I'm using a formula in Excel 2007 to grab a mailbox size from a string. I'm stripping out all of the text before and after, and removing the , characters, yet Excel will not format the result as a number.
Because of this, I can't run any statistics such as total size or average size.
=SUBSTITUTE(MID(MailboxEX01[[#This Row],[TotalItemSize]], FIND("(", MailboxEX01[[#This Row],[TotalItemSize]]) + 1, FIND("bytes", MailboxEX01[[#This Row],[TotalItemSize]]) - (FIND("(", MailboxEX01[[#This Row],[TotalItemSize]]) + 2)), ",", "")
I tried =TEXT({the above}, "#,##0"), which successfully added the , character as the thousands separator, but (I guess unsurprisingly) still failed to format the cell as a number.
Does anybody know how I can force the result in this cell to format as a number? Thanks.
Your formula takes text values, strips stuff out, and replaces stuff. But the result is still text. If the result of that formula contains only the characters 0 to 9, you can coerce it into a number by using
={your formula}+0
or
={your formula}*1
or
=--({your formula})
Using =TEXT({your formula}, "format") will not produce a number. The TEXT() function returns text, as the name implies.
But if you use a mathematical operator on a number that is stored as text (or a text that represents a number), the maths operation will coerce that text value into a real number. The third suggestion uses the double unary (Google that) to coerce the text into a number.
Related
I can't really seem to find a standard for this. I know inputs are taken as ASCII values, but are they required to be single characters? If not, how are multi-character inputs handled?
Command line inputs in most (if not all) programming languages are taken a line at a time. When you hit enter into a console after typing a line, the whole line gets sent into the program as a return value from the function you called to get the input.
In brainfuck, you have more control over this: You can get as many characters as you want at a time, and stop when you want to.
A single comma "," will get one byte's worth of input (a.k.a one character). If you want to handle getting a string until a newline is met, you can try implementing something like the following code (10 being the ascii value of newline and the number of repetitions of "+" and "-" chars):
[-]>,----------[++++++++++>,----------]<[<]
An array of non zero values starting and ending with zero values is saved into memory containing the ascii values of input chars.
I have an excel created from a comma-delimited text file originally from a .sql file with an SQL INSERT query.
In one of the columns I have: "Cast(0x123456AB...) As TIME
Obviously this is NOT the jsondate format... so no help from that question...
I replaced the Cast( and replaced the ") As TIME" with empty strings.
So now I have the time values in hexadecimal.
How do I convert them into Excel Time or Datetime?
OK Playing around with it showed me that it's exactly the same as the jquery date answer. You take the numeric portion starting with 0x.
Take the 10 digits AFTER the 0x. e.g. in A2: =MID(A1, 3, 10)
Turn it into hexadecimal e.g. in A3: = HEX2DEC(A2)
Divide by 86400 e.g. A4: =A3/86400
And add the result to 1/1/1970 date. e.g. = A5: =A4 + Date(1970, 1, 1)
Or in short:
=(hex2dec(mid(a1,numstart,10))/86400) + date(1970,1,1)
Replace numstart with the 1-starting index of the number.
e.g. 3 if you have a 12 or 13 digit number like 0x12345678AB and you'll get 12345678AB
This is similar to the Convert JSON Date /Date(1388624400000)/ to Date in Excel
Except that:
a. The question was answered wrong and wouldn't work. (I edited it)
b. The .sql file was retrieved in a stored procedure from the database via SQL. While in the question they were using jquery returned ajax data, which seemed to differ. Turns out they're the same number with a different format.
As an added remark, I had a space mark at the beginning of my hex number. Until I did the MID on it, I didn't see that.
Note: When using ajax returned formatted dates like /date:0x12345678ab/ you'll set numstart to 8. If hex2dec fails, try turning the hex string into uppercase
before calling hex2dec. To debug just put each formula in a separate cell, so you see what works and what doesn't.
In my database I should only have data written using Polish alphabet but sometimes there are symbols not included in Polish alphabet (words copied from source with different encoding) that correspond to Polish letters in another encoding. Is it possible to somehow convert symbols outside of Polish alphabet to corresponding letters?
The only solution I figured is to manually find and replace those characters but maybe you have better solution to my problem.
Question concerns Oracle SQL Language.
I don't have database in front of me but as I remember correctly the example could look like this - two rows from my db:
ŚWIAT
ÚWIAT
and what I need is to convert Ú that doesn't belong to Polish alphabet to Ś.
You can try this. Experiment with it first to see if it works.
If I want to change every occurrence of the letter z with a j in a string, I would use the translate function: translate(text_string, 'z', 'j'). I don't have to use the letters z and j; instead, I can write translate(text_string, chr(122), chr(106) - to find out the character code, I use select ascii('z') from dual;. For example:
SQL> select translate('banzo', chr(122), chr(106)) from dual;
TRANS
-----
banjo
This changes every occurrence of z to j in text_string.
Now, you will have to find the code for the characters you want to change (both the "from" and the "to" characters) in your character set - it should be your session character set, not the database character set. (At least I think this is correct; experiment with it or read the documentation for CHR and perhaps for TRANSLATE - CHR returns the character code in the DATABASE character set unless you indicate otherwise, while I believe TRANSLATE uses the session character set.)
The function ascii may or may not work for non-ASCII characters, but if you google the name of your character set, you should find a character set table that will show you the codes for all the letters available in that character set.
Then, if this works, you can do the translation in one shot - translate(text_string, 'abcd', 'qrst') will change every 'a' to a 'q', every 'b' to an 'r' etc. And with chr(...), instead of 'abcd' you can write chr(97) || chr(98) || chr(99) || chr(100).
I'm in the process of uploading data into an access database, and some of the data has phone numbers listed in the format of 9999999999 and others are listed as 999-999-9999. I would like for all the numbers to read 9999999999 so that way they can be cross referenced. I've been trying to run an update query on the numbers that are in the undesired format, but I am having no success. Blow is how I have the query set up:
Field: Wireless Number
Table: Table to be updated
Update to: Mid([Table].[Wireless Number],2,3)+Mid([Table].[Wireless Number],7,3)+Right([Table].[Wireless Number],4)
Criteria: Not Like "**********"
Obviously, I'm not sure how to go about this, so that set up is a shot in the dark. What is the best way to go about getting the format that I need ?
This SQL function should work, replace [wireless num] with your field name:
test: IIf(Mid([wireless num],4,1)="-",Left([wireless num],3) & Mid([wireless num],5,3) & Right([wireless num],4),[Wireless Num])
If the 4th character is a -, that means it is undesired. In that scenario, it extracts each section of the phone number as substrings, concatenates them, and displays them as one string.
If the 4th character is not a -, we can assume the phone number is in the desired format.
This should also work:
Replace([wireless num],"-","")
It searches the Wireless Num field for -, and replaces it with a zero length string.
I have created a Fortran 90 code to filter and convert the text output of another program in a csv form. The file contains a table with columns of various types (character, real, integer). There is a column that generally contains decimal values (probability values). BUΤ, in some rows, where the value should be decimal "1.000", the value is actually integer "1".
I use "F5.3" specifier to read this column and I have the same format statement for every row of the table. So, when the code finds "1", it reads ".001", because it does not find a decimal point.
What ways could I use to correctly (and generally) read integers among other decimals?
Could I specify "unformatted" input only for a number of "spaces"?
The data edit descriptor fw.d for floating point format specification is for input normally used with zero d (it cannot be ommited). Nonzero d is used in the rare case when the floating point data is stored as scaled integers, or you do some unit conversion from the integer values.
You could try using list-directed input: use a * instead of a format specifier. This would be for the entire read, not selected items. Or you could read the lines into a string test their contents to decide how to read them. If the sub-string has a decimal point: read (string(M:N), '(F5.3)') value. If it doesn't, use a different format, e.g., perhaps read as as F5.0.
P.S. "unformatted" is reading binary data without conversion ... it is a direct copy of the data from the file to the data item. "listed-directed" is the Fortran term for reading & converting data without using a format specification.
well here's someting new to me: f90 allows a mix of comma and space delimiters for a simple list directed read:
read(unit,*)v1,v2,v3,v4
with input
1.222 2 , 3.14 , 4
yields
1.222000 2.000000 3.140000 4.000000