I want to add $ symbol to column values and convert the column values to western number system
Dollars
4255
25454
467834
Expected Output:
$ 4,255
$ 25,454
$ 467,834
My Query:
select ID, MAX(Date) Date, SUM(Dollars) Dollars, MAX(Funded) Funding from Application
Dollars is the int datatype and needs to be changed.
You can do something like that. Converting from money to varchar with style 1 adds thousand separator:
declare #value int = 4255
select '$ ' + replace(convert(varchar(100), convert(money, #value), 1), '.00', '')
-- output: $ 4,255
If you process the data from SQL Server in any application, formatting is much easier to do in the code though.
Hello basing on your output you can approach like this also
declare #table Table (ID INT)
INSERT INTO #table (ID) VALUES (4255)
INSERT INTO #table (ID) VALUES (25454)
INSERT INTO #table (ID) VALUES (467834)
SELECT '$' + LEFT(CONVERT(VARCHAR(100),CAST(id AS MONEY),1),LEN(id)+ 1) from #table
Thanks
Related
Values in Column are in format Name_city_age_ID (underscore separated).
Age was always blank. Other values may or not be blank. So values in column are like:
John_London__1223,
Mary_Paris__,
Dave____,
Smith____1012,
___2334
Now I have the age as 22 for all rows & I want to replace all values in the column, So the new columns should be:
John_London_22_1223,
Mary_Paris_22_,
Dave__22_,
Smith__22_1012,
__22_2334,
How to write the update query for this?
Using STUFF, but you should really normalize your data. This looks for the second instance of _ and adds 22.
declare #table table(col varchar(64))
insert into #table
values
('John_London__1223'),
('Mary_Paris__'),
('Dave____'),
('Smith____1012'),
('___2334')
select * from #table
--update the column
update #table
set col = stuff(col,charindex('_',col) + charindex('_',right(col,len(col) - charindex('_',col))) + 1,0,'22')
--see the results
select * from #table
Calling CHARINDEX function twice should do it. The following is the SELECT query for reviewing results, convert to UPDATE:
SELECT
str,
STUFF(str, CHARINDEX('_', str, CHARINDEX('_', str) + 1) + 1, 0, '22') AS newstr
FROM testdata
SQL Fiddle
This is possible 2x questions in 1x. Sorry about that, but here goes:
PROBLEM
I am creating a unique batch id everytime a user uploads some data to SQL Server. Currently, I do this by looking at the last value of the 'Identity Specification' and add +1 to that.
Problem arises, as you might have guessed, if multiple users input data at the same, they both would get the same batch id...
Possible Solution
In order to mitigate this issue, I have come up with this method to generate 3 letter + random number; and the (last id value + 1):
DECLARE #tmp CHAR(3) = CHAR(CAST(RAND()*26 AS int)+65) + CHAR(CAST(RAND()*26 AS int)+65) + CHAR(CAST(RAND()*26 AS int)+65);
SELECT #tmp;
select cast(RAND()*9999 as int)
(1) I am not sure how to concatenate this into one line of string.
(2) The other question, is there a way to 100% guarantee every user is given a unique batch id every time they submit a request, regardless of how many are doing it simultaneously?
I would really appreciate your input in this.
1 - Concatenation part is very simple, you can do the following:
DECLARE #tmp VARCHAR(10);
SET #tmp = CHAR(CAST(RAND()*26 AS int)+65)
+ CHAR(CAST(RAND()*26 AS int)+65)
+ CHAR(CAST(RAND()*26 AS int)+65)
+ CAST(cast(RAND()*9999 as int) AS VARCHAR(4));
SELECT #tmp;
2 - I would suggest to populate a table with the Random values you would like to issue to users and then select from it, to avoid the race-condition.
Create a table called BatchNumbers with two Columns BatchNumber and Used.
Populate the batch number table and 0 as default value for Used Column.
Then everytime you need a batch number do the following.
CREATE PROC dbo.usp_Get_BatchNumber
#BatchNumber VARCHAR(10) OUTPUT
AS
BEGIN
SET NOCOUNT ON;
Declare #t TABLE (BN VARCHAR(10));
UPDATE TOP (1) BatchNumbers
SET Used = 1
OUTPUT inserted.BatchNumber INTO #t (BN )
WHERE Used = 0;
SELECT #BatchNumber = BN FROM #t;
END
You need an "Upload" table with a Bigint Identity column for the BatchID, then add a new row for every user upload.
The server will maintain the correct values and prevent collisions.
I would use the built in function for this:
select newid()
> 240CA878-135E-4176-AE57-0FA83FF74037
For the first problem, you can either create a variable for your random number as a char(4) and just simply concatenate the 2, or create it as an int and then CAST it as a VARCHAR while concatenating. Everything that is concatenated into a string must be a string.
DECLARE #tmp CHAR(3) = CHAR(CAST(RAND()*26 AS int)+65) + CHAR(CAST(RAND()*26 AS int)+65) + CHAR(CAST(RAND()*26 AS int)+65);
SELECT #tmp;
DECLARE #randNum VARCHAR(4) = CAST(RAND()*9999 AS INT)
-- OR DECLARE #randNum INT = CAST(Rand()*9999) AS INT)
SELECT #randNum
DECLARE #batchID VARCHAR(MAX) = #tmp + #randNum
-- OR DECLARE #batchID VARCHAR(MAX) = #tmp + CAST(#randNum AS VARCHAR)
SELECT #batchID
try the following:
1)
DECLARE #tmp CHAR(7) = CHAR(CAST(RAND()*26 AS int)+65) + CHAR(CAST(RAND()*26 AS int)+65) + CHAR(CAST(RAND()*26 AS int)+65) + cast(cast(RAND()*9999 as int) as varchar(4));
SELECT #tmp;
2) Yes, I think so.
I upvoted Terry Carmen's answer, but from his comments it sounds like he's suggesting something different from what I first thought, so here's a complete example. I think you want a table that has a key defined with the IDENTITY property, which will tell SQL Server that you want unique, sequential values in that column and you want the database to worry about the details of guaranteeing that this is so.
create table dbo.Import
(
-- identity(1, 1) means that SQL Server will automatically assign values for
-- this column when you insert a record, with 1 being the first value
-- assigned and each subsequent value incrementing by 1.
Identifier bigint not null identity(1, 1),
-- This column for illustration only; replace it with whatever data you need
-- to store.
YourStuffHere varchar(max)
);
-- Now simply use any INSERT or MERGE command against dbo.Import, and omit the
-- Identifier column from the list of columns whose values the command supplies.
-- Then you can use the SCOPE_IDENTITY() function or an OUTPUT clause to capture
-- the Identifier value that SQL Server has inserted.
-- Example 1: INSERT with explicit values and OUTPUT.
insert dbo.Import
(YourStuffHere)
output
inserted.Identifier
values
('Example 1');
-- Example 2: INSERT/SELECT with OUTPUT.
insert dbo.Import
(YourStuffHere)
output
inserted.Identifier
select
'Example 2';
-- Example 3: INSERT with SCOPE_IDENTITY().
insert dbo.Import
(YourStuffHere)
values
('Example 3');
select Identifier = convert(bigint, scope_identity());
-- Show table contents.
select * from dbo.Import;
The first INSERT statement above produces the following result:
Identifier
1
The second:
Identifier
2
The SELECT following the third INPUT gives:
Identifier
3
And the final SELECT shows you the contents of the table:
Identifier YourStuffHere
1 Example 1
2 Example 2
3 Example 3
This is the easiest way to go about this as it allows SQL Server to do all the real work for you. Please let me know if I've misunderstood your requirements.
I have a conundrum....
There is a table with one NVARCHAR(50) Float column that has many rows with many numbers of various decimal lengths:
'3304.063'
'3304.0625'
'39.53'
'39.2'
I need to write a query to find only numbers with decimal places >= 4
First the query I wrote was:
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9]%'
The above code finds all numbers with decimal places >= 2:
'3304.063'
'3304.0625'
'39.53'
Perfect! Now, I just need to increase the [0-9] by 2...
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9][0-9][0-9]%'
this returned nothing! What?
Does anyone have an explanation as to what went wrong as well and/or a possible solution? I'm kind of stumped and my hunch is that it is some sort of 'LIKE' limitation..
Any help would be appreciated!
Thanks.
After your edit, you stated you are using FLOAT which is an approximate value stored as 4 or 8 bytes, or 7 or 15 digits of precision. The documents explicitly state that not all values in the data type range can be represented exactly. It also states you can use the STR() function when converting it which you'll need to get your formatting right. Here is how:
declare #table table (columnName float)
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
--see the conversion
select * , str(columnName,20,4)
from #table
--now use it in a where clause.
--Return all values where the last digit isn't 0 from STR() the conversion
select *
from #table
where right(str(columnName,20,4),1) != 0
OLD ANSWER
Your LIKE statement would do it, and here is another way just to show they both work.
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
select *
from #table
where len(right(columnName,len(columnName) - charindex('.',columnName))) >= 4
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
One thing that could be causing this is a space in the number somewhere... since you said the column type was VARCHAR this is a possibility, and could be avoided by storing the value as DECIMAL
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304. 0625'), --notice the space here
('39.53'),
('39.2')
--this would return nothing
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
How to find out if this is the case?
select *
from #table
where columnName like '% %'
Or, anything but numbers and decimals:
select *
from #table
where columnName like '%[^.0-9]%'
The following is working fine for me:
declare #tab table (val varchar(50))
insert into #tab
select '3304.063'
union select '3304.0625'
union select '39.53'
union select '39.2'
select * from #tab
where val like '%.[0-9][0-9][0-9][0-9]%'
Assuming your table only has numerical data, you can cast them to decimal and then compare:
SELECT COLUMN
FROM tablename
WHERE CAST(COLUMN AS DECIMAL(19,4)) <> CAST(COLUMN AS DECIMAL(19,3))
You'd want to test the performance of this against using the character data type solutions that others have already suggested.
You can use REVERSE:
declare #vals table ([Val] nvarchar(50))
insert into #vals values ('3304.063'), ('3304.0625'), ('39.53'), ('39.2')
select [Val]
from #Vals
where charindex('.',reverse([Val]))>4
I have a column (XID) that contains a varchar(20) sequence in the following format: xxxzzzzzz Where X is any letter or a dash and zzzzz is a number.
I want to write a query that will strip the xxx and evaluate and return which is the highest number in the table column.
For example:
aaa1234
bac8123
g-2391
After, I would get the result of 8123
Thanks!
A bit painful in SQL Server, but possible. Here is one method that assumes that only digits appear after the first digit (which you actually specify as being the case):
select max(cast(stuff(col, 1, patindex('%[0-9]%', col) - 1, '') as float))
from t;
Note: if the last four characters are always the number you are looking for, this is probably easier to do with right():
select max(right(col, 4))
Using Numbers table
declare #string varchar(max)
set #string='abc1234'
select top 1 substring(#string,n,len(#string))
from
numbers
where n<=len(#string)
and isnumeric(substring(#string,n,1))=1
order by n
Output:1234
Using PATINDEX you can achieve it, like this -
DECLARE #test table
(
id INT,
player varchar(100)
)
INSERT #test
VALUES (1,'aaa1234'),
(2,'bac8123'),
(3,'g-2391')
SELECT
MAX(CONVERT(INT, LTRIM(SUBSTRING(player, PATINDEX('%[0-9]%', player), LEN(player)))))
FROM #test
Try:
Select MAX(RIGHT(XID,17))
from table
You can also use this method
CREATE TABLE #Tmp
(
XID VARCHAR(20)
)
INSERT INTO #Tmp(XID)
VALUES ('aaa1234'), ('bac8123'), ('g-2391')
SELECT MAX(RIGHT(XID, LEN(XID) - 3))
FROM #Tmp
i have written a query in which i am fetching an amount which is a number like '50,000','80,000'.
select Price_amount
from per_prices
As these values contain ',' these are considered to be varchar.Requirement is to to print these as 'number' with ','
that is how can '50,000' be considered as number and not varchar
If a value has anything other than numbers in it, it is not an integer it is string containing characters. in your case you have a string containing character 5, 0 and ,.
If this is what is stored in your database and this is what you want to display then go ahead you do not need to change it to Integer or anything else. But if you are doing some calculations on these values before displaying them, Yes then you need to change them to an Integer values. do the calculation. Change them back to the varchar datatype to show , between thousands and hundred thousands and display/select them.
Example
DECLARE #TABLE TABLE (ID INT, VALUE VARCHAR(100))
INSERT INTO #TABLE VALUES
(1, '100,000'),(2, '200,000'),(3, '300,000'),(4, '400,000'),
(1, '100,000'),(2, '200,000'),(3, '300,000'),(4, '400,000')
SELECT ID, SUM(
CAST(
REPLACE(VALUE, ',','') --<-- Replace , with empty string
AS INT) --<-- Cast as INT
) AS Total --<-- Now SUM up Integer values
FROM #TABLE
GROUP BY ID
SQL Fiddle
you could combine the Replace and cast function
SELECT CAST(REPLACE(Price_amount, ',', '') AS int) AS Price_Number FROM per_prices
for more information visit 'replace', 'cast'
SQLFiddle