When I display numbers as strings in scientific notation using tostring("E4"), the leading zeros are displayed so that the exponent is always three digits. How can I get rid of these leading zeros?
For example, I want this: "5.5E9", and not this: "5.5E+009".
Use a Custom Format string:
314159.ToString("#.###+E0")
Produces
3.142+E5
Related
I need a regular expression which can find a trail of "0" in the decimal space.
F.e. following format should be recognized:
1.0
1.00
1.000
etc...
Is there somekind of "wildcard" for that?
Any idea?
Thanks,
KS
Please see the following regular expression that matches trailing zeros on the end of any decimal. Note that this does match trailing zeros in the case where there is a meaningful decimal value, but zeros occur after.
https://regex101.com/r/BJvLrO/1/
When working with regex, it is very valuable to always use a tool like https://regex101.com or https://regexr.com. Both of these tools will help you truly understand the Regular Expression. Try hovering your mouse over the different elements of the regex in my example and the tool will describe each part. You can also read the "Explanation" section to on the right side.
when converting javascript floating point numbers to string format insignificant trailing decimal zeros are lost.
for an example
var num = 20.0;
altert(num);
will give output as 20
how can i stop removing insignificant decimal trailing zeros when formatted as string
Answer that was already given
Please take above reference
So, I made a program that for the most part, converts numbers to letters. My problem before was it was converting each individual digit instead of each number e.g. (1-0-1 instead of 101). Someone suggested that I use the Split function:
Dim numbers As String() = DTB.Split(" ")
So now it's reading the number all the way through being that it will only the split if there's a space in between. My problem now is that it's translating for example: "[102, 103, 104]" as "[102", "103" and "104]" because it will only split if there's a space between. Obviously, you can't convert "[102" or "104]" because they aren't actual numbers.
Does anyone have a solution on what I should do to get this to convert no matter the spacing? Would Regex be the way to go?
use a regular expression with \d+ it will match numbers
so
12234abcsdf23434
will return two matches
12234
23434
I have a string representing a number, and I want to convert it an NSInteger. The problem is, that the string is formatted with thousand separators:
"1,234"
when using [value intValue], I get 1 as the value.
Is it because it thinks the thousand separator is a decimal separator? (my locale uses comma as decimal separator and a space or a dot as thousand separator)
How can I ensure that I get the right number?
-Vegar
There's the NSNumberFormatter class which can not only encode numbers, but also decode them according to the current locale.
I would find a class that can decode numbers from strings just as Georg suggests, but a quick solution could also be to chop off the extra thousand separators using the stringByReplacing… method of the NSString class.
I need to pad numbers with leading zeros (total 8 digits) for display. I'm using oracle.
select to_char(1011,'00000000') OPE_NO from dual;
select length(to_char(1011,'00000000')) OPE_NO from dual;
Instead of '00001011' I get ' 00001011'.
Why do I get an extra leading blank space? What is the correct number formatting string to accomplish this?
P.S. I realise I can just use trim(), but I want to understand number formatting better.
#Eddie: I already read the documentation. And yet I still don't understand how to get rid of the leading whitespace.
#David: So does that mean there's no way but to use trim()?
Use FM (Fill Mode), e.g.
select to_char(1011,'FM00000000') OPE_NO from dual;
From that same documentation mentioned by EddieAwad:
Negative return values automatically
contain a leading negative sign and
positive values automatically contain
a leading space unless the format
model contains the MI, S, or PR format
element.
EDIT: The right way is to use the FM modifier, as answered by Steve Bosman. Read the section about Format Model Modifiers for more info.