model:
public function week($gid)
{
$sensor = Yii::app()->zdb->createCommand("select nid ,sdata,stype,timestamp from tbl_sensor where timestamp >= date('now','-30 days') antimestamp<date('now');")->queryAll();
return $sensor;
}
Your Model Should be:
public function week()
{
$sensor = Yii::app()->zdb->createCommand("select nid ,sdata,stype,timestamp from tbl_sensor where timestamp >= date('now','-30 days') antimestamp<date('now');")->queryAll();
return $sensor;
}
And Your Controller Should Be:
public function actionReport() {
$user = User::model()->findByPk(Yii::app()->user->getId());
$gwinfo =Sensor::model()->find('(gid)=?', array($user->gid));
$model='';
if(isset($_POST['week'])) {
$model= Sensor::model()->week();
}
//$this->render('Reportht', array('gw'=>$gwinfo, 'user'=>$user));
$this->redirect('index.php?r=site/report', array('gw'=>$gwinfo, 'user'=>$user,'model'=>$model));
}
NOTE: I have passed model object to your view now you can use that object when needed
I hope you are looking for "How to create a method in Model and how to use in Controller"
Try like this
create a method in Model called "MyModel"
function foo($param)
{
$model = ModelName::model()->findAll("property=$param");
return $model;
}
Using it in my Controller
function actionBar()
{
$result=MyModel::model()->foo($param);
//print_r($result);
}
I hope to God you are not overwriting the existing model to create your own query. If so, it is not best to do that in your model. You should read more about PDO because using that query will be more vulnerable to SQL injections. You should put your query in your controller by using CActiveRecord. You can read this tutorial as it is very intuitive and very easy to learn. You should not modify your Model unless needed.
If by any chance you are using a custom query for querying your database. You can use CDbCriteria to generate a custom query.
Related
I'm trying to create my first component in Joomla but I can't understand how it works really :D
I create a basic component with "Component Creator". (I saved a lot of time...).
Now, I have a table in my DB where I've put my data:
id = 1
name = Andrea
note = Ciao
Now, I want to call it from the page using Joomla Language.
On my models/component.php i wrote:
class Variabili extends JModelLegacy
{
function estraivariabili()
{
$db =& JFactory::getDBO();
$db->setQuery("SELECT * FROM #__table")->loadObjectList();
return $value;
}
}
and on my default.php I wrote
$model=$this->Variabili();
//call the method
$items=$model->estraivariabili();
//print
print_r($items);
But on the page I have this error:
0 Call to undefined method Calcolo_imposteViewCalcoloonline::Variabili()
Where is a mistake?
Please be gentle with me because I'm a beginner: D
Thanks in advance
Andrea
You have committed a few wrongs. I've rewritten your functions so that you can get it. Let's have a look-
The model, it looks almost okay. Just change it like-
class Variabili extends JModelLegacy
{
// Make the function public
public function estraivariabili()
{
$db = &JFactory::getDBO();
// Put the result into a variable first, then return it.
$value = $db->setQuery("SELECT * FROM #__table")->loadObjectList();
return $value;
}
}
And now call the model functions not from default.php, rather than write your code inside view.html.php file.
Inside the display function of view.html.php file first, get the model instance by using getModel() function.
$model = $this->getModel();
Now you can get the items by using this $model class instance.
$this->items = $model->estraivariabili();
This will bring you the data from the database table. And you can use the data at default.php file.
Just try at default.php file-
print_r($this->items);
I've set up Yii2 REST API with custom actions and everything is working just fine. However, what I'm trying to do is return some data from the API which would include database relations set by foreign keys. The relations are there and they are actually working correctly. Here's an example query in one of the controllers:
$result = \app\models\Person::find()->joinWith('fKCountry', true)
->where(..some condition..)->one();
Still in the controller, I can, for example, call something like this:
$result->fKCountry->name
and it would display the appropriate name as the relation is working. So far so good, but as soon as I return the result return $result; which is received from the API clients, the fkCountry is gone and I have no way to access the name mentioned above. The only thing that remains is the value of the foreign key that points to the country table.
I can provide more code and information but I think that's enough to describe the issue. How can I encode the information from the joined data in the return so that the API clients have access to it as well?
Set it up like this
public function actionYourAction() {
return new ActiveDataProvider([
'query' => Person::find()->with('fKCountry'), // and the where() part, etc.
]);
}
Make sure that in your Person model the extraFields function includes fKCountry. If you haven't implemented the extraFields function yet, add it:
public function extraFields() {
return ['fKCountry'];
}
and then when you call the url make sure you add the expand param to tell the action you want to include the fkCountry data. So something like:
/yourcontroller/your-action?expand=fKCountry
I managed to solve the above problem.
Using ActiveDataProvider, I have 3 changes in my code to make it work.
This goes to the controller:
Model::find()
->leftJoin('table_to_join', 'table1.id = table_to_join.table1_id')
->select('table1.*, table_to_join.field_name as field_alias');
In the model, I introduced a new property with the same name as the above alias:
public $field_alias;
Still in the model class, I modified the fields() method:
public function fields()
{
$fields = array_merge(parent::fields(), ['field_alias']);
return $fields;
}
This way my API provides me the data from the joined field.
use with for Eager loading
$result = \app\models\Person::find()->with('fKCountry')
->where(..some condition..)->all();
and then add the attribute 'fkCountry' to fields array
public function fields()
{
$fields= parent::fields();
$fields[]='fkCountry';
return $fields;
}
So $result now will return a json array of person, and each person will have attribute fkCountry:{...}
I'm trying to make a call to a database using RequestFactory with Hibernate/JPA, and I want to retrieve a list of entities with embedded entities returned as well. I know that the .with() method works for methods like .find(), but it doesn't seem to work with custom queries.
The current way I'm doing it is as follows:
I used a named query in the entity class for the query. (Primary Entity is Name, embedded entity is a Suffix entity called nameSuffix)
#NamedQueries({ #NamedQuery(name = "Query.name", query = "select * from NameTable") })
Then in the service class, the .list() method, which is what I'd like to call with RequestFactory, is as follows.
public List<Name> list() {
return emp.get().createNamedQuery("Query.name").getResultList();
}
Finally, this is how I make the call in my client side code:
NameRequest context = requestFactory.createNameRequest();
context.list().with("nameSuffix").fire(new Receiver<List<NameProxy>>(){
public void onSuccess(List<NameProxy> response) {
String suff = response.get(0).getNameSuffix().getText();
}
});
In the above code, it says that getNameSuffix() returns null, which would imply that .with("nameSuffix") does not work with the .list() call like it does with the standard .find() method.
Is there a way to build a call that would return a list of entities and their embedded entities using .with(), or do I need to do it another way? If I need to do it another way, has anyone figured out a good way of doing it?
I think you misunderstood what the method with() is thought for, unless you had a method getNameSuffix which returns the NameSuffixentity. This is what the documentation says about it:
When querying the server, RequestFactory does not automatically populate relations in the object graph. To do this, use the with() method on a request and specify the related property name as a String
So, what you have to pass to the method is a list of the name of the child entities you want to retrieve. I hope this example could be helpful:
class A {
String getS(){return "s-a"}
B getB(){return new B();}
}
class B {
String getS(){return "s-b";}
C getC(){return new C();}
}
class C {
String getS(){return "s-c";}
}
context.getA().fire(new Receiver<A>(){
public void onSuccess(A response) {
// return 's-a'
response.getS();
// trhows a NPE
response.getB().getS();
}
});
context.getA().with("b").fire(new Receiver<A>(){
public void onSuccess(A response) {
// return 's-a'
response.getS();
// return 's-b'
response.getB().getS();
// trhows a NPE
response.getB().getC().getS();
}
});
context.getA().with("b.c").fire(new Receiver<A>(){
public void onSuccess(A response) {
// return 's-a'
response.getS();
// return 's-b'
response.getB().getS();
// return 's-c'
response.getB().getC().getS();
}
});
i have a behavior for my models, the behavior has beforeFind, beforeSave, in methods i override user_id, something like:
...
public functio beforeSave() {
$this->owner->user_id = Yii::app()->user->id
}
I have model User, how can i disable behavior for registration new user?
Saving code:
$user = new User();
$user->id = 1332;
$user->field1 = 'data';
$user->save();
but on save i have null in $user->id (because work behavior).
i tried
$user->disableBehaviors();
$user->detachBehavior();
Without result.
Maybe its not right way? I create behaviors for identify users in system (find only user something, save only with user id...), but that if i have new user with full previegies, i should again detach behaviors?
If condition can be changed in future I just pass it as callback parameter into behavior from model.
This give you a bit more control over the condition. Hence, behavior becomes more reusable - if it is used by several models this condition can be unique for each.
Example below is a bit simplified, but you should get the idea.
Behavior:
class SomeBehavior extends CActiveRecordBehavior
{
public $trigger;
public function beforeSave($event)
{
if(!call_user_func($this->trigger))
return;
// do what you need
$this->owner->user_id = Yii::app()->user->id;
}
}
Model:
class SomeModel extends CActiveRecord
{
public function behaviors()
{
$me=$this;
return array(
'some'=>array(
'class'=>'SomeBehavior',
'trigger'=>function() use($me){
return $me->scenario=='some-scenario';
}
)
);
}
}
Also I use PHP 5.3. So, I use closure for trigger callback.
If your PHP version is less than 5.3 - anything callable can be used instead. Check here http://www.php.net/manual/en/function.is-callable.php
Because of behavior is a method, you can declare your own logic inside.
The model knows about its scenario, so there is no problem to return different arrays for different conditions:)
Hope it be helpful for somebody.
You can check Yii::app()-user->isGuest to determine if the user is logged in or not. or you can just try looking for the null. Like this:
if (!Yii::app()->user->isGuest)
$this->owner->user_id = Yii::app()->user->id;
or
if (null !== Yii::app()->user->id)
$this->owner->user_id = Yii::app()->user->id;
Can I filter out results from an arrayCollection in Doctrine 2 while using lazy loading? For example,
// users = ArrayCollection with User entities containing an "active" property
$customer->users->filter('active' => TRUE)->first()
It's unclear for me how the filter method is actually used.
Doctrine now has Criteria which offers a single API for filtering collections with SQL and in PHP, depending on the context.
https://www.doctrine-project.org/projects/doctrine-orm/en/latest/reference/working-with-associations.html#filtering-collections
Update
This will achieve the result in the accepted answer, without getting everything from the database.
use Doctrine\Common\Collections\Criteria;
/**
* #ORM\Entity
*/
class Member {
// ...
public function getCommentsFiltered($ids) {
$criteria = Criteria::create()->where(Criteria::expr()->in("id", $ids));
return $this->getComments()->matching($criteria);
}
}
The Boris Guéry answer's at this post, may help you:
Doctrine 2, query inside entities
$idsToFilter = array(1,2,3,4);
$member->getComments()->filter(
function($entry) use ($idsToFilter) {
return in_array($entry->getId(), $idsToFilter);
}
);
Your use case would be :
$ArrayCollectionOfActiveUsers = $customer->users->filter(function($user) {
return $user->getActive() === TRUE;
});
if you add ->first() you'll get only the first entry returned, which is not what you want.
# Sjwdavies
You need to put () around the variable you pass to USE. You can also shorten as in_array return's a boolean already:
$member->getComments()->filter( function($entry) use ($idsToFilter) {
return in_array($entry->getId(), $idsToFilter);
});
The following code will resolve your need:
//$customer = ArrayCollection of customers;
$customer->getUsers()->filter(
function (User $user) {
return $user->getActive() === true;
}
);
The Collection#filter method really does eager load all members.
Filtering at the SQL level will be added in doctrine 2.3.