I am using SQL Server 2008 R2. I do have records as below in a table :
Id Sys Dia Type UniqueId
1 156 20 first 12345
2 157 20 first 12345
3 150 15 last 12345
4 160 17 Average 12345
5 150 15 additional 12345
6 157 35 last 891011
7 156 25 Average 891011
8 163 35 last 789521
9 145 25 Average 789521
10 156 20 first 963215
11 150 15 last 963215
12 160 17 Average 963215
13 156 20 first 456878
14 157 20 first 456878
15 150 15 last 456878
16 160 17 Average 456878
17 150 15 last 246977
18 160 17 Average 246977
19 150 15 additional 246977
Regarding this data, these records are kind of groups that have common UniqueId. The records can be of type "first, last, average and additional". Now, from these records I want to select "average" type of records only if they have "first" or "additional" kind of reading in group. Else I want to exclude them from selection..
The expected result is :
Id Sys Dia Type UniqueId
1 156 20 first 12345
2 157 20 first 12345
3 150 15 last 12345
4 160 17 Average 12345
5 150 15 additional 12345
6 157 35 last 891011
7 163 35 last 789521
8 156 20 first 963215
9 150 15 last 963215
10 160 17 Average 963215
11 156 20 first 456878
12 157 20 first 456878
13 150 15 last 456878
14 160 17 Average 456878
15 150 15 last 246977
16 160 17 Average 246977
17 150 15 additional 246977
In short, I don't want to select the record that have type="Average" and have only "last" type of record with same UniqueId. Any solution?
Using EXISTS operator along correlated sub-query:
SELECT * FROM dbo.Table1 t1
WHERE [Type] != 'Average'
OR EXISTS (SELECT * FROM Table1 t2
WHERE t1.UniqueId = t2.UniqueId
AND t1.[Type] = 'Average'
AND t2.[Type] IN ('first','additional'))
SQLFiddle DEMO
Try something like this:
SELECT * FROM MyTable WHERE [Type] <> 'Average'
UNION ALL
SELECT * FROM MyTable T WHERE [Type] = 'Average'
AND EXISTS (SELECT * FROM MyTable
WHERE [Type] IN ('first', 'additional')
AND UniqueId = T.UniqueId)
The first SELECT statement gets all records except the ones with Type = 'Average'. The second SELECT statement gets only the Type = 'Average' records that have at least one record with the same UniqueId, that is of type 'first' or 'additional'.
Related
I need your help for a little issue.
I use MS ACCESS to work with a database and I need to resolve a query. My query asks:
Find the CUSTOMER_ID and TRANSC_ID where 2 consecutive value between 200 and 500 WITHIN the same transc_id.
I explain.
I have this table in this format:
CUSTOMER_ID TRANSC_ID VALUE VALUE_DATE
51 10 15 29-12-1999
51 10 20 15-07-2000
51 10 35 18-08-2000
51 10 250 30-08-2000
51 10 13 10-09-2000
51 10 450 15-09-2000
51 11 5 15-09-2000
51 11 23 30-09-2000
51 11 490 10-10-2000
51 11 300 12-10-2000
51 11 85 30-10-2000
51 11 98 01-01-2000
53 10 65 15-10-2000
53 10 14 29-12-2000
And I need just
51 11 490 10-10-2000
51 11 300 12-10-2000
because the two values is consecutive (and both of them is >250 and <500).
How can I make a query in MS ACCESS to obtain this result?
Thank you.
You can get the "next" and "previous" values using correlated subqueries, and then do the comparison:
select t.*
from t
where t.value between 200 and 500 and
( (select top 1 t2.value
from t as t2
where t2.CUSTOMER_ID = t.CUSTOMER_ID and t2.TRANSC_ID = t.TRANSC_ID and
t2.value_date > t.value_date
order by t2.value_date
) between 200 and 500 or
(select top 1 t2.value
from t as t2
where t2.CUSTOMER_ID = t.CUSTOMER_ID and t2.TRANSC_ID = t.TRANSC_ID and
t2.value_date < t.value_date
order by t2.value_date desc
) between 200 and 500
);
Lets say I have a table which holds all exports for some time back in Microsoft SQL database:
Name:
ExportTable
Columns:
id - numeric(18)
exportdate - datetime
In order to get the number of exports per week I can run the following query:
SELECT DATEPART(ISO_WEEK,[exportdate]) as 'exportdate', count(exportdate) as 'totalExports'
FROM [ExportTable]
Group By DATEPART(ISO_WEEK,[exportdate])
order by exportdate;
Returns:
exportdate totalExports
---------- ------------
27 13
28 12
29 15
30 8
31 17
32 10
33 7
34 15
35 4
36 18
37 10
38 14
39 14
40 21
41 19
Would it be possible to aggregate the week results by quarter so the output becomes something like the bellow?
UPDATE
Sorry for not being crystal clear, I would like the current result to add upp with previous result up to a new quarter.
Note week 41 contains 21+19 = 40
Week 39 contains 157 (13+12+15+8+17+10+7+15+4+18+10+14+14)
exportdate totalExports Quarter
---------- ------------ -------
27 13 3
28 25 3
29 40 3
30 48 3
31 65 3
32 75 3
33 82 3
34 97 3
35 101 3
36 119 3
37 129 3
38 143 3
39 157 3 -- Sum of 3 Quarter values.
40 21 4 -- New Quarter show current week value
41 40 4 -- (21+19)
You can use this.
SELECT
DATEPART(ISO_WEEK,[exportdate]) as 'exportdate'
, SUM( count(exportdate) ) OVER ( PARTITION BY DATEPART(QUARTER,MIN([exportdate])) ORDER BY DATEPART(ISO_WEEK,[exportdate]) ROWS UNBOUNDED PRECEDING ) as 'totalExports'
, DATEPART(QUARTER,MIN([exportdate])) [Quarter]
FROM [ExportTable]
Group By DATEPART(ISO_WEEK,[exportdate])
order by exportdate;
You could use a case statement to separate the dates into quarters.
e.g.
CASE
WHEN EXPORT_DATE BETWEEN '1' AND '4' THEN 1
WHEN Export_Date BETWEEN '5' and '9' THEN 2
ELSE 0 AS [Quarter]
END
Its just an example but you get the idea.
You could then use the alias from the case
SELECT DATEPART(ISO_WEEK,[exportdate]) as 'exportdate', count(exportdate) as 'totalExports', DATEPART(quarter,[exportdate]) as quarter FROM [ExportTable] Group By DATEPART(ISO_WEEK,[exportdate]), DATEPART(quarter,[exportdate]) order by exportdate;
I have a query that looks like this:
select nvl(trim(a.code), 'Blanks') as Ward, count(b.apcasekey) as UNSP, count(c.apcasekey) as GRAPH,
count(d.apcasekey) as "ANI/PIG",
(count(b.apcasekey) + count(c.apcasekey) + count(d.apcasekey)) as "TOTAL ACTIVE",
count(a.apcasekey) as "TOTAL OPEN" from (etc...)
group by a.code
order by Ward
The reason I have nvl(trim(a.code), 'Blanks') as Ward is that sometimes a.code is a blank string, sometimes it's a null.
The problem is that when I use the Group By statement, I can't use Ward or I get the error
Ward: Invalid Identifier
I can only use a.code so I get 2 rows for 'Blanks', as per below
1 Blanks 7 0 0 7 7
2 Blanks 23 1 1 25 30
3 W01 75 4 0 79 91
4 W02 62 1 0 63 72
5 W03 140 2 0 142 162
6 W04 6 1 0 7 7
7 W05 46 0 1 47 48
8 W06 322 46 1 369 425
9 W07 91 0 1 92 108
10 W08 93 2 0 95 104
11 W09 28 1 0 29 30
12 W10 25 0 0 25 28
What I need, is for the row with 'Blanks' to combined into 1 row. Little help?
Thanks.
You can not use the alias in the GROUP BY, but you can use the expression that builds the value:
GROUP BY nvl(trim(a.code), 'Blanks')
I have one table like below in my SQL server.
Trans_id br_code bill_no amount
1 22 111 10
2 22 111 20
3 22 111 30
4 22 111 40
5 22 111 10
6 23 112 20
7 23 112 20
8 23 112 20
9 23 112 30
and I want desired output like below table
s.no br_code bill_no amount
1 22 111 110
2 23 112 90
try this:
select br_code, bill_no, sum(amount)
from TABLE
group by br_code, bill_no
I am new to Microsoft access.
I need a query that will allow me to sum a rolling total for every 5 lines of data. So on the sixth day I need a line to drop off the total and the new line to be added.
Fields:
ID, Daily_SUM
The results should be
ID Daily sum Weekly Sum
1 12
2 41
3 46
4 125
5 120 344
6 42 374
7 41 374
8 57 385
9 207 467
10 215 562
11 187 707
12 -43 623
13 45 611
14 56 460
15 40 285
16 8 106
17 95 244
18 580 779
19 360 1083
20 337 1380
You can do this with a correlated subquery. The challenge is actually getting NULL values on the first few rows:
select t.id, t.daily,
(select iif(count(*) = 7, sum(t3.daily), NULL)
from (select top 7 t2.daily
from table t2
where t2.id <= t.id
order by t2.id desc
) t3
) as weekly
from table t;
EDIT:
If we assume that the ids are assigned sequentially with no gaps, then you can use an explicit join:
select t.id, t.daily,
iif(count(*) = 7, sum(t2.daily), NULL) as weekly
from table t inner join
table t2
on t2.id between t.id - 6 and t.id
group by t.id, t.daily;