I have a string representing a number, and I want to convert it an NSInteger. The problem is, that the string is formatted with thousand separators:
"1,234"
when using [value intValue], I get 1 as the value.
Is it because it thinks the thousand separator is a decimal separator? (my locale uses comma as decimal separator and a space or a dot as thousand separator)
How can I ensure that I get the right number?
-Vegar
There's the NSNumberFormatter class which can not only encode numbers, but also decode them according to the current locale.
I would find a class that can decode numbers from strings just as Georg suggests, but a quick solution could also be to chop off the extra thousand separators using the stringByReplacing… method of the NSString class.
Related
I would like to have ""apple"" as the element in the array as the output. The sad thing is it has to be in this kind of format.
But presto automatically added the escape character "/". (i.e "/"apple/"")
How do I get rid of it
Simply use two double quotes around the string apple ""apple""
I'm currently trying to read from a CSV files ( separated with semicolon ';') with decimal numbers formatted with a comma(,) as a decimal separator instead of a dot (.).
i.e: the number 12356.12 is stored as 12356,12.
In the source's projection, what would be the correct format to read the value correctly?
The format should in Java Decimal Format
If your CSV file's columnDelimiter is a comma (','), your first concern is how to avoid your number data won't be treated as different columns. Since your number data is stored as 12356,12, so my suggests as below :
Change the columnDelimiter as | or other special characters.
2.Set escape char. Please see this description:
In addition, 12356,12 can't be identified as Decimal format in ADF automatically. And no such mechanism o turn , into .. So I think you need to transfer data as string temporary. Then convert it into Decimal in your destination with java code.
True answer is in the comments: In the copy job the culture can be defined, which influences the decimal separator. Go to "mapping" > "Type conversion settings" > "culture" and chose en-us, de-de or whatever works for you. Be aware that this will also influence other types like dates.
When I display numbers as strings in scientific notation using tostring("E4"), the leading zeros are displayed so that the exponent is always three digits. How can I get rid of these leading zeros?
For example, I want this: "5.5E9", and not this: "5.5E+009".
Use a Custom Format string:
314159.ToString("#.###+E0")
Produces
3.142+E5
So, I made a program that for the most part, converts numbers to letters. My problem before was it was converting each individual digit instead of each number e.g. (1-0-1 instead of 101). Someone suggested that I use the Split function:
Dim numbers As String() = DTB.Split(" ")
So now it's reading the number all the way through being that it will only the split if there's a space in between. My problem now is that it's translating for example: "[102, 103, 104]" as "[102", "103" and "104]" because it will only split if there's a space between. Obviously, you can't convert "[102" or "104]" because they aren't actual numbers.
Does anyone have a solution on what I should do to get this to convert no matter the spacing? Would Regex be the way to go?
use a regular expression with \d+ it will match numbers
so
12234abcsdf23434
will return two matches
12234
23434
I would like a regular expression to find the %s in the source string that don't form the start of a valid two-hex-digit escaped character (defined as a % followed by exactly two hexadecimal digits, upper or lower case) that can be used to replace only these % symbols with %25.
(The motivation is to make the best guess attempt to create legally escaped strings from strings of various origins that may be legally percent escaped and may not, and may even be a mixture of the two, without damaging the data intent if the original string was already correctly encoded, e.g. by blanket re-encoding).
Here's an example input string.
He%20has%20a%2050%%20chance%20of%20living%2C%20but%20there%27s%20only%20a%2025%%20chance%20of%20that.
This doesn't conform to any encoding standard because it is a mix of valid escaped characters eg. %20 and two loose percentage symbols. I'd like to convert those %s to %25s.
My progress so far is to identify a regex %[0-9a-z]{2} that finds the % symbols that are legal but I can't work out how to modify it to find the ones that aren't legal.
%(?![0-9a-fA-F]{2})
Should do the trick. Use a look-ahead to find a % NOT followed by a valid two-digit hexadecimal value then replace the found % symbol with your %25 replacement.
(Hopefully this works with (presumably) NSRegularExpression, or whatever you're using)
%(?![a-fA-F0-9]{2})
That's a percent followed by a negative lookahead for two hex digits.