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I'm using SQL Server Compact 4.0 version, and although it might seem a simple thing to find in google, the examples I've tried none of them work.
My column signup_date is a DateTime with a value 04-09-2016 09:05:00.
What I've tried so far without success:
SELECT FORMAT(signup_date, 'Y-m-d') AS signup_date;
SELECT CONVERT(signup_date, GETDATE()) AS signup_date
SELECT CAST(data_registo, date) AS signup_date
I found that I could use DATEPART function, but that would force me to concat the values, is this the right path to follow? If so, how do I concat as Y-m-d?
SELECT DATEPART(month, signup_date)
SQL Server Compact has no date type.
If you don't want to see the time, convert the datetime value to a string:
SELECT CONVERT(nvarchar(10), GETDATE(), 120)
(This has been tested and actually works against SQL Server Compact)
you were actually on track with the CAST function just a slight error in the syntax. In the CAST function, there needs to be 'as' i.e CAST(data_registo as date)
SELECT CAST(data_registo as date) AS signup_date;
Most of the answers seek to achieve same thing but the explanation to the codes is not enough
CONVERT(date, Date_Updated, 120)
this code does the conversion with mssql. The first item 'date' is the datatype to return. it could be 'datetime', 'varchar', etc.
The second item 'Date_Updated' is the name of the column to be converted.
the last item '120' is the date style to be returned. There are various styles and the code entered will determine the output. '120' represent YYYY-MM-DD.
Hope this helps
The old fashioned way of doing this in SQL Server might work for your purposes:
select dateadd(day, datediff(day, 0, signup_date), 0)
The datediff() gets the number of days (as an integer) since time 0. The dateadd() adds this number back.
If you don't like 0 as a date, you can put any valid date in its place:
select dateadd(day, datediff(day, '2000-01-01', signup_date), '2000-01-01')
EDIT:
If you simply don't want to see the time, convert the date to a string:
select convert(nvarchar(10), signup_date, 120)
(I recommend the YYYY-MM-DD format, but others are available.)
I have tried this and many other solutions. I wanted a generic solution that would work with any LCID. My solution is a bit of convoluted code, but it works perfectly for me. It's a booking system where I needed to find out who was arriving on a particular date. ArriveDate is the column, d is the DATE I want.
SQL = "SELECT * FROM tablename WHERE dateadd(day, datediff(day, 0,
ArriveDate), 0)=' " & Format(d, "yyyy-MM-dd") & " ' "
This will return only date value in original datetime type. So you can do any comparison using the output
SELECT convert(datetime, CONVERT(nvarchar(10), GETDATE(), 120))
Just saw the Question today, a bit late I know :) but maybe this will help..,
select convert(date,(convert(varchar(20),'04-09-2016 09:05:00')))
select convert(nvarchar, getdate(), 1) = 09/25/19
select convert(nvarchar, getdate(), 2) = 19.09.25
select convert(nvarchar, getdate(), 3) = 25/09/19
select convert(nvarchar, getdate(), 4) = 25.09.19
select convert(nvarchar, getdate(), 5) = 25-09-19
select convert(nvarchar, getdate(), 6) = 25 Sep 19
select convert(nvarchar, getdate(), 7) = Sep 25, 19
select convert(nvarchar, getdate(), 10) = 09-25-19
select convert(nvarchar, getdate(), 11) = 19/09/25
select convert(nvarchar, getdate(), 12) = 190925
select convert(nvarchar, getdate(), 23) = 2019-09-25
select convert(nvarchar, getdate(), 101) = 09/25/2019
select convert(nvarchar, getdate(), 102) = 2019.09.25
select convert(nvarchar, getdate(), 103) = 25/09/2019
select convert(nvarchar, getdate(), 104) = 25.09.2019
select convert(nvarchar, getdate(), 105) = 25-09-2019
select convert(nvarchar, getdate(), 106) = 25 Sep 2019
select convert(nvarchar, getdate(), 107) = Sep 25, 2019
select convert(nvarchar, getdate(), 110) = 09-25-2019
select convert(nvarchar, getdate(), 111) = 2019/09/25
select convert(nvarchar, getdate(), 112) = 20190925
select convert(nvarchar, getdate(), 8) = 13:48:36
select convert(nvarchar, getdate(), 14) = 13:49:48:713
select convert(nvarchar, getdate(), 24) = 13:49:57
select convert(nvarchar, getdate(), 108) = 13:50:07
select convert(nvarchar, getdate(), 114) = 13:50:14:490
select convert(nvarchar, getdate(), 0) = Sep 25 2019 1:50PM
select convert(nvarchar, getdate(), 9) = Sep 25 2019 1:50:31:813PM
select convert(nvarchar, getdate(), 13) = 25 Sep 2019 13:50:39:307
select convert(nvarchar, getdate(), 20) = 2019-09-25 13:50:49
select convert(nvarchar, getdate(), 21) = 2019-09-25 13:50:58.923
select convert(nvarchar, getdate(), 22) = 09/25/19 1:51:07 PM
select convert(nvarchar, getdate(), 25) = 2019-09-25 13:51:14.473
select convert(nvarchar, getdate(), 100) = Sep 25 2019 1:51PM
select convert(nvarchar, getdate(), 109) = Sep 25 2019 1:51:32:227PM
select convert(nvarchar, getdate(), 113) = 25 Sep 2019 13:51:38:740
select convert(nvarchar, getdate(), 120) = 2019-09-25 13:51:50
select convert(nvarchar, getdate(), 121) = 2019-09-25 13:51:57.153
select convert(nvarchar, getdate(), 126) = 2019-09-25T13:52:03.627
Use this, i had the same problem
SELECT CAST(data_registo as date) AS "signup_date"
To get a string value, use CONVERT
select convert(varchar(10), signup_date, 11)
Check here for various formats:
https://msdn.microsoft.com/en-us/library/ms187928.aspx
To get a DATE, and just strip out the time, do this
Select Cast (signup_date as DATE)
Is there a function in SQL that formats a date when given the date and format string?
Similar to how .NET's DateTime.ToString(string format) method works?
I'd like to be able to call something like FORMAT(#myDateTime, 'ddMMMyyyy') and have it give me a string formatted as such.
I know the convert function works but it doesn't quite cover all formats. As an example, SQL can do "dd MMM yyyy" but not "ddMMMyyyy"
As far as I know there is no direct function that will convert date in format passed by you if you are on older SQL version. Format function is available starting from SQL 2012.
You can use convert function but it may not always suit your need.
Refer this: https://msdn.microsoft.com/en-IN/library/ms186724.aspx
To answer your question, this will give you date in DD-MMM-YYYY Format:
select REPLACE(REPLACE(CONVERT(VARCHAR,getdate(),106), ' ','-'), ',','')
For DDMMMYYYY format:
select REPLACE(REPLACE(REPLACE(CONVERT(VARCHAR,getdate(),106), ' ','-'), ',',''),'-','')
Also, you can check the date formats supported by convert function using this:
select convert(varchar, getdate(), 101)
select convert(varchar, getdate(), 102)
select convert(varchar, getdate(), 103)
select convert(varchar, getdate(), 104)
select convert(varchar, getdate(), 105)
select convert(varchar, getdate(), 106)
select convert(varchar, getdate(), 107)
select convert(varchar, getdate(), 108)
select convert(varchar, getdate(), 109)
select convert(varchar, getdate(), 110)
select convert(varchar, getdate(), 111)
select convert(varchar, getdate(), 112)
select convert(varchar, getdate(), 113)
I have a datetime column that I need to display in the following format:
YYYY/MM/DD 00:00:00:000
With CONVERT, I can't find any suitable styles.
The / in the format is really important as it needs to be compared with a VARCHAR column that has text YYYY/MM/DD 00:00 as part of the description like below:
If I can find a way/style then I can use a SUBSTRING function to compare it to the value below:
Diary item added for : 2013/08/20 14:12
I have had a look at:
http://databases.aspfaq.com/database/what-are-the-valid-styles-for-converting-datetime-to-string.html
But, I can't find any sufficient styles that has / 's. Only -'s.
You can use the style that most closely resembles what you want to compare on and use REPLACE to replace the - with \.
SELECT REPLACE(CONVERT(<yourstyle>),'-','/');
Edit Cudo's to #bluefeet
SELECT REPLACE(CONVERT(varchar(23), yourdate, 121),'-','/');
From Technet: Cast and Convert
21 or 121 (2) ODBC canonical (with milliseconds) yyyy-mm-dd
hh:mi:ss.mmm(24h)
Well you can convert both Dates in any format before you compare the two just use any of these: run this and you can select from them, make sure to convert both dates before Comparing
Select
convert(varchar, GetDate(), 100) as '100 Conversion',
convert(varchar, GetDate(), 101) as '101 Conversion',
convert(varchar, GetDate(), 102) as '102 Conversion',
convert(varchar, GetDate(), 103) as '103 Conversion',
convert(varchar, GetDate(), 104) as '104 Conversion',
convert(varchar, GetDate(), 105) as '105 Conversion',
convert(varchar, GetDate(), 106) as '106 Conversion',
convert(varchar, GetDate(), 107) as '107 Conversion',
convert(varchar, GetDate(), 108) as '108 Conversion',
convert(varchar, GetDate(), 109) as '109 Conversion',
convert(varchar, GetDate(), 110) as '110 Conversion',
convert(varchar, GetDate(), 111) as '111 Conversion',
convert(varchar, GetDate(), 112) as '112 Conversion',
convert(varchar, GetDate(), 113) as '113 Conversion',
convert(varchar, GetDate(), 114) as '114 Conversion',
convert(varchar, GetDate(), 120) as '120 Conversion',
convert(varchar, GetDate(), 121) as '121 Conversion',
convert(varchar, GetDate(), 126) as '126 Conversion',
convert(varchar, GetDate(), 130) as '130 Conversion',
convert(varchar, GetDate(), 131) as '131 Conversion'
Or Use this
select REPLACE(convert(varchar, GetDate(), 121),'-','/')
Why cant you do the reverse. Convert the varchar column to date instead of converting date to varchar
I have been trying to find a date format: dd/mm/yyyy hh:mm.
I am using convert (varchar, rc.CreatedDateTime, ???). 131 is not what i need either.
I seem to be able to find an awful lot that are very close, but not this particular one, am I missing something glaringly obvious or is there another function I can use??
You can use this, just replace the getdate() with your field:
select convert(char(10), getdate(), 103) + ' '
+ convert(char(8), getdate(), 108)
which gives you the results:
14/03/2012 17:05:47
If you just want the hour and seconds then:
select convert(char(10), getdate(), 103) + ' '
+ Left(convert(char(8), getdate(), 108), 2) + ':'
+ Right(convert(char(8), getdate(), 108), 2)
Here is a helpful link with date/time conversions:
http://anubhavg.wordpress.com/2009/06/11/how-to-format-datetime-date-in-sql-server-2005/
Based on your comment that it should be dd/mm/yyyy hh:mm then the query would be:
select convert(char(10), getdate(), 103) + ' '
+ Left(convert(char(8), getdate(), 108), 5)
OR without the LEFT()
select convert(varchar(10), getdate(), 103) + ' '
+ convert(char(5), getdate(), 108)
Assuming that you need dd/mm/yyyy hh:mm not dd/mm/yyyy hh:ss
SELECT convert (varchar(10), rc.CreatedDateTime, 103) + ' ' +
convert(varchar(5), rc.CreatedDateTime, 108)
SELECT CONVERT(CHAR(10), rc.CreatedDateTime, 103) + ' '
+ CONVERT(CHAR(5), rc.CreatedDateTime, 108)
FROM dbo.[table_name];
How can i convert the datetime format below
2010-10-25 11:13:36.700
into
25-Oct-2010 or 2010-10-25 00:00:00.000
To get "25-Oct-2010"
Assuming the value is supplied as a string, not a DATETIME data type:
SELECT REPLACE(CONVERT(VARCHAR, CAST('2010-10-25 11:13:36.700' AS DATETIME), 106), ' ', '-')
See the CAST/CONVERT documentation for other formats, though the one you requested requires post-processing.
To get "2010-10-25 00:00:00.000"
The best performing means is to use DATEADD & DATEDIFF:
SELECT DATEADD(d, DATEDIFF(dd, 0, '2010-10-25 11:13:36.700'), 0)
References:
DATEADD
DATEDIFF
Testing
WITH sample AS (
SELECT CAST('2010-10-25 11:13:36.700' AS DATETIME) dt)
SELECT REPLACE(CONVERT(VARCHAR, s.dt, 106), ' ', '-') AS col1,
DATEADD(d, DATEDIFF(dd, 0, s.dt), 0) AS col2
FROM sample s
Returns:
col1 col2
-------------------------------------
25-Oct-2010 2010-10-25 00:00:00.000
Addendum
Being that you're on SQL Server 2005, you could make date formatting easier for yourself by creating a SQLCLR function that would allow you to use the .NET date formatting.
check this one
SELECT convert(VARCHAR, getdate(),106)
this will give you 25 Oct 2010
AND
SELECT REPLACE(convert(VARCHAR, getdate(),106), ' ' , '-')
this will give you 25-Oct-2010
Check if this can help you:
SELECT REPLACE(CONVERT(VARCHAR(11), GETDATE(), 106), ' ', '-')
You can get more info Here
PD. Stackoverflow can be too addicted sometimes, you might wanna try google before
select CONVERT(NVARCHAR(20),getDATE(),105)
Please try
SELECT CONVERT(varchar, GETDATE(), 1) --12/30/06
SELECT CONVERT(varchar, GETDATE(), 2) --06.12.30
SELECT CONVERT(varchar, GETDATE(), 3) --30/12/06
SELECT CONVERT(varchar, GETDATE(), 4) --30.12.06
SELECT CONVERT(varchar, GETDATE(), 5) --30-12-06
SELECT CONVERT(varchar, GETDATE(), 6) --30 Dec 06
SELECT CONVERT(varchar, GETDATE(), 7) --Dec 30, 06
SELECT CONVERT(varchar, GETDATE(), 10) --12-30-06
SELECT CONVERT(varchar, GETDATE(), 11) --06/12/30
SELECT CONVERT(varchar, GETDATE(), 12) --061230
SELECT CONVERT(varchar, GETDATE(), 23) --2006-12-30
SELECT CONVERT(varchar, GETDATE(), 101) --12/30/2006
SELECT CONVERT(varchar, GETDATE(), 102) --2006.12.30
SELECT CONVERT(varchar, GETDATE(), 103) --30/12/2006
SELECT CONVERT(varchar, GETDATE(), 104) --30.12.2006
SELECT CONVERT(varchar, GETDATE(), 105) --30-12-2006
SELECT CONVERT(varchar, GETDATE(), 106) --30 Dec 2006
SELECT CONVERT(varchar, GETDATE(), 107) --Dec 30, 2006
SELECT CONVERT(varchar, GETDATE(), 110) --12-30-2006
SELECT CONVERT(varchar, GETDATE(), 111) --2006/12/30
SELECT CONVERT(varchar, GETDATE(), 112) --20061230