEEK of each ISO year begins on the Monday before the first Thursday of the Gregorian calendar year.
So I did this:
SELECT EXTRACT(ISOWEEK FROM created) as week
And if you want to see the week's last day, rather than the week's number in a year, then:
SELECT last_day(datetime(created), isoweek) as week
I've been trying to add and update data to a table in MS Access by month. This is so I can calculate any expenditures or sales per month. So if stock for a company were bought in March It would add this to the March expenditure row. And would be kept different from the expenditure in February or April for example.
I am unsure how to do this and how to have my program check the current month and year to see where it should input the data/make a new row for the month.
I know how to write to a database, I'm just not sure how to make my program write to a row in the database that depends on the current month and year
Any help would be greatly appreciated and sorry If this is all long winded or this is an easy fix, its my first post here and I'm a novice when it comes to programming.
In Access, to get the current date you use the date() function. I.E. if you were to do:
SELECT DATE()
the query would return the system date, which, today would be:
26/03/2015
To do math (add or subtract a specified interval) against the date, the syntax, again in Access, is:
DATEADD([Interval],[Number],[Date])
So, if I wanted to add one month to the current date I would write:
DATEADD(m, 1, DATE())
Or conversely, subtract two months from the current date:
DATEADD(m, -2, DATE())