I've got the code below which displays the location_id and total number of antisocial crimes but I would like to get the location_name from a different table called location_dim be output as well. I tried to find a way to UNION it but couldn't get it to work. Any ideas?
SELECT fk5_location_id , COUNT(fk3_crime_id) as TOTAL_ANTISOCIAL_CRIMES
from CRIME_FACT
WHERE fk1_time_id = 3 AND fk3_crime_id = 1
GROUP BY fk5_location_id;
You want to use join to lookup the location name. The query would probably look like this:
SELECT ld.location_name, COUNT(cf.fk3_crime_id) as TOTAL_ANTISOCIAL_CRIMES
from CRIME_FACT cf join
LOCATION_DIM ld
on cf.fk5_location_id = ld.location_id
WHERE cf.fk1_time_id = 3 AND cf.fk3_crime_id = 1
GROUP BY ld.location_name;
You need to put in the right column names for ld.location_name and ld.location_id.
you need to find a relationship between the two tables to link a location to crime. that way you could use a "join" and select the fields from each table you are interested in.
I suggest taking a step back and reading up on the fundamentals of relational databases. There are many good books out there which is the perfect place to start.
Related
I am looking for a query that separate the data with the condition WHERE in the same output but in separates columns.
Example: I have the table Product_2:
I have two separates queries (to separate the products by Produt_Tag):
SELECT
Product_Mark AS "PIT-10_Product_Mark",
Product_Model AS "PIT-10_Product_Model"
FROM Product_2
WHERE Product_Tag = 'PIT-10';
SELECT
Product_Mark AS "PIT-11_Product_Mark",
Product_Model AS "PIT-11_Product_Model"
FROM Product_2
WHERE Product_Tag = 'PIT-11';
And I get this output:
But I need the output to be like this:
Can someone tell me how I need to modify my query to have the four columns in the same table/ output?
Thank you
I forgot to tell that in the data I Have the “Porduct_Mark” that only appears one time. (in reality the data in “Product_Mark” is the name of the place where the instrument is located and one place can have one or two instruments “Product_Model”. At the end I’m looking for the result show in the image here below. I tried to use LEFT JOIN but that don’t work.
here is the new table "Product_2"
Result that I'm looking for:
Luis Ardila
I am assuming Product_PK is the primary key for the table and the repeated value 1002 shown in the question is a mistake. Considering this assumption, you can get the result set using self join as below.
SELECT pa.Product_Mark AS "PIT-10_Product_Mark", pa.Product_Model AS "PIT-10_Product_Model",
pb.Product_Mark AS "PIT-11_Product_Mark", pb.Product_Model AS "PIT-11_Product_Model"
FROM Product_2 pa
INNER JOIN Product_2 pb
ON pa.Product_Mark = pb.Product_Mark
WHERE pa.product_pk != pb.product_pk
and pa.Product_Tag = 'PIT-10'
and pb.Product_Tag = 'PIT-11';
verified same in https://dbfiddle.uk/NiOO8zc1
What do I have to change to get different results from different names.The table should give me the debts of each of them, this is calculated by the amount and the price of the drink. Now it should show all the names with the corresponding invoice that happens after the select
%sql select name, sum(getraenk.preis*schulden.menge) schulden from schulden \
join person on (fk_person = person.id)\
join getraenk on (fk_getraenk = getraenk.id)\
where name like ("dani")
Edit: it should spend all the names with their debts, that is:
dani = 8.5
michael = 12.5
...
Just in case your problem is very simple, you should be able to see all names and values with an SQL that looks like this:
select name, getraenk.preis*schulden.menge schulden
from schulden
join person on (fk_person = person.id)
join getraenk on (fk_getraenk = getraenk.id)
Note that I removed the where clause... this was the part that limited it to one name.
You also don't need the sum clause here unless you are doing a group by
Have you considered simply using GROUP BY name at the end of this query?
https://www.w3schools.com/sql/sql_groupby.asp
This will give you the sum of total debt for all names in your table which sounds like the result you are looking for.
You're missing
GROUP BY name
in the query.
I pop into a problem recently, and Im sure its because of how I Join them.
this is my code:
select LP_Pending_Info.Service_Order,
LP_Pending_Info.Pending_Days,
LP_Pending_Info.Service_Type,
LP_Pending_Info.ASC_Code,
LP_Pending_Info.Model,
LP_Pending_Info.IN_OUT_WTY,
LP_Part_Codes.PartCode,
LP_PS_Codes.PS,
LP_Confirmation_Codes.SO_NO,
LP_Pending_Info.Engineer_Code
from LP_Pending_Info
join LP_Part_Codes
on LP_Pending_Info.Service_order = LP_Part_Codes.Service_order
join LP_PS_Codes
on LP_Pending_Info.Service_Order = LP_PS_Codes.Service_Order
join LP_Confirmation_Codes
on LP_Pending_Info.Service_Order = LP_Confirmation_Codes.Service_Order
order by LP_Pending_Info.Service_order, LP_Part_Codes.PartCode;
For every service order I have 5 part code maximum.
If the service order have only one value it show the result correctly but when it have more than one Part code the problem begin.
for example: this service order"4182134076" has only 2 part code, first'GH81-13601A' and second 'GH96-09938A' so it should show the data 2 time but it repeat it for 8 time. what seems to be the problem?
If your records were exactly the same the distinct keyword would have solved it.
However in rows 2 and 3 which have the same Service_Order and Part_Code if you check the SO_NO you see it is different - that is why distinct won't work here - the rows are not identical.
I say you have some problem in one of the conditions in your joins. The different data is in the SO_NO column so check the raw data in the LP_Confirmation_Codes table for that Service_Order:
select * from LP_Confirmation_Codes where Service_Order = 4182134076
I assume you are missing an and with the value from the LP_Part_Codes or LP_PS_Codes (but can't be sure without seeing those tables and data myself).
By this sentence If the service order have only one value it show the result correctly but when it have more than one Part code the problem begin. - probably you are missing and and with the LP_Part_Codes table
Based on your output result, here are the following data that caused multiple output.
Service Order: 4182134076 has :
2 PartCode which are GH81-13601A and GH96-09938A
2 PS which are U and P
2 SO_NO which are 1.00024e+09 and 1.00022e+09
Therefore 2^3 returns 8 rows. I believe that you need to check where you should join your tables.
Use DINTINCT
select distinct LP_Pending_Info.Service_Order,LP_Pending_Info.Pending_Days,
LP_Pending_Info.Service_Type,LP_Pending_Info.ASC_Code,LP_Pending_Info.Model,
LP_Pending_Info.IN_OUT_WTY, LP_Part_Codes.PartCode,LP_PS_Codes.PS,
LP_Confirmation_Codes.SO_NO,LP_Pending_Info.Engineer_Code
from LP_Pending_Info
join LP_Part_Codes on LP_Pending_Info.Service_order = LP_Part_Codes.Service_order
join LP_PS_Codes on LP_Part_Codes.Service_Order = LP_PS_Codes.Service_Order
join LP_Confirmation_Codes on LP_PS_Codes.Service_Order = LP_Confirmation_Codes.Service_Order
order by LP_Pending_Info.Service_order, LP_Part_Codes.PartCode;
distinct will not return duplicates based on your select. So if a row is same, it will only return once.
I have been given a database, the structure and data values are all unchangable and have been provided with a question.
Produce a query to list the holiday code, holiday description, holiday duration and site description for all holidays which visit site code 101. Your answer must not assume that site code 101 will always have the same site description.
I am confused on how to tackle this question. I have tried Multiple joins, different dot notation and googled the question to hell and back. Any help?
Table 1 - Holiday_Details
Holiday_Code - Country_Visited - Holiday_Duration - Holiday_Desc - Rating_Code - Cost
Table 2 - Site_Of_Holiday
Site_Description - Site_Code
Table 3 - Site_Visited
Holiday_Code - Site_Code
Comments have asked for previous attempts. This was my first.
SELECT holiday_code,
holiday_desc,
holiday_duration site_of_holiday.Site_Name
FROM holiday_details
JOIN site_visited
ON holiday_code = site_visited.holiday_code
JOIN site_of_holiday
ON site_visited.site_code = site_of_holiday.site_code
WHERE site_of_holiday.site_code = 101;
For future reference, you'll get a better response if you post a lot more detail about your failed attempts. By that, I mean code. Using SO to solve your homework assignments is frowned upon but, like a commenter said, once you've wracked your brain we're willing to help.
You seem like you may have actually tried real hard, so I'll throw you a bone...
The trick to navigating multiple tables is to find the "pairs" of matching columns. In this case you want to find a path between the tables Site_Of_Holiday (which has Site_Description) and Holiday_Details (which has everything else).
The columns that match between each pair of tables are:
Holiday_Code is found in both Site_Visited and Holiday_Details
Site_Code is found in both Site_Of_Holiday and Site_Visited
This allows you to build a path between the tables that contain all of the columns we want in the output. You would do this, in this case, using INNER JOINs across those matching column pairs.
Once you've joined the tables, think of the result like a giant table whose columns include all columns from all three tables (prefixed with whatever you 'name' the table during the joins). Now you just filter on the Site_Code with the usual WHERE clause.
Here's the full example - let me know if it works for you:
SELECT hd.Holiday_Code, hd.Holiday_Desc, hd.Holiday_Duration, soh.Site_Description
FROM Holiday_Details hd
INNER JOIN Site_Visited sv ON hd.Holiday_Code = sv.Holiday_Code
INNER JOIN Site_Of_Holiday soh ON sv.Site_Code = soh.Site_Code
WHERE sv.Site_Code = 101
Good luck!
P.S. In case any Americans get a similar assignment, here's the translation ;-)
SELECT vd.Vacation_Code, vd.Vacation_Desc, vd.Vacation_Duration, sov.Site_Description
FROM Vacation_Details vd
INNER JOIN Site_Visited sv ON vd.Vacation_Code = sv.Vacation_Code
INNER JOIN Site_Of_Vacation sov ON sv.Site_Code = sov.Site_Code
WHERE sv.Site_Code = 101
I have a PHP page running in postgres. I have 3 tables - workorders, wo_parts and part2vendor. I am trying to multiply 2 table column row datas together, ie wo_parts has a field called qty and part2vendor has a field called cost. These 2 are joined by wo_parts.pn and part2vendor.pn. I have created a query like this:
$scoreCostQuery = "SELECT SUM(part2vendor.cost*wo_parts.qty) as total_score
FROM part2vendor
INNER JOIN wo_parts
ON (wo_parts.pn=part2vendor.pn)
WHERE workorder=$workorder";
But if I add the costs of the parts multiplied by the qauntities supplied, it adds to a different number than what the script is doing. Help....I am new to this but if someone can show me in SQL I can modify it for postgres. Thanks
Without seeing example data, there's no way for us to know why you're query totals are coming out differently that when you do the math by hand. It could be a bad join, so you are getting more/less records than you expected. It's also possible that your calculations are off. Pick an example with the smallest number of associated records & compare.
My suggestion is to add a GROUP BY to the query:
SELECT SUM(p.cost * wp.qty) as total_score
FROM part2vendor p
JOIN wo_parts wp ON wp.pn = p.pn
WHERE workorder = $workorder
GROUP BY workorder
FYI: MySQL was designed to allow flexibility in the GROUP BY, while no other db I've used does - it's a source of numerous questions on SO "why does this work in MySQL when it doesn't work on db x...".
To Check that your Quantities are correct:
SELECT wp.qty,
p.cost
FROM WO_PARTS wp
JOIN PART2VENDOR p ON p.pn = wp.pn
WHERE p.workorder = $workorder
Check that the numbers are correct for a given order.
You could try a sub-query instead.
(Note, I don't have a Postgres installation to test this on so consider this more like pseudo code than a working example... It does work in MySQL tho)
SELECT
SUM(p.`score`) AS 'total_score'
FROM part2vendor AS p2v
INNER JOIN (
SELECT pn, cost * qty AS `score`
FROM wo_parts
) AS p
ON p.pn = p2v.pn
WHERE p2n.workorder=$workorder"
In the question, you say the cost column is in part2vendor, but in the query you reference wo_parts.cost. If the wo_parts table has its own cost column, that's the source of the problem.