I have a system that is generating a text file that contains an unknown amount of data. I have two separate chunks of code one for Payment and one for Distribution. I know I will have at least one Payment and one Distribution (Payment has 23 fields with varying widths and Distribution has 12 fields).
Payment Field lengths are: {10, 1, 10, 8, 1, 20, 13, 1, 8, 8, 8, 40, 40, 40, 40, 40, 25, 2, 9, 40, 10, 20, 6}
Distribution Field lengths are: {10, 1, 10, 20, 40, 13, 1, 40, 40, 10, 1, 14}
The payment field is 400 characters and then the Distribution field is 200 characters. I can have one distribution field or many distribution fields as well as payment fields, but the payment fields do not go in order.
Example of the Payment structure [DO NOT REMOVE SPACES] I need to maintain the structure just in case there is a value there:
00000041285111 20140106EDA0000-001 0000010636317+201401012014010320140106 Some Tax Company Non testing agency service TEST GROUP INC 11#####23
Example of the Distribution structure [DO NOT REMOVE SPACES] I need to maintain the structure just in case there is a value there:
00000041286111 DA0000-005 0000000016731+ 666111 98552
I need to be able to parse through the first Payment gather all of the values in the fixed length, and somehow switch the length of fields to be the distribution fields until I get all of those, and switch it back if it goes back to a Payment.
Here is the code that I have:
Using MyReader As New Microsoft.VisualBasic.FileIO.
TextFieldParser("C:\COM_20140103_173912.txt")
'This field parser gives me the first 400characters with not problems
MyReader.TextFieldType =
Microsoft.VisualBasic.FileIO.FieldType.FixedWidth
MyReader.FieldWidths = {10, 1, 10, 8, 1, 20, 13, 1, 8, 8, 8, 40, 40, 40, 40, 40, 25, 2, 9, 40, 10, 20, 6}
Dim currentRow As String()
While Not MyReader.EndOfData
Try
currentRow = MyReader.ReadFields()
Dim currentField As String
For Each currentField In currentRow
MsgBox(currentField)
Next
Catch ex As Microsoft.VisualBasic.FileIO.MalformedLineException
MsgBox("Line " & ex.Message &
"is not valid and will be skipped.")
End Try
End While
End Using
I got this code from http://msdn.microsoft.com/en-us/library/microsoft.visualbasic.fileio.textfieldparser.fieldwidths.aspx
I have done research and I can't figure out how to manipulate this to do what I need it to do. Any help would be appreciated. I hope I gave enough information, and if you need me to explain it differently I can.
Thanks,
John
Here's one idea. The TextFielParser constructor can also take a stream as its parameter. Use a regular StreamReader to read the file line by line and then use a StringReader with the TextFieldParser to process each line based on it's length. Something like the following (untested):
Imports Microsoft.VisualBasic.FileIO
Imports System.IO
Sub Main
Using rdr As New StreamReader("C:\COM_20140103_173912.txt")
Dim currentLine As String = rdr.ReadLine()
While currrentLine IsNot Nothing
Dim currentRow As String()
If currentLine.Length = 400 Then
currentRow = processDistributionRow(currentLine)
Else
currentRow = processPaymentRow(currentLine)
End If
If currentRow IsNot Nothing Then
'Process current set of fields
End If
currentLine = rdr.ReadLine()
End While
End Using
End Sub
'This method uses a TextFieldParser to process a single line of a file that is passed in
Private Function processDistributionRow(currentLine As String)
Dim result As String()
Using strStream As New StringStream(currentLine)
Using MyReader As New TextFieldParser(strStream)
MyReader.TextFieldType = FieldType.FixedWidth
MyReader.FieldWidths = {10, 1, 10, 8, 1, 20, 13, 1, 8, 8, 8, 40, 40, 40, 40, 40, 25, 2, 9, 40, 10, 20, 6}
Try
result = MyReader.ReadFields()
Dim currentField As String
Catch ex As Microsoft.VisualBasic.FileIO.MalformedLineException
MsgBox("Line " & ex.Message & "is not valid and will be skipped.")
End Try
End Using
End Using
return result
End Function
'This method uses a TextFieldParser to process a single line of a file that is passed in
Private Function processPaymentRow(currentLine As String)
Dim result As String()
Using strStream As New StringStream(currentLine)
Using MyReader As New TextFieldParser(strStream)
MyReader.TextFieldType = FieldType.FixedWidth
MyReader.FieldWidths = {?, ?, ?} 'Set proper field widths for the payment row here
Try
result = MyReader.ReadFields()
Dim currentField As String
Catch ex As Microsoft.VisualBasic.FileIO.MalformedLineException
MsgBox("Line " & ex.Message & "is not valid and will be skipped.")
End Try
End Using
End Using
return result
End Function
' Define other methods and classes here
Related
I have a Custom Control that displays color selections in a drop down and it works good.
I found the performance was poor with multiple controls on the same Form so I changed it to store the Color index in the Items collection.
This works good but the Designer gets populated with a large array of values and this causes empty items in the control.
How do I stop the designer from storing the Items?
Here is the designer code I don't want:
Me.cboCWarcColor.Items.AddRange(New Object()
{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18,
19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35,
36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52,
53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69,
70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86,
87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102,
103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115,
116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128,
129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140}
)
Here is the Custom Control code:
Imports System.Collections.Generic
Public Class ColorCombo
Inherits System.Windows.Forms.ComboBox
Private mSelectedColor As Color = Nothing
Private Shared myColors As New List(Of Color)
Private Shared myColorsIndices As New List(Of Object)
Private Sub ColorCombo_DrawItem(ByVal sender As Object, ByVal e As System.Windows.Forms.DrawItemEventArgs) Handles Me.DrawItem
Try
If e.Index < 0 Or e.Index >= myColors.Count Then
e.DrawBackground()
e.DrawFocusRectangle()
Exit Try
End If
' Get the Color object from the Items list
Dim aColor As Color = myColors.Item(e.Index) 'myColors.Item(e.Index)
' get a square using the bounds height
Dim rect As Rectangle = New Rectangle(4, e.Bounds.Top + 2, CInt(e.Bounds.Height * 1.5), e.Bounds.Height - 4)
' call these methods first
e.DrawBackground()
e.DrawFocusRectangle()
Dim textBrush As Brush
' change brush color if item is selected
If e.State = DrawItemState.Selected Then
textBrush = Brushes.White
Else
textBrush = Brushes.Black
End If
' draw a rectangle and fill it
Dim p As New Pen(aColor)
Dim br As New SolidBrush(aColor)
e.Graphics.DrawRectangle(p, rect)
e.Graphics.FillRectangle(br, rect)
' draw a border
rect.Inflate(1, 1)
e.Graphics.DrawRectangle(Pens.Black, rect)
' draw the Color name
e.Graphics.TextRenderingHint = Drawing.Text.TextRenderingHint.ClearTypeGridFit
e.Graphics.DrawString(aColor.Name, Me.Font, textBrush, rect.Width + 5, ((e.Bounds.Height - Me.Font.Height) \ 2) + e.Bounds.Top)
p.Dispose()
br.Dispose()
Catch ex As Exception
e.DrawBackground()
e.DrawFocusRectangle()
End Try
End Sub
Public Sub New()
' This call is required by the Windows Form Designer.
InitializeComponent()
Try
Dim aColorName As String
Me.BeginUpdate()
Items.Clear()
SelectedItem = Nothing
If myColors.Count = 0 Then
Dim names() As String = System.Enum.GetNames(GetType(System.Drawing.KnownColor))
For Each aColorName In names
If aColorName.StartsWith("Active") _
Or aColorName.StartsWith("Button") _
Or aColorName.StartsWith("Window") _
Or aColorName.StartsWith("Inactive") _
Or aColorName.StartsWith("HighlightText") _
Or aColorName.StartsWith("Control") _
Or aColorName.StartsWith("Scroll") _
Or aColorName.StartsWith("Menu") _
Or aColorName.StartsWith("Gradient") _
Or aColorName.StartsWith("App") _
Or aColorName.StartsWith("Desktop") _
Or aColorName.StartsWith("GrayText") _
Or aColorName.StartsWith("HotTrack") _
Or aColorName.StartsWith("Transparent") _
Or aColorName.StartsWith("Info") Then
Else
AddColor(Color.FromName(aColorName))
End If
Next
Else
Me.Items.AddRange(myColorsIndices.ToArray)
End If
Catch
Finally
Me.EndUpdate()
End Try
' Add any initialization after the InitializeComponent() call.
End Sub
Public Function AddColor(clr As Color) As Integer
myColors.Add(clr)
Dim idx As Integer = myColors.Count - 1
myColorsIndices.Add(idx)
Me.Items.Add(idx)
Return idx
End Function
''' <summary>
''' Returns a named color if one matches else it returns the passed color
''' </summary>
Public Function GetKnownColor(ByVal c As Color, Optional ByVal tolerance As Double = 0) As Color
For Each clr As Color In myColors
If ColorDistance(c, clr) <= tolerance Then
Return clr
End If
Next
Return c
End Function
''' <summary>
''' Returns index if one matches
''' </summary>
Public Function ContainsColor(ByVal c As Color) As Integer
Dim idx As Integer = 0
For Each clr As Color In myColors
If c.ToArgb = clr.ToArgb Then
Return idx
End If
idx += 1
Next
Return -1
End Function
Sub ColorCombo_SelectedIndexChanged(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.SelectedIndexChanged
If SelectedIndex >= 0 Then
mSelectedColor = myColors.Item(SelectedIndex)
End If
End Sub
Public Property SelectedColor() As Color
Get
'If mSelectedColor.Name = "Transparent" Then
' Return Color.Black
'End If
Return mSelectedColor
End Get
Set(ByVal value As Color)
Try
Dim smallestDist As Double = 255
Dim currentDist As Double = 0
Dim bestMatch As Integer = 0
Dim idx As Integer = -1
For Each c As Color In myColors
idx += 1
currentDist = ColorDistance(c, value)
If currentDist < smallestDist Then
smallestDist = currentDist
bestMatch = idx
End If
Next
If Me.Items.Count >= bestMatch Then
Me.SelectedIndex = bestMatch
End If
Catch ex As Exception
Debug.Print(ex.Message)
End Try
End Set
End Property
Private Function ColorDistance(ByRef clrA As Color, ByRef clrB As Color) As Double
Dim r As Long, g As Long, b As Long
r = CShort(clrA.R) - CShort(clrB.R)
g = CShort(clrA.G) - CShort(clrB.G)
b = CShort(clrA.B) - CShort(clrB.B)
Return Math.Sqrt(r * r + g * g + b * b)
End Function
End Class
Since you're adding the Color selection to the ComboBox.Items collection, the Form Designer serializes this this collection, adding all items to the Form.Designer.vb file. This also happens when you add Items a ComboBox using the Properties pane in the Designer: same effect.
You can instead set the DataSource of the ComboBox: it's faster and the object you add are not serialized. I also suggest not to add these values in the Control Constructor, but in the OnHandleCreated() override: the values are loaded only when the Control Handle is created, at run-time, so you don't load (not so useful) collections of items in the designer.
Since the handle can be recreated at run-time, more than once, there's a check for that (to avoid building the collection more than once).
Here, I'm using the ColorConverter's GetStandardValues() method to build a collection of known colors, excluding from the enumeration colors that have the IsSystemColor property set.
The collection is store in an array of Color objects, here named supportedColors.
You can also filter the collection returned by [Enum].GetValues() to get the same result, e.g.:
Dim colors As Color() = [Enum].GetValues(GetType(KnownColor)).OfType(Of KnownColor)().
Where(Function(kc) kc > 26 AndAlso kc < 168).
Select(function(kc) Color.FromKnownColor(kc)).ToArray()
SystemColors have Indexes < 27 and > 167 (I suggest not to rely on these values).
I've made a few changes to Custom Control:
When a Control is derived from an existing class, we don't subscribe to the events (e.g., DrawItem), we override the methods that rise the events (e.g., OnDrawItem()), then call base (MyBase) to rise the event (eventually, we can also not do that, if necessary). We are always one step ahead this way.
The drawing part needed some refactoring:
The Item's background actually was drawn 3 times
Disposable object should be declared with a Using statement, so we don't forget to dispose of them: very important when it comes to Graphics objects.
Replaced Graphics.DrawString() with TextRenderer.DrawText, to respect the original drawing.
Simplified the calculations: it's important to be as fast as possible here.
Thus also remove all Try/Catch blocks: costly and not really needed (don't use Try/Catch blocks when drawing, a few If conditions and some constraints - e.g., Math.Min(Math.Max()) - are better).
Also overridden OnMeasureItem() to change the height of the Items, set to Font.Height + 4 (pretty standard).
Other stuff you can see in the source code.
I've changed the SelectedColor custom property to be more reliable and to make it work with both OnSelectedIndexChanged() and OnSelectionChangeCommitted().
All Items represent a Color, so you can get the Color selected as, e.g.:
Private Sub ColorCombo1_SelectionChangeCommitted(sender As Object, e As EventArgs) Handles ColorCombo1.SelectionChangeCommitted
SomeControl.BackColor = DirectCast(ColorCombo1.SelectedItem, Color)
' Or
SomeControl.BackColor = ColorCombo1.SelectedColor
End Sub
Modified the ComboBox Custom Control:
Remove what you have in Public Sub New and InitializeComponent(), it's not needed anymore.
Imports System.Collections.Generic
Imports System.ComponentModel
Imports System.Drawing
Imports System.Windows.Forms
Public Class ColorCombo
Inherits ComboBox
Private mSelectedColor As Color = Color.Empty
Private supportedColors As Color() = Nothing
Public Sub New()
DropDownStyle = ComboBoxStyle.DropDownList
DrawMode = DrawMode.OwnerDrawVariable
FlatStyle = FlatStyle.Flat
FormattingEnabled = False
' Set these just to show that the background color is important here
ForeColor = Color.White
BackColor = Color.FromArgb(32, 32, 32)
End Sub
Protected Overrides Sub OnHandleCreated(e As EventArgs)
MyBase.OnHandleCreated(e)
If DesignMode OrElse Me.Items.Count > 0 Then Return
supportedColors = New ColorConverter().GetStandardValues().OfType(Of Color)().
Where(Function(c) Not c.IsSystemColor).ToArray()
' Preserves a previous selection if any
Dim tmpCurrentColor = mSelectedColor
Me.DisplayMember = "Name"
Me.DataSource = supportedColors
If Not tmpCurrentColor.Equals(Color.Empty) Then
mSelectedColor = tmpCurrentColor
SelectedColor = mSelectedColor
End If
End Sub
Private flags As TextFormatFlags = TextFormatFlags.NoPadding Or TextFormatFlags.VerticalCenter
Protected Overrides Sub OnDrawItem(e As DrawItemEventArgs)
e.DrawBackground()
If e.Index < 0 Then Return
Dim itemColor = supportedColors(e.Index)
Dim colorRect = New Rectangle(e.Bounds.X + 1, e.Bounds.Y + 1, e.Bounds.Height - 2, e.Bounds.Height - 2)
Using colorBrush As New SolidBrush(itemColor)
e.Graphics.FillRectangle(colorBrush, colorRect)
Dim textRect = New Rectangle(New Point(colorRect.Right + 6, e.Bounds.Y), e.Bounds.Size)
TextRenderer.DrawText(e.Graphics, itemColor.Name, e.Font, textRect, e.ForeColor, Color.Transparent, flags)
End Using
e.DrawFocusRectangle()
MyBase.OnDrawItem(e)
End Sub
Protected Overrides Sub OnMeasureItem(e As MeasureItemEventArgs)
e.ItemHeight = Font.Height + 4
MyBase.OnMeasureItem(e)
End Sub
Protected Overrides Sub OnSelectedIndexChanged(e As EventArgs)
If SelectedIndex >= 0 Then mSelectedColor = supportedColors(SelectedIndex)
MyBase.OnSelectedIndexChanged(e)
End Sub
Protected Overrides Sub OnSelectionChangeCommitted(e As EventArgs)
mSelectedColor = supportedColors(SelectedIndex)
MyBase.OnSelectionChangeCommitted(e)
End Sub
Public Property SelectedColor As Color
Get
Return mSelectedColor
End Get
Set
mSelectedColor = Value
If Not IsHandleCreated Then Return
If mSelectedColor.IsKnownColor Then
SelectedItem = mSelectedColor
Else
If supportedColors Is Nothing Then Return
Dim smallestDist As Double = 255
Dim currentDist As Double = 0
Dim bestMatch As Integer = 0
Dim idx As Integer = -1
For Each c As Color In supportedColors
idx += 1
currentDist = ColorDistance(c, Value)
If currentDist < smallestDist Then
smallestDist = currentDist
bestMatch = idx
End If
Next
If supportedColors.Count >= bestMatch Then
mSelectedColor = supportedColors(bestMatch)
SelectedItem = mSelectedColor
End If
End If
End Set
End Property
Private Function ColorDistance(clrA As Color, clrB As Color) As Double
Dim r As Integer = CInt(clrA.R) - clrB.R
Dim g As Integer = CInt(clrA.G) - clrB.G
Dim b As Integer = CInt(clrA.B) - clrB.B
Return Math.Sqrt(r * r + g * g + b * b)
End Function
Public Function GetKnownColor(c As Color, Optional ByVal tolerance As Double = 0) As Color
For Each clr As Color In supportedColors
If ColorDistance(c, clr) <= tolerance Then Return clr
Next
Return c
End Function
Public Function ContainsColor(c As Color) As Integer
Dim idx As Integer = 0
For Each clr As Color In Me.Items
If c.ToArgb = clr.ToArgb Then Return idx
idx += 1
Next
Return -1
End Function
End Class
This is how it works:
I have been banging my head against the wall trying to figure out how to make numbers not repeat from a specific list that I have created. Can someone please help? Once a number is chosen I dont want it to be chosen again. Seems like numbers.Remove(number) isnt working
Private Sub GetMoneyRand()
If randomLog.Count = numberList.Count Then
MsgBox("No more number for random")
Return
End If
For i As Integer = 1 To 100
Dim rndDummy As Integer = CInt(numMax.Value * Rnd())
lblRandomNumber.Text = rndDummy
Threading.Thread.Sleep(30)
Application.DoEvents()
Next
Randomize()
Dim r As New Random
Dim numbers As New List(Of Integer)
numbers.AddRange(New Integer() {1, 16, 31, 46, 61, 10, 15, 14, 75, 33, 11, 19, 25, 44, 50, 72, 2, 44, 20, 30})
Dim number As Integer = numbers(r.Next(0, numbers.Count))
For x As Integer = 1 To 20
numbers.Remove(number)
Next
randomLog.Add(number)
lblRandomNumber.Text = number
numberList(number).BackColor = Color.LightBlue
Please turn on Option Strict. This is a 2 part process. First for the current project - In Solution Explorer double click My Project. Choose Compile on the left. In the Option Strict drop-down select ON. Second for future projects - Go to the Tools Menu -> Options -> Projects and Solutions -> VB Defaults. In the Option Strict drop-down select ON. This will save you from bugs at runtime.
To create a list with unique random numbers use the .Contains method of List(of T) before adding the new random to the list.
Private numbers As New List(Of Integer) From {1, 16, 31, 46, 61, 10, 15, 14, 75, 33, 11, 19, 25, 44, 50, 72, 2, 44, 20, 30}
Private r As New Random
Private Sub AddRandomsToList()
Dim i = r.Next(0, 21)
If numbers.Contains(i) Then
MessageBox.Show("Sorry that number is already in the list. Try Again.")
Else
numbers.Add(i)
End If
End Sub
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
AddRandomsToList()
End Sub
To remove duplicates from an existing list use the .Distinct extension method. It will return a new list of unique elements when you call .ToList
Private numbers As New List(Of Integer) From {1, 16, 1, 46, 61, 16, 15, 14, 61, 46, 11, 19, 25, 46, 50, 50, 2, 44, 20, 30}
Private r As New Random
Private Sub RemoveDuplicate()
Dim UniqueNumbers = numbers.Distinct().ToList
For Each i In UniqueNumbers
Debug.Print(i.ToString)
Next
End Sub
You should be using a stack or a queue. They both remove items as they are used.
Private numbers As Integer() = {1, 16, 31, 46, 61, 10, 15, 14, 75, 33, 11, 19, 25, 44, 50, 72, 2, 44, 20, 30}
Private rng As New Random
Private Sub OutputNumbersInRandomOrder()
Dim randomisedNumbers As New Queue(Of Integer)(numbers.OrderBy(Function(n) rng.NextDouble()))
Do Until randomisedNumbers.Count = 0
Dim number = randomisedNumbers.Dequeue()
Console.WriteLine(number)
Loop
End Sub
Each time you call Dequeue, the first number is removed from the list and returned. You can do this as many times as you like, creating a new queue each time the previous one is empty, e.g.
Private numbers As Integer() = {1, 16, 31, 46, 61, 10, 15, 14, 75, 33, 11, 19, 25, 44, 50, 72, 2, 44, 20, 30}
Private randomisedNumbers As Queue(Of Integer)
Private rng As New Random
Private Function GetRandomNumber() As Integer
If randomisedNumbers Is Nothing OrElse randomisedNumbers.Count = 0 Then
randomisedNumbers = New Queue(Of Integer)(numbers.OrderBy(Function(n) rng.NextDouble()))
End If
Return randomisedNumbers.Dequeue()
End Function
You can do the same thing with a Stack(Of Integer) and calling Pop. The only difference is that a stack takes items from the other end - LIFO instead of FIFO. As the items are randomised and all added at the same time, there's really no difference in the outcome, especially given that calling OrderByDescending would reverse the outcomes of the two types anyway. To illustrate:
Dim numbers = {1, 2, 3, 4, 5}
Dim q1 As New Queue(Of Integer)(numbers)
Dim s1 As New Stack(Of Integer)(numbers)
Console.WriteLine("q1:")
Do Until q1.Count = 0
Console.WriteLine(q1.Dequeue())
Loop
Console.WriteLine("s1:")
Do Until s1.Count = 0
Console.WriteLine(s1.Pop())
Loop
Array.Reverse(numbers)
Dim q2 As New Queue(Of Integer)(numbers)
Dim s2 As New Stack(Of Integer)(numbers)
Console.WriteLine("q2:")
Do Until q2.Count = 0
Console.WriteLine(q2.Dequeue())
Loop
Console.WriteLine("s2:")
Do Until s2.Count = 0
Console.WriteLine(s2.Pop())
Loop
Output:
q1:
1
2
3
4
5
s1:
5
4
3
2
1
q2:
5
4
3
2
1
s2:
1
2
3
4
5
I'm having trouble aligning my four columns:
My string format for the titles works properly. When I read the next line and put it into a list, the String.Format takes the video name and creates the columns adjusting to the video names length. How can I fix this?
Private Sub pdPrint_PrintPage(sender As Object, e As Printing.PrintPageEventArgs) Handles pdPrint.PrintPage
e.Graphics.DrawString("Movie Collection", New Font("Courier", 20, FontStyle.Bold), Brushes.Black, 300, 10)
e.Graphics.DrawString(String.Format("{0, -20} {1,-20} {2, -20} {3,-20}", "VIDEO NAME", "YEAR PRODUCED", "RUNNING TIME", "RATING"), New Font("Courier", 12, FontStyle.Bold), Brushes.Black, 10, 70)
Using reader As New StreamReader("testing.txt")
Dim intVertPosition As Integer = 90
While Not reader.EndOfStream
Dim videoName As String = reader.ReadLine()
Dim yearProduced As String = reader.ReadLine()
Dim runningTime As String = reader.ReadLine()
Dim rating As String = reader.ReadLine()
Dim extraline As String = reader.ReadLine()
e.Graphics.DrawString(String.Format("{0, -30} {1,30} {2, 30} {3,30}", videoName.ToString(), yearProduced.ToString(), runningTime.ToString(), rating.ToString()), New Font("Courier", 12, FontStyle.Regular), Brushes.Black, 10, intVertPosition)
intVertPosition += 14
End While
End Using
End Sub
e.Graphics.DrawString(..., New Font("Courier", 20, FontStyle.Bold), ...)
This is where the problem started. This kind of formatting can only work correctly if the width a space is the same as the width of a letter. Or in other words, it requires a fixed-pitch font. But you can clearly tell from the screen-shot that you got a proportionally pitched font. So, roughly, the more text in the first column, the more it pushes out the next column.
This happened because you picked "Courier". It is the name of a legacy device font, useful only in programs that were written 27 years ago. Graphics.DrawString() requires a scalable font outline, a True-Type font to be specific, and cannot use device fonts. So the font mapper kicks in to provide an alternative, unfortunately it isn't smart enough to recognize that you wanted a fixed-pitch font.
Fix the problem by using "Courier New" instead.
i want to campare 2 arraylist and show the values ..
arraylist1 = {1,2,3,4,5,6,7,8,9}
arraylist2 = {2,4,5}
i have compare and the value to listview .. like this
1 Not available
2 available
3 Not available
4 available
5 available
6 Not available
i write the program like this but looping many times ..
For position As Integer = 0 To arraylist1.Count - 1
Dim words As String() = arraylist2(position).Split(New Char() {" "c})
arr(1) = words(3)
For i = 0 To arr.Length - 1
If arraylist1(i).Contains(arr(1)) Then
arr(0) = i
arr(2) = "working"
itm = New ListViewItem(arr)
lv1.Items.Add(itm)
Else
arr1(0) = i
arr1(1) = arrproc(i)
arr1(2) = "NOT working"
itm = New ListViewItem(arr1)
lv1.Items.Add(itm)
End If
Next
Next
as Tim was suggesting use List(Of Integer)
kind of like this
Dim list1 As New List(Of Integer) From {1, 2, 3, 4, 5, 6, 7, 8, 9}
Dim list2 As New List(Of Integer) From {2, 4, 5}
For Each i As Integer In list1
If list2.Contains(i) Then
Console.WriteLine(i & " available")
Else
Console.WriteLine(i & " Not available")
End If
Next
also in your code within the first loop, you use the index of arraylist1 in arraylist2 to get the words this will fail if both lists don't have the same amount of items and will run into an out of bounds exception
EDIT
So there are a few more problems to solve i guess
you loop over the arraylist1 to retrieve items from arraylist2
you use the forth word of that items and assign it to a random array (arr())
then you loop over that random array and compare the second item in
that array with all item from the arraylist1 at the indices of that
random array
so my suggestion is to review your code again
this might work but still some questions to answer
For Each item_list1 As String In arraylist2
Dim words As String() = item_list1.Split(New Char() {" "c})
If arraylist1.contains(words(3)) Then
itm = New ListViewItem(arraylist1.IndexOf(words(3)))
itm.SubItems.Add(words(3))
itm.SubItems.Add("working")
Else
itm = New ListViewItem(arraylist1.IndexOf(words(3)))
itm.SubItems.Add(arrproc(arraylist1.IndexOf(words(3))))
itm.SubItems.Add("NOT working")
End If
lv1.items.add(itm)
Next
You can use such linq query to compare those lists and return the appearance status of items of first list in seccond list:
Dim list1 = {1, 2, 3, 4, 5, 6, 7, 8, 9}
Dim list2 = {2, 4, 5}
Dim data = list1.Select(Function(item)
Return New With
{
.Value = item,
.Status = String.Format("{0} {1}", item, IIf(list2.Contains(item), "Available", "Not Available"))
}
End Function).ToList()
Then you can simply add them to ListView this way:
For Each item In data
Me.ListView1.Items.Add(item.Value.ToString()).SubItems.Add(item.Status)
Next
Full example
Sub Main()
Dim list1 As New List(Of Integer)() From {1, 2, 3, 4, 5, 6, 7, 8, 9}
Dim list2 As New List(Of Integer)() From {2, 4, 5}
Dim rows = From i In list1
Group Join j In list2
On j Equals i Into g = Group
From j In g.DefaultIfEmpty()
Select i, j
For Each r In rows
Console.WriteLine("{0} {1}", r.i, If(r.i = r.j, "exist", "not exist"))
Next
Console.ReadLine()
End Sub
This question is about this topic:
Vb.net all combinations
Question:
I use this code for my application but i've got a problem.
The chance exists that i have much items which has to be combinated.
But i just want to show the first 10 combinations/results.
What i want is the text to be completely unique.
so the example at my topic you see in the beginning of this question there's an ape cow deer ... example.
It doesn't matter here.
but if i got something like this:
1|2|3|4|5
6|7|8|9
3|2|1
0|9|8|7|6|5
( sometimes it's even bigger )
the first 10 results are:
1-6-3-0
1-6-3-9
1-6-3-8
1-6-3-7
1-6-3-6
1-6-3-5
1-6-2-0
1-6-2-9
1-6-2-8
1-6-2-7
but they are almost the same.
i want the first 10 results to be something like this then:
1-8-1-6
3-6-1-5
4-8-3-0
etc...
Is this possible??
Here is my solution that I converted from c# using http://www.developerfusion.com/tools/convert/csharp-to-vb/:
Dim numbers = New Integer()() { _
New Integer() {1, 2, 3, 4, 5}, _
New Integer() {6, 7, 8, 9}, _
New Integer() {3, 2, 1}, _
New Integer() {0, 9, 8, 7, 6, 5} _
}
Dim random = New Random()
Dim codes = New HashSet(Of String)()
Dim newCode As String
For resultNr As Integer = 0 To 9
' Try to generate random codes until a non exisiting one is found.
Do
Dim sb = New StringBuilder()
For i As Integer = 0 To 3
Dim r As Integer = random.[Next](numbers(i).Length)
sb.Append(numbers(i)(r)).Append("-")
Next
sb.Length -= 1
newCode = sb.ToString()
Loop While codes.Contains(newCode)
codes.Add(newCode)
Console.WriteLine(newCode)
Next
Console.ReadKey()