I am having a hard time with this not knowing if there's a solution for this.
I am trying to detect missing hourly data. Sample:
Table HRLY_DATA:
NAME HOUR
Me 0
Me 1
Me 2
Me 3
Me 6
Me 7
You 0
You 1
You 2
You 3
You 4
You 5
You 6
You 7
As you can see, [HOUR] data of Me is missing 4 and 5. I want a query that will output:
NAME HOUR
Me 4
Me 5
For now, here's what I've got:
SELECT d.NAME, HR FROM HRs c
LEFT OUTER JOIN
(
SELECT distinct a.NAME
FROM HRLY_DATA a
INNER JOIN
(
SELECT NAME FROM
(
SELECT NAME, count(*) as CNT
FROM
(
SELECT DISTINCT NAME, HOUR
FROM HRLY_DATA
) as i
GROUP BY NAME
) as ii
WHERE CNT < 8
) as b
ON a.NAME=b.NAME
) as d
ON c.HR=d.HOUR
WHERE d.HOUR IS NULL
HRs
HR
0
1
2
3
4
5
6
7
I am getting this output:
NAME HR
NULL 4
NULL 5
Data for HOUR will range only from 0 - 7..
BTW, I am using SQL SERVER/ MSSQL for this.
:(
Sorry if I can't explain my problem clearly. :(
Please try:
select
distinct x.NAME, number HOUR
From
master.dbo.spt_values cross join HRLY_DATA x
where number between 0 and 7
except
select NAME, HOUR FROM HRLY_DATA
Since table HR contains data 0-7, try:
select
distinct NAME, HR
From
#HR cross join HRLY_DATA
except
select * from HRLY_DATA
Related
I have the following query
select S.id, X.id, 15,15,1 from schema_1.tbl_2638 S
JOIN schema_1.tbl_2634_customid X on S.field_1=x.fullname
That returns the following results, where you can see the first column is duplicated on matches to the 2nd table.
1 1 15 15 1
2 3 15 15 1
2 2 15 15 1
3 5 15 15 1
3 4 15 15 1
I'm trying to get a query that would just give me a single row per 1st ID, and the min value from 2nd ID. So I want a result that would be:
1 1 15 15 1
2 2 15 15 1
3 4 15 15 1
I'm a little rust on my SQL skills, how would I write the query to provide the above result?
From your result you can do,this to achieve your result, for much more compicated structures, you can always take a look at window fucntions
select S.id, MIN(X.id) x_id, 15,15,1 from schema_1.tbl_2638 S
JOIN schema_1.tbl_2634_customid X on S.field_1=x.fullname
GROUP BY 1,3,4,5
window function can be used, need always a outer SELECT
SELECT
s_id,x_idm a,b,c
FROM
(select S.id as s_id, X.id as x_id, 15 a ,15 b,1 c
, ROW_NUMBER() OVER (PARTITION BY S.id ORDER BY X.id ASC) rn
from schema_1.tbl_2638 S
JOIN schema_1.tbl_2634_customid X on S.field_1=x.fullname)
WHERE rn = 1
Or as CTE
WITH CTE as (select S.id as s_id, X.id as x_id, 15 a ,15 b,1 c
, ROW_NUMBER() OVER (PARTITION BY S.id ORDER BY X.id ASC) rn
from schema_1.tbl_2638 S
JOIN schema_1.tbl_2634_customid X on S.field_1=x.fullname)
SELECT s_id,x_id,a,b,c FROM CTE WHERE rn = 1
I am working with an Oracle Database and I am new to SQL in general.
I have a table with data and month columns. After filtering the data I have just a few rows left. But I want to get two columns: 1-st column with 12 months listed (1,2,3,4,5,6,7,8,9,10,11,12) and second column with values from original data (if exist) or zeroes.
F.e.: Original data:
MONTH VALUE
9 96
What I want:
MONTH VALUE
1 0
2 0
3 0
4 0
5 0
6 0
7 0
8 0
9 96
10 0
11 0
12 0
I have already tried to use join and union all functions but it didn't work out.
First generate a sequence of 12 months number then use left join
select monthNo, coalesce(Value,0) as value from
(
SELECT 1 MonthNo
FROM dual
CONNECT BY LEVEL <= 12
)A left join originaltable b on A.monthNo=b.month
is this what are you looking for?
WITH tab AS(SELECT LEVEL AS m , null as value FROM DUAL CONNECT BY LEVEL <= 12)
, tab2 AS(SELECT 9 as m, 96 as VALUE FROM DUAL)
select t1.m
,coalesce(t2.value,0) as value
from tab t1
left join tab2 t2 on t1.m = t2.m
order by 1
Bro enjoy...
select months.month ,original_data.VALUE
from original_data
Right JOIN (VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)) months(month) on
months.month = original_data.MONTH
order by months.month --optional
I'm trying to find the total count of active users in a database. "Active" users here as defined as those who have registered an event on the selected day or later than the selected day. So if a user registered an event on days 1, 2 and 5, they are counted as "active" throughout days 1, 2, 3, 4 and 5.
My original dataset looks like this (note that this is a sample - the real dataset will run to up to 365 days, and has around 1000 users).
Day ID
0 1
0 2
0 3
0 4
0 5
1 1
1 2
2 1
3 1
4 1
4 2
As you can see, all 5 IDs are active on Day 0, and 2 IDs (1 and 2) are active until Day 4, so I'd like the finished table to look like this:
Day Count
0 5
1 2
2 2
3 2
4 2
I've tried using the following query:
select Day as days, sum(case when Day <= days then 1 else 0 end)
from df
But it gives incorrect output (only counts users who were active on each specific days).
I'm at a loss as to what I could try next. Does anyone have any ideas? Many thanks in advance!
I think I would just use generate_series():
select gs.d, count(*)
from (select id, min(day) as min_day, max(day) as max_day
from t
group by id
) t cross join lateral
generate_series(t.min_day, .max_day, 1) gs(d)
group by gs.d
order by gs.d;
If you want to count everyone as active from day 1 -- but not all have a value on day 1 -- then use 1 instead of min_day.
Here is a db<>fiddle.
A bit verbose, but this should do:
with dt as (
select 0 d, 1 id
union all
select 0 d, 2 id
union all
select 0 d, 3 id
union all
select 0 d, 4 id
union all
select 0 d, 5 id
union all
select 1 d, 1 id
union all
select 1 d, 2 id
union all
select 2 d, 1 id
union all
select 3 d, 1 id
union all
select 4 d, 1 id
union all
select 4 d, 2 id
)
, active_periods as (
select id
, min(d) min_d
, max(d) max_d
from dt
group by id
)
, days as (
select distinct d
from dt
)
select d.d
, count(ap.id)
from days d
join active_periods ap on d.d between ap.min_d and ap.max_d
group by 1
order by 1 asc
You need count by day.
select
id,
count(*)
from df
GROUP BY
id
I have a simple table with values that I want to chunk/partition into distinct groups based on the sum of those values (up to a certain limit group sum total).
e.g.,. imagine a table like the following:
Key Value
-----------
A 1
B 4
C 2
D 2
E 5
F 1
And I would like to group into sets such that no one grouping's sum will exceed some given value (say, 5).
The result would be something like:
Group Key Value
-------------------
1 A 1
B 4
--------
Total: 5
2 C 2
D 2
--------
Total: 4
3 E 5
--------
Total: 5
4 F 1
--------
Total: 1
Is such a query possible?
While I am inclined to agree with the comments that this is best done outside of SQL, here is some SQL which would seem to do roughly what you're asking:
with mytable AS (
select 'A' AS [Key], 1 AS [Value] UNION ALL
select 'B', 4 UNION ALL
select 'C', 2 UNION ALL
select 'D', 2 UNION ALL
select 'E', 5 UNION ALL
select 'F', 1
)
, Sums AS (
select T1.[Key] AS T1K
, T2.[Key] AS T2K
, (SELECT SUM([Value])
FROM mytable T3
WHERE T3.[Key] <= T2.[Key]
AND T3.[Key] >= T1.[Key]) AS TheSum
from mytable T1
inner join mytable T2
on T2.[Key] >= T1.[Key]
)
select S1.T1K AS StartKey
, S1.T2K AS EndKey
, S1.TheSum
from Sums S1
left join Sums S2
on (S1.T1K >= S2.T1K and S1.T2K <= S2.T2K)
and S2.TheSum > S1.TheSum
and S2.TheSum <= 5
where S1.TheSum <= 5
AND S2.T1K IS NULL
When I ran this code on SQL Server 2008 I got the following results:
StartKey EndKey Sum
A B 5
C D 4
E E 5
F F 1
It should be straightforward to construct the required groups from these results.
If you want to have only two members or less in each set, you can use the following query:
Select
A.[Key] as K1 ,
B.[Key] as K2 ,
isnull(A.value,0) as V1 ,
isnull(B.value,0) as V2 ,
(A.value+B.value)as Total
from Table_1 as A left join Table_1 as B
on A.value+B.value<=5 and A.[Key]<>B.[Key]
For finding sets having more members, you can continue to use joins.
i have two access tables
tableA
num count
1 7
2 8
3 9
4 9
5 13
6 6
tableB
num count
0 1
1 14
2 12
3 5
4 5
5 11
6 5
how can i create an access query that will ignore the numbers which have count less than 6 in any of the two tables. i.e. 0,3,4 & 6 and create a table with the rest of the numbers sorted by combined count
tableC
num count
5 24
1 21
2 20
any help appreciated
Maybe....
SELECT a.num, a.count + b.count
FROM tableA a
JOIN tableB b on b.num = a.num
WHERE a.count >= 6
AND b.count >= 6
this will include numbers which are in both A and B. To include numbers with count >= 6 that are in one table and not the other you'll have to add a Join and a "isnull" for the a.count and b.count values. ie; isnull(a.count,0) + isnull(b.count,0)
You can try something like this
SELECT DISTINCT tableA.num, [tableA].[val]+[tableB].[val] AS Expr1
FROM tableA INNER JOIN tableB ON tableA.num = tableB.num
WHERE (((tableA.val)>=6) AND ((tableB.val)>=6));
How about
SELECT x.Num, x.Count FROM (
SELECT Num, Count(*)
FROM tableA
GROUP BY Num
HAVING Count(*)>6
UNION ALL
SELECT Num, Count(*)
FROM tableB
GROUP BY Num
HAVING Count(*)>6) x
Or if count is a field, rather than a calculation:
SELECT x.Num, x.Count FROM (
SELECT Num, Count
FROM tableA
WHERE Count>6
UNION ALL
SELECT Num, Count
FROM tableB
WHERE Count>6) x