JacksonJsonProvider set non_null inclusion in spring xml - jackson

Hi following is my cxfrs server configuration
<cxf:rsServer id="itemService"
address="{{esb.item.rest.address}}"
serviceClass="com.test.esb.service.flm.ItemServiceImpl"
loggingFeatureEnabled="false">
<cxf:providers>
<bean class="org.codehaus.jackson.jaxrs.JacksonJsonProvider"/>
</cxf:providers>
</cxf:rsServer>
I need to configure Inclusion.NON_NULL here so that it can exclude the null fields from the generated gson string. Any idea how i can achieve this.

One option is to create a customized provider instance using your own factory method. Here is an example factory class:
public class JacksonJsonProviderFactory {
public static JacksonJsonProvider create() {
ObjectMapper mapper = new ObjectMapper();
mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL);
return new JacksonJsonProvider(mapper);
}
}
And here is an example XML Blueprint fragment:
<cxf:providers>
<bean class="JacksonJsonProviderFactory" factory-method="create"/>
</cxf:providers>

Related

How to mock a MyBatis mapper method using JMockit

We have a service component (#service) which internally uses MyBatis to do CRUD operations. All the components are managed by Spring.
Lets assume our MyBatis mapper file
class MyBatisMapper{
public void getData(Map<String,Object> arg);
}
In our mybatis xml file,we have element defined for a callable statement. arg is a map which holds IN and OUT parameters.
Our service component is like
#Service("myService")
class MyService{
#Autowired
private MyBatisMapper myMapper;
public void processData(){
Map<String,Object> input = new HashMap<String,Object>();
............
............
myMapper.getDat(input);
Object response = input.get("RESPONSE");
//process response and so on
}
My objective is to write Junits for the service component and don't have to interact with DB. So, I tried to use JMockIt to mock some of the DAO operations
My attempt is ike
#Mocked
#Injectable
private MyBatisMapper myMapper;
#Test
public void testService() {
new NonStrictExpectations(){
{
Map<String,Object> input = new HashMap<String,Object>();
input.put("xxx,"yyy");
myMapper.getData(input);
}
};
}
But when I ran my tests, I noticed that call went through actualy DB , instead of mocked one.
How to make sure only the mocked components gets called, instead of the actual object
#Injectable mock instances only get injected into #Tested objects. And to specify a return value from a mocked method, you need to assign it to the result field. So, the test should look like the following:
#Tested MyService myService;
#Injectable MyBatisMapper myMapper;
#Test
public void testService() {
final Map<String,Object> data = new HashMap<String, Object>();
data.put("RESPONSE", "yyy");
new Expectations() {{
myMapper.getData((Map<String, Object>) any); result = data;
}};
myService.processData();
// Assert some expected outcome.
}
Thank you Rogerio. I tried to follow the approach you mentioned, but still I see the call going to the actual object. There is a point which I did not mention earlier. My project is spring based and the components are all autowired.
My test has
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(locations = {"classpath:spring/test-applicationContext.xml"})
and test-applicationContext.xml has component scan. So I think, Spring is injecting the actual object ignoring the mock instruction.
Am I wrong ?

Unrecognized field "_links" since the 2.0.0.RC1 of Spring Data REST

On one side, I have just update the version of spring-data-rest-webmc to the latest 2.0.0.RC1 version of my server. In this version, the json format change to an HAL format.
On the other side, I have a client which use the spring-hateoas library with the 0.9.0.RELEASE version.
In this client, I use RestTemplate to get a resource from my server like this :
AuthorResource authorResource = restTemplate.getForObject(BASE_URL+"authors/"+ authorId, AuthorResource.class);
The AuthorResource class extends ResourceSupport.
Now, I have this error :
Nested exception is com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "_links" (class org.example.hateoas.AuthorResource)
How can i configure my client to support this new format ?
I try
#EnableHypermediaSupport(type =
EnableHypermediaSupport.HypermediaType.HAL)
But it does not work.
thx for your help.
Problem is that halMapperObject is not setted because of context is not spring web.
You have to create your own RestTemplate class like this
#Component
public class EraRestTemplate extends RestTemplate implements InitializingBean {
#Autowired
#Qualifier("_halObjectMapper")
ObjectMapper halObjectMapper;
static class HALMessageConverter extends MappingJackson2HttpMessageConverter {
}
#Override
public void afterPropertiesSet() throws Exception {
halObjectMapper.registerModule(new Jackson2HalModule());
HALMessageConverter converter = new HALMessageConverter();
converter.setObjectMapper(halObjectMapper);
this.getMessageConverters().clear();
this.getMessageConverters().add(converter);
}
}
It works fine now for me thanks a friend who knows Spring very well.

Registering a Jackson module for Spring Data REST

I have a working project based on the Spring Data REST example project, and I'm trying to do custom serialization using a Jackson module based on this wiki page.
Here's my Jackson module:
public class CustomModule extends SimpleModule {
public static Logger logger = LoggerFactory.getLogger(CustomModule.class);
public CustomModule() {
super("CustomModule", new Version(1, 0, 0, null));
}
#Override
public void setupModule(SetupContext context) {
logger.debug("CustomModule.setupModule");
SimpleSerializers simpleSerializers = new SimpleSerializers();
simpleSerializers.addSerializer(new CustomDateTimeSerializer());
context.addSerializers(simpleSerializers);
}
}
The wiki page says:
Any Module bean declared within the scope of your ApplicationContext will be picked up by the exporter and registered with its ObjectMapper.
I'm still pretty new to Spring, so I might just be putting my module bean definition in the wrong place; currently it's in src/main/resources/META-INF/spring-data-rest/shared.xml, which is imported from repositories-export.xml:
<bean id="customModule" class="org.hierax.wpa.schema.mapping.CustomModule" />
I don't see the log statement in setupModule, but I do see log output for other classes in the same package.
I'm using Spring Data REST 1.0.0.RC2.
Currently, it's possible to customize a module in Spring Boot like this:
#Bean
public Module customModule() {
return new CustomModule();
}
Reference: Latest Jackson integration improvements in Spring
I've had success using the solution outlined in the wiki entry that you have linked to (although perhaps it has changed since this stack overflow post)
In my instance I was using spring-data-rest-webmvc#1.0.0.RELEASE
Your code seems to be correct and provided that your application context is being loaded correctly I don't see any reason for it not to be working.
I've attached my simpler Module which exemplifies the use of a date formatter:
#Component
public class JsonMarshallingConfigModule extends SimpleModule {
public JsonMarshallingConfigModule() {
super("JsonMarshallingConfigModule", new Version(1, 0, 0, "SNAPSHOT"));
}
#Override public void setupModule(SetupContext context) {
context.getSerializationConfig().setDateFormat(new SimpleDateFormat("yyyy-MM-dd'T'HH:mm'Z'"));
}
}
Perhaps it can be used to outline if it is infact the jackson module that is the problem or spring-data-rest-mvcweb.

Castle DynamicProxy generated class names

Does anybody know if it is possible to control the names of the types generated through Castle DynamicProxy? I was hoping to take advantage of the ability to persist the assembly generated by Castle to add some additional classes with some specific functionality to my project, but I would like to be able to control the names of these generated proxy types. Any help would be greatly appreciated.
I actually plan to persist instances of these classes as well as instances of the original classes that are the sources of the proxies with NHibernate. So, I need these names to be consistent across multiple generations of the assembly.
I did some interesting digging. Specifying proxy names appears to be possible using an INamingScope, but it is far from straightforward to get the INamingScope wedged in. You would need to create your own ProxyFactoryFactory, which would create a ProxyFactory identical to NHibernate.ByteCode.Castle.ProxyFactory, except it would initilize ProxyGenerator:
public class CustomProxyFactory : AbstractProxyFactory {
private static readonly ProxyGenerator ProxyGenerator = new ProxyGenerator(new CustomProxyBuilder());
// remainder of code is identical
}
public class CustomProxyBuilder : DefaultProxyBuilder {
public CustomProxyBuilder() : base(new CustomModuleScope()) {}
}
public class CustomModuleScope : ModuleScope {
public CustomModuleScope() : base(false, false, new CustomNamingScope(), DEFAULT_ASSEMBLY_NAME, DEFAULT_FILE_NAME, DEFAULT_ASSEMBLY_NAME, DEFAULT_FILE_NAME) {}
}
public class CustomNamingScope : INamingScope {
public CustomNamingScope() {}
private CustomNamingScope(INamingScope parent) {
ParentScope = parent;
}
public string GetUniqueName(string suggestedName) {
// your naming logic goes here
}
public INamingScope SafeSubScope() {
return new CustomModuleScope(this);
}
public INamingScope ParentScope { get; private set; }
}
I honestly haven't tried running or compiling any of this. Just digging through the NHibernate and Castle.Core source code. Hopefully it gives you some ideas...
Take a look at the ProxyGenerators project in NHContrib. It allows you to pre-generate NHibernate's lazy loading proxies.
http://nhforge.org/wikis/proxygenerators10/default.aspx
Whether you use the ProxyGenerators or not, you integrate your custom proxies into NHibernate via the Proxy Factory Factory. In hibernate.cfg.xml:
<hibernate-configuration xmlns="urn:nhibernate-configuration-2.2">
<session-factory>
<property name="proxyfactory.factory_class">YOUR_PROXY_FACTORY_FACTORY</property>
</session-factory>
</hibernate-configuration>

How to change configs in Spring.Net

An advantage of an IoC container is that you can swap in a mock service at the bottom of your object graph. However this seems much harder to do in Spring.Net than in other IoC Containers. Here's some code that does it in Unity and has Spring.Net code;
namespace IocSpringDemo
{
using Microsoft.Practices.Unity;
using NUnit.Framework;
using Spring.Context;
using Spring.Context.Support;
public interface ISomeService
{
string DoSomething();
}
public class ServiceImplementationA : ISomeService
{
public string DoSomething()
{
return "Hello A";
}
}
public class ServiceImplementationB : ISomeService
{
public string DoSomething()
{
return "Hello B";
}
}
public class RootObject
{
public ISomeService SomeService { get; private set; }
public RootObject(ISomeService service)
{
SomeService = service;
}
}
[TestFixture]
public class UnityAndSpringDemo
{
[Test]
public void UnityResolveA()
{
UnityContainer container = new UnityContainer();
container.RegisterType<ISomeService, ServiceImplementationA>();
RootObject rootObject = container.Resolve<RootObject>();
Assert.AreEqual("Hello A", rootObject.SomeService.DoSomething());
}
[Test]
public void UnityResolveB()
{
UnityContainer container = new UnityContainer();
container.RegisterType<ISomeService, ServiceImplementationB>();
RootObject rootObject = container.Resolve<RootObject>();
Assert.AreEqual("Hello B", rootObject.SomeService.DoSomething());
}
[Test]
public void SpringResolveA()
{
IApplicationContext container = ContextRegistry.GetContext();
RootObject rootObject = (RootObject)container.GetObject("RootObject");
Assert.AreEqual("Hello A", rootObject.SomeService.DoSomething());
}
[Test]
public void SpringResolveB()
{
// does not work - what to do to make this pass?
IApplicationContext container = ContextRegistry.GetContext();
RootObject rootObject = (RootObject)container.GetObject("RootObject");
Assert.AreEqual("Hello B", rootObject.SomeService.DoSomething());
}
}
}
For the benefit of Spring, the following needed to be in the App.config file. Clearly this only serves the first spring test, and not the second. Can you put multiple spring configurations in the config file? If so, what is the syntax and how do you access them? Or is there another way to do this?
<configSections>
<sectionGroup name="spring">
<section name="context" type="Spring.Context.Support.ContextHandler, Spring.Core"/>
<section name="objects" type="Spring.Context.Support.DefaultSectionHandler, Spring.Core" />
</sectionGroup>
</configSections>
<spring>
<context>
<resource uri="config://spring/objects"/>
</context>
<objects xmlns="http://www.springframework.net">
<object name="RootObject" type="IocSpringDemo.RootObject, IocDemo" autowire="constructor" />
<object name="service" type="IocSpringDemo.ServiceImplementationA, IocDemo" autowire="constructor" />
</objects>
</spring>
Update
Here is a partial answer based at code at the links that Marko Lahma gave to Mark Pollack's blog. I have the above tests passing, with the following code:
public static class SpringHelper
{
public static T Resolve<T>(this IApplicationContext context, string name)
{
return (T)context.GetObject(name);
}
public static void RegisterType<T>(this GenericApplicationContext context, string name)
{
context.RegisterType(name, typeof(T));
}
public static void RegisterType(this GenericApplicationContext context, string name, Type type)
{
IObjectDefinitionFactory objectDefinitionFactory = new DefaultObjectDefinitionFactory();
ObjectDefinitionBuilder builder = ObjectDefinitionBuilder.RootObjectDefinition(objectDefinitionFactory, type);
builder.SetAutowireMode(AutoWiringMode.AutoDetect);
context.RegisterObjectDefinition(name, builder.ObjectDefinition);
}
}
...
[Test]
public void SpringResolveA()
{
GenericApplicationContext container = new GenericApplicationContext();
container.RegisterType<RootObject>("RootObject");
container.RegisterType<ServiceImplementationA>("service");
RootObject rootObject = container.Resolve<RootObject>("RootObject");
Assert.AreEqual("Hello A", rootObject.SomeService.DoSomething());
}
[Test]
public void SpringResolveB()
{
GenericApplicationContext container = new GenericApplicationContext();
container.RegisterType<RootObject>("RootObject");
container.RegisterType<ServiceImplementationB>("service");
RootObject rootObject = container.Resolve<RootObject>("RootObject");
Assert.AreEqual("Hello B", rootObject.SomeService.DoSomething());
}
This raises a few questions to me:
I want to integrate this technique into existing code that uses the usual container. Why do I have to use a different container type, GenericApplicationContext in this case? What if I want to read data into this object from the existing spring config in app.config or web.config? Would it work as the usual context? Could I then write data over these registrations with code?
How can I specify that ISomeService is to be created as a singleton? I don't mean supply a singleton instance to the container, but the container to create the instance, resolving its constructor, and use it when that type is needed.
how can I do the equivalent of container.RegisterType<ISomeService, ServiceImplementationA>(); ? I want to register type mappings to use in all cases where that type is needed by a constructor.
What exactly does container.RegisterType<ServiceImplementationA>("service"); do? It seems to register ServiceImplementationA as the implementation of ISomeService but ISomeServiceis never mentioned, so there could be ambiguity. e.g. what if ServiceImplementationA implemented more than one interface.
What is the string name given to the registration for? It won't work with en empty string, but it doesn't seem to matter what it is.
Am I trying to use spring in a way that it just does not work? I'm trying to use it like other IoC containers, but it's not quite working.
Adding as new answer trying to address the open points...
I want to integrate this technique
into existing code that uses the usual
container. Why do I have to use a
different container type,
GenericApplicationContext in this
case? What if I want to read data into
this object from the existing spring
config in app.config or web.config?
Would it work as the usual context?
Could I then write data over these
registrations with code?
Spring has concrete application context implementations for different kind of initialization tactics. The most common ones to use are GenericApplicationContext (manual), XmlApplicationContext (XML files) and WebApplicationContext (very much like XmlApplicationContext but tailored for web use). They all implement common interface: IApplicationContext which is the preferred way to access these containers.
Unfortonately altering registrations with code usually means that you need to use the specific sub-class directly. With GenericApplicationContext and StaticApplicationContext this is quite natural but XmlApplicationContext is usually considered to be XML only and this ways "fixed" to XML definition.
How can I specify that ISomeService is
to be created as a singleton? I don't
mean supply a singleton instance to
the container, but the container to
create the instance, resolving its
constructor, and use it when that type
is needed.
Your SpringHelper does just that, by default all objects in Spring are singletons. You could alter this behavior by calling ObjectDefinitionBuilder's SetSingleton method with false.
how can I do the equivalent of
container.RegisterType(); ? I want to
register type mappings to use in all
cases where that type is needed by a
constructor.
Spring uses object names (ids) to distinct between different implementations. So if you want to get specific type to serve a specific instance in case that there are many alternatives you should refer to this specific instance by name. If you are using autowiring and your object has dependency to interface ISomeService and there's only one object registered that implements it, the autowiring can set it without ambiguity.
What exactly does
container.RegisterType("service");
do? It seems to register
ServiceImplementationA as the
implementation of ISomeService but
ISomeServiceis never mentioned, so
there could be ambiguity. e.g. what if
ServiceImplementationA implemented
more than one interface.
Continuing from previous answer, this registers singleton of type ServiceImplementationA with name "service". This object comes autowiring candidate with all it's implemented interfaces (and with it's concrete type of course).
What is the string name given to the
registration for? It won't work with
en empty string, but it doesn't seem
to matter what it is.
It matters a great deal as explained earlier. The name is unique id within that context (parent context could have object with same name) and can be used to access specific object registrations. In short where other frameworks may associate a type as key to object registration, Spring uses name.
That's a bit apples and oranges comparison as the unit test uses code configuration for Unity and XML (app.config) configuration for Spring.NET.
If you go the XML route, then you can either comment out old implementation A and define the B implementation as the one to use - that what's configuration is all about right? Other option is to have dedicated XML files for each scenario (configuration setup) and include them via context's resource definitions (you have inline resource now). Other options include file system and assembly, see the web configuration section in Spring.NET's manual for a nice example.
If you go the code configuration route I would suggest to check Spring.NET Recoil and upcoming CodeConfig.