I want to optimize this
WITH a as
(SELECT *
,ROW_NUMBER() OVER (PARTITION BY applicationid ORDER BY AgreementStartDate desc) rn
,(select count(*) from RM_TbPackages where d.ApplicationID=ApplicationID) as PackageCount
FROM CM_VwSupplierApplications d)
select * from a
where rn=1
order by a.ApplicationID
As per the comment, there is nothing wrong with the partition. One possible inefficiency is the subquery (select count(*) from RM_TbPackages where d.ApplicationID=ApplicationID) - a set based approach to this by computing all counts per Application and then joining to the count should improve performance:
WITH a as
(
SELECT * ,
ROW_NUMBER() OVER (PARTITION BY applicationid ORDER BY AgreementStartDate desc) rn,
x.PackageCount
FROM CM_VwSupplierApplications d
INNER JOIN
(select ApplicationID, count(*) as PackageCount
from RM_TbPackages
group by ApplicationID )x
on x.ApplicationID = d.ApplicationID
)
select * from a
where rn=1
order by a.ApplicationID;
This query will run faster since it is not making a subselect for ever row in CM_VwSupplierApplications:
;WITH a AS
(
SELECT * ,ROW_NUMBER() OVER (PARTITION BY applicationid ORDER BY AgreementStartDate desc) rn
FROM CM_VwSupplierApplications d
)
SELECT a.*, b.PackageCount
FROM a
OUTER APPLY
( SELECT count(*) PackageCount
FROM RM_TbPackages
WHERE d.ApplicationID=ApplicationID) b
WHERE a.rn=1
ORDER BY a.ApplicationID
To improve it even more, you could consider index on table CM_VwSupplierApplications on the columns applicationid and AgreementStartDate
Related
I need to select the data of all my customers with the records displayed in the image. But I need to get the most recent record only, for example I need to get the order # E987 for John and E888 for Adam. As you can see from the example, when I do the select statement, I get all the order records.
You don't mention the specific database, so I'll answer with a generic solution.
You can do:
select *
from (
select t.*,
row_number() over(partition by name order by order_date desc) as rn
from t
) x
where rn = 1
You can use analytical function row_number.
Select * from
(Select t.*,
Row_number() over (partition by customer_id order by order_date desc) as rn
From your_table t) t
Where rn = 1
Or you can use not exists as follows:
Select *
From yoir_table t
Where not exists
(Select 1 from your_table tt
Where t.customer_id = tt.custome_id
And tt.order_date > t.order_date)
You can do it with a subquery that finds the last order date.
SELECT t.*
FROM yoir_table t
JOIN (SELECT tt.custome_id,
MAX(tt.order_date) MaxOrderDate
FROM yoir_table tt
GROUP BY tt.custome_id) AS tt
ON t.custome_id = tt.custome_id
AND t.order_date = tt.MaxOrderDate
I have the following data that is returned to me. I need to get a distinct or max sum of all the commission by taxid for a single repnbr. The 'qtrlycommrep' column is the value I'm trying to get to, but not able to. For repnbr c590, I need to get the 854.66 commission amount, which is the max for each taxid.
What am I doing wrong?
Any help would be much appreciated!
Here's what I've tried so far. Using the Row_number
select distinct
sub.Repnbr
, (sub.QtrLYComm) as qtrlycommrep
from (
select distinct repnbr, QtrLYComm
, rn = row_number() over(partition by repnbr order by QtrLYComm desc)
from #qtrly
) sub
where sub.rn = 1
Cross Apply
select distinct
#qtrly.repnbr
, x.QtrLYComm as qtrlycommrep
from #qtrly
cross apply (
select top 1
*
from #qtrly as i
where i.repnbr = Repnbr
order by i.qtrlycomm desc
) as x;
inner join
select
#qtrly.repnbr, #qtrly.qtrlycomm as qtrlycommrep
from #qtrly
inner join (
select maxvalue = max(qtrlycomm), repnbr
from #qtrly
group by repnbr
) as m
on #qtrly.repnbr = m.repnbr
and #qtrly.qtrlycomm = m.maxvalue;
order by row_number
select top 1 with ties
#qtrly.repnbr, #qtrly.qtrlycomm as qtrlycommrep
from #qtrly
order by
row_number() over(partition by repnbr
order by qtrlycomm desc)
You want one value per tax id. You need to include that. For instance:
select q.Repnbr, sum(q.QtrLYComm) as qtrlycommrep
from (select q.*,
row_number() over(partition by repnbr, taxid order by QtrLYComm desc) as seqnum
from #qtrly q
) q
where seqnum = 1
group by q.Repnbr;
However, I would be inclined to use two levels of aggregation:
select q.Repnbr, sum(q.QtrLYComm) as qtrlycommrep
from (select distinct repnbr, taxid, QtrLYComm
from #qtrly q
) q
group by q.Repnbr;
I have the following table:
I want to get the most recent status for each dept_code that a CL_ID has. So the desired output would be this:
I have tried the following but this give me just the most recent status for each client and not each of their dept_codes.
SELECT *
FROM [CIMSHR6_MERGED].[dbo].[C3CLSTAT] C
INNER JOIN
(SELECT CLIENT_NUMBER, MAX(STATUS_DATE) AS SDATE
FROM [CIMSHR6_MERGED].[dbo].[C3CLSTAT]
GROUP BY CLIENT_NUMBER) X
ON X.CLIENT_NUMBER = C.CLIENT_NUMBER
AND X.SDATE = C.STATUS_DATE
ORDER BY C.CLIENT_NUMBER
Any help would be much appreciated. Thanks.
A convenient method that works in SQL Server is:
select top (1) cl.*
from [CIMSHR6_MERGED].[dbo].[C3CLSTAT] cl
order by row_number() over (partition by cl_id, dept_code order by status_date desc);
A method that is efficient with the right indexes in almost any database is:
select cl.*
from [CIMSHR6_MERGED].[dbo].[C3CLSTAT] cl
where cl.status_date = (select max(cl2.status_date)
from [CIMSHR6_MERGED].[dbo].[C3CLSTAT] cl2
where cl2.cl_id = cl.cl_id and cl2.dept_code = cl.dept_code
);
The right index is on (cl_id, dept_code, status_date).
I would also use ROW_NUMBER, but with a subquery:
SELECT CL_ID, Status_date, Status, Dept_code
FROM
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY CL_ID, Dept_code ORDER BY Status_date DESC) rn
FROM CIMSHR6_MERGED].[dbo].[C3CLSTAT]
) t
WHERE rn = 1;
1) Firstly group everything on Dept_Code,CL_ID and assign rank for each row with in the group in descending order.
2) Select all the rows with rnk=1 which would display your desired result.
SELECT Z.CL_ID,
Z.Status_Date,
Z.Status,
Z.Dept_Code
FROM
(
SELECT *,
RANK() OVER( PARTITION BY Dept_Code,CL_ID, ORDER BY Status_Date DESC ) AS rnk
FROM [CIMSHR6_MERGED].[dbo].[C3CLSTAT]
) Z
WHERE Z.rnk = 1;
This would work for almost all databases
select * from c3clstat c
where exists
(select 1 from c3clstat c1
where c1.cl_id=c.cl_id
and c1.dept_code=c.dept_code
group by cl_id,dept_code
having c.status_date=max(c1.status_date)
)
I've got a question about a sql result and how to achieve the following.
In the Screenshot, there is a Rownumber for every ID, and every ID has another column which has a status 'old' or 'processed'. What i want is, if the RN is = 1 and the Status is processed, than all other RN of this ID should also have the status 'processed'.
Is there a possibility to achieve this in sql?
SELECT RN = ROW_NUMBER() OVER (PARTITION BY [NODE_NAME]
ORDER by REPORTING_RELEVANT_STATUS_ID DESC, BILLING_PERIOD DESC)
,[CI_EQUIPMENT_ID] AS ID_PART
,[REPORTING_RELEVANT_STATUS_ID] AS REPORTING_RELEVANT
,[BILLING_PERIOD]
, [NODE_NAME]
FROM Table
Put your query in CTE? then JOIN it with actual table:
;WITH cte AS (
SELECT RN = ROW_NUMBER() OVER (PARTITION BY [NODE_NAME]
ORDER by REPORTING_RELEVANT_STATUS_ID DESC, BILLING_PERIOD DESC)
,[CI_EQUIPMENT_ID] AS ID_PART
,[REPORTING_RELEVANT_STATUS_ID] AS REPORTING_RELEVANT
,[BILLING_PERIOD]
, [NODE_NAME]
FROM Table
)
SELECT t.[CI_EQUIPMENT_ID] AS ID_PART,
CASE WHEN c.RN is NOT NULL THEN c.REPORTING_RELEVANT ELSE t.[REPORTING_RELEVANT_STATUS_ID] END AS REPORTING_RELEVANT,
t.[BILLING_PERIOD],
t.[NODE_NAME]
FROM Table t
LEFT JOIN (
SELECT *
FROM cte
WHERE RN = 1 AND REPORTING_RELEVANT = 'PROCESSED'
) as c
ON c.ID_PART = t.[CI_EQUIPMENT_ID]
Creating common table expression
Updating the CTE values based on RN=1 and Status=Processed. using the Self Join
here:
;with CTE (RN,ID_PART,REPORTING_RELEVANT,BILLING_PERIOD,NODE_NAME) AS
(
SELECT RN = ROW_NUMBER() OVER (PARTITION BY [NODE_NAME]
ORDER by REPORTING_RELEVANT_STATUS_ID DESC, BILLING_PERIOD DESC)
,[CI_EQUIPMENT_ID] AS ID_PART
,[REPORTING_RELEVANT_STATUS_ID] AS REPORTING_RELEVANT
,[BILLING_PERIOD]
, [NODE_NAME]
FROM Table
)
Update CTE1
set CTE1.Status='Processed'
from CTE CTE1 inner join CTE CTE2
on CTE1.ID_PART=CTE2.ID_PART
where CTE2.RN=1 and CTE2.Status='Processed'
I think it's easier to show you an image:
So, for each fld_call_id, go to the next value, if it's identical. When we get to the last value, I need the value in column fld_menu_id.
Or, to put it in another way, eliminate fld_call_id duplicates and save only the last one.
You can use ROW_NUMBER:
WITH CTE AS(
SELECT RN = ROW_NUMBER() OVER (PARTITION BY fld_call_id ORDER BY fld_id DESC),
fld_menu_id
FROM dbo.TableName
)
SELECT fld_menu_id FROM CTE WHERE RN = 1
You can create a Rank column and only select that row, something along the lines of the following:
;WITH cte AS
(
SELECT
*
,RANK() OVER (PARTITION BY fld_call_id ORDER BY fld_id DESC) Rnk
FROM YourTable
)
SELECT
*
FROM cte
WHERE Rnk=1
So you GROUP BY fld_call_id and ORDER BY fld_id in descending order so that the last value comes first. These are the rows where Rnk=1.
Edit after comments of OP.
SELECT Table.*
FROM Table
INNER JOIN
(
SELECT MAX(fldMenuID) AS fldMenuID,
fldCallID
FROM Table
GROUP BY fldCallID
) maxValues
ON (maxValues.fldMenuID = Table.fldMenuID
AND maxValues.fldCallID= Table.fldCallID)
Hope This works
SELECT A.*
FROM table A
JOIN (SELECT fld_id,
ROW_NUMBER() OVER (PARTITION BY Fld_call_id ORDER BY fld_id DESC) [Row]
FROM table) LU ON A.fld_id = LU.fld_id
WHERE LU.[Row] = 1