I have a table in SQL Server that contains a column yesno.
If at least one of the rows has the column yesno=1 then I need to return only one row yes.
I made a query that returns for every row if is yes or no.
(select (case when isnull(coalesce(dl.yesno,'2'),'2')='1' then 'Yes' else 'NO' END)
from table dl where dl.ID='A5454322-C239-4FF2-A458-8A9BD79C1839')
select 'yes'
where exists (select 1 from the_table where yesno = '1');
SQLfiddle example: http://sqlfiddle.com/#!3/069204/1
select 'yes' where exists (select * from MyTable where [yesno]='1')
select top 1 'yes' from table where yesno = 1
Related
I have a table named Bank that contains a Bank_Values column. I need a calculated Bank_Value_Unique column to shows whether each Bank_Value exists somewhere else in the table (i.e. whether its count is greater than 1).
I prepared this query, but it does not work. Could anyone help me with this and/or modify this query?
SELECT
CASE
WHEN NULLIF(LTRIM(RTRIM(Bank_Value)), '') =
(SELECT Bank_Value
FROM [Bank]
GROUP BY Bank_Value
HAVING COUNT(*) = 1)
THEN '0' ELSE '1'
END AS Bank_Key_Unique
FROM [Bank]
A windowed count should work:
SELECT
*,
CASE
COUNT(*) OVER (PARTITION BY Bank_Value)
WHEN 1 THEN 1 ELSE 0
END AS Bank_Value_Unique
FROM
Bank
;
It works also, but I found solution also:
select CASE WHEN NULLIF(LTRIM(RTRIM(Bank_Value)),'') =
(select Bank_Value
from Bank
group by Bank_Value
having (count(distinct Bank_Value) > 2 )) THEN '1' ELSE '0' END AS
Bank_Value_Uniquness
from Bank
It was missing "distinct" in having part.
I have to do a select query to create a view with specific criteria.
I have multiple tables which contains many many columns and lines.
However, I have extracted a value to use as my key (e.g.: id). I have 7000+ of those unique keys that I extracted from all my tables with the function UNION to avoid duplicates.
Now, I want to add a column INDICATOR_1 which will affect the value YES or NO based on criteria.
This is where I struggle.
I need to find the line in those tables that contain the id. After that, I'd like to check, always in that line, if the field XYZ contains the value 'N' (example). If yes, affect the value 'YES' to INDICATOR_1, else it's no.
In a matter of pseudo-code, what I want to do looks like this :
CASE
WHEN id = (id from table_1) AND (if table_1.xyz = 'N')
THEN 'YES'
ELSE 'NO'
END AS INDICATOR_1
I don't know if I'm clear enough, but your help will be greatly appreciated.
If I understand correctly, you want a separate indicator for each table. Something like this:
select i.*,
(case when exists (select 1
from table1 t1
where t1.id = i.id and t1.xyz = 'N'
)
then 'YES' else 'NO'
end) as indicator_1,
(case when exists (select 1
from table2 t2
where t2.id = i.id and t2.xyz = 'N'
)
then 'YES' else 'NO'
end) as indicator_2,
. . .
from (<your id list here>) i
I think you should fix this in the union, where you have all the data you need. You probably have something like:
SELECT Id
FROM table_1
UNION
SELECT Id
FROM table_2
How about selecting the information you want as well (I use distinct here to clarify):
SELECT DISTINCT Id
, CASE WHEN table_1.xyz = 'N' THEN 'N'
ELSE 'Y'
END INDICATOR_1
FROM table_1
This can lead to more records than you had, if id's can have records of both flavours exist. We can fix that with a row number in an outer query. You end up with something like:
SELECT Id
, INDICATOR_1
FROM (
SELECT Id
, INDICATOR_1
, ROW_NUMBER()OVER(PARTITION BY ID ORDER BY CASE WHEN INDICATOR_1 ='N' THEN 0 ELSE 1 END) RN
FROM (
SELECT Id
, CASE WHEN table_1.xyz = 'N' THEN 'N'
ELSE 'Y'
END INDICATOR_1
FROM table_1
UNION
...
) T
) S
WHERE S.RN = 1
You can in fact shorten that by using the inner most case expression in the ROW_NUMBER expression.
I Have in table some records:
ID Services
2 A
2 C
2 C1
2 D2
I`m trying make query that will be select a link between services.
For example: If for ID 2 exists Services C then check if exist Service C1, result Yes or No.
SELECT a. ID, a.service,
CASE
WHEN (a.service ='C') = (a.service = 'C1') THEN 'Yes'
ELSE 'No'
END
FROM t1 a
Try this query:
SELECT *
FROM yourTable t1
WHERE NOT EXISTS (SELECT 1 FROM yourTable t2
WHERE (t2.Services LIKE t1.Services + '%' OR
t1.Services LIKE t2.Services + '%') AND
t1.ID = t2.ID AND t1.Services <> t2.Services);
This returns A and D2 only.
Demo
Hmm... what about this? But I now have problem with checking relationship for each ID independently...
SELECT a. ID, a.service,
CASE
WHEN a.service IN ('C','C1') THEN 'Yes'
ELSE 'No'
END
FROM t1 a
If I understand correctly, you can use aggregation:
SELECT ID,
(CASE WHEN SUM(CASE WHEN service = 'C' THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN service = 'C1' THEN 1 ELSE 0 END) > 0
THEN 'Yes' ELSE 'No'
END) as c_c1_flag
FROM t1
GROUP BY ID;
The SUM(CASE . . . ) counts the number of rows that match the conditions. The > 0 simply says that at least one row exists.
I have a table STATUSES which contain columns NAME and ACTIVE_FLAG.The column value of NAME may have new, pending, cancel. I want to generate a new output for the count of each NAME with ACTIVE_FLAG=Y
By thinking to use EXISTS to select records for single NAME,
SELECT COUNT(*) AS PENDING
FROM STATUSES
WHERE EXISTS (select NAME from STATUSES where NAME='Pending' and ACTIVE_FLAG = 'Y')
Anyway if I can join other statuses count in a single SQL?
Seems like count and group by
SELECT
name
, count(*)
FROM statuses
WHERE active_flag = 'Y'
GROUP BY name
You can use something like this as i don't see any need to use EXISTS :
SELECT sum(case when name='Pending' then 1 else 0 end) AS PENDING,
sum(case when name='new' then 1 else 0 end) AS NEW,
sum(case when name='cancel' then 1 else 0 end) AS CANCEL
FROM STATUSES
WHERE ACTIVE_FLAG = 'Y'
SQL HERE
I have a historization table called CUR_VALID. This table looks something like this:
ID CUR_VALID
1 N
1 N
1 Y
2 N
2 Y
3 Y
For every ID there needs to be one Y. If there is no Y or multiple Y there is something wrong. The statment for checking if there are multiple Y I already got. Now I only need to check for every ID if there is one Y existing. Im just not sure how to do that. This is what I have so far. So how do I check if the Value 'Y' exists?
SELECT Count(1) [Number of N]
,MAX(CUR_VALID = 'N')
,[BILL_ID]
,[BILL_MONTH]
,[BILL_SRC_ID]
FROM db.dbo.table
GROUP BY [BILL_ID]
,[BILL_MONTH]
,[BILL_SRC_ID]
Having MAX(CUR_VALID = 'N') > 1
Why are you fiddling with 'N' when you are interested in 'Y'?
Use conditional aggregation to get the count of the value your are interested in.
SELECT
COUNT(*) AS number_of_all,
COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) AS number_of_y,
COUNT(CASE WHEN cur_valid = 'N' THEN 1 END) AS number_of_n,
bill_id,
bill_month,
bill_src_id,
FROM db.dbo.table
GROUP BY bill_id, bill_month, bill_src_id;
Add a HAVING clause in order to get only valid
HAVING COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) = 1
or invalid
HAVING COUNT(CASE WHEN cur_valid = 'Y' THEN 1 END) <> 1
bills.
The following query will give you the list of id for which your integrity condition is not met: For every ID there needs to be one Y. If there is no Y or multiple Y there is something wrong.
select T1.id from table T1 where (select count(*) from table T2 where T2.id=T1.id and T2.CUR_VALID='Y')!=1
This query returns both not having at least one 'Y' value and more than one 'Y' value ID's.
First, sum up the Y values and relate to each id, then select not 1 ones from that table.
select * from (
select ID, SUM(case when CUR_VALID = 'Y' then 1 else 0 end) as CNT
from table
group by ID
) b where b.CNT <> 1
DBFiddle
As I understand, you want to get all the id for which your integrity check passes. And integrity check for you means, there is only one row with CUR_VALID value equal to Y in the CUR_VALID table.
This can be achieved by a group by clause:
select id from CUR_VALID
where CUR_VALID.CUR_VALID = 'Y'
group by id
having count(CUR_VALID.CUR_VALID) = 1;