I am using SQL Server 2005 and I have a problem with my SQL query. Basically, I want to get the total amount of all transactions of customers, grouped by company, based on the latest dates from all customer transactions.
Sample data:
Customer_Id Date Amount COMPANY
-------------------------------------------------
1 3/3/2014 9021 COMPANY X
2 3/3/2014 12000 COMPANY Y
2 3/15/2014 10000 COMPANY Y
2 3/30/2014 8000 COMPANY Y
4 3/13/2014 10000 COMPANY Z
5 3/14/2014 1400 COMPANY X
1 3/16/2014 2500 COMPANY X
7 3/14/2014 110 COMPANY Y
3 3/17/2014 1500 COMPANY Z
2 3/19/2014 2044 COMPANY Y
3 3/09/2014 9400 COMPANY Z
3 3/11/2014 8950 COMPANY Z
2 3/31/2014 3455 COMPANY Y
3 3/15/2014 950 COMPANY Z
6 3/15/2014 5543 COMPANY X
What I want to accomplish is like this:
COMPANY TOTAL
COMPANY X 9443 --> sum from customer_id 1 (2500, as of 3/16/2014) and customer_id 6 (5542, 3/15/2014) and customer_id 5 (1400 as of 3/14/2014)
COMPANY Y 3455 --> sum from customer_id 2 (3455, as of 3/31/2014)
COMPANY Z 10950 --> sum from customer_id 4 (1000, as of 3/13/2014) and customer_id 3 (950, as of 3/15/2014)
Below are some SQL queries I've tried which doesn't work on my goal:
SELECT TOP (1) WITH TIES
Date, Company, SUM(Amount) AS total
FROM
tbl_Table
GROUP BY
Date, Company
ORDER BY
Date DESC
SELECT
t1.Date, t1.Company, SUM(t1.Amount) AS total
FROM
tbl_Table AS t1
INNER JOIN
(SELECT
MAX(Date) AS date, Company
FROM
tbl_Table
GROUP BY
Company) AS t2 ON t1.Date = t2.Date AND t1.Company = t2.Company
GROUP BY
t1.Date, t1.Company
WITH latest AS
(SELECT
Company, MAX(Date) AS maxdate
FROM
tbl_Table
GROUP BY
Company
)
SELECT
a.Date, a.Company, SUM(a.Amount) AS total
FROM
tbl_Table AS a
INNER JOIN
latest AS b ON a.Company = b.Company AND a.Date = b.maxdate
GROUP BY
a.Date, a.Company
Your results are still not correct by data you give.
SQLFIDDLEExample
Query:
SELECT t1.Company,
SUM(t1.Amount) Total
FROM Table1 t1
LEFT JOIN Table1 t2
ON t1.COMPANY = t2.COMPANY
AND t1.Customer_Id = t2.Customer_Id
AND t1.Date < t2.Date
WHERE t2.Customer_Id is null
GROUP BY t1.Company
Result:
| COMPANY | TOTAL |
|-----------|-------|
| COMPANY X | 9443 |
| COMPANY Y | 3565 |
| COMPANY Z | 11500 |
Try This
WITH cte AS (
SELECT Amount,Company,
ROW_NUMBER() OVER (PARTITION BY Customer_Id ORDER BY CAST([Date] AS DATETIME) desc )
AS dateRowRank
)
SELECT Company,SUM(Amount)
FROM cte
WHERE dateRowRank=1
GROUP BY Company
Related
I have the following sales table that displays the customer ID, their name, the order amount, and the order date.
ID
Name
Order
Date
1
A
25
11/10/2006
1
A
10
5/25/2010
1
A
10
6/18/2018
2
B
20
3/31/2008
2
B
15
11/15/2010
3
C
35
1/1/2019
3
C
20
4/12/2007
3
C
10
3/20/2010
3
C
5
10/19/2012
4
D
15
12/12/2013
4
D
15
2/18/2010
5
E
25
12/11/2006
6
F
10
5/1/2016
I am trying to group the data so that for each customer it would only show me their most recent order and the amount, as per below:
ID
Name
Order
Date
1
A
10
6/18/2018
2
B
15
11/15/2010
3
C
35
1/1/2019
4
D
15
12/12/2013
5
E
25
12/11/2006
6
F
10
5/1/2016
So far I've only been able to group by ID and Name, because adding the Order column would also group by that column as well.
SELECT
ID,
Name,
MAX(Date) 'Most recent date'
FROM Table
GROUP BY Customer, Customer
How can I also add the order amount for each Customer?
SELECT ID, Name, Order, Date FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Date DESC) AS sn
FROM your_table_name
) A WHERE sn = 1;
You could use a subqoery for max date
SELECT
ID,
Name,
MAX(Date) 'Most recent date'
FROM Table
GROUP BY Customer, Customer
select a.ID, a.Name, b.max_date
from Table a
inner join (
select name, max(Date) max_date
from Table
group by name
) b on a. name = b.name and a.date = b.max_date
You can use this query to get the expected result:
SELECT S.*
FROM Sales S
CROSS APPLY
(
SELECT ID, Max(Date) MaxDate
FROM Sales
GROUP BY ID
)T
WHERE S.ID = T.ID
AND S.Date = T.MaxDate
ORDER BY S.ID
I am trying to write a SQL statement that will return a set of Distinct set of CompanyNames from a table based on the most recent SaleDate withing a specified date range from another table.
T01 = Account
T02 = TransHeader
The fields of importance are:
T01.ID, T01.CompanyName
T02.AccountID, T02.SaleDate
T01.ID = T02.AccountID
What I want to return is the Max SaleDate for each CompanyName without any duplicate CompanyNames and only the Max(SaleDate) as LastSale. I will be using a Where Clause to limit the SaleDate range.
I tried the following but it returns all the records for all SalesDates in the range. This results in the same company being listed multiple times.
Current MS-SQL Query
SELECT T01.CompanyName, T02.LastSale
FROM
(SELECT DISTINCT ID, IsActive, ClassTypeID, CompanyName FROM Account) T01
FULL OUTER JOIN
(SELECT DISTINCT AccountID, TransactionType, MAX(SaleDate) LastSale FROM TransHeader group by AccountID, TransactionType, SaleDate) T02
ON T01.ID = T02.AccountID
WHERE ( ( T01.IsActive = 1 )AND
( (Select Max(SaleDate)From TransHeader Where AccountID = T01.ID AND TransactionType in (1,6) AND SaleDate is NOT NULL)
BETWEEN '01/01/2016' AND '12/31/2018 23:59:00' AND (Select Max(SaleDate)From TransHeader Where AccountID = T01.ID AND TransactionType in (1,6) AND SaleDate is NOT NULL) IS NOT NULL
)
)
ORDER BY T01.CompanyName
I thought the FULL OUTER JOIN was the ticket but it did not work and I am stuck.
Sample data Account Table (T01)
ID CompanyName IsActive ClassTypeID
1 ABC123 1 1
2 CDE456 1 1
3 EFG789 1 1
4 Test123 0 1
5 Test456 1 1
6 Test789 0 1
Sample data Transheader table (T02)
AccountID TransactionType SaleDate
1 1 02/03/2012
2 1 03/04/2013
3 1 04/05/2014
4 1 05/06/2014
5 1 06/07/2014
6 1 07/08/2015
1 1 08/09/2016
1 1 01/15/2016
2 1 03/20/2017
2 1 03/21/2017
3 1 03/04/2017
3 1 04/05/2018
3 1 05/27/2018
4 1 06/01/2018
5 1 07/08/2018
5 1 08/01/2018
5 1 10/11/2018
6 1 11/30/2018
Desired Results
CompanyName LastSale (Notes note returned in the result)
ABC123 01/15/2016 (Max(SaleDate) LastSale for ID=1)
CDE456 03/21/2017 (Max(SaleDate) LastSale for ID=2)
EFG789 05/27/2018 (Max(SaleDate) LastSale for ID=3)
Testing456 10/11/2018 (Max(SaleDate) LastSale for ID=5)
ID=4 & ID=6 are note returned because IsActive = 0 for these records.
One option is to select the maximum date in the select clause.
select
a.*,
(
select max(th.saledate)
from transheader th
where th.accountid = a.id
and th.saledate >= '2016-01-01'
and th.saledate < '2019-01-01'
) as max_date
from account a
where a.isactive = 1
order by a.id;
If you only want to show transaction headers with sales dates in the given date range, then you can just inner join the maximum dates with the accounts. In order to do so, you must group your date aggregation per account:
select a.*, th.max_date
from account a
join
(
select accountid, max(saledate) as max_date
from transheader
and saledate >= '2016-01-01'
and saledate < '2019-01-01'
group by accountid
) th on th.accountid = a.id
where a.isactive = 1
order by a.id;
select CompanyName,MAX(SaleDate) SaleDate from Account a
inner join Transheader b on a.id = b.accountid
group by CompanyName
order by 1
i have two tables in sql.
table_team
t_id team_name
1 ABC
2 XYZ
3 PQR
i have another table_player
p_id t_id player_name payment
10 1 Sam 1000
20 1 jon 500
30 2 will 680
40 1 bob 700
50 3 rob 890
i want to get the team's total payment from these two tables.
i'e sum of payemnt of each player in a particular team, and for all teams.
i thought of trying
select t_id,team_name,sum(b.payment) as total_payment from table_team a
left join table_player b on a.t_id = b.t_id
Join to a subquery which computes the total payment for each team:
SELECT t1.t_id, t1.team_name, t2.total_payment
FROM table_team t1
INNER JOIN
(
SELECT t_id, SUM(payment) AS total_payment
FROM table_player
GROUP BY t_id
) t2
ON t1.t_id = t2.t_id
-- WHERE t1.team_name IN ('ABC', 'XYZ')
select t_id,team_name,sum(b.payment) as total_payment
from table_team a
left join table_player b on a.t_id = b.t_id
group by t_id,team_name
select t_id,team_name,sum(isnull(b.payment,0)) as total_payment from table_team a
left join table_player b on a.t_id = b.t_id
group by t_id, team_name
Just add a group by and it should work
I'm trying to query some data from SQL such that it sums some columns, gets the max of other columns and the corresponding value from another table. For example,
|table1|
|order id| |id| |shares| |date| other stuff
12345 1 100 05/13/16 XXX
12345 2 200 05/15/16 XXX
12345 3 300 06/12/16 XXX
12345 4 400 02/22/16 XXX
56789 5 1000 03/30/16 XXX
56789 6 200 02/25/16 XXX
22222 7 5000 01/10/16 XXX
|table2|
|id| |price|
1 21.2
2 20.2
3 19.1
4 21.3
5 100.0
6 110.0
7 5.0
I want my output to be:
|shares| |date| |price| other stuff
1000 06/12/16 19.1 max(other stuff)
1200 03/30/16 1000.0 max(other stuff)
5000 01/10/16 5.0 max(other stuff)
The shares have been summed up, the date is max(date), and the price is the price at the corresponding max(date).
So far, I have:
select
orderid, stock, side, exchange,
max(startdate), max(enddate),
sum(shares), sum(execution_price * shares) / sum(shares),
max(limitprice), max(price)
from
table1 t1
inner join
table2 t2 on t2.id = t1.id
where
location = 'CHICAGO'
and startdate > '1/1/2016'
and order_type = 'limit'
group by
orderid, stock, side, exchange
However, this returns:
|shares| |date| |price| |other stuff|
1000 06/12/16 21.3 max(other stuff)
1200 03/30/16 1100.0 max(other stuff)
5000 01/10/16 5.0 max(other stuff)
which isn't the corresponding price for the max(date).
The only link between the two datasets are their id numbers, which is why
inner join
table2 t2 on t2.id = t1.id
is done. No dates in the second table at all. Any help?
Thanks.
You can resolve this using Sub-query. You need not use any aggregate function on price column, just find the max date and then get price of that particular date.Try something like this..
select t5.*, t4.price
from
(select t1.order_id, sum(t1.shares) as shares, max(t1.date) as maxdate, max(other_stuff) as other_stuff
from Table1 t1
inner join
Table2 t2 on t2.id = t1.id
group by t1.order_id) t5
inner join Table1 t3
on t5.maxdate = t3.date and t5.order_id = t3.order_id
inner join Table2 t4
on t3.id = t4.id;
ONLINE DEMO HERE
Try this (don't forget to replace #table1 and #table2 with your own table names):
SELECT Aggregated.shares
, Aggregated.date
, Aggregated.other_stuff
, T2.price
FROM (
SELECT order_id
, SUM(shares) as shares
, MAX(date) as date
, MAX(other_stuff) as other_stuff
FROM #table1 AS T1
GROUP BY order_id
) AS Aggregated
INNER JOIN #table1 AS T1 ON Aggregated.order_id = T1.order_id AND Aggregated.date = T1.date
INNER JOIN #table2 AS T2 ON T2.id = T1.id
So, before I write you a query, you basically want the price during that max date, correct? You have MAX on price, sum of shares, max on limit price, sum on shares again and so on.
My guess is you want the latest price based on the latest date (Max) then run the calculations for the latest date, latest # of shares for that max date, and sum that all together? You're also grouping on ID, Shares, and other things that don't really make sense, it would seem you would want to group on Shares, Side and Exchange but not ID. Looks like you put a max on other things just so they show up without having to group on them, this is not going to work for what you want as long as I think I know what you're looking for =) Let me know and I can definitely help if I know what your end result "specs" are.
I would do a sub-query with a max over partition ordered by date to display the last date price, then do the aggregations on the upper level, here is an example of how it would work.
Sample data
pk id shares date id price
------- --- -------- -------------------------- --- -------
100 1 100 2016-07-08 10:40:34.707 1 50
100 2 200 2016-07-06 10:40:34.707 2 20
101 3 500 2016-07-09 10:40:34.707 3 70
101 4 150 2016-07-07 10:40:34.707 4 80
102 5 300 2016-07-10 10:40:34.707 5 40
Query
with t1 as (
select 100 pk,1 id, 100 shares, getdate()-3 date union all
select 100 pk,2 id, 200 shares, getdate()-5 date union all
select 101 pk,3 id, 500 shares, getdate()-2 date union all
select 101 pk,4 id, 150 shares, getdate()-4 date union all
select 102 pk,5 id, 300 shares, getdate()-1 date ),
t2 as (
select 1 id, 50 price union all
select 2 id, 20 price union all
select 3 id, 70 price union all
select 4 id, 80 price union all
select 5 id, 40 price
)
SELECT pk,sum(shares) shares,max(date) date, max(price) from(
SELECT pk,
shares,
date,
MAX(price) over(partition by pk order by date desc) price
FROM t1
JOIN t2 ON t1.id = t2.id) a
group by pk
Result
pk shares date Price
--- ------- ------------------------ -----
100 300 2016-07-08 10:51:16.023 50
101 650 2016-07-09 10:51:16.023 80
102 300 2016-07-10 10:51:16.023 40
Here is my table CusOrder that collect customer order
OrderID Cus_ID Product_ID NumberOrder OrderDate
1 0000000001 9 1 6/5/2553 0:00:00
2 0000000001 10 1 6/5/2553 0:00:00
3 0000000004 9 2 13/4/2553 0:00:00
4 0000000004 9 1 17/3/2553 0:00:00
5 0000000002 9 1 22/1/2553 0:00:00
7 0000000005 9 1 16/12/2552 0:00:00
8 0000000003 9 3 13/12/2552 0:00:00
10 0000000001 9 2 19/11/2552 0:00:00
11 0000000003 9 2 10/11/2552 0:00:00
12 0000000002 9 1 23/11/2552 0:00:00
I need to select 3 lastest order for each customer and I need all customer
so it will show each customer and his/her 3 lastest order
how can I do it
sorry for my bad english
This CTE should work for you:
;with cteTop3PerGroup as
(
select row_number() over(partition by Cus_ID order by OrderDate DESC) as RN
, *
from CusOrder
)
select * from cteTop3PerGroup
where RN <= 3
WITH Temp AS
(
SELECT *, (ROW_NUMBER() OVER (PARTITION BY Cus_ID ORDER BY OrderDate DESC)) AS Number
FROM CusOrder
)
SELECT * FROM Temp WHERE Number <= 3
Should work. Not tested with this exact database structure, but something similar.
"Pure" SQL solution.
With Customers As (
Select Cus_ID From test Group By Cus_ID
),
TopLastOrders as (
Select o.Cus_ID, Max(OrderDate) as OrderDate
From test o Inner Join Customers c on c.Cus_ID = o.Cus_ID
Group By o.Cus_ID
),
TopSecondOrders as (
Select o.Cus_ID, Max(OrderDate) as OrderDate
From test o Inner Join Customers c on c.Cus_ID = o.Cus_ID
Where Not Exists (Select 1 From TopLastOrders Where Cus_ID=o.Cus_ID And OrderDate=o.OrderDate)
Group By o.Cus_ID
),
TopThirdOrders as (
Select o.Cus_ID, Max(OrderDate) as OrderDate
From test o Inner Join Customers c on c.Cus_ID = o.Cus_ID
Where Not Exists (Select 1 From TopLastOrders Where Cus_ID=o.Cus_ID And OrderDate=o.OrderDate)
And Not Exists (Select 1 From TopSecondOrders Where Cus_ID=o.Cus_ID And OrderDate=o.OrderDate)
Group By o.Cus_ID
)
Select
c.Cus_ID,
t1.OrderDate,
t2.OrderDate,
t3.OrderDate
From
Customers c
Left Outer Join TopLastOrders t1 on t1.Cus_ID = c.Cus_ID
Left Outer Join TopLastOrders t2 on t2.Cus_ID = c.Cus_ID
Left Outer Join TopLastOrders t3 on t3.Cus_ID = c.Cus_ID
Order By
c.Cus_ID
I'm not sure what output you need but this should not be hard.