I'm trying to get latest inserted id from a table using this code:
$id = $tbl->fetchAll (array('public=1'), 'id desc');
but it's always returning "1"
any ideas?
update: I've just discovered toArray();, which retrieves all the data from fetchAll. The problem is, I only need the ID. My current code looks like this:
$rowsetArray = $id->toArray();
$rowCount = 1;
foreach ($rowsetArray as $rowArray) {
foreach ($rowArray as $column => $value) {
if ($column="id") {$myid[$brr] = $value;}
//echo"\n$myid[$brr]";
}
++$rowCount;
++$brr;
}
Obviously, I've got the if ($column="id") {$myid[$brr] = $value;} thing wrong.
Can anyone point me in the right direction?
An aternative would be to filter ID's from fetchAll. Is that possible?
Think you can use:
$id = $tbl->lastInsertId();
Aren't you trying to get last INSERT id from SELECT query?
Use lastInsertId() or the value returned by insert: $id = $db->insert();
Why are you using fetchAll() to retrieve the last inserted ID? fetchAll() will return a rowset of results (multiple records) as an object (not an array, but can be converted into an array using the toArray() method). However, if you are trying to reuse a rowset you already have, and you know the last record is the first record in the rowset, you can do this:
$select = $table->select()
->where('public = 1')
->order('id DESC');
$rows = $table->fetchAll($select);
$firstRow = $rows->current();
$lastId = $firstRow->id;
If you were to use fetchRow(), it would return a single row, so you wouldn't have to call current() on the result:
$select = $table->select()
->where('public = 1')
->order('id DESC');
$row = $table->fetchRow($select);
$lastId = $row->id;
It sounds like it's returning true rather than the actual value. Check the return value for the function fetchAll
Related
I have two tables in one database, table one called: ci_admin, and table two called active_ingredient.
I want to get user data from the active_ingredient table where user_id equals admin_id from ci_admin table using the current user session.
this code, get data for all user, I need the data inserted by the user only:
$wh =array();
$SQL ='SELECT * FROM active_ingredient';
$wh[] = "SELECT 1
FROM ci_admin
WHERE ci_admin.admin_id = active_ingredient.user_id";
if(count($wh)>0)
{ $WHERE = implode(' and ',$wh);
return $this->datatable->LoadJson($SQL,$WHERE);
}
else
{
return $this->datatable->LoadJson($SQL);
}
Try this, it will help you.
$this->db->select('ai.*,ca.*');
$this->db->from('active_ingredient ai');
$this->db->join('ci_admin ca', 'ca.admin_id = ai.user_id', 'left');
$this->db->where($data); //pass the session data for exact filter
$query = $this->db->get();
return $query->result();
Im trying to list the results of my sql query (picking up all the movies from a category), but I cannot figure out how to get all the rows instead of only one.
Here's the code :
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->row();
$this->response($data, 200);
I've tried :
while($row = mysql_fetch_assoc($query)){
$data = $query->row();
}
$this->response($data, 200);
And it doesn't work. Any suggestion ? Thank you !
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
$data = $query->result();
To traverse the $data array:
foreach($data AS $row)
{
//to retrieve the data from each row.
$col1 = $row->col1;
$col2 = $row->col2;
}
Use result() instead of row(). result() will return an array of objects that are your results. Alternatively, you can useresult_array() which will resturn an array of arrays keyed according to your columns. Please refer to here for a better outline of the result() and row() methods.
Do you have a database configuration file? the load->database() requires it. Where is $movies_category coming from? This will let you iterate over your results.
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = "'.$movies_category.'";';
$query = $this->db->query($sql);
foreach ($query->result() as $row)
{
echo $row->column;
}
Where column corresponds with one of the values in the movies table.
I'm surprised nobody has mentioned the potential hazards of using variables (possibly user input) in your SQL. You should seriously consider using query bindings or the active record features of CodeIgniter to build safer queries.
Consider the following solution to your problem:
$this->load->database();
$sql = 'SELECT * FROM movies WHERE category = ?';
$query = $this->db->query($sql, array($movies_category));
// $data = $query->result(); // returns result as an array of objects
$data = $query->result_array(); // returns result as array
$this->response($data, 200);
I'm assuming this is for some sort of API? If so, consider using the result_array() method as it will probably be better suited for your needed output, and also really easy to convert into JSON:
$json_data = json_encode($data);
Hope that helps,
Cheers.
For your question row() return only one value its good for checking in ID and if you want get all the rows use result_array() or simple result()
You can try this code....
Model:
function get_movies($movies_category){
$this->db->where("category",$movies_category);
$query = $this->db->get("movies");
return $query->result_array();
}
Controller:
$this->data['movies'] = $this->'name of model'->get_movies('here is the movie categories');
View:
foreach($movies as $m){
print_r($m);
}
exit();
Note you can directly add the code in function in model to controller add this in your controller if you want directly...
$this->data['movies] = $this->db->get('movies')->result_array();
In my controller
$agent = University::model()->findByPK($university_id);
I hope it will return value of a row of value.
I want a single attribute(field3) value say university_name, (with out using findByPK), how to get it
SELECT field3 FROM table [WHERE Clause]
Try this
$usercriteria = new CDbCriteria();
$usercriteria->select = "university_name";
$usercriteria->condition = "university_id=$university_id";
$university = University::model()->findAll($usercriteria);
echo $university->university_name;
Or simply do like u did first
$agent = University::model()->findByPK($university_id);
echo $agent-> university_name;
$agent = University::model()->findByPK($university_id);
echo $agent->university_name;
It should be like this:
$agent = University::model()->findByPK($university_id)->university_name;
Try this:
$university_name = University::model()->findByPK($university_id, array('select'=>'univeersity_name'))->university_name;
#Query: SElECT university_name FROM table_name where id=x;
Instead of
$university_name = University::model()->findByPK($university_id)->university_name;
#Query: SElECT * FROM table_name where id=x;
Second query returns all the fields. So better to avoid those fields are not necessary.
in case if you need to view on the yii _views, i have implemented this on my project
i put this inside my '_view.php' at /protected/views/myTable/
$agent = University::model()->findByPK($data->id_university/*this is the PK field name*/);
echo $agent->university_name /*university field name*/;
sorry again for my bad english :o
It can be done like this:
$agent = University::model()->findAllByAttributes(array('field3'),"WHERE `id` = :id", array(':id' => $university_id));
First argument of findByAttributes is an array of attributes you wish it to return. If left empty it returns all (*).
I have a codeigniter app.
My active record syntax works perfectly and is:
function get_as_09($q){
$this->db->select('m3');
$this->db->where('ProductCode', $q);
$query = $this->db->get('ProductList');
if($query->num_rows > 0){
foreach ($query->result_array() as $row){
$row_set[] = htmlentities(stripslashes($row['m3'])); //build an array
}
return $row_set;
}
}
This is effectively
select 'm3' from 'ProductList' where ProductCode='$1'
What I need to do is convert the below query into an active record type query and return it to the controller as per above active record syntax:
select length from
(SELECT
[Length]
,CONCAT(([width]*1000),([thickness]*1000),REPLACE([ProductCode],concat(([width]*1000),([thickness]*1000),REPLACE((convert(varchar,convert(decimal(8,1),length))),'.','')),'')) as options
FROM [dbo].[dbo].[ProductList]) as p
where options='25100cr' order by length
I picture something like below but this does not work.
$this->db->select(length);
$this->db->from(SELECT [Length],CONCAT(([width]*1000),([thickness]*1000),REPLACE[ProductCode],concat(([width]*1000),([thickness]*1000),REPLACE((convert(varchar,convert(decimal(8,1),length))),'.','')),'')) as options
FROM [dbo].[dbo].[ProductList]);
$this->db->where(options, $q);
$this->db->order(length, desc);
Help appreciated as always. Thanks again.
You can use sub query way of codeigniter to do this for this purpose you will have to hack codeigniter. like this
Go to system/database/DB_active_rec.php Remove public or protected keyword from these functions
public function _compile_select($select_override = FALSE)
public function _reset_select()
Now subquery writing in available And now here is your query with active record
$select = array(
'Length'
'CONCAT(([width]*1000)',
'thickness * 1000',
'REPLACE(ProductCode, concat((width*1000),(thickness*1000),REPLACE((convert(varchar,convert(decimal(8,1),length))),'.','')),'')) as options'
);
$this->db->select($select);
$this->db->from('ProductList');
$Subquery = $this->db->_compile_select();
$this->db->_reset_select();
$this->db->select('length');
$this->db->from("($Subquery)");
$this->db->where('options','25100cr');
$this->db->order_by('length');
And the thing is done. Cheers!!!
Note : While using sub queries you must use
$this->db->from('myTable')
instead of
$this->db->get('myTable')
which runs the query.
Source
I am using codeIgniter..
I want to update a table column is_close when id=$ticket_id of my table= tbl_tickets.
I am doing this :-
$data=array(
'is_close'=>1
);
$this->db->where('id',$title_id);
$this->db->update('tbl_tickets',$data);
and I have also done this :-
$sql = "UPDATE tbl_tickets SET is_close={1} WHERE id='$title_id'";
$this->db->query($sql);
both are not working,i.e., my table is not updating the value to 1 and also no error is being shown in the broswer. :(
Edited: Included my model part :
function setClosePost($title_id){
$sql = "UPDATE tbl_tickets SET is_close=0 WHERE id='$title_id'";
$this->db->query($sql);
// $data=array(
// 'is_close'=>1
// );
// $this->db->where('id',$title_id);
// $this->db->update('tbl_tickets',$data);
}
My controller :-
function closePost(){
$this->load->model('helpdesk_model');
$this->helpdesk_model->setClosePost($this->input->post('title_id'));
}
first of all use a get method to check if ticket_id is exist or not.
another thing is always use return in your functions in models so you can check them by if(function_name){...}else{...}
then if your get method returned data correctly try
Model Method
public function set_closed($ticket_id){
$this->db->set(array(
'is_close'=>1
)); // pass fields in array
$this->db->where('id',$ticket_id);
$this->db->update('tbl_tickets'); // table name
return true;
}
then check that in your controller
if($this->Ticket_model->set_closed($ticket_id) == true){
echo 'ticket set to closed correctly';
}else{
echo 'there is some error on updating database'.$this->db->error(); // to checkout db error .
}
First, check $title_id before passing:
var_dump($title_id);
Then, try do "select a row with this id" before updating and after.
$query = $this->db->get_where('tbl_tickets', array('id' => $id));
foreach ($query->result() as $row)
{
var_dump($row->is_close);
}
$data=array(
'is_close'=>1
);
$this->db->where('id',$title_id);
$this->db->update('tbl_tickets',$data);
$query = $this->db->get_where('tbl_tickets', array('id' => $id));
foreach ($query->result() as $row)
{
var_dump($row->is_close);
}
Then, give your table structure.
Just try like this
$sql = "UPDATE tbl_tickets SET is_close='1' WHERE id=".$title_id;
$this->db->query($sql);
just try like this
**function edit($close,$id) {
$sql = "UPDATE tbl_tickets SET is_close= ? WHERE id = ? ";
$this->db->query($sql, array($close,$id));
}**
To handle this type of errors, i mean if reflection is not happen in database, then use below steps to resolve this type of error.
1) use $this->db->last_query() function to print query, using this we can make sure our variable have correct value (should not null or undefined), using that we can make sure also SQL query is valid or not.
2) If SQL query is valid then open phpmyadmin & fire same query into phpmyadmin, it will return error if query columns or table names are invalid.
Use this way, its best way to cross check our SQL queries issues.
I hope it will work.
Thanks
You are trying to update integer(INT) type value, just cross check with your column datatype if that is varchar then you have to put value in a single or double quote.
Like this
$data=array('is_close'=> '1');