Doctrine inheritance mapping multiple entities on single table - oop

Question

I am doing a translate system (not based on the existing ones because of some constraints).
I've got one class/table Product with default language (french) the others are in another table.
A super class named TranslateProduct, it will be abstract, it depends on the solution I'll find.
There is a class EnProduct for english product, DeProduct for german etc.
These classes are mapped on a single table named translate_product.
In the translateProduct.orm.xml I have this for the inheritance :
<discriminator-column name="translate_type" type="string" />
<discriminator-map>
<discriminator-mapping value="en" class="EnProduct" />
<discriminator-mapping value="de" class="DeProduct" />
<discriminator-mapping value="nl" class="NlProduct" />
<discriminator-mapping value="it" class="ItProduct" />
<discriminator-mapping value="es" class="EsProduct" />
</discriminator-map>
So far it's ok but, the thing I want to do is that each translate of product is in a single row. for example :
I create an object :
$enProduct = new EnProduct();
$emProduct->setProductCode("123456");
$enProduct->setName("Door");
$em->persist($enProduct);
$em->flush();
In the database I'll have :
id | product_code | en_name
1 | 123456 | Door
I have mapped the variables name to column en_name and de_name
through the xml file
So now I want to get an object TranslateProduct with the Id = 1 and cast it to a DeProduct object the problem is the discriminator-column (translate_type) it is already set to enProduct and it's normally but how can I transform a single row in multiple objects of different types ?
I dont know if it was clear...

Answer 1

I found a solution. I don't know if my question was really clear...
So I wanted to get from for example this row :
You can see that this row is an EnProduct object, but I want also get a DeProduct from this same row.
I did the inheritance like in the Doctrine documentation said (still single_table)
And in every repository class I put this code :
public function findOneByPk($id){
$className = $this->getClassMetadata()->name;
$fields = $this->getClassMetadata()->fieldNames;
$rsm = new ResultSetMapping();
$rsm->addEntityResult($className, 'p');
$sql = "Select ";
foreach($fields as $column => $field){
$rsm->addFieldResult('p', $column, $field);
$sql .= "p.".$column. " as ".$field.", ";
}
$sql = trim($sql);
$sql = trim($sql,",");
$sql .= " FROM translate_product p";
$sql .= " WHERE p.id=".$id;
$query = $this->getEntityManager()->createNativeQuery($sql, $rsm);
return $query->getOneOrNullResult();
}
This will hydrate the right object.
Edit:
If using PostgreSQL database and using camelcase fields, you have to put double-quotes on the alias :
public function findOneByPk($id){
$className = $this->getClassMetadata()->name;
$fields = $this->getClassMetadata()->fieldNames;
$rsm = new ResultSetMapping();
$rsm->addEntityResult($className, 'p');
$sql = "Select ";
foreach($fields as $column => $field){
$rsm->addFieldResult('p', $column, $field);
$sql .= 'p.'.$column. ' as "'.$field.'", ';
}
$sql = trim($sql);
$sql = trim($sql,",");
$sql .= " FROM translate_product p";
$sql .= " WHERE p.id=".$id;
$query = $this->getEntityManager()->createNativeQuery($sql, $rsm);
return $query->getOneOrNullResult();
}