How do I swap ani and dnis values around if direction is 0? If direction is 1 it should be left unchanged - xslt-1.0

Question

How do I swap ani and dnis values around if direction is 0? If direction is 1 it should be left unchanged.
I have tried with a if command but can get it to work. I hope samebody have a solution for this little issue :)
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes" />
<xsl:template match="/">
<Call xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Data>
<time_offset>
<xsl:number value="0"/>
</time_offset>
<audio>
<audio_segement>
<channel_id>0</channel_id>
<recording_order>1</recording_order>
<audio_url>
<xsl:value-of select="callinfo/location"/>
</audio_url>
<xsl:apply-templates select="callinfo/startdate"/>
<xsl:apply-templates select="StartTime"/>
<Duration>
<xsl:value-of select="callinfo/duration"/>
</Duration>
</audio_segement>
</audio>
<direction>
<xsl:value-of select="callinfo/direction"/>
</direction>
<ani>
<xsl:value-of select="callinfo/local"/>
</ani>
<dnis>
<xsl:value-of select="callinfo/remote"/>
</dnis>
<unique_identifier>
<xsl:value-of select="callinfo/startdate"/>
</unique_identifier>
<pbx_login_id>
<xsl:value-of select="callinfo/local"/>
</pbx_login_id>
<switch_name>Mobile Data Source</switch_name>
</Data>
</Call>
</xsl:template>
<xsl:template match="callinfo/startdate">
<StartTime>
<xsl:variable name="StartTime">
<xsl:value-of select="concat(substring-before(., ' '), 'T', substring-after(., ' '))"/>
</xsl:variable>
<xsl:variable name="startTimeSize" select = "string-length(.)"/>
<xsl:if test="$startTimeSize = 19">
<xsl:value-of select="$StartTime"/>.00+00:00
</xsl:if>
<xsl:if test="$startTimeSize = 33">
<xsl:value-of select="substring($StartTime,0,24)"/>
<xsl:value-of select="substring($StartTime,28,7)"/>
</xsl:if>
<xsl:if test="$startTimeSize != 33 and $startTimeSize != 19">
<xsl:value-of select="$StartTime"/>
</xsl:if>
</StartTime>
</xsl:template>
</xsl:stylesheet>
Any help will be greatly appreciated.

Answer 1

I am still not sure I understand this. If you just want to change the order in which the elements appear in the output document, without changing their contents, change this part:
<ani>
<xsl:value-of select="callinfo/local"/>
</ani>
<dnis>
<xsl:value-of select="callinfo/remote"/>
</dnis>
to:
<xsl:choose>
<xsl:when test="callinfo/direction=1">
<ani><xsl:value-of select="callinfo/local"/></ani>
<dnis><xsl:value-of select="callinfo/remote"/></dnis>
</xsl:when>
<xsl:otherwise>
<dnis><xsl:value-of select="callinfo/remote"/></dnis>
<ani><xsl:value-of select="callinfo/local"/></ani>
</xsl:otherwise>
</xsl:choose>
Note that in a well-designed XML, the order of siblings should not matter - that's what element names are there for.