Doctrine query with ManyToMany relation - sql

I have a simple relation ManyToMany between two entities "article" and "category" (for a blog). I would like to fetch every article with a particular category, but I don't know how to create that query. What I did is :
$query = $em->createQuery(
'SELECT u
FROM SiteBlogBundle:article u
WHERE u.categorie.name = :cat
ORDER BY u.date DESC'
)
->setParameter('cat', '$cateogory')
The line WHERE u.categorie.name = :cat doesn't work. How can I achieve that?

If you are okay with using a query-builder for better readability instead of DQL:
$articles = $em
->getRepository('SiteBlogBundle:Article')
->createQueryBuilder('article')
->leftJoin('article.category', 'category')
->where('category.name = :category_name')
->orderBy('article.date', 'DESC')
->setParameter('category_name', $category->getName())
->getQuery()
->getResult()
;
But i would strongly advise you to put this query into the repository like this:
// ArticleRepository.php
public function findArticlesByCategoryName($name)
{
return $this->createQueryBuilder('article')
->leftJoin('article.category', 'category')
->where('category.name = :category_name')
->orderBy('article.date', 'DESC')
->setParameter('category_name', $name)
->getQuery()
->getResult()
;
}
Then inside your controller just do:
public function getArticles(Category $category)
{
$em = $this->getDoctrine()->getEntityManager();
return $em->
getRepository('SiteBlogBundle:Article')
->findArticlesByCategoryName($category->getName())
;
}

Related

Query giving double result instead of single

I have two tables: products and current_product_attribute_values
I have tried a join query to filter them as per attribute selected by the user but when I try this with an additional condition it gives me 2 results instead of one it is including the first one which is not matching as per query:
select * from `products` inner join `current_product_attribute_values` on `products`.`id` = `current_product_attribute_values`.`product_id` where `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `product_name` LIKE ?
here is my laravel Controller code :
$all = Input::all();
$q = Input::get('search_text');
$att_val = Input::get('attribute_value');
$subcat = Input::get('subcat_id');
$subcat_name = DB::table('subcategories')->where('id', $subcat)->value('subcategory_name');
$brandname = DB::table('brands')->where('subcat_id', $subcat)->value('brand_name');
$brand_id = DB::table('brands')->where('subcat_id', $subcat)->value('id');
$product_count = DB::table('products')->where('brand_id', $brand_id)->count();
if ($q != "") {
// getting multiple same name params
$query = DB::table('products');
$query->join('current_product_attribute_values', 'products.id', '=', 'current_product_attribute_values.product_id');
$j = 0;
foreach ($all as $key => $values) {
//echo 'my current get key is : ' . urldecode($key). '<br>';
if ($key == $name[$j]) {
$query->where('current_product_attribute_values.attribute_id', '=', $att_id_value[$j]);
echo'<br>';
print_r($query->toSql());
echo'<br>';
//echo '<br> key matched and have some value : <br>';
//echo count($values);
if (count($values) >= 1) {
//echo '<br> it has array inside <br>';
foreach ($values as $val) {
// or waali query in same attribute
echo'<br>';
$query->orwhere('current_product_attribute_values.attribute_value_id', '=', $val);
print_r($query->toSql());
echo'<br>';
}
}
$j++;
}
}
$records = $query->toSql();
$query->where('product_name', 'LIKE', '%' . $q . '%');
$records = $query->toSql();
print_r($records);
$products = $query->paginate(10)->setPath('');
$pagination = $products->appends(array(
'q' => Input::get('q')
));
if (count($products) > 0) {
$filters = DB::table('product_attributes')->where('subcategory_id', $subcat)->get(['attribute_title']);
} else {
$filters = array();
}
$categories = categories::where('add_to_menu', 1)->with('subcategories')->with('brands')->get();
$categoryhome = categories::where('add_to_menu', 1)->with('subcategories')->get();
return view('searchfilter')
->with('productsdata', $products)
->with('filtersdata', $filters)
->with('categories', $categories)
->with('categorieshome', $categoryhome)
->with('subcat_name', $subcat_name)
->with('subcat_id', $subcat)
->with('brandname', $brandname)
->with('product_count', $product_count)
->with('querytext', $q);
}
return 'No Details found. Try to search again !';
its easier if you use raw sql as calling db select function. ex:
$query=DB::select("select * from `products` inner join `current_product_attribute_values` on `products`.`id` = `current_product_attribute_values`.`product_id` where `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `current_product_attribute_values`.`attribute_id` = ? or `current_product_attribute_values`.`attribute_value_id` = ? and `product_name` LIKE ?
");
indeed you can concat vars in raw sql if you need to, ex:
$queryBrands = "select id from brands where subcat_id =".$subcat;
//echo $queryBrands
$queryBrands = DB::select($queryBrands);
By looking at your tables, product table with id value 17 has two records in table current_product_attribute_values in column product_id (I assume this column is used as foreign key to product table).
With select *, you select all of the columns from both tables. So it would most likely cause your query to return multiple records.
My suggestions:
Only select the columns you need. Avoid using select * in the long run, i.e. select product.id, product.description, current_product_attribute_values.attribute_values ......
Make use of GROUP BY
Hope these helps.

Doctrine QueryBuilder multiple distinct

I would like to restrict results with DISTINCT on two columns using doctrine ORM
My function is like this :
public function findFdvLinkedToPdv($pointVenteCodes){
$queryBuilder =
$this->createQueryBuilder('r')
->leftJoin('r.forceVente', 'forceVente')
->leftJoin('r.pointVente', 'pointVente')
->leftJoin('r.signature', 'signature')
->leftJoin('signature.affaire', 'affaire')
->andWhere('pointVente.code IN (:pointvente_codes)')
->orderBy('forceVente.matricule', 'ASC')
->addOrderBy('pointVente.code', 'ASC')
->addOrderBy('affaire.code', 'ASC')
->addOrderBy('r.type', 'ASC')
->setParameters(array('pointvente_codes' => $pointVenteCodes,))
->select(array(
'forceVente.matricule AS forcevente_matricule',
'pointVente.code AS pointvente_code',
'affaire.code AS affaire_code',
'r.id AS id',
'r.profil AS profil',
'r.type AS type',
'forceVente.nom AS nom',
'forceVente.prenom AS prenom',
'forceVente.email AS email',
'r.deletedAt AS deletedAt'));
return $queryBuilder->getQuery()->getArrayResult();
}
For each forcevente.matricule and each pointVente.code , I have from 2 to 6 rows. I would like to get one row for each couple forcevente.matricule/pointVente.code I have to do a distinct on both columns, but when I try :
->select(array(
'DISTINCT forceVente.matricule AS forcevente_matricule',
'DISTINCT pointVente.code AS pointvente_code',
'affaire.code AS affaire_code', etc ...
I have a doctrine error ...
[EDIT]
I do this in PHP after executing the request to filter the results...
//BEGIN PATCH
$i=0;
$linkedForceVentes2 = array();
foreach ($linkedForceVentes as $item) {
if (!isset($linkedForceVentes2[$item['pointvente_code']][$item['forcevente_matricule']])){
$linkedForceVentes2[$item['pointvente_code']][$item['forcevente_matricule']] = $item;
}else{
unset($linkedForceVentes[$i]);
}
$i++;
}
//END PATCH
I finaly resolved it with a groupBy :
->groupBy('forcevente_matricule', 'pointvente_code', 'type' , 'affaire_code');
Just after the select statement.

Select sql code in Laravel

Following query returning six values
SELECT tbl_start FROM timetable inner join route ON tbl_rte_id = id WHERE rte_origin = "UL" and rte_destination = "HW" ORDER BY(tbl_start) DESC;
And my laravel code is returning only one value
$tables = Timetable::join('route', 'tbl_rte_id', '=', 'id')
->where('rte_origin', $origin, 'AND')
->where('rte_destination', $destination)
->orderBy('tbl_start', 'desc')
->get();
foreach ($tables as $table) {
$result[$table->id] = $table->tbl_start;
}
This laravel code is not similar or similar. Can anyone help me.
Change this part:
->where('rte_origin', $origin, 'AND')
// to:
->where('rte_origin', $origin)
It will know by default that it's AND operator
And if you want to provide this operator, then do this:
->where('rte_origin', '=', $origin, 'AND')
You may try something like this:
$tables = Timetable::join('route', 'tbl_rte_id', '=', 'timetable.id')
->where('rte_origin', $origin)
->where('rte_destination', $destination)
->orderBy('tbl_start', 'desc')
->get()->lists('tbl_start', 'id');
The $tables will contain an array of id => tbl_start pairs.
Add a listener in your routes.php
Event::listen('illuminate.query', function($sql){
var_dump($sql);
});
Then execute both queries and check if you have the same result

$data = $query->row(); returns only one row

Im trying to list the results of my sql query (picking up all the movies from a category), but I cannot figure out how to get all the rows instead of only one.
Here's the code :
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->row();
$this->response($data, 200);
I've tried :
while($row = mysql_fetch_assoc($query)){
$data = $query->row();
}
$this->response($data, 200);
And it doesn't work. Any suggestion ? Thank you !
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->result();
To traverse the $data array:
foreach($data AS $row)
{
//to retrieve the data from each row.
$col1 = $row->col1;
$col2 = $row->col2;
}
Use result() instead of row(). result() will return an array of objects that are your results. Alternatively, you can useresult_array() which will resturn an array of arrays keyed according to your columns. Please refer to here for a better outline of the result() and row() methods.
Do you have a database configuration file? the load->database() requires it. Where is $movies_category coming from? This will let you iterate over your results.
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
foreach ($query->result() as $row)
{
echo $row->column;
}
Where column corresponds with one of the values in the movies table.
I'm surprised nobody has mentioned the potential hazards of using variables (possibly user input) in your SQL. You should seriously consider using query bindings or the active record features of CodeIgniter to build safer queries.
Consider the following solution to your problem:
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = ?';
$query = $this->db->query($sql, array($movies_category));
// $data = $query->result(); // returns result as an array of objects
$data = $query->result_array(); // returns result as array
$this->response($data, 200);
I'm assuming this is for some sort of API? If so, consider using the result_array() method as it will probably be better suited for your needed output, and also really easy to convert into JSON:
$json_data = json_encode($data);
Hope that helps,
Cheers.
For your question row() return only one value its good for checking in ID and if you want get all the rows use result_array() or simple result()
You can try this code....
Model:
function get_movies($movies_category){
$this->db->where("category",$movies_category);
$query = $this->db->get("movies");
return $query->result_array();
}
Controller:
$this->data['movies'] = $this->'name of model'->get_movies('here is the movie categories');
View:
foreach($movies as $m){
print_r($m);
}
exit();
Note you can directly add the code in function in model to controller add this in your controller if you want directly...
$this->data['movies] = $this->db->get('movies')->result_array();

How to get particular column in zend using Left join

I am new to zend framework,
Following is the plain mysql query which takes particular column from table,
SELECT jobs_users.id,jobs_users.first_name from jobs_users left join friends on jobs_users.id=friends.friend_id where friends.member_id=29
I tried with zend to implement the above query like below,
public function getFriendsProfileList($id){
$db = Zend_Db_Table::getDefaultAdapter();
$select = $db->select();
$select->from('jobs_users')
->joinLeft(
'friends',
'jobs_users.id=friends.friend_id',
array('jobs_users.id','jobs_users.first_name','jobs_users.last_name','jobs_users.photo')
)
->where("friends.member_id = ?", $id);
$result = $db->fetchAll($select);
return $result;
}
Here i got result with all column name , not with exact column name which i have given in query.
Kindly help me on this.
Use this instead:
$select->from('jobs_users', array('jobs_users.id','jobs_users.first_name','jobs_users.last_name','jobs_users.photo'))
->joinLeft('friends', 'jobs_users.id=friends.friend_id')
->where("friends.member_id = ?", '20');
You may also try this:
$select = $db->select();
$select->setIntegrityCheck(false);
$select->joinLeft('jobs_users','',array('jobs_users.id','jobs_users.first_name','jobs_users.last_name','jobs_users.photo'));
$select->joinLeft('friends','jobs_users.id=friends.friend_id', array());
$select->where("friends.member_id = ?", $id);
$result = $db->fetchAll($select);
return $result;