I'm trying to set up a subquery in ZendFramework 2 and I got an issue with the limit function for a Select object. Whatever I do, numeric value is put between quotes and makes my query fails : I should get LIMIT 1 and instead I get LIMIT '1'.
Seems this is not the first time this issue has been encountered, I saw some have asked about this issue before (like 8 months ago) but without getting any proper answer.
I also saw this issue has been marker as resolved in 2012 (https://github.com/zendframework/zf2/pull/2775) so I really don't understand what's happening there.
Here's my code in ZF2 :
$resultSet = $this->tableGateway->select( function (Select $select) use ($params) {
$sub = new Select();
$sub->from(array('temp' => 'scores'))
->columns(array(new \Zend\Db\Sql\Expression("id AS id")))
->where(array('temp.glitch' => array('None', 'Glitch')))
->where('temp.zone=scores.zone')
->order('temp.multi DESC, temp.score DESC')
->limit(1);
$select->join('players', 'player=players.id', array('player_name' => 'name', 'player_url' => 'name_url'))
->join('countries', 'players.country=countries.id', array('country_name' => 'name', 'country_iso' => 'iso'))
->join('cars', 'car=cars.id', array('car_name' => 'name'), 'left')
->join('zones', 'zone=zones.id', array('zone_name' => 'name'));
$select->where(array('scores.id' => $sub));
$select->order('scores.zone ASC');
print_r($select->getSqlString());
});
This should render the following query (which I get right except LIMIT '1' instead of LIMIT 1) :
SELECT "scores".*, "players"."name" AS "player_name", "players"."name_url" AS "player_url", "countries"."name" AS "country_name", "countries"."iso" AS "country_iso", "cars"."name" AS "car_name", "zones"."name" AS "zone_name"
FROM "scores" INNER JOIN "players" ON "player"="players"."id"
INNER JOIN "countries" ON "players"."country"="countries"."id"
LEFT JOIN "cars" ON "car"="cars"."id"
INNER JOIN "zones" ON "zone"="zones"."id"
WHERE "scores"."id" = (SELECT id AS id FROM "scores" AS "temp" WHERE "temp"."glitch" IN ('None', 'Glitch')
AND temp.zone=scores.zone ORDER BY "temp"."multi" DESC, "temp"."score" DESC LIMIT 1)
ORDER BY "scores"."zone" ASC
Since this doesn't seem to work this way, is there another way I could proceed to get my limit (using Mysql 5 database) ?
EDIT :
Thanks for your help. Finally I figured out a way to get things done the way I want and to remove the quotes by simply remove the subquery construction and to write it directly in the where function :
$select->where('scores.id = (SELECT id FROM scores AS lookup WHERE lookup.zone = scores.zone ORDER BY multi DESC , score DESC LIMIT 1)');
Although I can continue my dev with this, I feel more like using a poor trick to get rid of this issue and so I will let this question unanswered until someone comes with a real solution there.
Anyway there might be no solution at all, since it might be an issue in ZF2 core itself.
Change the line -
$select->where(array('scores.id' => $sub));
with
$select->where(array('scores.id' => new \Zend\Db\Sql\Expression("({$sub->getSqlString($this->tableGateway->adapter->getPlatform())})"));
Try with just above change.
And if it still doesn't work then make changes to the core Select class file located at -
PROJECT_FOLDER/vendor/zendframework/zendframework/library/Zend/Db/Sql/Select.php
Line No. 921 -
Change $sql = $platform->quoteValue($limit); with $sql = $limit;
Line No. 940 -
Change return array($platform->quoteValue($offset)); with return array($offset);
I have come across the issue from github and wondered as why it is still not working with the latest ZF2 files. I know the solution given above doesn't look like the proper one but I had to somehow make it work. I have tried it and it works.
Its only a quick fix before the actual solution comes into picture.
Related
I have logic querying a MSSQL Server database view and I've been searching for a solutions along with trying different techniques. Of course I don't expect a full solution where this is two parts (query builder & frontend javascript/chart) but any helpful direction would greatly appreciated. Here I'm getting the count of Leads on a particular day grouped by the date created and source of the leads. I'm trying build this the Laravel way so to speak, and display in charts.js. I'm thinking I might need to make two different database calls/queries. One count and one for the group by source text.
Thank you for your help for a solutions or an helpful direction I can take.
I have already done total leads for another chart but this project has some extra sugar to it.
SELECT count([LeadID]) as numleads,[LeadSource],cast(leadcreated as date) as
`enter code here`createddate
FROM [myDatabase].[dbo].[viewAllLeads]
where companyid=001
group by cast(leadcreated as date),[LeadSource]
order by createddate
Chart.js set up:
- Top links (horizontal) the groupby info by LeadSource
- Left, y-axis - the count of the leads
- Bottom x-axis - the date lead was created
It should actually be straight forward, but you need to be aware that using DB::raw() is necessary. To begin with, here your query a little bit nicer formatted:
SELECT
[LeadSource],
CAST([leadcreated] as date) as createddate,
COUNT([LeadID]) as numleads
FROM [dbo].[viewAllLeads]
WHERE [companyid] = '001'
GROUP BY [LeadSource], CAST([leadcreated] as date)
ORDER BY [createddate]
And converted to an Eloquent query:
DB::table('viewAllLeads') // the query builder doesn't care if it's a table or view
->select([
'LeadSource',
DB::raw('CAST(leadcreated as date) as createddate'),
DB::raw('COUNT(LeadID) as numleads')
])
->where('companyid', '001')
->groupBy('LeadSource', DB::raw('CAST(leadcreated as date)'))
->orderBy('createddate')
->get();
This will return a Illuminate\Support\Collection containing stdClass objects of the following form:
object(stdClass)#1 (3) {
["LeadSource"] => string(3) "ABC"
["createddate"] => string(10) "2019-08-05"
["numleads"] => int(15)
}
$leads = Lead::where('companyid', $companyid)->get()->groupBy(function ($item) {
return $item->created_at->format('Y-m-d');
})->sortBy(function ($item) {
return $item->created_at->format('x');
});
if you use dd($leads) you can see the data structure.
I'm sure I have done something like this before, but can't find it and google not being helpful.
Using Phalcon model if possible, I want to select the items from a table whose ID appears the most - i.e. 10 most popular items ordered by popularity. Is this possible using Model::find("conditions")? I do I have to use PHQL for this?
using model::find
Model::find([
'columns' => 'id,count(id) as counter',
'group' => 'id',
'order' => 'counter DESC'
]);
PHQL:
$this->modelsManager->executeQuery('SELECT count(id) AS counter,id FROM ModelName GROUP BY id ORDER BY counter DESC');
find() does have a group clause, but I don't think it's possible to do what you want because you also need to do a count.
Talal's answer is close, but won't work if you want a list of model objects.
Something like this should work:
$Results = $this->modelsManager->executeQuery('SELECT * FROM ModelName GROUP BY id ORDER BY count(id) DESC LIMIT 10');
$Results->setHydrationMode(\Phalcon\Mvc\Model\Resultset::HYDRATE_RECORDS);
Setting the hydration mode may not be necessary, as Phalcon may default to that mode based on the fact the query is asking for *.
I currently have a scope where I am attempting to find last record created in an association and select it if a particular boolean value is false
IE Foo has_many Bar's and Bar's has a boolean column named bazzed
scope :no_baz, joins(:bars).order("bars.id DESC").limit(1).where("bars.bazzed = 'f'")
The problem with this is that rails turns this query into something like this
SELECT "foos".* FROM "foos" INNER JOIN "bars" ON "bars"."foo_id" = "foos"."id" WHERE (bars.bazzed = 'f') ORDER BY bars.id DESC LIMIT 1
the problem lies that rails is calling the order and limit after the where clause, what i'm looking for is to do the order and limit first to try and find the last bar that has bazzed set to false.
Is there a native AR way to perform the query I am attempting to accomplish?
EDIT
I am trying to grab the foo's that have a bar where the last bar they have has bazzed set to false and only if the last bar that that foo has has a false bazzed.
Ok, I would suggest this for the query on the "foo" model:
Foo.bars.where("bars.bazzed = ?", 'f').all( :order => "created_at DESC").first
Note: 'f' can be replaced by false, depending on the value you use in your "bazzed" column, of course.
[Edit]
Ok, as I think I better understand the problem, here is a suggestion, but for a public method and not a scoped query.
def no_baz
all_no_baz_foos = Array.new
Foo.all.each do |foo|
last_bar = foo.bars.all.order("bars.id DESC").first
if last_bar.bazzed == 'f'
all_no_baz_foos << foo
end
end
return all_no_baz_foos
end
This method will return an Array with all the no_baz_foos record in it. As I did not test my code, you may have to change few things for it to work, but I think you get the idea.
For the "scope" method, I just can't find a way to chain correctly the queries to have the desired result. If anyone else knows how to achieve that using a scope, I'll be glad to hear the solution too.
Using a class method for now but the problem with that lies that it returns an array object and not an active record relation which is what i'm trying to return. Still attempting to get the query correctly done.
I'm doing a rails app. I have to do a comparison engine a bit complex. I'm currently trying to do a prototype. My query can vary widely so i have to work with a lot of scopes, but that's not my problem.
My query have to compare candidates. These candidates have answered some tests. These tests belongs to category. Theses tests have different max value, and i have to be able to compare candidates by categories.
So i have to calculate a % of good answers. I have to be able to compare candidates in all possible use cases in one category. So, i have to be able to compare the average good answer rate for all this category.
In a nutshell : I have to be able to use subqueries in order to compare some candidates. I have to be able to compare them for a test or a category. My problem is using a subquery able to return a good answer rate for all tests a candidats may have passed in a category.
And I have to be able to use this subquery in an order_by or having clause.
How can I construct this subquery ? I have no problem to handle complex conditional queries with some scopes. This has to be a real subquery, because I am working with 6 or 7 models here.
I ask for an active record way, cause this must work with whatever database supported by rails.
Excuse my poor English.
Edit :
An example is worth 1000 words so how could do something like this :
Sessiontest.find(Candidat.where(:firstname => 'toto'))
This example is stupid, ok. So, is it possible to do something like this ?
Edit2 :
I saw some posts about AREL. I wish to know if it is possible to do this without a third party plugin.
Is it possible to do some sub queries in subqueries with arel? Because for example, my number of points per test, is the sum of the points of all his questions. (Sad, but I have to keep it). And I need this, so my subquery can calculate my good answers %.
So you got the idea. That's something, which has to be really powerful, so I need something powerful, and not too much error prone.
Edit3 : I made some progress, but I can't for a while post an answer.
It seem possible to get this work without any plugin. I have some success in buildings some subqueries like this :
toto = Candidat.where(:lastname => Candidat.select(:lastname).where(:lastname => "ulysse").limit(1))
The request :
Candidat Load (1.0ms)[0m SELECT "candidats".* FROM "candidats" WHERE "candidats"."lastname" IN (SELECT "candidats"."id" FROM "candidats" WHERE "candidats"."lastname" = 'ulysse' LIMIT 1
This works and create a real subquery. I will try some more advanced experiences, in order to get the level I actually need.
Just tried sub-subquery works wonder too.
Edit 5 :
I am trying some more advanced things, and there is a lot of things, i still don't understand.
- toto = Candidat.where("id = ? / ? ", Sessiontest.select(:id).where(:id => 6), Sessiontest.select(:id).where(:id => 2))
This is just a stupid example in order to get an object with an id of 3. This code works, but not as i expected.
See, the sql :
1m[35m (1.0ms)[0m SELECT COUNT("sessiontests"."id") FROM "sessiontests" WHERE "sessiontests"."id" = 6
[1m[36mSessiontest Load (0.0ms)[0m [1mSELECT id FROM "sessiontests" WHERE "sessiontests"."id" = 6[0m
[1m[35m (1.0ms)[0m SELECT COUNT("sessiontests"."id") FROM "sessiontests" WHERE "sessiontests"."id" = 2
[1m[36mSessiontest Load (1.0ms)[0m [1mSELECT id FROM "sessiontests" WHERE "sessiontests"."id" = 2[0m
[1m[35mCandidat Load (1.0ms)[0m SELECT "candidats".* FROM "candidats" WHERE (id = 6 / 2)
So, it does not use a subqueries. I tried with .to_sql. But it introduce my sql this way :
1m[36mCandidat Load (0.0ms)[0m [1mSELECT "candidats".* FROM "candidats" WHERE (id = 'SELECT id FROM "sessiontests" WHERE "sessiontests"."id" = 6' / 2 )[0m
So active record quoted the subreust for security purpose. this is closer to my wish, but not really what i want.
This does not work
Candidat.where("id = (?) / ? ", Sessiontest.select(:id).where(:id => 6).to_sql, Sessiontest.select(:id).where(:id => 2))
Quotes prevents the subquery to work.
But this work :
Candidat.where("id = (" + Sessiontest.select(:id).where(:id => 6).to_sql + ") / (" + Sessiontest.select(:id).where(:id => 2).to_sql + ") ")
[1m[36mCandidat Load (1.0ms)[0m [1mSELECT "candidats".* FROM "candidats" WHERE (id = (SELECT id FROM "sessiontests" WHERE "sessiontests"."id" = 6) / (SELECT id FROM "sessiontests" WHERE "sessiontests"."id" = 2) )[0m
But I find this ugly. I will try to get these subqueries working in a more dynamic way. I mean replace the integer values by columns name.
I don't have anymore the exact answer to this question, because i do not work in the same enterprise anymore. But the solution to this problem, was to use a group_by clause. So the request became really easy.
With a group_by, i was able to manipulate, category or a technology with ease.
ActiveRecord objects of the class 'Location' (representing the db-table Locations) have the attributes 'url', 'lat' (latitude) and 'lng' (longitude).
Lat-lng-combinations on this model should be unique. The problem is, that there are a lot of Location-objects in the database having duplicate lat-lng-combinations.
I need help in doing the following
Find objects that share the same
lat-lng-combination.
If the 'url' attribute of the object
isn't empty, keep this object and delete the
other duplicates. Otherwise just choose the
oldest object (by checking the attribute
'created_at') and delete the other duplicates.
As this is a one-time-operation, solutions in SQL (MySQL 5.1 compatible) are welcome too.
If it's a one time thing then I'd just do it in Ruby and not worry too much about efficiency. I haven't tested this thoroughly, check the sorting and such to make sure it'll do exactly what you want before running this on your db :)
keep = []
locations = Location.find(:all)
locations.each do |loc|
# get all Locations's with the same coords as this one
same_coords = locations.select { |l| l.lat == loc.lat and \
l.lng == loc.lng }
with_urls = same_coords.select { |l| !l.url.empty? }
# decide which list to use depending if there were any urls
same_coords = with_urls.any? ? with_urls : same_coords
# pick the best one
keep << same_coords.sort { |a,b| b.created_at <=> a.created_at }.first.id
end
# only keep unique ids
keep.uniq!
# now we just delete all the rows we didn't decide to keep
locations.each do |loc|
loc.destroy unless keep.include?( loc.id )
end
Now like I said, this is definitely poor, poor code. But sometimes just hacking out the thing that works is worth the time saved in thinking up something 'better', especially if it's just a one-off.
If you have 2 MySQL columns, you can use the CONCAT function.
SELECT * FROM table1 GROUP BY CONCAT(column_lat, column_lng)
If you need to know the total
SELECT COUNT(*) AS total FROM table1 GROUP BY CONCAT(column_lat, column_lng)
Or, you can combine both
SELECT COUNT(*) AS total, table1.* FROM table1
GROUP BY CONCAT(column_lat, column_lng)
But if you can explain more on your question, perhaps we can have more relevant answers.