I have a project that involves rabbitmq. The problem that I have is illustrated as follows:
So now, let me describe the scenario. I have n number of queues which subscribed to topic1.
Now my question is if I publish 3 messages in sequence, which are shown as 1, 2 and 3 into broker called Exchange, will rabbitmq Guarantee the sequence of those messages in all queues?
The only thing that I found was in rabbitmq documentation Message ordering guarantees which was taking about
Section 4.7 of the AMQP 0-9-1 core specification explains the conditions under which ordering is guaranteed: messages published in one channel, passing through one exchange and one queue and one outgoing channel will be received in the same order that they were sent. RabbitMQ offers stronger guarantees since release 2.7.0.
So can anyone help me out and point me to the right doc or example that shows whether it is guaranteed or not?
Thanks
As the other poster mentioned, your scenario should work fine assuming a simple/basic consumer setup. But here's some additional info that might explain why.
I wasn't sure quite what nuances might have been wrapped up in that section of the documentation either, until I looked up exactly what a Channel was. A connection to RabbitMQ can have multiple "mini-connections" within it called channels. Each of these channels are independent and thus you could send multiple messages to the broker via multiple channels.
So as long as the messages in your scenario are sent on a single channel (you'd have to explicitly try to use multiple channels), they'll arrive in the queue in the same order you sent them. As long as the messages are consumed via a single channel, they'd arrive on the consumer in the same order they arrived in the queue (also being the same order they were sent).
From: https://www.rabbitmq.com/tutorials/amqp-concepts.html
Some applications need multiple connections to an AMQP broker. However, it is undesirable to keep many TCP connections open at the same time because doing so consumes system resources and makes it more difficult to configure firewalls. AMQP 0-9-1 connections are multiplexed with channels that can be thought of as "lightweight connections that share a single TCP connection".
What you have quoted answers your question perfectly. The only question is what your consumer set up looks like. If you have each queue connected to its own channel and that consumer is running in its own thread, that thread will see each message in order as they were published.
Related
After reading documentation about what is Rabbit and what does, I have some common questions:
Case is: Producer sends one message to some consumers (subscribers).
I need a short explanation for all points of list below, what to use, and what to dig further.
How to clear queue and stop sending message to consumers after
specific time/date?
Can I include to confirmed message user's data like JSON?
Where is stored this data? In the same queue?
How to filter confirmed messages and then clear queue?
How to clear queue after specific time/date?
What happens if not one consumer no confirms message, how long they are stored?
Does consumer subscribe on queue or can subscribe on exchange too?
Using model one to many for sending message, how to set who have to
get message first/last or at the same time, here described that, but not clear is it on client or server side?
If no consumers, how to re-push message to another queue and close
current?
Each consumer has own queue?
Thank you in advance and any comment to this question!
If you can elaborate some of your questions and include what is your use case, I can edit the answer.
1 - As long as consumer is alive rabbitmq sends incoming messages to consumer. You can give TTL to messages/queues if you want them to expire after some time.
https://www.rabbitmq.com/ttl.html
2 - What you mean?
3 - Rabbitmq stores the data in mnesia database.
https://www.rabbitmq.com/persistence-conf.html
https://www.rabbitmq.com/relocate.html
4 - What you mean by filterig messages and clear queue? Successfully consumed messages removed from the queue immediatly.
5 - You can give ttl to queue or declare queue as auto delete
https://www.rabbitmq.com/ttl.html
https://www.rabbitmq.com/queues.html
6 - If consumers don't send ack to rabbit, messages stays unack as long as memory becomes full or rabbit becomes unavailable
7 - Both. A consumer can create its own queue and bind it to an exchange or it can consume from existing queue. It depends on the use case.
8 - It is hard to answer this without knowing details of what you mean by one-to-many. Direct exchange or fanout or whatelse, how many queues etc.
But, in rabbitmq, messages ordered by publish order by default.
According to link you shared, rabbitmq sends messages first to higher priority consumers until consumer prefetch count (unack messages on consumer) becomes its limits.
9 - You need to handle this case in the code. Or you can use management ui with Shovel plugin.
https://www.rabbitmq.com/management.html
https://www.rabbitmq.com/shovel.html
10 - Again, it depends on the design and use case.
One of the main characteristics of a message queue service, RabbitMQ included, is preserving message publication order. This is confirmed in the RabbitMQ documentation:
[QUOTE 1] Section 4.7 of the AMQP 0-9-1 core specification explains the
conditions under which ordering is guaranteed: messages published in
one channel, passing through one exchange and one queue and one
outgoing channel will be received in the same order that they were
sent. RabbitMQ offers stronger guarantees since release 2.7.0.
Let's assume in the following that there are no consumers active, to simplify things. We are publishing over one single channel.
So far, so good.
RabbitMQ also provides possibility to inform the publisher that a certain publication has been completely and correctly processed [*]. This is explained here. Basically, the broker will either send a basic.ack or basic.nack message. The documentation also says this:
[QUOTE 2] basic.ack for a persistent message routed to a durable queue will be
sent after persisting the message to disk.
In most cases, RabbitMQ will acknowledge messages to publishers in the
same order they were published (this applies for messages published on
a single channel). However, publisher acknowledgements are emitted
asynchronously and can confirm a single message or a group of
messages. The exact moment when a confirm is emitted depends on the
delivery mode of a message (persistent vs. transient) and the
properties of the queue(s) the message was routed to (see above).
Which is to say that different messages can be considered ready for
acknowledgement at different times. This means that acknowledgements
can arrive in a different order compared to their respective messages.
Applications should not depend on the order of acknowledgements when
possible.
At first glance, this makes sense: persisting a message takes much more time than just storing it in memory, so it's perfectly possibly that the acknowledgment of a later transient message will arrive before the acknowledgement of an earlier persistent message.
But, if we re-read the first quote regarding message order [QUOTE 1] here above, it gets confusing. I'll explain. Assume we are sending two messages to the same exchange: first a persistent and then a transient message. Since RabbitMQ claims to preserve message order, how can it send an acknowledgment of the second/transient message before it knows that the first/persistent message is indeed completely written to disk?
In other words, does the remark regarding illogical acknowledgement order [QUOTE 2] here above only apply in case the two messages are each routed to completely different target queue(s) (which might happen if they have different routing keys, for example)? In that case, we don't have to guarantee anything as done in [QUOTE 1].
[*] In most cases, this means 'queued'. However, if there are no routing rules applicable, it cannot be enqueued in a target queue. However, this is still a positive outcome regarding publication confirmation.
update
I read this answer on a similar question. This basically says that there are no guarantees whatsoever. Even the most naive implementation, where we delay the publication of message 2 to the point after we got an acknowledgment of message 1, might not result in the desired message order. Basically, [QUOTE 1] is not met.
Is this correct?
From this response on rabbitmq-users:
RabbitMQ knows message position in a queue regardless of whether it is transient or not.
My guess (I did not write that part of the docs) the ack ordering section primarily tries to communicate that if two messages are routed to two different queues, those queues will handle/replicate/persist them concurrently. Reasoning about ordering in more than one queue is pretty hard. A message can go into more than one queue as well.
Nonetheless, RabbitMQ queues know what position a message has in what queues. Once all routing/delivery acknowledgements are received by a channel that handled the publish, it is added to the list of acknowledgements to send out. Note that that
list may or may not be ordered the same way as the original publishes and worrying about that is not practical for many reasons, most importantly: the user typically primarily cares about the ordering in the queues.
NOTE: the RabbitMQ team monitors the rabbitmq-users mailing list and only sometimes answers questions on StackOverflow.
Consider a group chat scenario where 4 clients connect to a topic on an exchange. These clients each send an receive messages to the topic and as a result, they all send/receive messages from this topic.
Now imagine that a 5th client comes in and wants to read everything that was send from the beginning of time (as in, since the topic was first created and connected to).
Is there a built-in functionality in RabbitMQ to support this?
Many thanks,
Edit:
For clarification, what I'm really asking is whether or not RabbitMQ supports SOW since I was unable to find it on the documentations anywhere (http://devnull.crankuptheamps.com/documentation/html/develop/configuration/html/chapters/sow.html).
Specifically, the question is: is there a way for RabbitMQ to output all messages having been sent to a topic upon a new subscriber joining?
The short answer is no.
The long answer is maybe. If all potential "participants" are known up-front, the participant queues can be set up and configured in advance, subscribed to the topic, and will collect all messages published to the topic (matching the routing key) while the server is running. Additional server configurations can yield queues that persist across server reboots.
Note that the original question/feature request as-described is inconsistent with RabbitMQ's architecture. RabbitMQ is supposed to be a transient storage node, where clients connect and disconnect at random. Messages dumped into queues are intended to be processed by only one message consumer, and once processed, the message broker's job is to forget about the message.
One other way of implementing such a functionality is to have an audit queue, where all published messages are distributed to the queue, and a writer service writes them all to an audit log somewhere (usually in a persistent data store or text file). This would be something you would have to build, as there is currently no plug-in to automatically send messages out to a persistent storage (e.g. Couchbase, Elasticsearch).
Alternatively, if used as a debug tool, there is the Firehose plug-in. This is satisfactory when you are able to manually enable/disable it, but is not a good long-term solution as it will turn itself off upon any interruption of the broker.
What you would like to do is not a correct usage for RabbitMQ. Message Queues are not databases. They are not long term persistence solutions, like a RDBMS is. You can mainly use RabbitMQ as a buffer for processing incoming messages, which after the consumer handles it, get inserted into the database. When a new client connects to you service, the database will be read, not the message queue.
Relevant
Also, unless you are building a really big, highly scalable system, I doubt you actually need RabbitMQ.
Apache Kafka is the right solution for this use-case. "Log Compaction enabled topics" a.k.a. compacted topics are specifically designed for this usecase. But the catch is, obviously your messages have to be idempotent, strictly no delta-business. Because kafka will compact from time to time and may retain only the last message of a "key".
I'm using NServiceBus 4.x with RabbitMQ 3.2.x as my transport.
I made the assumption that by using RabbitMQ as my transport I would be given the competing consumer model as an option. I understand that NServiceBus employs the "Fannout" exchange type for all exchanges and does not support round robin at this time. However is there a way to configure NServiceBus to take advantage of the levels of indirection via Exchanges and channels that RabbitMQ offers.
I have several consumers I would like to compete for messages from a given queue. What I am observing is subscribers' blocking access to further message retrieval from the queue until the message is consumed. So having more then one consumer at this point does me no good other then redundancy.
After reading some documentation on RabbitMQ I'm assuming that it's normal to block until the Ack receipt is sent from the subscriber. But I had assumed that subscriber #2 would have free access to the queue to fetch another message.
There is mention of increasing the prefetch count on RabbitMQ channel.
Example:
channel.BasicQos(0,prefetchcount,false)
I don't see anywhere that I can change this setting via configuration in NServiceBus. Furthermore as I read what prefetch does I'm really not sure this what i'm looking for.
Is it possible to use RabbitMQ with out a distirbutor type pattern used with MSMQ? Or should I move to MassTransit or Rebus?
Put prefetchcount=2 in your connection string. Any value above 1 will tell the broker to allow more than X unacked message to go out. You need to fiddle with this setting to find the optimum for your scenario.
I have two questions about RabbitMQ Work Queues:
As I understand it from the RabbitMQ tutorials, it seems that if I have a basic queue consumer client (just a basic "Hello, World!" consumer) and then I add a second consumer client for the same queue, then RabbitMQ will automatically dispatch the messages between those two queues in a round robin manner. Is that true (without adding in any extra configuration)?
My consumer clients are configured to only ever receive one message at a time, using (GetResponse response = channel.basicGet("my_queue", false). Since I am only ever receiving one message at a time, is it still necessary to set a prefetchCount (channel.basicQos(1)) for fair dispatch?
Answers to your questions:
Yes
No
However, your two questions 1 and 2 are not compatible. If you are using a consumer, it is designed to have messages pushed to it, and you don't use Basic.Get. When you use a consumer, you will need to use Basic.QoS to specify that the consumer can only "own" one unacknowledged message at a time. RabbitMQ will not push additional messages beyond the QoS limit.
Your alternative is to "pull" from the queue using Basic.Get, and you will control your own destiny as far as how many messages you run at a time.
Does this make sense?