sql adding specific columns - sql

Question

I have a table in oracle containing fields
id,location,stock,rate
select decode(grouping(id),1,'Total',id) id,loction,
sum(stock) stock,avg(rate) rate from product
group by rollup(id),location
I have got
ID Location stock rate
------------------------------------------
A xx 2 10
A xy 5 20
Total 7 10
B SD 3 4
B RT 6 10
Total 9 7
C FG 12 12
C GH 20 18
Total 32 15
**Now I want a row of Total rows where sum of stock and
sum of rate is shown.**
My desired output is
ID Location stock rate
------------------------------------------
A xx 2 10
A xy 5 20
Total 7 10
B SD 3 4
B RT 6 10
Total 9 7
C FG 12 12
C GH 20 18
Total 32 15
Grand Total 48 32
Note : Rate is not average but sum of average rate of total rows.

Answer 1

You could use UNION to append the total:
select decode(grouping(id),1,'Total',id) id,loction,
sum(stock) stock,avg(rate) rate from product
group by rollup(id),location
UNION
select 'Grand Total','',sum(stock) stock,sum(rate) rate
from product
If you weren't mixing different aggregates you could get a grand total with ROLLUP or with grouping sets, but I don't think you can get a SUM() grand total with AVG() subtotals.

Answer 2

Doing a rollup on all columns will produce the grand total:
select (case when grouping(id) = 1 then 'Total' else id end) as id, loction,
sum(stock) stock,avg(rate) rate
from product
group by rollup(id, location)
However, you do not want the rollup on location. So you can filter that out with a having clause:
select (case when grouping(id) = 1 then 'Total' else id end) as id, loction,
sum(stock) stock, avg(rate) rate
from product
group by rollup(id, location)
having not (grouping(product.location) = 1 and grouping(product.id) = 0);

Answer 3

May be like this:
select decode(grouping(id),1,'Total',id) id,loction,
sum(stock) stock,avg(rate) rate from product
group by rollup(id),location
union
select sum(stock), sum(rate) from
(
select decode(grouping(id),1,'Total',id) id,loction,
sum(stock) stock,avg(rate) rate from product
group by rollup(id),location
) where id='Total' group by id;