I need your help for a little issue.
I use MS ACCESS to work with a database and I need to resolve a query. My query asks:
Find the CUSTOMER_ID and TRANSC_ID where 2 consecutive value between 200 and 500 WITHIN the same transc_id.
I explain.
I have this table in this format:
CUSTOMER_ID TRANSC_ID VALUE VALUE_DATE
51 10 15 29-12-1999
51 10 20 15-07-2000
51 10 35 18-08-2000
51 10 250 30-08-2000
51 10 13 10-09-2000
51 10 450 15-09-2000
51 11 5 15-09-2000
51 11 23 30-09-2000
51 11 490 10-10-2000
51 11 300 12-10-2000
51 11 85 30-10-2000
51 11 98 01-01-2000
53 10 65 15-10-2000
53 10 14 29-12-2000
And I need just
51 11 490 10-10-2000
51 11 300 12-10-2000
because the two values is consecutive (and both of them is >250 and <500).
How can I make a query in MS ACCESS to obtain this result?
Thank you.
You can get the "next" and "previous" values using correlated subqueries, and then do the comparison:
select t.*
from t
where t.value between 200 and 500 and
( (select top 1 t2.value
from t as t2
where t2.CUSTOMER_ID = t.CUSTOMER_ID and t2.TRANSC_ID = t.TRANSC_ID and
t2.value_date > t.value_date
order by t2.value_date
) between 200 and 500 or
(select top 1 t2.value
from t as t2
where t2.CUSTOMER_ID = t.CUSTOMER_ID and t2.TRANSC_ID = t.TRANSC_ID and
t2.value_date < t.value_date
order by t2.value_date desc
) between 200 and 500
);
Related
I have the following set of Data
SET
START
END
QTY
A
1
10
10
A
11
20
10
A
21
30
10
B
51
60
10
B
61
70
10
B
81
90
10
B
91
100
10
C
101
200
100
C
201
300
100
C
401
500
100
And wanted to have the following result:
SET
START
END
TOTAL_QTY
A
1
30
30
B
51
70
20
B
81
100
20
C
101
300
200
C
401
500
100
So it will check previous "End" range and if it's a continuous from the previous "Start" range then it will be grouped into one "Start - End" ranges with the Sum of Qty.
I don't know how this can be achieved with Oracle SQL, can anyone help?
select "SET"
,min("START") as "START"
,max("END") as "END"
,sum(QTY) as QTY
from (
select t.*
,count(mrk) over(partition by "SET" order by "START") as grp
from (
select t.*
,case when "START" - lag("END") over(partition by "SET" order by "START") > 1 then 1 end as mrk
from t
) t
) t
group by "SET", grp
SET
START
END
QTY
A
1
30
30
B
51
70
20
B
81
100
20
C
101
300
200
C
401
500
100
Fiddle
I want to show the date field can not group.
My Query:
SELECT DAY(T1.UI_CreateDate) AS DATEDAY, SUM(1) AS TOTALCOUNT
FROM mydb.dbo.LP_UseImpression T1 WHERE T1.UI_BR_BO_ID = 45
GROUP BY DAY(T1.UI_CreateDate)
Result:
DATEDAY TOTALCOUNT
----------- -----------
15 186
9 1
3 2
26 481
21 297
27 342
18 18
30 14
4 183
25 553
13 8
22 469
16 1
17 28
20 331
28 90
14 33
8 1
But i want to show the full date...
Example result:
DATEDAY TOTALCOUNT
----------- -----------
15/06/2015 186
9/06/2015 1
3/06/2015 2
26/06/2015 481
21/06/2015 297
27/06/2015 342
18/06/2015 18
30/06/2015 14
4/06/2015 183
25/06/2015 553
13/06/2015 8
22/06/2015 469
16/06/2015 1
17/06/2015 28
20/06/2015 331
28/06/2015 90
14/06/2015 33
8/06/2015 1
I want to see the results...
I could not get a kind of results...
How can I do?
Thanx!
How about just casting to date to remove any time component:
SELECT CAST(T1.UI_CreateDate as DATE) AS DATEDAY, COUNT(*) AS TOTALCOUNT
FROM mydb.dbo.LP_UseImpression T1
WHERE T1.UI_BR_BO_ID = 45
GROUP BY CAST(T1.UI_CreateDate as DATE)
ORDER BY DATEDAY;
SUM(1) for calculating the count does work. However, because SQL has the COUNT(*) function, it seems a bit awkward.
So you can group by DAY(T1.UI_CreateDate) or use full date for grouping. But these are different . As both these dates '2015-04-15' and '2015-12-15' result in same DAY value of 15.
Assuming you want to group on DAY rather than date please try the below version of query:
SELECT DISTINCT
T1.UI_CreateDate as DATEDAY,
count(1) over (PARTITION BY DAY(T1.UI_CreateDate) ) AS TOTALCOUNT
FROM mydb.dbo.LP_UseImpression T1 WHERE T1.UI_BR_BO_ID = 45
sql fiddle for demo: http://sqlfiddle.com/#!6/c3337/1
I have a query that shows my counter's accuracy and I'm doing a simple order by accuracy. But, what is happening it is ordering correctly BUT 100% appears at the bottom and not in correct order. I have moved the order by, but I may be missing something?
QUERY:
select counted_by_user_id, total, defects, trunc((total-defects)/total*100,2)||'%' as accuracy from
(
select counted_by_user_id, sum(locations) as total, sum(numberOfDefectBins) as defects from
(
select counted_by_user_id, locations, numberOfDefectBins from
(
select trunc(ical.last_updated_date_utc) as CountDate,ip.process_name,ipl.icqa_process_id,ical.counted_by_user_id,count(*) as locations, (
SELECT COUNT(iid.icqa_ical_detail_id)
FROM icqa_process_locations ipl1, icqa_count_attempt_logs ical1, icqa_ical_details iid
WHERE ipl1.icqa_process_id = ipl.icqa_process_id
AND ical1.icqa_count_attempt_id = ipl1.icqa_count_attempt_id
AND ical1.counted_by_user_id = ical.counted_by_user_id
AND iid.icqa_count_attempt_log_id = ical1.icqa_count_attempt_log_id
AND iid.is_defective = 'Y' and trunc(ipl1.last_updated_date_utc) = trunc(sysdate)) as numberOfDefectBins
from icqa_count_attempt_logs ical left join icqa_process_locations ipl
on ical.icqa_count_attempt_id = ipl.icqa_count_attempt_id
left join ICQA_PROCESSES ip on ipl.icqa_process_id= ip.icqa_process_id
where trunc(ical.last_updated_date_utc) = trunc(sysdate)
AND ical.counted_by_user_id IS NOT NULL
group by trunc(ical.last_updated_date_utc), ip.process_name, ipl.icqa_process_id, ical.counted_by_user_id
order by ical.counted_by_user_id
))
group by counted_by_user_id
)
order by accuracy desc;
RESULT:
counted_by_user_id total defects accuracy
dggonza 346 1 99.71%
giermanc 225 1 99.55%
kylecoll 659 4 99.39%
manansal 71 1 98.59%
jssuarez 271 5 98.15%
jhheredi 464 10 97.84%
tabilinl 185 4 97.83%
darinc 102 3 97.05%
tostab 484 18 96.28%
alicmena 25 1 96%
reyesk 733 31 95.77%
genej 478 22 95.39%
yadirac 73 4 94.52%
lhherold 505 28 94.45%
anamarih 465 30 93.54%
pineiror 380 25 93.42%
nallelys 349 31 91.11%
almquij 112 12 89.28%
kustance 357 50 85.99%
arteagaa 54 12 77.77%
gardne 848 0 100%
willij 5 0 100%
castnera 21 0 100%
pbarbara 43 0 100%
caudilr 493 0 100%
jennifei 27 0 100%
Of course. Because you are sorting a string not a number.
There are multiple solutions:
order by length(accuracy) desc, accuracy;
is probably the easiest.
Some others:
order by cast(replace(accuracy, '%', '') as float);
order by (total-defects)/total;
order by (case when accuracy = '100%' then 1
when accuracy >= '10%' then 2
else 3
end), accuracy desc
I am new to Microsoft access.
I need a query that will allow me to sum a rolling total for every 5 lines of data. So on the sixth day I need a line to drop off the total and the new line to be added.
Fields:
ID, Daily_SUM
The results should be
ID Daily sum Weekly Sum
1 12
2 41
3 46
4 125
5 120 344
6 42 374
7 41 374
8 57 385
9 207 467
10 215 562
11 187 707
12 -43 623
13 45 611
14 56 460
15 40 285
16 8 106
17 95 244
18 580 779
19 360 1083
20 337 1380
You can do this with a correlated subquery. The challenge is actually getting NULL values on the first few rows:
select t.id, t.daily,
(select iif(count(*) = 7, sum(t3.daily), NULL)
from (select top 7 t2.daily
from table t2
where t2.id <= t.id
order by t2.id desc
) t3
) as weekly
from table t;
EDIT:
If we assume that the ids are assigned sequentially with no gaps, then you can use an explicit join:
select t.id, t.daily,
iif(count(*) = 7, sum(t2.daily), NULL) as weekly
from table t inner join
table t2
on t2.id between t.id - 6 and t.id
group by t.id, t.daily;
I am using SQL Server 2008 R2. I do have records as below in a table :
Id Sys Dia Type UniqueId
1 156 20 first 12345
2 157 20 first 12345
3 150 15 last 12345
4 160 17 Average 12345
5 150 15 additional 12345
6 157 35 last 891011
7 156 25 Average 891011
8 163 35 last 789521
9 145 25 Average 789521
10 156 20 first 963215
11 150 15 last 963215
12 160 17 Average 963215
13 156 20 first 456878
14 157 20 first 456878
15 150 15 last 456878
16 160 17 Average 456878
17 150 15 last 246977
18 160 17 Average 246977
19 150 15 additional 246977
Regarding this data, these records are kind of groups that have common UniqueId. The records can be of type "first, last, average and additional". Now, from these records I want to select "average" type of records only if they have "first" or "additional" kind of reading in group. Else I want to exclude them from selection..
The expected result is :
Id Sys Dia Type UniqueId
1 156 20 first 12345
2 157 20 first 12345
3 150 15 last 12345
4 160 17 Average 12345
5 150 15 additional 12345
6 157 35 last 891011
7 163 35 last 789521
8 156 20 first 963215
9 150 15 last 963215
10 160 17 Average 963215
11 156 20 first 456878
12 157 20 first 456878
13 150 15 last 456878
14 160 17 Average 456878
15 150 15 last 246977
16 160 17 Average 246977
17 150 15 additional 246977
In short, I don't want to select the record that have type="Average" and have only "last" type of record with same UniqueId. Any solution?
Using EXISTS operator along correlated sub-query:
SELECT * FROM dbo.Table1 t1
WHERE [Type] != 'Average'
OR EXISTS (SELECT * FROM Table1 t2
WHERE t1.UniqueId = t2.UniqueId
AND t1.[Type] = 'Average'
AND t2.[Type] IN ('first','additional'))
SQLFiddle DEMO
Try something like this:
SELECT * FROM MyTable WHERE [Type] <> 'Average'
UNION ALL
SELECT * FROM MyTable T WHERE [Type] = 'Average'
AND EXISTS (SELECT * FROM MyTable
WHERE [Type] IN ('first', 'additional')
AND UniqueId = T.UniqueId)
The first SELECT statement gets all records except the ones with Type = 'Average'. The second SELECT statement gets only the Type = 'Average' records that have at least one record with the same UniqueId, that is of type 'first' or 'additional'.