How to generate random alphabet (vowels only) - vb.net

My Current Code
Public Class Form1
Dim randomObject As New Random()
Dim alphaRand As Integer = randomObject.Next(65, 91)
Dim alpha As String = Me.textAlphabet.Text.ToUpper
Dim asciicode As Integer = Asc(alpha)
If asciicode = alphaRand Then
Me.lblAlphaResult.Text = "Congratulation! Your guess: " & textAlphabet.Text & " is correct,you win"
Me.cmdAlphaNewGame.Enabled = True
Me.cmdAlphaGuess.Enabled = False
ElseIf asciicode < alphaRand Then
Me.lblAlphaResult.Text = "You guess is too low.Try again"
ElseIf asciicode > alphaRand Then
Me.lblAlphaResult.Text = "Your guess is too high.Try again"
End If
End Sub
End Class
*randomObject.Next(65, 91) ' which means it take generate random alpha to A-Z only according to asciicode , what about only vowels ?*
Can i use something like array
Dim vowels As String() = {"A", "E", "I", "O", "U"}
then generate the random alphabet from my string
for me to guess later

You can do something like
Dim vowels As String() = {"A","E","I","O","U"}
Dim i As Int32 = randomObject.Next (0, 5)
Return vowels(i)

or just use a string
Dim randomObject As New Random
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim vowels As String = "AEIOU"
Dim vowelpicked As String
vowelpicked = vowels.Substring(randomObject.Next(vowels.Length), 1)
Debug.Write(vowelpicked)
End Sub

Related

How to set the decimal places to auto according user entries in VB.NET?

I have textbox receives number by the user.
the problem is that I want to format this textbox to show the numbers as the next face:
15000.25 >> 15,000.25
I used FormatNumber Function:
dim x as double
x = FormatNumber(textbox1.text,2)
textbox1.text = x
but here the problem is I want to keep the decimal places as entered by the user, examples:
15000.225 >> 15,000.225 NOT 15,000.22
0.00083 >> 0.00083 NOT 0
I hope my problem is clear.
I found the next solution:
Dim xStr As String = CStr(Me.Text)
Dim xCount As Integer = Len(Split(xStr, ".")(1))
Me.textbox1.Text = FormatNumber(Me.Text, xCount)
it's working for me.
thanks
Try this out:
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim dbl As Double
If Double.Parse(TextBox1.Text, dbl) Then
Dim parts() As String = dbl.ToString.Split(".")
Dim strDecimalPattern As String = ""
If parts.Length = 2 Then
strDecimalPattern = New String("#", parts(1).Length)
End If
Dim strPattern As String = "{0:#,##0" &
If(strDecimalPattern <> "", ".", "") &
strDecimalPattern & "}"
TextBox1.Text = String.Format(strPattern, dbl)
End If
End Sub

I want to make a maths quiz on vb.net that uses bracket questions

So I've used visual basics (vb.net) for a bit now and understand some stuff. Right now I want to make a maths quiz that when I click a button it takes me to a new form and starts the quiz. When the quiz starts I want it so it gives the user random numbers and the user needs to answer it in a textbox and if correct it moves on to the next question (Basic, I should be able to do). IMPORTANT - my question is, there's a maths rule called BODMAS (Bracket.Order.Division.Multiply.Add.Subtract) and I want to add this rule into my coding instead of doing regular simple maths...
EXAMPLE question is 2 x (2+3) - 1 = ?
2 x 5 - 1 = ?
10 - 1 = ?
9 = 9
person writes answer to textbox and moves to next similar question
This is my first time using this but I wanted to write in-depth so people can understand. Please help me if you find a video explaining what I'm looking for or if someone has a file with a similar code I could download would be greatly appreciated!
Basically,you need to determine the range of numbers you use, and then match them randomly among '*', '/', '+', '-'. Then randomly insert brackets into it.
Private codeStr As String
Private Function GenerateMathsQuiz() As String
Dim r As Random = New Random()
Dim builder As StringBuilder = New StringBuilder()
'The maximum number of operations is five, and you can increase the number [5] to increase the difficulty
Dim numOfOperand As Integer = r.[Next](1, 5)
Dim numofBrackets As Integer = r.[Next](0, 2)
Dim randomNumber As Integer
For i As Integer = 0 To numOfOperand - 1
'All numbers will be random between 1 and 10
randomNumber = r.[Next](1, 10)
builder.Append(randomNumber)
Dim randomOperand As Integer = r.[Next](1, 4)
Dim operand As String = Nothing
Select Case randomOperand
Case 1
operand = "+"
Case 2
operand = "-"
Case 3
operand = "*"
Case 4
operand = "/"
End Select
builder.Append(operand)
Next
randomNumber = r.[Next](1, 10)
builder.Append(randomNumber)
If numofBrackets = 1 Then
codeStr = InsertBrackets(builder.ToString())
Else
codeStr = builder.ToString()
End If
Return codeStr
End Function
Public Function InsertBrackets(ByVal source As String) As String
Dim rx As Regex = New Regex("\d+", RegexOptions.Compiled Or RegexOptions.IgnoreCase)
Dim matches As MatchCollection = rx.Matches(source)
Dim count As Integer = matches.Count
Dim r As Random = New Random()
Dim numIndexFirst As Integer = r.[Next](0, count - 2)
Dim numIndexLast As Integer = r.[Next](1, count - 1)
While numIndexFirst >= numIndexLast
numIndexLast = r.[Next](1, count - 1)
End While
Dim result As String = source.Insert(matches(numIndexFirst).Index, "(")
result = result.Insert(matches(numIndexLast).Index + matches(numIndexLast).Length + 1, ")")
Return result
End Function
When you finish this, you will get a math quiz, then you need to know how to compile and run code at runtime.
Private Function GetResult(ByVal str As String) As String
Dim sb As StringBuilder = New StringBuilder("")
sb.Append("Namespace calculator" & vbCrLf)
sb.Append("Class calculate " & vbCrLf)
sb.Append("Public Function Main() As Integer " & vbCrLf)
sb.Append("Return " & str & vbCrLf)
sb.Append("End Function " & vbCrLf)
sb.Append("End Class " & vbCrLf)
sb.Append("End Namespace" & vbCrLf)
Dim CompilerParams As CompilerParameters = New CompilerParameters()
CompilerParams.GenerateInMemory = True
CompilerParams.TreatWarningsAsErrors = False
CompilerParams.GenerateExecutable = False
CompilerParams.CompilerOptions = "/optimize"
Dim references As String() = {"System.dll"}
CompilerParams.ReferencedAssemblies.AddRange(references)
Dim provider As VBCodeProvider = New VBCodeProvider()
Dim compile As CompilerResults = provider.CompileAssemblyFromSource(CompilerParams, sb.ToString())
If compile.Errors.HasErrors Then
Dim text As String = "Compile error: "
For Each ce As CompilerError In compile.Errors
text += "rn" & ce.ToString()
Next
Throw New Exception(text)
End If
Dim Instance = compile.CompiledAssembly.CreateInstance("calculator.calculate")
Dim type = Instance.GetType
Dim methodInfo = type.GetMethod("Main")
Return methodInfo.Invoke(Instance, Nothing).ToString()
End Function
Finally, you can use these methods like:
Private Sub GetMathQuizBtn_Click(sender As Object, e As EventArgs) Handles GetMathQuizBtn.Click
Label1.Text = GenerateMathsQuiz()
End Sub
Private Sub ResultBtn_Click(sender As Object, e As EventArgs) Handles ResultBtn.Click
If TextBox1.Text = GetResult(Label1.Text) Then
MessageBox.Show("bingo!")
TextBox1.Text = ""
Label1.Text = GenerateMathsQuiz()
Else
MessageBox.Show("result is wrong")
End If
End Sub
Result:

Repeat character in Two or More Textboxes VB Net

I want to compare the Textbox1 with TextBox2, or Textbox line 1 of the text box to the 2nd line, to show me the existing Character in another textbox, or show me how many characters are repeated. iI really like learning, so I would be helpful because I want to learn...
TextBox1.Text = 1,4,7,11,13,16,19,20,28,31,44,37,51,61,62,63,64,69,71,79,80
TextBox2.Text = 1,5,7,10,13,16,26,20,28,31,44,37,51,72,73,74,69,71,79,80
TextBox3.Text = Character Repeated: 1,7,13,16,20,28,31,44,37,51,69,71,79,80
TextBox4.Text = Number of Character Repeated = 14
TextBox5.Text = Number of Character which has not been repeated: 4,11,19,61,62,63,64 etc, you got to idea
TextBox6.Text = Number of Character isn't Repeated: 7
here are some codes: but I do not know how to apply them correctly.
Code 1: Show repetable character:
' Split string based on space
TextBox1.Text = System.IO.File.ReadAllText(Mydpi.Text)
TextBox2.Text = System.IO.File.ReadAllText(Mydpi.Text)
TextBox4.Text = System.IO.File.ReadAllText(Mydpi.Text)
For i As Integer = 0 To TextBox2.Lines.Count - 1
Dim textsrtring As String = TextBox4.Lines(i)
Dim words As String() = textsrtring.Split(New Char() {","c})
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
TxtbValBeforeCompar.Text = TextBox1.Lines(i)
CompareNumbers()
If TextBox1.Lines(i).Contains(word) Then
found = True
Dim tempTextBox As TextBox = CType(Me.Controls("Checkertxt" & i.ToString), TextBox)
On Error Resume Next
If TextBox2.Lines(i).Contains(word) Then
If tempTextBox.Text.Contains(word) Then
Else
tempTextBox.Text = tempTextBox.Text + " " + TxtbValAfterCompar.Text()
End If
Else
End If
End If
Next
Next
Private Sub CompareNumbers()
'First Textbox that is to be used for compare
Dim textBox1Numbers As List(Of Integer) = GetNumbersFromTextLine(N1Check.Text)
'Second Textbox that is to be used for compare
Dim textBox2Numbers As List(Of Integer) = GetNumbersFromTextLine(TxtbValBeforeCompar.Text)
'Union List of Common Numbers (this uses a lambda expression, it can be done using two For Each loops instead.)
Dim commonNumbers As List(Of Integer) = textBox1Numbers.Where(Function(num) textBox2Numbers.Contains(num)).ToList()
'This is purely for testing to see if it worked you can.
Dim sb As StringBuilder = New StringBuilder()
For Each foundNum As Integer In commonNumbers
sb.Append(foundNum.ToString()).Append(" ")
TxtbValAfterCompar.Text = (sb.ToString())
Next
End Sub
Private Function GetNumbersFromTextLine(ByVal sTextLine As String) As List(Of Integer)
Dim numberList As List(Of Integer) = New List(Of Integer)()
Dim sSplitNumbers As String() = sTextLine.Split(" ")
For Each sNumber As String In sSplitNumbers
If IsNumeric(sNumber) Then
Dim iNum As Integer = CInt(sNumber)
TxtbValAfterCompar.Text = iNum
If Not numberList.Contains(iNum) Then
TxtbValAfterCompar.Text = ("")
numberList.Add(iNum)
End If
Else
End If
Next
Return numberList
End Function
Code 2: Remove Duplicate Chars (Character)
Module Module1
Function RemoveDuplicateChars(ByVal value As String) As String
' This table stores characters we have encountered.
Dim table(value.Length) As Char
Dim tableLength As Integer = 0
' This is our result.
Dim result(value.Length) As Char
Dim resultLength As Integer = 0
For i As Integer = 0 To value.Length - 1
Dim current As Char = value(i)
Dim exists As Boolean = False
' Loop over all characters in the table of encountered chars.
For y As Integer = 0 To tableLength - 1
' See if we have already encountered this character.
If current = table(y) Then
' End the loop.
exists = True
y = tableLength
End If
Next
' If we have not encountered the character, add it.
If exists = False Then
' Add character to the table of encountered characters.
table(tableLength) = current
tableLength += 1
' Add character to our result string.
result(resultLength) = current
resultLength += 1
End If
Next
' Return the unique character string.
Return New String(result, 0, resultLength)
End Function
Sub Main()
' Test the method we wrote.
Dim test As String = "having a good day"
Dim result As String = RemoveDuplicateChars(test)
Console.WriteLine(result)
test = "areopagitica"
result = RemoveDuplicateChars(test)
Console.WriteLine(result)
End Sub
End Module
You could make use of some LINQ such as Intersect and Union.
Assuming your TextBox1 and TextBox2 contains the text you have provided.
Here's a simple method to find repeated and non repeated characters.
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim firstBoxList = TextBox1.Text.Split(",").ToList()
Dim secondBoxList = TextBox2.Text.Split(",").ToList()
Dim intersectionList = firstBoxList.Intersect(secondBoxList)
For Each str As String In intersectionList
TextBox3.Text = TextBox3.Text & str & ","
Next
TextBox4.Text = intersectionList.Count()
Dim notRepeatedCharacter = firstBoxList.Union(secondBoxList).ToList
notRepeatedCharacter.RemoveAll(Function(x) intersectionList.Contains(x))
For each str As String In notRepeatedCharacter
TextBox5.Text = TextBox5.Text & str & ","
Next
TextBox6.Text = notRepeatedCharacter.Count()
End Sub
The output is something like that:
This consider both of the textboxes not repeated character.
If you just want to find the not repeated characters from first list to the second, this should do it:
firstBoxList.RemoveAll(Function(x) secondBoxList.Contains(x))
For Each str As String In firstBoxList
TextBox7.Text = TextBox7.Text & str & ","
Next
TextBox8.Text = firstBoxList.Count
And this is the output:
Here's the full code using String.Join to make the lists look smoother in the text boxes:
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
'First we grab all the numbers written inside the textboxes (I am not verifying anything)
Dim firstBoxList = TextBox1.Text.Split(",").ToList()
Dim secondBoxList = TextBox2.Text.Split(",").ToList()
'Second we intersect the two lists and show them
Dim intersectionList = firstBoxList.Intersect(secondBoxList)
TextBox3.Text = String.Join(",", intersectionList)
TextBox4.Text = intersectionList.Count()
'We're checking the distintc character from both lists
Dim notRepeatedCharacter = firstBoxList.Union(secondBoxList).ToList
notRepeatedCharacter.RemoveAll(Function(x) intersectionList.Contains(x))
TextBox5.Text = String.Join(",", notRepeatedCharacter)
TextBox6.Text = notRepeatedCharacter.Count()
'we're checkng the distinct character inside first list that doesn't show in second list
firstBoxList.RemoveAll(Function(x) secondBoxList.Contains(x))
TextBox7.Text = String.Join(",", firstBoxList)
TextBox8.Text = firstBoxList.Count
End Sub

How can I get String values rather than integer

How To get StartString And EndString
Dim startNumber As Integer
Dim endNumber As Integer
Dim i As Integer
startNumber = 1
endNumber = 4
For i = startNumber To endNumber
MsgBox(i)
Next i
Output: 1,2,3,4
I want mo make this like sample: startString AAA endString AAD
and the output is AAA, AAB, AAC, AAD
This is a simple function that should be easy to understand and use. Every time you call it, it just increments the string by one value. Just be careful to check the values in the text boxes or you can have an endless loop on your hands.
Function AddOneChar(Str As String) As String
AddOneChar = ""
Str = StrReverse(Str)
Dim CharSet As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
Dim Done As Boolean = False
For Each Ltr In Str
If Not Done Then
If InStr(CharSet, Ltr) = CharSet.Length Then
Ltr = CharSet(0)
Else
Ltr = CharSet(InStr(CharSet, Ltr))
Done = True
End If
End If
AddOneChar = Ltr & AddOneChar
Next
If Not Done Then
AddOneChar = CharSet(0) & AddOneChar
End If
End Function
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim S = TextBox1.Text
Do Until S = TextBox2.Text
S = AddOneChar(S)
MsgBox(S)
Loop
End Sub
This works as a way to all the codes given an arbitrary alphabet:
Public Function Generate(starting As String, ending As String, alphabet As String) As IEnumerable(Of String)
Dim increment As Func(Of String, String) = _
Function(x)
Dim f As Func(Of IEnumerable(Of Char), IEnumerable(Of Char)) = Nothing
f = _
Function(cs)
If cs.Any() Then
Dim first = cs.First()
Dim rest = cs.Skip(1)
If first = alphabet.Last() Then
rest = f(rest)
first = alphabet(0)
Else
first = alphabet(alphabet.IndexOf(first) + 1)
End If
Return Enumerable.Repeat(first, 1).Concat(rest)
Else
Return Enumerable.Empty(Of Char)()
End If
End Function
Return New String(f(x.ToCharArray().Reverse()).Reverse().ToArray())
End Function
Dim results = New List(Of String)
Dim text = starting
While True
results.Add(text)
If text = ending Then
Exit While
End If
text = increment(text)
End While
Return results
End Function
I used it like this to produce the required result:
Dim alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
Dim results = Generate("S30AB", "S30B1", alphabet)
This gave me 63 values:
S30AB
S30AC
...
S30BY
S30BZ
S30B0
S30B1
It should now be very easy to modify the alphabet as needed and to use the results.
One option would be to put those String values into an array and then use i as an index into that array to get one element each iteration. If you do that though, keep in mind that array indexes start at 0.
You can also use a For Each loop to access each element of the array without the need for an index.
if the default first two string value of your output is AA.
You can have a case or if-else conditioning statement :
and then set 1 == A 2 == B...
the just add or concatenate your default two string and result string of your case.
I have tried to understand that you are looking for a series using range between 2 textboxes. Here is the code which will take the series and will give the output as required.
Dim startingStr As String = Mid(TextBox1.Text, TextBox1.Text.Length, 1)
Dim endStr As String = Mid(TextBox2.Text, TextBox2.Text.Length, 1)
Dim outputstr As String = String.Empty
Dim startNumber As Integer
Dim endNumber As Integer
startNumber = Asc(startingStr)
endNumber = Asc(endStr)
Dim TempStr As String = Mid(TextBox1.Text, 1, TextBox1.Text.Length - 1)
Dim i As Integer
For i = startNumber To endNumber
outputstr = outputstr + ", " + TempStr + Chr(i)
Next i
MsgBox(outputstr)
The First two lines will take out the Last Character of the String in the text box.
So in your case it will get A and D respectively
Then outputstr to create the series which we will use in the loop
StartNumber and EndNumber will be give the Ascii values for the character we fetched.
TempStr to Store the string which is left off of the series string like in our case AAA - AAD Tempstr will have AA
then the simple loop to get all the items fixed and show
in your case to achive goal you may do something like this
Dim S() As String = {"AAA", "AAB", "AAC", "AAD"}
For Each el In S
MsgBox(el.ToString)
Next
FIX FOR PREVIOUS ISSUE
Dim s1 As String = "AAA"
Dim s2 As String = "AAZ"
Dim Last As String = s1.Last
Dim LastS2 As String = s2.Last
Dim StartBase As String = s1.Substring(0, 2)
Dim result As String = String.Empty
For I As Integer = Asc(s1.Last) To Asc(s2.Last)
Dim zz As String = StartBase & Chr(I)
result += zz & vbCrLf
zz = Nothing
MsgBox(result)
Next
**UPDATE CODE VERSION**
Dim BARCODEBASE As String = "SBA0021"
Dim BarCode1 As String = "SBA0021AA1"
Dim BarCode2 As String = "SBA0021CD9"
'return AA1
Dim FirstBarCodeSuffix As String = Replace(BarCode1, BARCODEBASE, "")
'return CD9
Dim SecondBarCodeSuffix As String = Replace(BarCode2, BARCODEBASE, "")
Dim InternalSecondBarCodeSuffix = SecondBarCodeSuffix.Substring(1, 1)
Dim IsTaskCompleted As Boolean = False
For First As Integer = Asc(FirstBarCodeSuffix.First) To Asc(SecondBarCodeSuffix)
If IsTaskCompleted = True Then Exit For
For Second As Integer = Asc(FirstBarCodeSuffix.First) To Asc(InternalSecondBarCodeSuffix)
For Third As Integer = 1 To 9
Dim tmp = Chr(First) & Chr(Second) & Third
Console.WriteLine(BARCODEBASE & tmp)
If tmp = SecondBarCodeSuffix Then
IsTaskCompleted = True
End If
Next
Next
Next
Console.WriteLine("Completed")
Console.Read()
Take a look into this check it and let me know if it can help

Generate "aa", "Aa", "aA", "AA", etc In order

How would I generate combinations of 2 lowercase/upercase letters/numbers in order?
Sub Main()
Dim Looper As Boolean = True
While Looper = True
'String = "aa", "Aa", "aA", "AA"
'WebClient.DownloadString("link.com/" & String")
End While
End Sub
Like this, but generate combination for String
You could loop over a string and just manipulate upper and lower case as required:
Sub Main()
Dim results as List(of String) = new List(of String)()
For Each c as Char in "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray()
results.Add(c.ToString().ToLower() & c.ToString().ToLower())
results.Add(c.ToString() & c.ToString().ToLower())
results.Add(c.ToString().ToLower() & c.ToString())
results.Add(c.ToString() & c.ToString())
Next
End Sub
This will generate a combination of two random characters, including numbers and uppercase/lowercase letters:
Public Function GetRandomString(ByVal iLength As Integer) As String
Dim sResult As String = ""
Dim rdm As New Random()
For i As Integer = 1 To iLength
sResult &= ChrW(rdm.Next(32, 126))
Next
Return sResult
End Function
Or you can do the common random string defining the valid caracters:
Public Function GenerateRandomString(ByRef iLength As Integer) As String
Dim rdm As New Random()
Dim allowChrs() As Char = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLOMNOPQRSTUVWXYZ0123456789".ToCharArray()
Dim sResult As String = ""
For i As Integer = 0 To iLength - 1
sResult += allowChrs(rdm.Next(0, allowChrs.Length))
Next
Return sResult
End Function