SQL to calculate time difference between two different rows and column - sql

Question

I have a table in SQL Server 2005 with two fields datetime, one is Start other End.
Example
select Start , End from launchings where id = 210423 order by 1 asc
My result is
2013-11-01 08:30:00.000 2013-11-01 12:00:00.000
2013-11-01 13:00:00.000 2013-11-01 19:00:00.000
2013-11-01 19:00:00.000 2013-11-01 20:00:00.000
2013-11-01 19:00:00.000 2013-11-01 20:00:00.000
2013-11-04 08:30:00.000 2013-11-04 12:00:00.000
2013-11-04 13:00:00.000 2013-11-04 19:30:00.000
I need get the first and the last time a day and the interval between them, which would for example lunchtime
Example
Day 04 - Result that I want
Day Start Start interval End interval End
2013-11-04 - 08:00 12:00 13:00 19:30
2013-11-01 - 08:30 12:00 13:00 20:00
Start and End I did. I need Interval
SELECT
convert(char(10), DATEADD(DAY, DATEDIFF(DAY, 0, Inicio), 0),103) AS Day,
MIN(convert(char(5),Inicio,108)) AS MinDate,
MAX(convert(char(5),Fim,108)) AS MaxDate
from Lancamentos where matricula = 210423
GROUP BY
DATEADD(DAY, DATEDIFF(DAY, 0, Inicio), 0)
Result
Day MinDate MaxDate
01/11/2013 08:30 20:00
04/11/2013 08:30 19:30

Answer 1

The key to solving this is to use ROW_NUMBER() to put your results in order by day:
WITH RankedData AS
( SELECT [Date] = CAST(Start AS DATE),
[Start],
[End],
RowNum = ROW_NUMBER() OVER(PARTITION BY ID, CAST(Start AS DATE) ORDER BY Start)
FROM Launchings
WHERE ID = 210423
)
SELECT Date,
[Start1] = MIN(CASE WHEN RowNum = 1 THEN Start END),
[End1] = MIN(CASE WHEN RowNum = 1 THEN [End] END)
[Start2] = MIN(CASE WHEN RowNum > 1 THEN Start END),
[End2] = MAX(CASE WHEN RowNum > 1 THEN [End] END)
FROM RankedData
GROUP BY Date;
EDIT
Sorry, missed the SQL-Server 2005 part of the question:
WITH RankedData AS
( SELECT [Date] = CAST(Start AS DATE),
[Start],
[End],
RowNum = ROW_NUMBER() OVER(PARTITION BY ID, DATEADD(DAY, DATEDIFF(DAY, 0, Start), 0) ORDER BY Start)
FROM Launchings
WHERE ID = 210423
)
SELECT Date,
[Start1] = MIN(CASE WHEN RowNum = 1 THEN Start END),
[End1] = MIN(CASE WHEN RowNum = 1 THEN [End] END)
[Start2] = MIN(CASE WHEN RowNum > 1 THEN Start END),
[End2] = MAX(CASE WHEN RowNum > 1 THEN [End] END)
FROM RankedData
GROUP BY Date;

Answer 2

--GarethD you still missed the SQL 2005 part of the question on the second line.
--But I think it's easy you should meant something like this:
--Didn't test it.`
WITH RankedData AS
( SELECT [Date] = DATEADD(DAY, DATEDIFF(DAY, 0, Start), 0),
[Start],
[End],
RowNum = ROW_NUMBER() OVER(PARTITION BY ID, DATEADD(DAY, DATEDIFF(DAY, 0, Start), 0) ORDER BY Start)
FROM Launchings
WHERE ID = 210423
)
SELECT Date,
[Start1] = MIN(CASE WHEN RowNum = 1 THEN Start END),
[End1] = MIN(CASE WHEN RowNum = 1 THEN [End] END)
[Start2] = MIN(CASE WHEN RowNum > 1 THEN Start END),
[End2] = MAX(CASE WHEN RowNum > 1 THEN [End] END)
FROM RankedData
GROUP BY Date;`