So how could we solve this exercise? I thougth about something like this:
- User is asked to enter a string
- The entered string is checked how many words does it have
-If the string consists of 1 word the first letter of this word is extracted, (like with an objectat) capitalized and printed out.
This may seem a bit strange from some of you but i try to figure it out the steps of resolving exercises simce i am still atbthe beginning of learning.
Very error prone solution:
NSString *name = #"Peter justus Falk";
NSArray *names = [name componentsSeparatedByString:#" "];
NSString *acronym = #"";
for (NSString *name in names) {
acronym = [acronym stringByAppendingString:[name substringToIndex:1].capitalizedString];
}
NSLog(acronym);
-> PJF
I have following string, and i want to show it in a UILabel properly with emojies and the new lines. Also I want to draw it using drawInRect method. How do I get them converted/Encoded/Decoded properly?
This string will change on runtime so should show any unicode character/ emoji or special characters such as \n or &
I'm sorry that I do not know proper terms to use to ask this question. Which makes it difficult for me to find an answer online. My knowledge about this topic is very low.
\ud83d\ude02\ud83d\ude02\ud83d\ude02\ud83d\ude02\ud83d\ude02\ud83d\ude05\ud83d\ude06
\u0db8\u0da0\u0d82
\u0d91\u0d9a\u0dca\u0d9a\n#set_with_machan\nkunuharapa na \n#Follow
#lankan_machan\nhttps://www.instagram.com/lankan_machan
after encoding the text should look like this with emojis, unicode characters & new lines.
I was able to find a solution and Edited it a bit. This un escapes the unicode characters perfectly and shows them properly. Shows the new lines too. Thanks #DanZimm for help.
- (NSString*) unescapeUnicodeString2:(NSString*)string
{
NSString* esc1 = [string stringByReplacingOccurrencesOfString:#"\\u" withString:#"\\U"];
NSString* esc2 = [esc1 stringByReplacingOccurrencesOfString:#"\"" withString:#"\\\""];
NSString* quoted = [[#"\"" stringByAppendingString:esc2] stringByAppendingString:#"\""];
NSData* data = [quoted dataUsingEncoding:NSUTF8StringEncoding];
NSString* unesc = [NSPropertyListSerialization propertyListWithData:data options:NSPropertyListImmutable format:NULL error:NULL];
assert([unesc isKindOfClass:[NSString class]]);
return unesc;
}
Solution found here I had to edit it because one of the methods were deprecated.
I'm looking for a way in the iPhone SDK to read in a Properties file (not the XML flavor) for example this one:
# a comment
! a comment
a = a string
b = a string with escape sequences \t \n \r \\ \" \' \ (space) \u0123
c = a string with a continuation line \
continuation line
d.e.f = another string
would result in four key/value pairs.
I can't change this format as it is sent to me by a web service. Can you please direct me?
Thanks,
Emmanuel
I would take a look at ParseKit http://parsekit.com/. Otherwise you could use RegexKitLite and create some regular expressions.
I've ended with this solution if anybody is interested :
#interface NSDictionary (PropertiesFile)
+ (NSDictionary *)dictionaryWithPropertiesFile:(NSString *)file;
#end
#implementation NSDictionary (PropertiesFile)
+ (NSDictionary *)dictionaryWithPropertiesFile:(NSString *)file {
NSError *error = nil;
NSString *propertyFileContent = [[NSString alloc] initWithContentsOfFile:file encoding:NSUTF8StringEncoding error:&error];
if (error) return nil;
NSArray *properties = [propertyFileContent componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]];
if (properties.count == 0) return nil;
NSMutableDictionary *result = [[NSMutableDictionary alloc] initWithCapacity:properties.count];
for (NSString *propertySting in properties) {
NSArray *property = [propertySting componentsSeparatedByString:#"="];
if (property.count != 2) continue;
[result setObject:property[1] forKey:property[0]];
}
return result.allKeys.count > 0 ? result : nil;
}
#end
It's a perfectly simple parsing problem. Read a line. Ignore if comment. Check for continuation, and read/append continuation lines as needed. Look for the "=". Make the left side of the "=" (after trimming white space) the key. Either parse the right side yourself or put it into an NSString and use stringWithFormat on it to "reduce" any escapes to pure character form. Return key and reduced right side.
(But refreshing my memory on the properties file format reminds me that:
The key contains all of the characters in the line starting with the
first non-white space character and up to, but not including, the
first unescaped '=', ':', or white space character other than a line
terminator. All of these key termination characters may be included in
the key by escaping them with a preceding backslash character;
So a little scanning of the line is required to separate the key from the rest. Nothing particularly difficult, though.)
Have you considered using lex/yacc or flex/bison to generate your own compiler code from a description of the grammar for properties files? I'm not sure if there are any existing grammars defined for a Java properties file, but it seems like it would be a pretty simple grammar to write.
Here's another SO post that mentions this approach for general purpose parsing
Take a look at this PropertyParser
NSString *text = #"sample key = sample value";
PropertyParser *propertyParser = [[PropertyParser alloc] init];
NSMutableDictionary *keyValueMap = [propertyParser parse:text];
You can now use NSRegularExpression class to do this.
How can I return the first three characters of an NSString?
mystr=[mystr substringToIndex:3];
Be sure your string has atleast 3 ch.. o.e. it will crash the app.
Here are some other links to check NSsting operations...
Link1
Link2
Apple Link
First, you have to make sure that the string contains at least 3 characters:
NSString *fullString = /* obtain from somewhere */;
NSString *prefix = nil;
if ([fullString length] >= 3)
prefix = [fullString substringToIndex:3];
else
prefix = fullString;
substringToIndex: will throw an exception if the index you provide is beyond the end of the string.
the right way is:
text = [text substringToIndex:NSMaxRange([text rangeOfComposedCharacterSequenceAtIndex:2])];
substringToIndex of NSString is indexing by code unit, emoji takes two code units.
make sure check the index yourself.
I'm trying to compare names without any punctuation, spaces, accents etc.
At the moment I am doing the following:
-(NSString*) prepareString:(NSString*)a {
//remove any accents and punctuation;
a=[[[NSString alloc] initWithData:[a dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES] encoding:NSASCIIStringEncoding] autorelease];
a=[a stringByReplacingOccurrencesOfString:#" " withString:#""];
a=[a stringByReplacingOccurrencesOfString:#"'" withString:#""];
a=[a stringByReplacingOccurrencesOfString:#"`" withString:#""];
a=[a stringByReplacingOccurrencesOfString:#"-" withString:#""];
a=[a stringByReplacingOccurrencesOfString:#"_" withString:#""];
a=[a lowercaseString];
return a;
}
However, I need to do this for hundreds of strings and I need to make this more efficient. Any ideas?
NSString* finish = [[start componentsSeparatedByCharactersInSet:[[NSCharacterSet letterCharacterSet] invertedSet]] componentsJoinedByString:#""];
Before using any of these solutions, don't forget to use decomposedStringWithCanonicalMapping to decompose any accented letters. This will turn, for example, é (U+00E9) into e ́ (U+0065 U+0301). Then, when you strip out the non-alphanumeric characters, the unaccented letters will remain.
The reason why this is important is that you probably don't want, say, “dän” and “dün”* to be treated as the same. If you stripped out all accented letters, as some of these solutions may do, you'll end up with “dn”, so those strings will compare as equal.
So, you should decompose them first, so that you can strip the accents and leave the letters.
*Example from German. Thanks to Joris Weimar for providing it.
On a similar question, Ole Begemann suggests using stringByFoldingWithOptions: and I believe this is the best solution here:
NSString *accentedString = #"ÁlgeBra";
NSString *unaccentedString = [accentedString stringByFoldingWithOptions:NSDiacriticInsensitiveSearch locale:[NSLocale currentLocale]];
Depending on the nature of the strings you want to convert, you might want to set a fixed locale (e.g. English) instead of using the user's current locale. That way, you can be sure to get the same results on every machine.
One important precision over the answer of BillyTheKid18756 (that was corrected by Luiz but it was not obvious in the explanation of the code):
DO NOT USE stringWithCString as a second step to remove accents, it can add unwanted characters at the end of your string as the NSData is not NULL-terminated (as stringWithCString expects it).
Or use it and add an additional NULL byte to your NSData, like Luiz did in his code.
I think a simpler answer is to replace:
NSString *sanitizedText = [NSString stringWithCString:[sanitizedData bytes] encoding:NSASCIIStringEncoding];
By:
NSString *sanitizedText = [[[NSString alloc] initWithData:sanitizedData encoding:NSASCIIStringEncoding] autorelease];
If I take back the code of BillyTheKid18756, here is the complete correct code:
// The input text
NSString *text = #"BûvérÈ!#$&%^&(*^(_()-*/48";
// Defining what characters to accept
NSMutableCharacterSet *acceptedCharacters = [[NSMutableCharacterSet alloc] init];
[acceptedCharacters formUnionWithCharacterSet:[NSCharacterSet letterCharacterSet]];
[acceptedCharacters formUnionWithCharacterSet:[NSCharacterSet decimalDigitCharacterSet]];
[acceptedCharacters addCharactersInString:#" _-.!"];
// Turn accented letters into normal letters (optional)
NSData *sanitizedData = [text dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
// Corrected back-conversion from NSData to NSString
NSString *sanitizedText = [[[NSString alloc] initWithData:sanitizedData encoding:NSASCIIStringEncoding] autorelease];
// Removing unaccepted characters
NSString* output = [[sanitizedText componentsSeparatedByCharactersInSet:[acceptedCharacters invertedSet]] componentsJoinedByString:#""];
If you are trying to compare strings, use one of these methods. Don't try to change data.
- (NSComparisonResult)localizedCompare:(NSString *)aString
- (NSComparisonResult)localizedCaseInsensitiveCompare:(NSString *)aString
- (NSComparisonResult)compare:(NSString *)aString options:(NSStringCompareOptions)mask range:(NSRange)range locale:(id)locale
You NEED to consider user locale to do things write with strings, particularly things like names.
In most languages, characters like ä and å are not the same other than they look similar. They are inherently distinct characters with meaning distinct from others, but the actual rules and semantics are distinct to each locale.
The correct way to compare and sort strings is by considering the user's locale. Anything else is naive, wrong and very 1990's. Stop doing it.
If you are trying to pass data to a system that cannot support non-ASCII, well, this is just a wrong thing to do. Pass it as data blobs.
https://developer.apple.com/library/ios/documentation/cocoa/Conceptual/Strings/Articles/SearchingStrings.html
Plus normalizing your strings first (see Peter Hosey's post) precomposing or decomposing, basically pick a normalized form.
- (NSString *)decomposedStringWithCanonicalMapping
- (NSString *)decomposedStringWithCompatibilityMapping
- (NSString *)precomposedStringWithCanonicalMapping
- (NSString *)precomposedStringWithCompatibilityMapping
No, it's not nearly as simple and easy as we tend to think.
Yes, it requires informed and careful decision making. (and a bit of non-English language experience helps)
Consider using the RegexKit framework. You could do something like:
NSString *searchString = #"This is neat.";
NSString *regexString = #"[\W]";
NSString *replaceWithString = #"";
NSString *replacedString = [searchString stringByReplacingOccurrencesOfRegex:regexString withString:replaceWithString];
NSLog (#"%#", replacedString);
//... Thisisneat
Consider using NSScanner, and specifically the methods -setCharactersToBeSkipped: (which accepts an NSCharacterSet) and -scanString:intoString: (which accepts a string and returns the scanned string by reference).
You may also want to couple this with -[NSString localizedCompare:], or perhaps -[NSString compare:options:] with the NSDiacriticInsensitiveSearch option. That could simplify having to remove/replace accents, so you can focus on removing puncuation, whitespace, etc.
If you must use an approach like you presented in your question, at least use an NSMutableString and replaceOccurrencesOfString:withString:options:range: — that will be much more efficient than creating tons of nearly-identical autoreleased strings. It could be that just reducing the number of allocations will boost performance "enough" for the time being.
To give a complete example by combining the answers from Luiz and Peter, adding a few lines, you get the code below.
The code does the following:
Creates a set of accepted characters
Turn accented letters into normal letters
Remove characters not in the set
Objective-C
// The input text
NSString *text = #"BûvérÈ!#$&%^&(*^(_()-*/48";
// Create set of accepted characters
NSMutableCharacterSet *acceptedCharacters = [[NSMutableCharacterSet alloc] init];
[acceptedCharacters formUnionWithCharacterSet:[NSCharacterSet letterCharacterSet]];
[acceptedCharacters formUnionWithCharacterSet:[NSCharacterSet decimalDigitCharacterSet]];
[acceptedCharacters addCharactersInString:#" _-.!"];
// Turn accented letters into normal letters (optional)
NSData *sanitizedData = [text dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *sanitizedText = [NSString stringWithCString:[sanitizedData bytes] encoding:NSASCIIStringEncoding];
// Remove characters not in the set
NSString* output = [[sanitizedText componentsSeparatedByCharactersInSet:[acceptedCharacters invertedSet]] componentsJoinedByString:#""];
Swift (2.2) example
let text = "BûvérÈ!#$&%^&(*^(_()-*/48"
// Create set of accepted characters
let acceptedCharacters = NSMutableCharacterSet()
acceptedCharacters.formUnionWithCharacterSet(NSCharacterSet.letterCharacterSet())
acceptedCharacters.formUnionWithCharacterSet(NSCharacterSet.decimalDigitCharacterSet())
acceptedCharacters.addCharactersInString(" _-.!")
// Turn accented letters into normal letters (optional)
let sanitizedData = text.dataUsingEncoding(NSASCIIStringEncoding, allowLossyConversion: true)
let sanitizedText = String(data: sanitizedData!, encoding: NSASCIIStringEncoding)
// Remove characters not in the set
let components = sanitizedText!.componentsSeparatedByCharactersInSet(acceptedCharacters.invertedSet)
let output = components.joinWithSeparator("")
Output
The output for both examples would be: BuverE!_-48
Just bumped into this, maybe its too late, but here is what worked for me:
// text is the input string, and this just removes accents from the letters
// lossy encoding turns accented letters into normal letters
NSMutableData *sanitizedData = [text dataUsingEncoding:NSASCIIStringEncoding
allowLossyConversion:YES];
// increase length by 1 adds a 0 byte (increaseLengthBy
// guarantees to fill the new space with 0s), effectively turning
// sanitizedData into a c-string
[sanitizedData increaseLengthBy:1];
// now we just create a string with the c-string in sanitizedData
NSString *final = [NSString stringWithCString:[sanitizedData bytes]];
#interface NSString (Filtering)
- (NSString*)stringByFilteringCharacters:(NSCharacterSet*)charSet;
#end
#implementation NSString (Filtering)
- (NSString*)stringByFilteringCharacters:(NSCharacterSet*)charSet {
NSMutableString * mutString = [NSMutableString stringWithCapacity:[self length]];
for (int i = 0; i < [self length]; i++){
char c = [self characterAtIndex:i];
if(![charSet characterIsMember:c]) [mutString appendFormat:#"%c", c];
}
return [NSString stringWithString:mutString];
}
#end
These answers didn't work as expected for me. Specifically, decomposedStringWithCanonicalMapping didn't strip accents/umlauts as I'd expected.
Here's a variation on what I used that answers the brief:
// replace accents, umlauts etc with equivalent letter i.e 'é' becomes 'e'.
// Always use en_GB (or a locale without the characters you wish to strip) as locale, no matter which language we're taking as input
NSString *processedString = [string stringByFoldingWithOptions: NSDiacriticInsensitiveSearch locale: [NSLocale localeWithLocaleIdentifier: #"en_GB"]];
// remove non-letters
processedString = [[processedString componentsSeparatedByCharactersInSet:[[NSCharacterSet letterCharacterSet] invertedSet]] componentsJoinedByString:#""];
// trim whitespace
processedString = [processedString stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
return processedString;
Peter's Solution in Swift:
let newString = oldString.componentsSeparatedByCharactersInSet(NSCharacterSet.letterCharacterSet().invertedSet).joinWithSeparator("")
Example:
let oldString = "Jo_ - h !. nn y"
// "Jo_ - h !. nn y"
oldString.componentsSeparatedByCharactersInSet(NSCharacterSet.letterCharacterSet().invertedSet)
// ["Jo", "h", "nn", "y"]
oldString.componentsSeparatedByCharactersInSet(NSCharacterSet.letterCharacterSet().invertedSet).joinWithSeparator("")
// "Johnny"
I wanted to filter out everything except letters and numbers, so I adapted Lorean's implementation of a Category on NSString to work a little different. In this example, you specify a string with only the characters you want to keep, and everything else is filtered out:
#interface NSString (PraxCategories)
+ (NSString *)lettersAndNumbers;
- (NSString*)stringByKeepingOnlyLettersAndNumbers;
- (NSString*)stringByKeepingOnlyCharactersInString:(NSString *)string;
#end
#implementation NSString (PraxCategories)
+ (NSString *)lettersAndNumbers { return #"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; }
- (NSString*)stringByKeepingOnlyLettersAndNumbers {
return [self stringByKeepingOnlyCharactersInString:[NSString lettersAndNumbers]];
}
- (NSString*)stringByKeepingOnlyCharactersInString:(NSString *)string {
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:string];
NSMutableString * mutableString = #"".mutableCopy;
for (int i = 0; i < [self length]; i++){
char character = [self characterAtIndex:i];
if([characterSet characterIsMember:character]) [mutableString appendFormat:#"%c", character];
}
return mutableString.copy;
}
#end
Once you've made your Categories, using them is trivial, and you can use them on any NSString:
NSString *string = someStringValueThatYouWantToFilter;
string = [string stringByKeepingOnlyLettersAndNumbers];
Or, for example, if you wanted to get rid of everything except vowels:
string = [string stringByKeepingOnlyCharactersInString:#"aeiouAEIOU"];
If you're still learning Objective-C and aren't using Categories, I encourage you to try them out. They're the best place to put things like this because it gives more functionality to all objects of the class you Categorize.
Categories simplify and encapsulate the code you're adding, making it easy to reuse on all of your projects. It's a great feature of Objective-C!