how to check difference in time - sql

Question

following code returns
CREATE TABLE #emp1
(
empid VARCHAR(50),
empname VARCHAR(50),
intime SMALLDATETIME,
outtime SMALLDATETIME
)
INSERT INTO #emp1
VALUES (2500,
'Arun',
'2014-01-01 09:00:00',
'2014-01-01 10:30:0'),
(2500,
'Arun',
'2014-01-01 11:00:00:00',
'2014-01-01 11:00:0'),
(2500,
'Arun',
'2014-01-01 11:30:00:00',
'2014-01-01 19:00:00')
SELECT empid,
Cast(intime AS DATE)
AS workingday,
empname,
RIGHT('0' + CONVERT(VARCHAR, Floor(Sum( Datediff( mi, intime, outtime)/
60.0))),
2)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR, Sum( Datediff( mi, intime, outtime))%60),
2) AS
[total work_hour(s)],
CONVERT(VARCHAR(5), Max(outtime) - Min(intime), 108)
AS Difference,
Cast(Dateadd(minute, Sum(Datediff(mi, intime, outtime)) - 45, 0) AS TIME)
AS
TotalTime,
Cast(Dateadd(minute, CASE
WHEN Sum(Datediff(mi, intime, outtime)) > 525 THEN
Sum(
Datediff(mi, intime, outtime)) - 525
ELSE 0
END, 0) AS TIME)
AS OverTime
FROM #emp1
GROUP BY empid,
empname,
Cast(intime AS DATE)
DROP TABLE #emp1
as
EmpId workingday EmpName total work_hour(s) Difference TotalTime OverTime
2500 2014-01-01 Arun 09:00 10:00 08:15:00.0000000 00:15:00.0000000
Here TotalTime is 08:15 and OverTime is 00:15. Everything is fine.
However, I need another field ActualTime
i.e. if TotalTime is greater than 8 hours then ActualTime is the difference of TotalTime and OverTime. In this example ActualTime should be 08:00.
If TotalTime is less than 8 hours then ActualTime is the same as TotalTime.
Finally, I also want to avoid excess zeros in TotalTime and OverTime

Answer 1

I imagine you want something like this: *EDIT nullcheck added
;with x as
(
SELECT empid,
Cast(intime AS DATE) workingday,
empname,
cast(dateadd(mi, sum(datediff(mi, 0, outtime - intime)), 0) as time) twh,
cast(dateadd(mi,datediff(mi,0,max(outtime)-min(intime)), 0) as time) Difference,
case when count(outtime)=count(*) then '' end nullcheck
FROM #emp1
GROUP BY empid, empname, Cast(intime AS DATE)
)
select empid, workingday, empname,
nullcheck+left(twh, 5) [total_hours],
nullcheck+left(Difference, 5) Difference,
nullcheck+left(cast(dateadd(mi, -45, twh)as time ),5) TotalTime,
nullcheck+left(case when twh > '08:45' then cast(dateadd(mi, -525, twh) as time) else '00:00' end, 5) OverTime,
nullcheck+left(case when twh > '08:00' then '08:00' else twh end, 5) actualtime
from x
Result:
empid workingday empname total_hours Difference TotalTime OverTime actualtime
2500 2014-01-01 Arun 09:00 10:00 08:15 00:15 08:00

Answer 2

First I'd wrap your entire current query in a Common Table Expression, so that the parts of it can be reused.
WITH CalculatedTime AS (SELECT empid,
Cast(intime AS DATE) AS workingday,
empname,
RIGHT('0' + CONVERT(VARCHAR, Floor(Sum( Datediff( mi, intime, outtime)/
60.0))),
2)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR, Sum( Datediff( mi, intime, outtime))%60),
2) AS [total work_hour(s)],
CONVERT(VARCHAR(5), Max(outtime) - Min(intime), 108)
AS Difference,
Cast(Dateadd(minute, Sum(Datediff(mi, intime, outtime)) - 45, 0) AS TIME)
TotalTime,
Cast(Dateadd(minute, CASE
WHEN Sum(Datediff(mi, intime, outtime)) > 525 THEN
Sum(
Datediff(mi, intime, outtime)) - 525
ELSE 0
END, 0) AS TIME)
OverTime
FROM #emp1
GROUP BY empid,
empname,
Cast(intime AS DATE) )
Now we can refer to CalculatedTime as a table in itself, and we don't need to repeat any of that nasty logic used for calculating the TotalTime column.
So the final step is to use a case statement to perform the calculation you are after:
SELECT *,
CASE WHEN DATEDIFF(minute,TotalTime,'08:00') > 0 THEN TotalTime
ELSE DATEADD(minute, DATEDIFF(minute,OverTime, 0), TotalTime)
END AS ActualTime
FROM CalculatedTime
The formatting part of the problem (remove the extra zeros) is a separate question that has been answered many times before on StackOverflow.