I have a view file add_rates.ctp and in that there is one select box . when i change the optiion, it will make a ajax call and fetch some values from the controller and load an element in that view.
but my problem is iam not getting the parameter values in the element.
i am getting params in rates.ctp
$params=$this->params['pass'];
it will return an array of parameters. but when i tried this in element i am not getting the value.
also i tried to set a value in the add_rates.ctp and try to access in element, that is also not working
$this->set('params',array($params));
what to do..if anybody have idea about this please reply.. i get stucked ...
If $params is the array you are trying to pass, then try this:
<?php $this->element('your-element-name', array('params' => $params)); ?>
Related
I wrapped my gridview with Pjax widget like this
\yii\widgets\Pjax::begin();
gridview
\yii\widgets\Pjax::end();
in order to make the gridview make ajax request when I click on each pagination.
I also use ['class' => 'yii\grid\CheckboxColumn'], in column as well.
and I find that when I'm on first pagination I checked some rows and then go to second page and check some rows but when I go back to first page what I've checked is gone.
My question is how can I keep all checkedrow for all pagination
With current conditions (Pjax, multiple pages, yii\grid\CheckboxColumn) it's impossible because of the way it works.
When you click on the pagination links all GridView html content is replaced by new one that comes from the AJAX response.
So obviously all selected checkboxes on the previous page are gone.
Few possible ways to solve that:
1) Write custom javascript and server side logic.
As one of the options, you can send AJAX request to server with parameter meaning that user has chosen to select all data for the bulk delete operation (or use separate controller action for bulk deletion). In this case actually we don't need to get the selected data from user, because we can simply get them from database (credits - Seng).
2) Increase number of displayed rows per page.
3) Use infinite scroll extension, for example this.
4) Break desired action in several iterations:
select needed rows on first page, do action (for example, delete).
repeat this again for other pages.
You can get selected rows like that:
$('#your-grid-view').yiiGridView('getSelectedRows');
[infinite scroll] : http://kop.github.io/yii2-scroll-pager/ will work good if you do not have any pjax filters. If you have filters also in play, do not use this plugin as it does not support pjax filters with it. For rest of the applications it is perfect to use.
Update1 : it seems to be straight forward than expected, here is the how I accomplished it
Add following lines to the checkbox column
'checkboxOptions' => function($data){
return ['id' => $data->id, 'onClick' => 'selectedRow(this)'];
}
Now add following JS to the common js file you will have in your project of the page where this datagrid resides
var selectedItems=[]; //global variable
/**
* Store the value of the selected row or delete it if it is unselected
*
* #param {checkbox} ele
*/
function selectedRow(ele){
if($(ele).is(':checked')) {
//push the element
if(!selectedItems.includes($(ele).attr('id'))) {
selectedItems.push($(ele).attr('id'));
}
} else {
//pop the element
if(selectedItems.includes($(ele).attr('id'))) {
selectedItems.pop($(ele).attr('id'));
}
}
}
Above function will store the selected row ids in the global variable array
Now add following lines to pjax:end event handler
$(document).on('pjax:end', function () {
//Select the already selected items on the grid view
if(!empty(selectedItems)){
$.each(selectedItems, function (index,value) {
$("#"+value).attr('checked',true);
});
}
});
Hope it helps.
I just solved this problem and it works properly with Pjax.
You may use my CheckboxColumn. I hope this can help. The checked items are recorded with cookies.
You can read the part with //add by hezll to understand how to fix it, because I didn't provide a complete general one.
Hope it works for you.
https://owncloud.xiwangkt.com/index.php/s/dGH3fezC5MGCx4H
I have a dropdown that I want to populate when an item in another dropdown is selected. Both the dropdown are tied to data/model passed on from controller. and the first dropdown is populated from DB by calling a function in the model. Heres' the form,
echo $form->dropDownListRow($modelunit,
'superunit',
$model->getSunits(),
array(
'ajax' => array(
'type'=>'POST',
'url'=>CController::createUrl('user/getunits'),
'update'=>'#unit_id',
)));
echo CHtml::dropDownList('unit_id','', array());
Here's the action user/getunits called by Ajax.
$data=Unit::model()->findAll('sid=:sid',
array(':sid'=>(int) $_POST['superunit']));
$data=CHtml::listData($data,'id','name');
foreach($data as $value=>$name)
{
echo CHtml::tag('option',
array('value'=>$value),CHtml::encode($name),true);
}
I keep getting an error "Undefined index: superunit" when first dropdown is selected. Also, you may notice I am using form->dropDownListRow for the first dropdown while using CHtml::dropDownList for the second. That's cause I am clueless on the syntax of how exactly to make sure the dropdown is populated correctly with ajax and at also properly bind to the model.
You use $form->dropDownListRow that's why you will get $_POST['MyModelName']['superunit'] on your server side
Change you code like
$data=Unit::model()->findAll('sid=:sid',
array(':sid'=>(int) $_POST['MyModelName']['superunit']));
Where MyModelName is a model that you use)
Or like
echo CHtml::dropDownList('superunit'.....
For others - this wiki may help.
i got a problem while updating a record for a model in yii. i have 2 models. im working on one model now. I'm creating a record for one model using create controller. in the form i've 1 fields which is the name field(im getting this name from other model(table). im getting the names from this second table and showing them in dropdown list. and storing them.
when it comes to update its again coming up with the same dropdown what i've shown using the _form.php for creating a record. can anyone pls tell me how can i show the name instead of dropdown list again??
thanks in advance.
Add a simple check in your view to see if the value has already been added or not. Something like this:
<?php if ($model->attribute && $model->attribute != ''): ?>
// Code to display a normal textfield here
<?php else: ?>
// Code to display dropdown
<?php endif; ?>
I have a php file under protected/views/directory_controller_name with formatting like that
<p>
<?php echo $model->title;?>
</p>
...
I display the file with classic method in the controller :
$this->render('filename',array('model'=>$model));
But know, I need to send an email with the same template/layout so I want to store the render of the file in an variable like
$msgHTML = $this->renderInternal('_items', array('model'=>$model));
But it doesn't work!
How can I get render view from a file and store in a variable?
Is it possible?
I don't want to use:
$msgHTML = '<p>'.$model->title.'</p>'
...
Because the file is very long and I don't want to duplicate code!!!
Don't use the renderInternal method, use renderPartial instead. Render internal is low level method and should not be used in such context. To catch the output just set the $return parameter to true:
<?php $output = $this->renderPartial('_subView', $dataArray, true); ?>
$msgHTML = $this->renderInternal('_items', array('model'=>$model), true);
http://www.yiiframework.com/doc/api/1.1/CBaseController#renderInternal-detail
I might be missing something, but can't you just use regular render() with the return argument set to true? Then you can just use a view 'name' instead of knowing the path. (And unless my trusty stack trace logger is broken, renderFile and renderInternal take the same fully qualified path argument. At least I can see renderPartial() passing the full path to my view file to renderFile.)
you can do this with these ways
1) if you want to get the output with header and footer (i.e ) full layout then do this
//add true in the last parameter if you want a return of the output
$htmloutput=$this->render('_pdfoutput',array('data'=>'nothing'),true);
2) similarly if you don't want to get the layout files just use renderpartial in the same way
$htmloutput=$this->renderpartial('_pdfoutput',array('data'=>'nothing'),true);
you will get the html of files in the variable . use this anywhere
I have a Zend_Form that has 4 or more subforms.
/**
Code Snippet
**/
$bigForm = new Zend_Form();
$littleForm1 = new Form_LittleForm1();
$littleForm1->setMethod('post');
$littleForm2 = new Form_LittleForm2();
$littleForm2->setMethod('post');
$bigForm->addSubForm($littleForm1,'littleForm1',0);
$bigForm->addSubForm($littleForm2,'littleForm2',0);
On clicking the 'submit' button, I'm trying to print out the values entered into the forms, like so:
/**
Code snippet, currently not validating, just printing
**/
if($this->_request->getPost()){
$formData = array();
foreach($bigForm->getSubForms() as $subForm){
$formData = array_merge($formData, $subForm->getValues());
}
/* Testing */
echo "<pre>";
print_r($formData);
echo "</pre>";
}
The end result is that - all the elements in the form do get printed, but the values entered before posting the form don't get printed.
Any thoughts are appreciated...I have run around circles working on this!
Thanks in advance!
This is what I did -
$bigForm->addElements($littleForm1->getElements());
Then, iterated over the form elements like so:
$displayGroup1 = array();
foreach($bigForm->getElements() as $name=>$value){
array_push($displayGroup1, $name);
}
Then, add a displayGroup to $bigForm:
$bigForm->addDisplayGroup($displayGroup1, 'test',array('legend'=>'Test'));
And repeat for multiple display groups.
I'm sure there is a better way to do it, but I'm currently unable to find one out.
This is currently one way I can think of to retrieve all the form values via $_POST, if a form is made up of one or more subforms.
If any one knows of a better solution, please post it!
A Zend_Form does not automatically retrieve values from the $_POST variable. Use:
$bigform->populate($_POST)
Or alternatively:
$bigform->populate($this->_request->getPost())
Another thing to keep in mind is that if the sub forms contain elements with the same name they will clash. To check this use the option View => Page Source in your browser and look at the HTML that is generated. When you see two <input> elements with the same name attribute, then this is the problem.
The Zend solution for this is to give the sub form elements different names using setElementsBelongTo:
$littleForm1->setElementsBelongTo('littleForm1');
$littleForm2->setElementsBelongTo('littleForm2');
Furthermore you should leave out these calls as they serve no purpose (but you should set them for the $bigForm):
$littleForm->setMethod('post');