How to get Nth big item [duplicate] - sql

Question

This question already has answers here:
Finding Nth Minimum of a Varchar value in Oracle
(2 answers)
Closed 9 years ago.
I am getting 11th older person from users table with the following SQL statement
select MAX(age)
from ( select *
from (select *
from users
order by age asc)
where rownum <12)
is there a simplified and efficient query to get 11th older person with full information?
USING
Oracle 11G

Answer 1

WITH AgeOrderedPersons AS (
SELECT usr.*
,ROW_NUMBER() OVER (ORDER BY Age) AS Number
FROM Users usr
)
SELECT *
FROM AgeOrderedPersons
WHERE Number = 11
If you want all users with same age use DENSE_RANK() instead of ROW_NUMBER()

Answer 2

SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE users ( age, x ) AS
SELECT 20, 1 FROM DUAL
UNION ALL SELECT 80, 2 FROM DUAL
UNION ALL SELECT 47, 3 FROM DUAL
UNION ALL SELECT 33, 4 FROM DUAL
UNION ALL SELECT 24, 5 FROM DUAL
UNION ALL SELECT 7, 6 FROM DUAL
UNION ALL SELECT 102, 7 FROM DUAL
UNION ALL SELECT 99, 8 FROM DUAL
UNION ALL SELECT 90, 9 FROM DUAL
UNION ALL SELECT 28, 10 FROM DUAL
UNION ALL SELECT 46, 11 FROM DUAL
UNION ALL SELECT 54, 12 FROM DUAL
UNION ALL SELECT 67, 13 FROM DUAL
UNION ALL SELECT 17, 14 FROM DUAL
UNION ALL SELECT 34, 15 FROM DUAL
UNION ALL SELECT 32, 16 FROM DUAL
UNION ALL SELECT 39, 17 FROM DUAL
UNION ALL SELECT 26, 18 FROM DUAL
UNION ALL SELECT 15, 19 FROM DUAL
UNION ALL SELECT 12, 20 FROM DUAL;
Query 1:
SELECT DISTINCT
NTH_VALUE( age, 11 ) IGNORE NULLS OVER ( ORDER BY age ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING ) AS age,
NTH_VALUE( x, 11 ) IGNORE NULLS OVER ( ORDER BY age ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING ) AS x
FROM users
Results:
| AGE | X |
|-----|----|
| 34 | 15 |
Query 2:
Include an ordering clause in the statement with ROW_NUMBER():
WITH ranked AS (
SELECT u.*,
ROW_NUMBER() OVER ( ORDER BY age ) AS rn
FROM users u
ORDER BY age
)
SELECT age, x
FROM ranked
WHERE rn = 11
Results:
| AGE | X |
|-----|----|
| 34 | 15 |
Query 3:
WITH ordered AS (
SELECT *
FROM users
ORDER BY age
),
ranked AS (
SELECT o.*,
ROWNUM AS rn
FROM ordered o
WHERE ROWNUM <= 11
)
SELECT age, x
FROM ranked
WHERE rn = 11
Results:
| AGE | X |
|-----|----|
| 34 | 15 |