I have a simple Access table [Parts] that stores the data
Part# CYTD_SALES CUST_NUM
I need to rank the parts in terms of CYTD Sales (Current Year To Day Sales) for each CUST_NUM (Customer Number) separately
I am using the following statement:
Rank:
(SELECT Count (*)
FROM [Parts] as R
Where [CYTD Sales] > [Parts].[CYTD Sales]
And > CUST_NUM= [Parts].[CUST_NUM] ) + 1
I ran into situation when the same amount was spent for more than 1 part by same customer, so the ranking looks like this
1 2 4 4 5
instead of
1 2 3 4 5
Is there a way to write a statement that would not allow identical rankings for the same customer?
Thank you!
Since Part# field is unique for each customer, below is the statement that worked for me:
(SELECT Count (*)
FROM [Parts] as R
Where ([CYTD Sales] > [Parts].[CYTD Sales] Or
([CYTD Sales]=[Parts].[CYTD Sales] And
[Part#]> [Parts].[Part#]))
And > CUST_NUM= [Parts].[CUST_NUM] ) + 1
Related
Select
Count(Distinct iif(t.HasReplyTask = 1, t.CustomerID, Null)) As Reply,
Count(Distinct iif(t.HasOverdueTask = 1, t.CustomerID, Null)) As Overdue,
Count(Distinct t.CustomerID) As Total
From
Table1 t
If a customer is in Reply, we need to remove that customer in Overdue count, That means if Customer 123 is in both, The Overdue count should be one less. How can I do this?
I am adding some data here,
Customer 123 has "HasReplyTask", so, we have to filter that customer from Count in OverDue(even though that customer has one Overdue task without HasReplyTask). 234 is one and Distinct of 456 is one.
So, the overdue count should be 2, Above query returns 3
If I've got it right, this can be done using a subquery to get the numbers for each customer, and then get the summary information as follows:
Select Sum(HasReplyTask) As Reply,
Sum(HasOverdueTask) As Overdue,
Count(CustomerID) As Total
From (
Select CustomerID,
IIF(Max(Cast(HasReplyTask As TinyInt))<>0, 0, Max(Cast(HasOverdueTask As TinyInt))) As HasOverdueTask,
Max(Cast(HasReplyTask As TinyInt)) As HasReplyTask
From Table1
Group by CustomerID) As T
I don't know about column data types, so I used cast function to use max function.
db<>fiddle
Reply
Overdue
Total
1
2
3
What would probably be more efficient for you is to pre-aggregate your table by customer ID and have counts per customer. Then your outer query can test for whatever you are really looking for. Something like
select
sum( case when PQ.ReplyCount > 0 then 1 else 0 end ) UniqReply,
sum( case when PQ.OverdueCount > 0 then 1 else 0 end ) UniqOverdue,
sum( case when PQ.OverdueCount - PQ.ReplyCount > 0 then 1 else 0 end ) PendingReplies,
count(*) as UniqCustomers
from
( select
yt.customerid,
count(*) CustRecs,
sum( case when yt.HasReplyTask = 1 then 1 else 0 end ) ReplyCount,
sum( case when yt.HasOverdueTask = 1 then 1 else 0 end ) OverdueCount
from
yourTable yt
group by
yt.customerid ) PQ
Now to differentiate the count you are REALLY looking for, you might need to do a test against the prequery (PQ) of ReplyCount vs OverdueCount such as... For a single customer ID (thus the pre query), if the OverdueCount is GREATER than the ReplyCount, then it is still considered overdue? So for customer 123, they had 3 overdue, but only 2 replies. You want that counted once? But for customers 234 and 456, the only had overdue entries and NO replies. So, the total where Overdue - Reply > 0 = 3 distinct people.
Is that your ultimate goal?
I am working on a project in which I want to use Case to calculate price of product under specific Reference Number in SQL server. Below is my Sql query
SELECT
product AS Products,
refNum AS Refrence,
COUNT(id) AS Count
FROM ProductPriceList
GROUP BY
refNum, product
By Executing Above query I get:
Product Reference Count
Product1 Ref08 24
Product2 Ref08 7
Product3 Ref07 32
Product2 Ref12 1
Product3 Ref12 18
Product1 Ref07 76
Product1 Null 56
Can anyone guide me how to use Case statement in Sql query with group by statement to show price Below is the case:
if count < 10 then price 1
if count > 10 and < 100 then price 2
if count > 100 then price 3
I don't want to add a new table in my database. I hope you can understand my query.
Thanks in advance.
I think a basic CASE expression can handle your requirement:
SELECT
product AS Products,
refNum AS Refrence,
CASE WHEN COUNT(*) < 10 THEN 1
WHEN COUNT(*) >= 10 AND COUNT(*) < 100 THEN 2
ELSE 3 END AS price
FROM ProductPriceList
GROUP BY
product, refNum;
Not much to explain here, except that the 2 price case uses a bound which includes the count of 10 (since the 1 price case excludes it).
Here's alternative (doesn't differ much from exisiting one though):
You can use your query in subquery and use case outside:
select product,
--to get NULL values back
case Reference when 'RefNull' then NULL else Reference end [Reference],
case when [Count] < 10 then 1
when [Count] between 10 and 100 then 2
else 3 end [price]
from (
SELECT product AS Products,
--to allow also null values to be grouped
coalesce(refNum, 'RefNull') AS Refrence,
COUNT(id) AS Count
FROM ProductPriceList
GROUP BY coalesce(refNum, 'RefNull'), product
) [a]
Dataset:
Create Table ProductPriceList
(
Product varchar(10)
,RefNum CHAR(5)
,Records Int
);
Insert into ProductPriceList
Values
('Product1','Ref08',24)
,('Product2','Ref08',7)
,('Product3','Ref07',32)
,('Product2','Ref12',1)
,('Product3','Ref12',18)
,('Product1','Ref07',76)
,('Product1', NULL, 56);
With RCTE AS
(
Select Product
,RefNum
,Records
,1 RowNo
From ProductPriceList PPL
Union All
Select Product
,RefNum
,Records
,RowNo + 1
From RCTE R
Where RowNo + 1 < Records
)
Insert Into ProductPriceList (Product, RefNum, Records)
Select Product, RefNum, Records
From RCTE
where Records > 1
Query to fetch desired result:
Select Product
,RefNum
,Case When Count(*) < 10 Then 1
When Count(*) Between 10 and 99 then 2
Else 3 End Price
From ProductPriceList
Group By Product, RefNum
SQL Fiddle
I have three columns, all consisting of 1's and 0's. For each of these columns, how can I calculate the percentage of people (one person is one row/ id) who have a 1 in the first column and a 1 in the second or third column in oracle SQL?
For instance:
id marketing_campaign personal_campaign sales
1 1 0 0
2 1 1 0
1 0 1 1
4 0 0 1
So in this case, of all the people who were subjected to a marketing_campaign, 50 percent were subjected to a personal campaign as well, but zero percent is present in sales (no one bought anything).
Ultimately, I want to find out the order in which people get to the sales moment. Do they first go from marketing campaign to a personal campaign and then to sales, or do they buy anyway regardless of these channels.
This is a fictional example, so I realize that in this example there are many other ways to do this, but I hope anyone can help!
The outcome that I'm looking for is something like this:
percentage marketing_campaign/ personal campaign = 50 %
percentage marketing_campaign/sales = 0%
etc (for all the three column combinations)
Use count, sum and case expressions, together with basic arithmetic operators +,/,*
COUNT(*) gives a total count of people in the table
SUM(column) gives a sum of 1 in given column
case expressions make possible to implement more complex conditions
The common pattern is X / COUNT(*) * 100 which is used to calculate a percent of given value ( val / total * 100% )
An example:
SELECT
-- percentage of people that have 1 in marketing_campaign column
SUM( marketing_campaign ) / COUNT(*) * 100 As marketing_campaign_percent,
-- percentage of people that have 1 in sales column
SUM( sales ) / COUNT(*) * 100 As sales_percent,
-- complex condition:
-- percentage of people (one person is one row/ id) who have a 1
-- in the first column and a 1 in the second or third column
COUNT(
CASE WHEN marketing_campaign = 1
AND ( personal_campaign = 1 OR sales = 1 )
THEN 1 END
) / COUNT(*) * 100 As complex_condition_percent
FROM table;
You can get your percentages like this :
SELECT COUNT(*),
ROUND(100*(SUM(personal_campaign) / sum(count(*)) over ()),2) perc_personal_campaign,
ROUND(100*(SUM(sales) / sum(count(*)) over ()),2) perc_sales
FROM (
SELECT ID,
CASE
WHEN SUM(personal_campaign) > 0 THEN 1
ELSE 0
end AS personal_campaign,
CASE
WHEN SUM(sales) > 0 THEN 1
ELSE 0
end AS sales
FROM the_table
WHERE ID IN
(SELECT ID FROM the_table WHERE marketing_campaign = 1)
GROUP BY ID
)
I have a bit overcomplicated things because your data is still unclear to me. The subquery ensures that all duplicates are cleaned up and that you only have for each person a 1 or 0 in marketing_campaign and sales
About your second question :
Ultimately, I want to find out the order in which people get to the
sales moment. Do they first go from marketing campaign to a personal
campaign and then to sales, or do they buy anyway regardless of these
channels.
This is impossible to do in this state because you don't have in your table, either :
a unique row identifier that would keep the order in which the rows were inserted
a timestamp column that would tell when the rows were inserted.
Without this, the order of rows returned from your table will be unpredictable, or if you prefer, pure random.
Suppose I have a sales table which is as follows:
ID | Price
----------------------
1 0.33
2 1.5
3 0.5
4 10
5 0.99
I would like to find, in a single query, the proportion of rows verifying a given condition. For example, if the condition is Price < 1, the result should be 3/5 = 0.6.
The only workaround that I have found so far is :
SELECT
SUM(
CASE
WHEN Price < 1
THEN 1
WHEN Price >= 1
THEN 0
END
)/COUNT(*)
FROM sales
but is there a way to do this without CASE ?
You can do it with IF:
SELECT SUM(IF(Price < 1, 1, 0))/COUNT(*) FROM sales
-but it's no big difference from CASE (your logic here is correct)
You may want to use WHERE (to sum only Price<1) - but since you're using total COUNT it's not valid in your case. Another option: get total count separately:
SELECT
COUNT(sales.Price)/total_count
FROM
sales
CROSS JOIN (SELECT COUNt(*) AS total_count FROM sales) AS c
WHERE
-- you're summing 1 or 0 depending of Price, so your sum is
-- just count where Price<1
sales.Price<1
I have table of bids, each bid has Amount and AuctionID.
I want to SUM/SELECT all the highest bids from each AuctionID..
Example:
The Result of:
SELECT AuctionID,Amount, Highest FROM Bids Where Burned=0 ORDER BY Amount DESC
AuctionID Amount Highest
1 44.4400 0
3 43.7800 0
2 42.3300 0
1 22.2200 0
4 21.2700 0
1 21.2600 0
4 21.2500 0
2 21.2400 0
1 12.6600 0
4 12.5200 0
It should return 44.44, 43.78, 42.33, 21.27 .
The 'Highest' is a flag that i thought may be helpful it still has no use.
I wanted to see if there is a method to do with without using a Flag.
A simple group by clause will do the trick:
select AuctionID, MAX(Amount)
from table
group by AuctionID
SELECT AuctionId, MAX(Amount) FROM TableName GROUP BY AuctionID
To get all the highest bids:
Select auctionid, max(amount) from auctions group by auctionid
To get the overall sum of the highest bids:
select sum(v1.max_amount) from
(Select auctionid, max(amount) max_amount from auctions group by auctionid
) as v1