Update / Merge table with summing values - sql

I have a schema:
http://sqlfiddle.com/#!4/e9917/1
CREATE TABLE test_table (
id NUMBER,
period NUMBER,
amount NUMBER
);
INSERT INTO test_table VALUES (1000, 1, 100);
INSERT INTO test_table VALUES (1000, 1, 500);
INSERT INTO test_table VALUES (1001, 1, 200);
INSERT INTO test_table VALUES (1001, 2, 300);
INSERT INTO test_table VALUES (1002, 1, 900);
INSERT INTO test_table VALUES (1002, 1, 250);
I want to update the amount field by adding amounts of records which has same (id, period) pair. like after op :
ID| period| amount
1000 1 600
1001 1 200
1001 2 300
1002 1 1150
I Couldn't figure out how :(
EDIT:
In actual case this table is populated by insertion operation from other 2 tables:
CREATE TABLE some_table1(
id NUMBER,
period NUMBER,
amount NUMBER
);
INSERT INTO some_table1 VALUES (1000, 1, 100);
INSERT INTO some_table1 VALUES (1000, 1, 500);
INSERT INTO some_table1 VALUES (1001, 1, 200);
INSERT INTO some_table1 VALUES (1001, 2, 300);
INSERT INTO some_table1 VALUES (1002, 1, 900);
INSERT INTO some_table1 VALUES (1002, 1, 250);
CREATE TABLE some_table2(
id NUMBER,
period NUMBER,
amount NUMBER
);
INSERT INTO some_table2 VALUES (1000, 1, 30);
INSERT INTO some_table2 VALUES (1000, 1, 20);
INSERT INTO some_table2 VALUES (1001, 1, 15);
INSERT INTO some_table2 VALUES (1001, 2, 20);
INSERT INTO some_table2 VALUES (1002, 1, 50);
INSERT INTO some_table2 VALUES (1002, 1, 60);
Dublicates occures when two insertions done:
INSERT INTO TEST_TABLE (id,period,amount) SELECT id,period,amount from some_table1
INSERT INTO TEST_TABLE (id,period,amount) SELECT id,period,amount from some_table2
new sqlfiddle link: http://sqlfiddle.com/#!4/cd45b/1
May be it can be solved during insertion from two table..

A script like this would do what you want:
CREATE TABLE test_table_summary (
id NUMBER,
period NUMBER,
amount NUMBER
);
INSERT INTO test_table_summary (id, period, amount)
SELECT id, period, SUM(amount) AS total_amount FROM test_table
GROUP BY id, period;
DELETE FROM test_table;
INSERT INTO test_table (id, period, amount)
SELECT id, period, total_amount FROM test_table_summary;
DROP TABLE test_table_summary;
But you should actually decide if test_table is to have a primary key and the total amount or all the detail data. It's not a good solution to use one table for both.
By what you have added, then I'd say you can use the Oracle MERGE INTO statement:
MERGE INTO test_table t
USING (SELECT id, period, amount FROM some_table1) s
ON (t.id=s.id AND t.period=s.period)
WHEN MATCHED THEN UPDATE SET t.amount=t.amount+s.amount
WHEN NOT MATCHED THEN INSERT (t.id, t.period, t.amount)
VALUES (s.id, s.period, s.amount);
Beware though... this will work only if test_table already has no duplicate id, period rows to begin with. So if your table is already messed up, you still have to reinitialize it properly a first time (and maybe add a unique id, period key to avoid problems in the future).

Related

SQL to assign covid patients to hospitals

I have 2 tables:
CREATE TABLE remdesivir_inventory
(
hospital_id int,
stock int,
state varchar(2)
);
CREATE TABLE remdesivir_requests
(
patient_id int,
prescribed_qty int,
state varchar(2)
);
I want to write a SQL that inserts rows in the remdesivir_assignments table
Every patient whose request can be fulfilled (until the stock runs out) will have a representative row in
the remdesivir_assignments table.
Each patient can be assigned to only 1 hospital (ie. requests cannot be split)
The 'state' of the patient and the hospital must match
CREATE TABLE remdesivir_assignments
(
patient_id int,
hospital_id int
);
Example:
INSERT INTO remdesivir_inventory VALUES (1, 200, 'CA');
INSERT INTO remdesivir_inventory VALUES (2, 100, 'FL');
INSERT INTO remdesivir_inventory VALUES (3, 500, 'TX');
INSERT INTO remdesivir_requests VALUES (10, 100, 'CA');
INSERT INTO remdesivir_requests VALUES (20, 200, 'FL');
INSERT INTO remdesivir_requests VALUES (30, 300, 'TX');
INSERT INTO remdesivir_requests VALUES (40, 100, 'AL');
INSERT INTO remdesivir_requests VALUES (50, 200, 'CA');
In this scenario, the following rows will be inserted to the remdesivir_assignments table
(10, 1)
(30, 3)
You can use a cumulative sum and join:
select rr.*, ri.hospital_id
from (select rr.*,
sum(prescribed_qty) over (partition by state order by patient_id) as running_pq
from remdesivir_requests rr
) rr join
remdesivir_inventory ri
on ri.state = rr.state and
rr.running_pq <= ri.stock
Here is a db<>fiddle.

How to calculate the average value of following n rows based on another column - SQL (Oracle)

I am trying to calculate average monthly value of premiums for each POLICY_ID in monthly basis as shown below. When a customer updates his/her yearly payment frequency to a value different than 12, I need to manually calculate the average monthly value for the PREMIUM. How can I achieve the values shown in MONTHLY _PREMIUM_DESIRED?
Thanks in advance.
Note: Oracle version 12c
What I've tried:
SELECT
T.*,
SUM(PREMIUM) OVER(PARTITION BY T.POLICY_ID ORDER BY T.POLICY_ID, T.PAYMENT_DATE ROWS BETWEEN CURRENT ROW AND 12/T.YEARLY_PAYMENT_FREQ-1 FOLLOWING ) / (12/T.YEARLY_PAYMENT_FREQ) MONTLY_PREMIUM_CALCULATED
FROM MYTABLE T
;
Code for data:
DROP TABLE MYTABLE;
CREATE TABLE MYTABLE (POLICY_ID NUMBER(11), PAYMENT_DATE DATE, PREMIUM NUMBER(5), YEARLY_PAYMENT_FREQ NUMBER(2),MONTHLY_PREMIUM_DESIRED NUMBER(5));
INSERT INTO MYTABLE VALUES (1, DATE '2014-10-01',120,12,120);
INSERT INTO MYTABLE VALUES (1, DATE '2014-11-01',360,4,120);
INSERT INTO MYTABLE VALUES (1, DATE '2014-12-01',0,4,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-01-01',0,4,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-02-01',360,4,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-03-01',0,4,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-04-01',0,4,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-05-01',720,2,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-06-01',0,2,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-07-01',0,2,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-08-01',0,2,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-09-01',0,2,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-10-01',0,2,120);
INSERT INTO MYTABLE VALUES (1, DATE '2015-11-01',120,12,120);
INSERT INTO MYTABLE VALUES (2, DATE '2015-01-01',60,3,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-02-01',0,3,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-03-01',0,3,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-04-01',0,3,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-05-01',180,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-06-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-07-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-08-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-09-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-10-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-11-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2015-12-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2016-01-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2016-02-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2016-03-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2016-04-01',0,1,15);
INSERT INTO MYTABLE VALUES (2, DATE '2016-05-01',15,12,15);
INSERT INTO MYTABLE VALUES (2, DATE '2016-06-01',15,12,15);
SELECT * FROM MYTABLE;
EDIT:
Regardless from payment frequency PREMIUM amount can also be changed by customer. Below, for the POLICY_ID = 1, I have added new records starting from "2015/11/01" to demonstrate this situation. In this case, average monthly premium increased from 120 to 240.
Also removed the screenshot to make the question more readable.
DROP TABLE MYTABLE2;
CREATE TABLE MYTABLE2 (POLICY_ID NUMBER(11), PAYMENT_DATE DATE, PREMIUM NUMBER(5), YEARLY_PAYMENT_FREQ NUMBER(2),MONTHLY_PREMIUM_DESIRED NUMBER(5));
INSERT INTO MYTABLE2 VALUES (1, DATE '2014-10-01',120,12,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2014-11-01',360,4,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2014-12-01',0,4,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-01-01',0,4,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-02-01',360,4,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-03-01',0,4,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-04-01',0,4,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-05-01',720,2,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-06-01',0,2,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-07-01',0,2,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-08-01',0,2,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-09-01',0,2,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-10-01',0,2,120);
INSERT INTO MYTABLE2 VALUES (1, DATE '2015-11-01',240,12,240);
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-12-01',240,12,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-01-01',960,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-02-01',0,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-03-01',0,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-04-01',0,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-05-01',960,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-06-01',0,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-07-01',0,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (1, DATE '2016-08-01',0,4,240); --newly added records
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-01-01',60,3,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-02-01',0,3,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-03-01',0,3,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-04-01',0,3,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-05-01',180,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-06-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-07-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-08-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-09-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-10-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-11-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2015-12-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2016-01-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2016-02-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2016-03-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2016-04-01',0,1,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2016-05-01',15,12,15);
INSERT INTO MYTABLE2 VALUES (2, DATE '2016-06-01',15,12,15);
SELECT * FROM MYTABLE2;
I think the calculation is:
select t.*,
premium / (12 / yearly_payment_freq)) as monthly_premium_calculated
from mytable t;
EDIT:
I see, you also need this spread over the intermediate months. So you can assign the groups by counting the number of non-zero payments. Then:
select t.*,
( max(premium) over (partition by policy_id, grp) /
(12 / yearly_payment_freq)
) as monthly_premium_calculated
from (select t.*,
sum(case when premium > 0 then 1 else 0 end) over (partition by policy_id order by payment_date) as grp
from mytable t
) t;
Here is a db<>fiddle (it uses Postgres because that is easier to set up than Oracle).

Can I reference this table?

I am trying to show amount paid for each tutor sorted by month and then by tutor id. I have the first part correct and can sort by month but cannot sort by tutor id because it is from a different table.
Here is the script for my tables:
create table match_history
(match_id number(3),
tutor_id number(3),
student_id number(4),
start_date date,
end_date date,
constraint pk_match_history primary key (match_id),
constraint fk1_match_history foreign key (tutor_id) references tutor(tutor_id),
constraint fk2_match_history foreign key (student_id) references student(student_id));
create table tutor_report
(match_id number(3),
month date,
hours number(3),
lessons number(3),
constraint pk_tutor_report primary key (match_id, month),
constraint fk1_tutor_report foreign key (match_id) references match_history(match_id));
insert into tutor values (100, '05-JAN-2017', 'Active');
insert into tutor values (101, '05-JAN-2017', 'Temp Stop');
insert into tutor values (102, '05-JAN-2017', 'Dropped');
insert into tutor values (103, '22-MAY-2017', 'Active');
insert into tutor values (104, '22-MAY-2017', 'Active');
insert into tutor values (105, '22-MAY-2017', 'Temp Stop');
insert into tutor values (106, '22-MAY-2017', 'Active');
insert into student values (3000, 2.3);
insert into student values (3001, 5.6);
insert into student values (3002, 1.3);
insert into student values (3003, 3.3);
insert into student values (3004, 2.7);
insert into student values (3005, 4.8);
insert into student values (3006, 7.8);
insert into student values (3007, 1.5);
insert into match_history values (1, 100, 3000, '10-JAN-2017', null);
insert into match_history values (2, 101, 3001, '15-JAN-2017', '15-MAY-2017');
insert into match_history values (3, 102, 3002, '10-FEB-2017', '01-MAR-2017');
insert into match_history values (4, 106, 3003, '28-MAY-2017', null);
insert into match_history values (5, 103, 3004, '01-JUN-2017', '15-JUN-2017');
insert into match_history values (6, 104, 3005, '01-JUN-2017', '28-JUN-2017');
insert into match_history values (7, 104, 3006, '01-JUN-2017', null);
insert into tutor_report values (1, '01-JUN-2017', 8, 4);
insert into tutor_report values (4, '01-JUN-2017', 8, 6);
insert into tutor_report values (5, '01-JUN-2017', 4, 4);
insert into tutor_report values (4, '01-JUL-2017', 10, 5);
insert into tutor_report values (1, '01-JUL-2017', 4, 2);
This is what I have so far:
Select (hours * 10) as amount paid from tutor_report group by month, tutor_id
however obviously I cannot just say tutor_id at the end.
You can join match_history to get the tutor_id.
But your statement and the query don't match. If you want to sort use ORDER BY.
SELECT tr.hours * 10 amount_paid
FROM tutor_report tr
INNER JOIN match_history mh
ON mh.match_id = tr.match_id
ORDER BY tr.month,
mh.tutor_id;
If you want to aggregate, hours needs to be argument to some aggregation function. Maybe you're after the sum of hours?
SELECT sum(tr.hours) * 10 amount_paid
FROM tutor_report tr
INNER JOIN match_history mh
ON mh.match_id = tr.match_id
GROUP BY tr.month,
mh.tutor_id;
If you are grouping based on columns on two tables,you need to join them on the matching Id and then use group by
Select (hours * 10) as amount paid
from tutor_report a
join match_history b on a. match_id = b.match_id
group by month, tutor_id

Sample observations per group without replacement in SQL

Using the provided table I would like to sample let's say 2 users per day so that users assigned to the two days are different. Of course the problem I have is more sophisticated, but this simple example gives the idea.
drop table if exists test;
create table test (
user_id int,
day_of_week int);
insert into test values (1, 1);
insert into test values (1, 2);
insert into test values (2, 1);
insert into test values (2, 2);
insert into test values (3, 1);
insert into test values (3, 2);
insert into test values (4, 1);
insert into test values (4, 2);
insert into test values (5, 1);
insert into test values (5, 2);
insert into test values (6, 1);
insert into test values (6, 2);
The expected results would look like this:
create table results (
user_id int,
day_of_week int);
insert into results values (1, 1);
insert into results values (2, 1);
insert into results values (3, 2);
insert into results values (6, 2);
You can use window functions. Here is an example . . . although the details do depend on your database (functions for random numbers vary by database):
select t.*
from (select t.*, row_number() over (partition by day_of_week order by random()) as seqnum
from test t
) t
where seqnum <= 2;

Sql Server query with date filter

I have a table like this;
ID int,
OrderedDate DateTime
I want to select only records of followed month.
For example result set:
ID OrderedDate
110 January
110 February
200 January
200 February
How can I write this query?
I think you want list of months that ID has orders in but with the months sorted by the month number instead of the name?
create table test21210
(
id int,
OrderedDate datetime
)
go
insert test21210 (id, OrderedDate) values (110, '1/1/2010')
insert test21210 (id, OrderedDate) values (110, '1/5/2010')
insert test21210 (id, OrderedDate) values (110, '1/10/2010')
insert test21210 (id, OrderedDate) values (110, '2/2/2010')
insert test21210 (id, OrderedDate) values (110, '2/4/2010')
insert test21210 (id, OrderedDate) values (110, '2/6/2010')
insert test21210 (id, OrderedDate) values (200, '1/3/2010')
insert test21210 (id, OrderedDate) values (200, '1/5/2010')
insert test21210 (id, OrderedDate) values (200, '1/7/2010')
insert test21210 (id, OrderedDate) values (200, '1/9/2010')
insert test21210 (id, OrderedDate) values (200, '2/3/2010')
insert test21210 (id, OrderedDate) values (200, '2/5/2010')
insert test21210 (id, OrderedDate) values (200, '2/7/2010')
insert test21210 (id, OrderedDate) values (200, '2/9/2010')
go
with idmonth (id, MonthNumber) as
(
select id, MONTH(ordereddate) as 'MonthNumber'
from test21210
group by id, MONTH(ordereddate)
)
select id, DATENAME(MONTH, STR(MonthNumber)+'/1/2000')
from idmonth
order by id, MonthNumber
The question seems a bit unclear. But the example makes it look like you are wanting to sort by ID then by month name. If so, then I think this will do it. I don't have SQL Server to test it, so I'm sure it has syntax or other errors.
SELECT ID, DATENAME(month, OrderedDate) AS OrderedDate from table
ORDER BY 1, MONTH( OrderedDate )