How to convert exponent and coefficient to an integer value in SQL - sql

****UPDATED****
How to convert an exponent and coefficient to an integer? Is there a built-in method in SQL?
This is the value in scientific notation 6,1057747657e+011

DECLARE #s VARCHAR(25);
DECLARE #i BIGINT;
SET #s = '6.1057747657e+011';
SET #i = CAST(#s as FLOAT(53));
SELECT #i;
Results 610577476570
You need to store the result as a BIGINT because the number is too large for a 32-bit INT. Note that an implicit conversion is being done from FLOAT(53) to BIGINT.
If you want to control the rounding, you can use the ROUND(), FLOOR() or CEILING() functions. For example:
SET #i = ROUND(CAST(#s as FLOAT(53)), -2);
If it is possible that the input string might contain an invalid number, you would need to add error handling.
DECLARE #s VARCHAR(25);
DECLARE #i BIGINT;
SET #s = 'rubbish';
BEGIN TRY
SET #i = CAST(#s as FLOAT(53));
SELECT #i;
END TRY
BEGIN CATCH
-- error handling goes here
END CATCH
(Tested using T-SQL on SQL Server 2012.)

I think like this but to make into a integer I guess use BigInteger? let me research more
try {
Console.WriteLine(Double.Parse("6.1057747657e+011"));
}
catch (OverflowException) {
Console.WriteLine("{0} is outside the range of the Double type.",
value);
}
Different answer below.
http://msdn.microsoft.com/en-us/library/dd268285(v=vs.110).aspx
The "e" or "E" character, which indicates that the value is
represented in exponential (scientific) notation. The value parameter
can represent a number in exponential notation if style includes the
NumberStyles.AllowExponent flag.
BigInteger value = BigInteger.Parse("-903145792771643190182");
string[] specifiers = { "C", "D", "D25", "E", "E4", "e8", "F0",
"G", "N0", "P", "R", "X", "0,0.000",
"#,#.00#;(#,#.00#)" };
foreach (string specifier in specifiers)
Console.WriteLine("{0}: {1}", specifier, value.ToString(specifier));
// The example displays the following output:
// C: ($903,145,792,771,643,190,182.00)
// D: -903145792771643190182
// D25: -0000903145792771643190182
// E: -9.031458E+020
// E4: -9.0315E+020
// e8: -9.03145793e+020
// F0: -903145792771643190182
// G: -903145792771643190182
// N0: -903,145,792,771,643,190,182
// P: -90,314,579,277,164,319,018,200.00 %
// R: -903145792771643190182
// X: CF0A55968BB1A7545A
// 0,0.000: -903,145,792,771,643,190,182.000
// #,#.00#;(#,#.00#): (903,145,792,771,643,190,182.00)
In your case you might do
BigInteger value = System.Numerics.BigInteger.Parse("6.1057747657e+011", NumberStyles.Float, CultureInfo.InvariantCulture);
You must have .NET Framework 4.5 or higher for this to work.

Related

Input out of range for Int datatype, not passing a testcase

I am trying to solve the following question on LeetCode; Write a function that takes an unsigned integer and returns the number of '1' bits it has. Constraints: The input must be a binary string of length 32.
I have written the following code for that which works fine for inputs 00000000000000000000000000001011 and 00000000000000000000000010000000 (provided internally by the website) but give output 0 for input 11111111111111111111111111111101 and in my local compiler for the last input it says "out of range"
class Solution {
// you need treat n as an unsigned value
fun hammingWeight(n:Int):Int {
var num = n
var setCountBit = 0
while (num > 0) {
setCountBit++
num= num and num-1
}
return setCountBit
}
}
To correctly convert binary string to Int and avoid "out of range error", you need to do the following (I believe LeetCode does the same under the hood):
fun binaryStringToInt(s: String): Int = s.toUInt(radix = 2).toInt()
"11111111111111111111111111111101" is equivalent to 4294967293. This is greater than Int.MAX_VALUE, so it will be represented as negative number after .toInt() convertion (-3 in this case).
Actually, this problem could be solved with one-liner in Kotlin 1.4:
fun hammingWeight(n: Int): Int = n.countOneBits()
But LeetCode uses Kotlin 1.3.10, so you need to adjust your solution to handle negative Ints as well.
Please change the type of your input variable from Int to a type like Double .At the moment The given value is bigger than the maximum value that a type Int number can store.

How to pass a logical R object to a data block in a Stan file

If a list of data includes a logical variable x, namely, x=TRUE or x=FALSE.
Then how to怀declare such a variable in a Stan file?
For example, if an R object x is an integer, then
data{
int <lower=0>x;
}
I want to know its logical version. I guess
data{
bool x;
}
and it does not work as following;
SYNTAX ERROR, MESSAGE(S) FROM PARSER:
error in 'foo' at line 16, column 0
-------------------------------------------------
14:
15:
16: bool x;
^
17:
-------------------------------------------------
PARSER EXPECTED: <one of the following:
a variable declaration, beginning with type,
(int, real, vector, row_vector, matrix, unit_vector,
simplex, ordered, positive_ordered,
corr_matrix, cov_matrix,
cholesky_corr, cholesky_cov
or '}' to close variable declarations>
Error in stanc(filename, allow_undefined = TRUE) :
failed to parse Stan model 'foo' due to the above error.
Stan does not have a proper boolean type. Like C and C++, we use integer value 0 to denote false and value 1 to denote true. To implement a boolean type in Stan, declare it as an integer with a lower bound of 0 (false) and upper bound of 1 (true).
int<lower = 0, upper = 1> c;
R distinguishes integer types from logical types, but allows a lot of conversion. For example, if we define b to be the result of comparing 1 with itself, its value is TRUE and its type is logical (logi in R):
> b = (1 == 1)
> b
[1] TRUE
> str(b)
logi TRUE
So if I write this Stan program whose behavior differs on a passed boolean,
data {
int<lower = 0, upper = 1> b;
}
parameters {
real y;
}
model {
if (b)
y ~ normal(0, 1);
else
y ~ normal(10, 10);
}
RStan is happy to coerce the boolean, so it's OK to have
fit <- sampling(model, data = list(b = b))
where the value b is a logi type in R.
I believe logicals are resolved to their integer values of 0L for FALSE and 1L for TRUE, so using int is appropriate.

Why single char and "single char String" not equal when converted to long (.toLong())

I wanted to sum the digits of Long variable and add it to the variable it self, I came with the next working code:
private fun Long.sumDigits(): Long {
var n = this
this.toString().forEach { n += it.toString().toLong() }
return n
}
Usage: assert(48.toLong() == 42.toLong().sumDigits())
I had to use it.toString() in order to get it work, so I came with the next test and I don't get it's results:
#Test
fun toLongEquality() {
println("'4' as Long = " + '4'.toLong())
println("\"4\" as Long = " + "4".toLong())
println("\"42\" as Long = " + "42".toLong())
assert('4'.toString().toLong() == 4.toLong())
}
Output:
'4' as Long = 52
"4" as Long = 4
"42" as Long = 42
Is it a good practice to use char.toString().toLong() or there is a better way to convert char to Long?
Does "4" represented by chars? Why it is not equal to it char representation?
From the documentation:
class Char : Comparable (source) Represents a 16-bit Unicode
character. On the JVM, non-nullable values of this type are
represented as values of the primitive type char.
fun toLong(): Long
Returns the value of this character as a Long.
When you use '4' as Long you actually get the Unicode (ASCII) code of the char '4'
As mTak says, Char represents a Unicode value. If you are using Kotlin on the JVM, you can define your function as follows:
private fun Long.sumDigits() = this.toString().map(Character::getNumericValue).sum().toLong()
There's no reason to return Long rather than Int, but I've kept it the same as in your question.
Non-JVM versions of Kotlin don't have the Character class; use map {it - '0'} instead.

Arrange the values in a column in ascending order [duplicate]

We have a large database on which we have DB side pagination. This is quick, returning a page of 50 rows from millions of records in a small fraction of a second.
Users can define their own sort, basically choosing what column to sort by. Columns are dynamic - some have numeric values, some dates and some text.
While most sort as expected text sorts in a dumb way. Well, I say dumb, it makes sense to computers, but frustrates users.
For instance, sorting by a string record id gives something like:
rec1
rec10
rec14
rec2
rec20
rec3
rec4
...and so on.
I want this to take account of the number, so:
rec1
rec2
rec3
rec4
rec10
rec14
rec20
I can't control the input (otherwise I'd just format in leading 000s) and I can't rely on a single format - some are things like "{alpha code}-{dept code}-{rec id}".
I know a few ways to do this in C#, but can't pull down all the records to sort them, as that would be to slow.
Does anyone know a way to quickly apply a natural sort in Sql server?
We're using:
ROW_NUMBER() over (order by {field name} asc)
And then we're paging by that.
We can add triggers, although we wouldn't. All their input is parametrised and the like, but I can't change the format - if they put in "rec2" and "rec10" they expect them to be returned just like that, and in natural order.
We have valid user input that follows different formats for different clients.
One might go rec1, rec2, rec3, ... rec100, rec101
While another might go: grp1rec1, grp1rec2, ... grp20rec300, grp20rec301
When I say we can't control the input I mean that we can't force users to change these standards - they have a value like grp1rec1 and I can't reformat it as grp01rec001, as that would be changing something used for lookups and linking to external systems.
These formats vary a lot, but are often mixtures of letters and numbers.
Sorting these in C# is easy - just break it up into { "grp", 20, "rec", 301 } and then compare sequence values in turn.
However there may be millions of records and the data is paged, I need the sort to be done on the SQL server.
SQL server sorts by value, not comparison - in C# I can split the values out to compare, but in SQL I need some logic that (very quickly) gets a single value that consistently sorts.
#moebius - your answer might work, but it does feel like an ugly compromise to add a sort-key for all these text values.
order by LEN(value), value
Not perfect, but works well in a lot of cases.
Most of the SQL-based solutions I have seen break when the data gets complex enough (e.g. more than one or two numbers in it). Initially I tried implementing a NaturalSort function in T-SQL that met my requirements (among other things, handles an arbitrary number of numbers within the string), but the performance was way too slow.
Ultimately, I wrote a scalar CLR function in C# to allow for a natural sort, and even with unoptimized code the performance calling it from SQL Server is blindingly fast. It has the following characteristics:
will sort the first 1,000 characters or so correctly (easily modified in code or made into a parameter)
properly sorts decimals, so 123.333 comes before 123.45
because of above, will likely NOT sort things like IP addresses correctly; if you wish different behaviour, modify the code
supports sorting a string with an arbitrary number of numbers within it
will correctly sort numbers up to 25 digits long (easily modified in code or made into a parameter)
The code is here:
using System;
using System.Data.SqlTypes;
using System.Text;
using Microsoft.SqlServer.Server;
public class UDF
{
[SqlFunction(DataAccess = DataAccessKind.None, IsDeterministic=true)]
public static SqlString Naturalize(string val)
{
if (String.IsNullOrEmpty(val))
return val;
while(val.Contains(" "))
val = val.Replace(" ", " ");
const int maxLength = 1000;
const int padLength = 25;
bool inNumber = false;
bool isDecimal = false;
int numStart = 0;
int numLength = 0;
int length = val.Length < maxLength ? val.Length : maxLength;
//TODO: optimize this so that we exit for loop once sb.ToString() >= maxLength
var sb = new StringBuilder();
for (var i = 0; i < length; i++)
{
int charCode = (int)val[i];
if (charCode >= 48 && charCode <= 57)
{
if (!inNumber)
{
numStart = i;
numLength = 1;
inNumber = true;
continue;
}
numLength++;
continue;
}
if (inNumber)
{
sb.Append(PadNumber(val.Substring(numStart, numLength), isDecimal, padLength));
inNumber = false;
}
isDecimal = (charCode == 46);
sb.Append(val[i]);
}
if (inNumber)
sb.Append(PadNumber(val.Substring(numStart, numLength), isDecimal, padLength));
var ret = sb.ToString();
if (ret.Length > maxLength)
return ret.Substring(0, maxLength);
return ret;
}
static string PadNumber(string num, bool isDecimal, int padLength)
{
return isDecimal ? num.PadRight(padLength, '0') : num.PadLeft(padLength, '0');
}
}
To register this so that you can call it from SQL Server, run the following commands in Query Analyzer:
CREATE ASSEMBLY SqlServerClr FROM 'SqlServerClr.dll' --put the full path to DLL here
go
CREATE FUNCTION Naturalize(#val as nvarchar(max)) RETURNS nvarchar(1000)
EXTERNAL NAME SqlServerClr.UDF.Naturalize
go
Then, you can use it like so:
select *
from MyTable
order by dbo.Naturalize(MyTextField)
Note: If you get an error in SQL Server along the lines of Execution of user code in the .NET Framework is disabled. Enable "clr enabled" configuration option., follow the instructions here to enable it. Make sure you consider the security implications before doing so. If you are not the db admin, make sure you discuss this with your admin before making any changes to the server configuration.
Note2: This code does not properly support internationalization (e.g., assumes the decimal marker is ".", is not optimized for speed, etc. Suggestions on improving it are welcome!
Edit: Renamed the function to Naturalize instead of NaturalSort, since it does not do any actual sorting.
I know this is an old question but I just came across it and since it's not got an accepted answer.
I have always used ways similar to this:
SELECT [Column] FROM [Table]
ORDER BY RIGHT(REPLICATE('0', 1000) + LTRIM(RTRIM(CAST([Column] AS VARCHAR(MAX)))), 1000)
The only common times that this has issues is if your column won't cast to a VARCHAR(MAX), or if LEN([Column]) > 1000 (but you can change that 1000 to something else if you want), but you can use this rough idea for what you need.
Also this is much worse performance than normal ORDER BY [Column], but it does give you the result asked for in the OP.
Edit: Just to further clarify, this the above will not work if you have decimal values such as having 1, 1.15 and 1.5, (they will sort as {1, 1.5, 1.15}) as that is not what is asked for in the OP, but that can easily be done by:
SELECT [Column] FROM [Table]
ORDER BY REPLACE(RIGHT(REPLICATE('0', 1000) + LTRIM(RTRIM(CAST([Column] AS VARCHAR(MAX)))) + REPLICATE('0', 100 - CHARINDEX('.', REVERSE(LTRIM(RTRIM(CAST([Column] AS VARCHAR(MAX))))), 1)), 1000), '.', '0')
Result: {1, 1.15, 1.5}
And still all entirely within SQL. This will not sort IP addresses because you're now getting into very specific number combinations as opposed to simple text + number.
RedFilter's answer is great for reasonably sized datasets where indexing is not critical, however if you want an index, several tweaks are required.
First, mark the function as not doing any data access and being deterministic and precise:
[SqlFunction(DataAccess = DataAccessKind.None,
SystemDataAccess = SystemDataAccessKind.None,
IsDeterministic = true, IsPrecise = true)]
Next, MSSQL has a 900 byte limit on the index key size, so if the naturalized value is the only value in the index, it must be at most 450 characters long. If the index includes multiple columns, the return value must be even smaller. Two changes:
CREATE FUNCTION Naturalize(#str AS nvarchar(max)) RETURNS nvarchar(450)
EXTERNAL NAME ClrExtensions.Util.Naturalize
and in the C# code:
const int maxLength = 450;
Finally, you will need to add a computed column to your table, and it must be persisted (because MSSQL cannot prove that Naturalize is deterministic and precise), which means the naturalized value is actually stored in the table but is still maintained automatically:
ALTER TABLE YourTable ADD nameNaturalized AS dbo.Naturalize(name) PERSISTED
You can now create the index!
CREATE INDEX idx_YourTable_n ON YourTable (nameNaturalized)
I've also made a couple of changes to RedFilter's code: using chars for clarity, incorporating duplicate space removal into the main loop, exiting once the result is longer than the limit, setting maximum length without substring etc. Here's the result:
using System.Data.SqlTypes;
using System.Text;
using Microsoft.SqlServer.Server;
public static class Util
{
[SqlFunction(DataAccess = DataAccessKind.None, SystemDataAccess = SystemDataAccessKind.None, IsDeterministic = true, IsPrecise = true)]
public static SqlString Naturalize(string str)
{
if (string.IsNullOrEmpty(str))
return str;
const int maxLength = 450;
const int padLength = 15;
bool isDecimal = false;
bool wasSpace = false;
int numStart = 0;
int numLength = 0;
var sb = new StringBuilder();
for (var i = 0; i < str.Length; i++)
{
char c = str[i];
if (c >= '0' && c <= '9')
{
if (numLength == 0)
numStart = i;
numLength++;
}
else
{
if (numLength > 0)
{
sb.Append(pad(str.Substring(numStart, numLength), isDecimal, padLength));
numLength = 0;
}
if (c != ' ' || !wasSpace)
sb.Append(c);
isDecimal = c == '.';
if (sb.Length > maxLength)
break;
}
wasSpace = c == ' ';
}
if (numLength > 0)
sb.Append(pad(str.Substring(numStart, numLength), isDecimal, padLength));
if (sb.Length > maxLength)
sb.Length = maxLength;
return sb.ToString();
}
private static string pad(string num, bool isDecimal, int padLength)
{
return isDecimal ? num.PadRight(padLength, '0') : num.PadLeft(padLength, '0');
}
}
Here's a solution written for SQL 2000. It can probably be improved for newer SQL versions.
/**
* Returns a string formatted for natural sorting. This function is very useful when having to sort alpha-numeric strings.
*
* #author Alexandre Potvin Latreille (plalx)
* #param {nvarchar(4000)} string The formatted string.
* #param {int} numberLength The length each number should have (including padding). This should be the length of the longest number. Defaults to 10.
* #param {char(50)} sameOrderChars A list of characters that should have the same order. Ex: '.-/'. Defaults to empty string.
*
* #return {nvarchar(4000)} A string for natural sorting.
* Example of use:
*
* SELECT Name FROM TableA ORDER BY Name
* TableA (unordered) TableA (ordered)
* ------------ ------------
* ID Name ID Name
* 1. A1. 1. A1-1.
* 2. A1-1. 2. A1.
* 3. R1 --> 3. R1
* 4. R11 4. R11
* 5. R2 5. R2
*
*
* As we can see, humans would expect A1., A1-1., R1, R2, R11 but that's not how SQL is sorting it.
* We can use this function to fix this.
*
* SELECT Name FROM TableA ORDER BY dbo.udf_NaturalSortFormat(Name, default, '.-')
* TableA (unordered) TableA (ordered)
* ------------ ------------
* ID Name ID Name
* 1. A1. 1. A1.
* 2. A1-1. 2. A1-1.
* 3. R1 --> 3. R1
* 4. R11 4. R2
* 5. R2 5. R11
*/
ALTER FUNCTION [dbo].[udf_NaturalSortFormat](
#string nvarchar(4000),
#numberLength int = 10,
#sameOrderChars char(50) = ''
)
RETURNS varchar(4000)
AS
BEGIN
DECLARE #sortString varchar(4000),
#numStartIndex int,
#numEndIndex int,
#padLength int,
#totalPadLength int,
#i int,
#sameOrderCharsLen int;
SELECT
#totalPadLength = 0,
#string = RTRIM(LTRIM(#string)),
#sortString = #string,
#numStartIndex = PATINDEX('%[0-9]%', #string),
#numEndIndex = 0,
#i = 1,
#sameOrderCharsLen = LEN(#sameOrderChars);
-- Replace all char that have the same order by a space.
WHILE (#i <= #sameOrderCharsLen)
BEGIN
SET #sortString = REPLACE(#sortString, SUBSTRING(#sameOrderChars, #i, 1), ' ');
SET #i = #i + 1;
END
-- Pad numbers with zeros.
WHILE (#numStartIndex <> 0)
BEGIN
SET #numStartIndex = #numStartIndex + #numEndIndex;
SET #numEndIndex = #numStartIndex;
WHILE(PATINDEX('[0-9]', SUBSTRING(#string, #numEndIndex, 1)) = 1)
BEGIN
SET #numEndIndex = #numEndIndex + 1;
END
SET #numEndIndex = #numEndIndex - 1;
SET #padLength = #numberLength - (#numEndIndex + 1 - #numStartIndex);
IF #padLength < 0
BEGIN
SET #padLength = 0;
END
SET #sortString = STUFF(
#sortString,
#numStartIndex + #totalPadLength,
0,
REPLICATE('0', #padLength)
);
SET #totalPadLength = #totalPadLength + #padLength;
SET #numStartIndex = PATINDEX('%[0-9]%', RIGHT(#string, LEN(#string) - #numEndIndex));
END
RETURN #sortString;
END
I know this is a bit old at this point, but in my search for a better solution, I came across this question. I'm currently using a function to order by. It works fine for my purpose of sorting records which are named with mixed alpha numeric ('item 1', 'item 10', 'item 2', etc)
CREATE FUNCTION [dbo].[fnMixSort]
(
#ColValue NVARCHAR(255)
)
RETURNS NVARCHAR(1000)
AS
BEGIN
DECLARE #p1 NVARCHAR(255),
#p2 NVARCHAR(255),
#p3 NVARCHAR(255),
#p4 NVARCHAR(255),
#Index TINYINT
IF #ColValue LIKE '[a-z]%'
SELECT #Index = PATINDEX('%[0-9]%', #ColValue),
#p1 = LEFT(CASE WHEN #Index = 0 THEN #ColValue ELSE LEFT(#ColValue, #Index - 1) END + REPLICATE(' ', 255), 255),
#ColValue = CASE WHEN #Index = 0 THEN '' ELSE SUBSTRING(#ColValue, #Index, 255) END
ELSE
SELECT #p1 = REPLICATE(' ', 255)
SELECT #Index = PATINDEX('%[^0-9]%', #ColValue)
IF #Index = 0
SELECT #p2 = RIGHT(REPLICATE(' ', 255) + #ColValue, 255),
#ColValue = ''
ELSE
SELECT #p2 = RIGHT(REPLICATE(' ', 255) + LEFT(#ColValue, #Index - 1), 255),
#ColValue = SUBSTRING(#ColValue, #Index, 255)
SELECT #Index = PATINDEX('%[0-9,a-z]%', #ColValue)
IF #Index = 0
SELECT #p3 = REPLICATE(' ', 255)
ELSE
SELECT #p3 = LEFT(REPLICATE(' ', 255) + LEFT(#ColValue, #Index - 1), 255),
#ColValue = SUBSTRING(#ColValue, #Index, 255)
IF PATINDEX('%[^0-9]%', #ColValue) = 0
SELECT #p4 = RIGHT(REPLICATE(' ', 255) + #ColValue, 255)
ELSE
SELECT #p4 = LEFT(#ColValue + REPLICATE(' ', 255), 255)
RETURN #p1 + #p2 + #p3 + #p4
END
Then call
select item_name from my_table order by fnMixSort(item_name)
It easily triples the processing time for a simple data read, so it may not be the perfect solution.
Here is an other solution that I like:
http://www.dreamchain.com/sql-and-alpha-numeric-sort-order/
It's not Microsoft SQL, but since I ended up here when I was searching for a solution for Postgres, I thought adding this here would help others.
EDIT: Here is the code, in case the link goes away.
CREATE or REPLACE FUNCTION pad_numbers(text) RETURNS text AS $$
SELECT regexp_replace(regexp_replace(regexp_replace(regexp_replace(($1 collate "C"),
E'(^|\\D)(\\d{1,3}($|\\D))', E'\\1000\\2', 'g'),
E'(^|\\D)(\\d{4,6}($|\\D))', E'\\1000\\2', 'g'),
E'(^|\\D)(\\d{7}($|\\D))', E'\\100\\2', 'g'),
E'(^|\\D)(\\d{8}($|\\D))', E'\\10\\2', 'g');
$$ LANGUAGE SQL;
"C" is the default collation in postgresql; you may specify any collation you desire, or remove the collation statement if you can be certain your table columns will never have a nondeterministic collation assigned.
usage:
SELECT * FROM wtf w
WHERE TRUE
ORDER BY pad_numbers(w.my_alphanumeric_field)
For the following varchar data:
BR1
BR2
External Location
IR1
IR2
IR3
IR4
IR5
IR6
IR7
IR8
IR9
IR10
IR11
IR12
IR13
IR14
IR16
IR17
IR15
VCR
This worked best for me:
ORDER BY substring(fieldName, 1, 1), LEN(fieldName)
If you're having trouble loading the data from the DB to sort in C#, then I'm sure you'll be disappointed with any approach at doing it programmatically in the DB. When the server is going to sort, it's got to calculate the "perceived" order just as you would have -- every time.
I'd suggest that you add an additional column to store the preprocessed sortable string, using some C# method, when the data is first inserted. You might try to convert the numerics into fixed-width ranges, for example, so "xyz1" would turn into "xyz00000001". Then you could use normal SQL Server sorting.
At the risk of tooting my own horn, I wrote a CodeProject article implementing the problem as posed in the CodingHorror article. Feel free to steal from my code.
Simply you sort by
ORDER BY
cast (substring(name,(PATINDEX('%[0-9]%',name)),len(name))as int)
##
I've just read a article somewhere about such a topic. The key point is: you only need the integer value to sort data, while the 'rec' string belongs to the UI. You could split the information in two fields, say alpha and num, sort by alpha and num (separately) and then showing a string composed by alpha + num. You could use a computed column to compose the string, or a view.
Hope it helps
You can use the following code to resolve the problem:
Select *,
substring(Cote,1,len(Cote) - Len(RIGHT(Cote, LEN(Cote) - PATINDEX('%[0-9]%', Cote)+1)))alpha,
CAST(RIGHT(Cote, LEN(Cote) - PATINDEX('%[0-9]%', Cote)+1) AS INT)intv
FROM Documents
left outer join Sites ON Sites.IDSite = Documents.IDSite
Order BY alpha, intv
regards,
rabihkahaleh#hotmail.com
I'm fashionably late to the party as usual. Nevertheless, here is my attempt at an answer that seems to work well (I would say that). It assumes text with digits at the end, like in the original example data.
First a function that won't end up winning a "pretty SQL" competition anytime soon.
CREATE FUNCTION udfAlphaNumericSortHelper (
#string varchar(max)
)
RETURNS #results TABLE (
txt varchar(max),
num float
)
AS
BEGIN
DECLARE #txt varchar(max) = #string
DECLARE #numStr varchar(max) = ''
DECLARE #num float = 0
DECLARE #lastChar varchar(1) = ''
set #lastChar = RIGHT(#txt, 1)
WHILE #lastChar <> '' and #lastChar is not null
BEGIN
IF ISNUMERIC(#lastChar) = 1
BEGIN
set #numStr = #lastChar + #numStr
set #txt = Substring(#txt, 0, len(#txt))
set #lastChar = RIGHT(#txt, 1)
END
ELSE
BEGIN
set #lastChar = null
END
END
SET #num = CAST(#numStr as float)
INSERT INTO #results select #txt, #num
RETURN;
END
Then call it like below:
declare #str nvarchar(250) = 'sox,fox,jen1,Jen0,jen15,jen02,jen0004,fox00,rec1,rec10,jen3,rec14,rec2,rec20,rec3,rec4,zip1,zip1.32,zip1.33,zip1.3,TT0001,TT01,TT002'
SELECT tbl.value --, sorter.txt, sorter.num
FROM STRING_SPLIT(#str, ',') as tbl
CROSS APPLY dbo.udfAlphaNumericSortHelper(value) as sorter
ORDER BY sorter.txt, sorter.num, len(tbl.value)
With results:
fox
fox00
Jen0
jen1
jen02
jen3
jen0004
jen15
rec1
rec2
rec3
rec4
rec10
rec14
rec20
sox
TT01
TT0001
TT002
zip1
zip1.3
zip1.32
zip1.33
I still don't understand (probably because of my poor English).
You could try:
ROW_NUMBER() OVER (ORDER BY dbo.human_sort(field_name) ASC)
But it won't work for millions of records.
That why I suggested to use trigger which fills separate column with human value.
Moreover:
built-in T-SQL functions are really
slow and Microsoft suggest to use
.NET functions instead.
human value is constant so there is no point calculating it each time
when query runs.

VARCHAR2(1000) limited to 100 chars only

When trying to store in an Oracle SQL table a string of more than 100 chars, while the field limitation is 1000 bytes which I understood is ~1000 English chars, I'm getting out of bounds exception:
StringIndexOutOfBoundsException: String index out of range: -3
What might be the cause for this low limitation?
Thanks!
EDIT :
The code where the error occurs is (see chat):
// Commenting the existing code, because for sensitive information
// toString returns masked data
int nullSize = 5;
int i = 0;
// removing '[' and ']', signs and fields with 'null' value and also add
// ';' as delimiter.
while (i != -1) {
int index1 = str.indexOf('[', i);
int index2 = str.indexOf(']', i + 1);
i = index2;
if (index2 != -1 && index1 != -1) {
int index3 = str.indexOf('=', index1);
if (index3 + nullSize > str.length() || !str.substring(index3 + 1, index3 + nullSize).equals("null")) {
String str1 = str.substring(index1 + 1, index2);
concatStrings = concatStrings.append(str1);
concatStrings = concatStrings.append(";");
}
}
}
Generally, when the string to store in a varchar field is too long, it is cropped silently. Anyway when there is an error message, it is generally specific. The error seems to be related to a operation on a string (String.substring()?).
Furthermore, even when the string is encoded in UTF-8, the ratio characters/bytes shouldn't be that low.
You really should put the code sample where your error occurs in you question and the string causing this and also have a closer look at the stacktrace to see where the error occurs.
From the code you posted in your chat, I can see this line of code :
String str1 = str.substring(index1 + 1, index2);
You check that index1 and index2 are different than -1 but you don't check if (index1 + 1) >= index2 which makes your code crash.
Try this with str = "*]ab=null[" (which length is under 100 characters) but you can also get the error with a longer string such as "osh]] [ = null ]Clipers: RRR was removed by user and customer called in to have it since it was an RRT".
Once again the size of the string doesn't matter, only the content!!!
You can reproduce your problem is a closing square bracket (]) before an opening one([) and between them an equal sign (=) followed (directly or not) by the "null" string.
I agree with Jonathon Ogden "limitations of 1000 bytes does not necessarily mean 1000 characters as it depends on character encoding".
I recommend you to Alter column in your Oracle table from VARCHAR2(1000 Byte) to VARCHAR2(1000 Char).