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Date Signal
1 2008-05-28 11:00:00 1.886108
2 2008-04-17 12:00:00 1.885108
3 2008-05-21 12:00:00 1.166525
4 2008-05-28 11:00:00 1.166525
5 2008-05-23 11:00:00 1.010902
Hi, is there a way I can match the above dataframe to a date, eg 2008-05-28 11:00:00 and print only the Signal value if it matches?
thanks in advance.
* apologies if this was a niave question. I tried many various methods but not .loc which has been kindly pointed out below and works perfectly, thank you.
Assuming you have data frame df
d = pandas.Timestamp("2008-05-28 11:00:00", tz=None)
df[df.Date == d].Signal
You can use loc too:
df.loc[df.Date == '2008-05-28 11:00:00', 'Signal']
Not tested but something along the lines of...
df['Signal'][df.Date == '2008-05-28 11:00:00']
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I am new to pandas.
I have been trying to solve a problem here
This is the problem statement where I want to drop any row where I have a duplicate A but non duplicate B
Here is the kind of output I want
enter image description here
IIUC, this is what you need
a = (df['A'].ne(df['A'].shift())).ne((df['B'].ne(df['B'].shift())))
df[~a].reset_index(drop=True)
Output
A B
0 2 z
1 3 x
2 3 x
I think you need:
cond=(df.eq(df.shift(-1))|df.eq(df.shift())).all(axis=1)
pd.concat([df[~cond].groupby('A').last().reset_index(),df[cond]])
A B
0 2 y
2 3 x
3 3 x
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I have a data frame called EPI.
it looks like this:
It has 104 countries. Each country has values from 1991 till 2008 (18 years).
I want to have average every 9 years. So, each country will have 2 averages.
An edit:
This is the command I used to use it to get average. But it gives me one value (average) for each country.
aver_economic_growth <- aggregate( HDI_growth_rate[,3], list(economic_growth$cname), mean, na.rm=TRUE)
But I need to get an average for each 9 years of a country.
Please note that I am a new user of r and I didn't find pandas in packages installment!
I think you can first convert years to datetime and then groupby with resample mean. Last convert to years.
#sample data for testing
np.random.seed(100)
start = pd.to_datetime('1991-02-24')
rng = pd.date_range(start, periods=36, freq='A')
df = pd.DataFrame({'cname': ['Albania'] * 18 + ['Argentina'] * 18,
'year': rng.year,
'rgdpna.pop': np.random.choice([0,1,2], size=36)})
#print (df)
df.year = pd.to_datetime(df.year, format='%Y')
df1 = df.set_index('year').groupby('cname').resample('9A',closed='left').mean().reset_index()
df1.year = df1.year.dt.year
print (df1)
cname year rgdpna.pop
0 Albania 1999 1.000000
1 Albania 2008 1.000000
2 Argentina 2017 0.888889
3 Argentina 2026 0.888889
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I want to get the line numbers where the implementation of objective c method start.
1 #include "foobar.h"
2 -(void)Foo{
3 ...
4 }
5
6 +(NSInteger *)bar{
7 ...
8 }
The output should be: 2,6
How can i achieve it with libclang.
I do not want to use a regex for that, because it will be sufficient.
Solution:
CXSourceRange range = clang_getCursorExtent(cursor);
CXSourceLocation startLocation = clang_getRangeStart(range);
CXSourceLocation endLocation = clang_getRangeEnd(range);
CXFile file;
unsigned int line, column, offset;
clang_getInstantiationLocation(startLocation, &file, &line, &column, &offset);
enum CXCursorKind curKind = clang_getCursorKind(cursor);
CXString curKindName = clang_getCursorKindSpelling(curKind);
const char *funcDecl="ObjCInstanceMethodDecl";
if(strcmp(clang_getCString(curKindName),funcDecl)==0){
printf("%u",line);
}
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I can't figure out this simple(?) pattern in vb.net.
So the problem is this: I have 4 arrays of integers, 2 of them are from 0 to 29, and the last 2 are from 0 to 9. Now I am trying to make the pattern look like this:
I hope it makes sense.
This simple LINQ-query should give you the expected result.
Dim big1 = Enumerable.Range(0, 30).ToArray()
Dim big2 = Enumerable.Range(0, 30).ToArray()
Dim small1 = Enumerable.Range(0, 10).ToArray()
Dim small2 = Enumerable.Range(0, 10).ToArray()
Dim result = From b1 in big1
From b2 in big2
From s1 in small1
From s2 in small2
Select New With {b1, b2, s1, s2}
...
It uses the Enumerable.SelectMany function:
Enumerable.SelectMany
Projects each element of a sequence to an IEnumerable and flattens the resulting sequences into one sequence.
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I have this problem getting the Standard Deviation (equiation here). My question is how could I get the sum of ([X interval] - mean) from a set of data wherein a certain criteria(s) is to be followed.
For example, the data is:
Gender Grade
M 36
M 32
F 25
F 40
I have acquired N needed in the equation via COUNTIFS and acquired the mean via SUMIFS. The problem is having the get the sum of the range (X interval minus mean) without declaring a cell/column for the said range. In the given example, I would want to get the Standard Deviation of Grade with respect to gender. It would be hard if record 2 gender would be changed to 'F' if I would add column for X interval minus mean.
Any thoughts how this maybe done?
With a little algebra the sd formula can be rewritten as
Ʃ(x²) - Ʃ(x)²/n
sd = √( --------------- )
n
which can be implemented with SUMIFS, COUNTIFS and SUMPRODUCT
Assuming gender data is in range A1:A4 and grade in B1:B4 and criteria in C1 use
=SQRT( (SUMPRODUCT($B$1:$B$4,$B$1:$B$4,--($A$1:$A$4=C1)) -
SUMIFS($B$1:$B$4,$A$1:$A$4,C1)^2/COUNTIFS($A$1:$A$4,C1)) /
COUNTIFS($A$1:$A$4,C1) )