if minute is less than 60 then remove hour part from result - sql

Question

I have a function like this:
ALTER FUNCTION [dbo].[testfunctionstacknew] (#dec NUMERIC(18, 2)) RETURNS Varchar(50)
AS
BEGIN
DECLARE
#hour decimal(18,2),
#Mns decimal(18,2),
#second decimal(18,3)
DECLARE #Average Varchar(50)
select #hour=CONVERT(int,#dec/60/60)
SELECT #Mns = convert(int, (#dec / 60) - (#hour * 60 ));
select #second=#dec % 60;
SELECT #Average =
convert(varchar(9), convert(int, #hour)) + ':' +
-- right('00' + convert(decimal(10,0), convert(decimal(18,2), #hour)), 2) + ':' +
right('00' + convert(decimal(10,0), convert(decimal(18,2), #Mns)), 2) + ':' +
right('00' + CONVERT(decimal(10,0), convert(varchar(10), #second)), 6)
RETURN #Average
END
and i have a stored procedure like this:
select dbo.testfunctionstacknew(
convert(decimal(10,1),
avg(convert(numeric(18,2), datediff(ss, t.dtime, t.PAICdate ))))
) as Avgparkingtime from (select top 10 * from transaction_tbl where locid=6 and dtime >= getdate()-1 order by transactID desc ) t
while executing stored procedure if the average time is less than 60 minutes i am getting result like this:
Avgparkingtime :
0:25:33
if the average time is less than 60 minutes then i dont want to get zero in front of minutes,,(this time only need to show minutes and seconds)..only hour need to show if the minutes is greater than 60 minutes...how i can do this? what changes i have to make in my function ?? any help is very appreciable..

Answer 1

Try changing the part where you build the formatted string like this:
SELECT #Average =
case
when convert(int, #hour) <> 0 then convert(varchar(9), convert(int, #hour)) + ':'
else ''
end +
right('00' + convert(decimal(10,0), convert(decimal(18,2), #Mns)), 2) + ':' +
right('00' + CONVERT(decimal(10,0), convert(varchar(10), #second)), 6)