Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 9 years ago.
Improve this question
I want to get the line numbers where the implementation of objective c method start.
1 #include "foobar.h"
2 -(void)Foo{
3 ...
4 }
5
6 +(NSInteger *)bar{
7 ...
8 }
The output should be: 2,6
How can i achieve it with libclang.
I do not want to use a regex for that, because it will be sufficient.
Solution:
CXSourceRange range = clang_getCursorExtent(cursor);
CXSourceLocation startLocation = clang_getRangeStart(range);
CXSourceLocation endLocation = clang_getRangeEnd(range);
CXFile file;
unsigned int line, column, offset;
clang_getInstantiationLocation(startLocation, &file, &line, &column, &offset);
enum CXCursorKind curKind = clang_getCursorKind(cursor);
CXString curKindName = clang_getCursorKindSpelling(curKind);
const char *funcDecl="ObjCInstanceMethodDecl";
if(strcmp(clang_getCString(curKindName),funcDecl)==0){
printf("%u",line);
}
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 3 years ago.
Improve this question
I am new to pandas.
I have been trying to solve a problem here
This is the problem statement where I want to drop any row where I have a duplicate A but non duplicate B
Here is the kind of output I want
enter image description here
IIUC, this is what you need
a = (df['A'].ne(df['A'].shift())).ne((df['B'].ne(df['B'].shift())))
df[~a].reset_index(drop=True)
Output
A B
0 2 z
1 3 x
2 3 x
I think you need:
cond=(df.eq(df.shift(-1))|df.eq(df.shift())).all(axis=1)
pd.concat([df[~cond].groupby('A').last().reset_index(),df[cond]])
A B
0 2 y
2 3 x
3 3 x
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
How can I get blocks from a string ( NSString ) and copy then to a array?
int BlockSize = 3
char array[3];
NSString *ns = #"ABCDEFGHI";
What I want to do is get the the first 3 elements and put on array[0] , the next 3 elements and put then on array[1] , the next 3 on array[2]
Thanks
to get character from string you can use below code:
NSString *ns = #"ABCDEFGHI";
arr[0]= [ns characterAtIndex:0];
NSLog(#"%c",arr[0]);
arr[1]= [ns characterAtIndex:1];
NSLog(#"%c",arr[1]);
Or even you go through forloop to iterate to complete string length
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
Date Signal
1 2008-05-28 11:00:00 1.886108
2 2008-04-17 12:00:00 1.885108
3 2008-05-21 12:00:00 1.166525
4 2008-05-28 11:00:00 1.166525
5 2008-05-23 11:00:00 1.010902
Hi, is there a way I can match the above dataframe to a date, eg 2008-05-28 11:00:00 and print only the Signal value if it matches?
thanks in advance.
* apologies if this was a niave question. I tried many various methods but not .loc which has been kindly pointed out below and works perfectly, thank you.
Assuming you have data frame df
d = pandas.Timestamp("2008-05-28 11:00:00", tz=None)
df[df.Date == d].Signal
You can use loc too:
df.loc[df.Date == '2008-05-28 11:00:00', 'Signal']
Not tested but something along the lines of...
df['Signal'][df.Date == '2008-05-28 11:00:00']
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist
Closed 9 years ago.
Improve this question
I can't figure out this simple(?) pattern in vb.net.
So the problem is this: I have 4 arrays of integers, 2 of them are from 0 to 29, and the last 2 are from 0 to 9. Now I am trying to make the pattern look like this:
I hope it makes sense.
This simple LINQ-query should give you the expected result.
Dim big1 = Enumerable.Range(0, 30).ToArray()
Dim big2 = Enumerable.Range(0, 30).ToArray()
Dim small1 = Enumerable.Range(0, 10).ToArray()
Dim small2 = Enumerable.Range(0, 10).ToArray()
Dim result = From b1 in big1
From b2 in big2
From s1 in small1
From s2 in small2
Select New With {b1, b2, s1, s2}
...
It uses the Enumerable.SelectMany function:
Enumerable.SelectMany
Projects each element of a sequence to an IEnumerable and flattens the resulting sequences into one sequence.
Closed. This question is off-topic. It is not currently accepting answers.
Want to improve this question? Update the question so it's on-topic for Stack Overflow.
Closed 10 years ago.
Improve this question
I have this problem getting the Standard Deviation (equiation here). My question is how could I get the sum of ([X interval] - mean) from a set of data wherein a certain criteria(s) is to be followed.
For example, the data is:
Gender Grade
M 36
M 32
F 25
F 40
I have acquired N needed in the equation via COUNTIFS and acquired the mean via SUMIFS. The problem is having the get the sum of the range (X interval minus mean) without declaring a cell/column for the said range. In the given example, I would want to get the Standard Deviation of Grade with respect to gender. It would be hard if record 2 gender would be changed to 'F' if I would add column for X interval minus mean.
Any thoughts how this maybe done?
With a little algebra the sd formula can be rewritten as
Ʃ(x²) - Ʃ(x)²/n
sd = √( --------------- )
n
which can be implemented with SUMIFS, COUNTIFS and SUMPRODUCT
Assuming gender data is in range A1:A4 and grade in B1:B4 and criteria in C1 use
=SQRT( (SUMPRODUCT($B$1:$B$4,$B$1:$B$4,--($A$1:$A$4=C1)) -
SUMIFS($B$1:$B$4,$A$1:$A$4,C1)^2/COUNTIFS($A$1:$A$4,C1)) /
COUNTIFS($A$1:$A$4,C1) )