The value of variables in a process after few executions - variables

Let say I have some process in which i have initialized some variable.
process (clk) is
variable integer := 0;
begin
if (clk'event and clk='1') and (integer<32) then
integer := integer +1;
end if;
if (integer = 32) then
BusyOUT <= '1'; -- This is some outside signal
end if;
end proces;
Will this code set integer to 0 each time clk is on rising edge (since it will execute the entire code), or will it initialize integer to 0 only once (on first read rising edge of the clock, since it is in sensitivity list) and than increment it every time the clk is on rising edge until it reaches 32 and than it will activate the control BusyOUT signal (some outer signal) with which it will stop raising integer?
Thanks in advance,
Bojan

Yes, in meanwhile I figured that the part between the process and begin is executed only once.

Related

Variable use in VHDL

I was reading some codes in VHDL and saw this example:
signal count : integer range 0 to width;
begin
process(clk, rst)
variable temp : integer range 0 to width;
begin
temp := count + 1;
count <= temp;
end process;
what's the purpose of count signal here? Why can't we just use the variable?
Variables are local to the process, and signals are used to communicate between processes.
So you would rather do without the variable, and in the process just have:
count <= count + 1;

Verilog Instantiating module inside a always block. Using Adder for multiplication

I have a code written for multiplying two 53 bit numbers (written below). I am using shift-add strategy using two other 106 bit registers. This code is working fine. Now I have another 53 bit highly optimized hans carlson adder module written in form:
module hans_carlson_adder(input [52:0] a, b, input c_in, output [52:0] sum, output c_out);
I want to use this adder to do the summation line in for loop (mentioned in code). I am having problem instantiating the adder inside an always block. Plus I dont want to have 106 instances (due to for loop) of this adder. Can you please help with this code
module mul1(
output reg [105:0] c,
input [52:0] x,
input [52:0] y,
input clk,
input state
);
reg [105:0] p;
reg [105:0]a;
integer i;
always #(posedge clk) begin
if (state==1) begin
a={53'b0,x[52:0]};
p=106'b0; // needs to zeroed
for(i=0;i<106;i=i+1) begin
if(y[i]) begin
p=p+a; //THIS LINE NEEDS TO BE REPLACED WITH HANS CARLSONADDER
end
a=a<<1;
end
c<=p;
end else begin
c=0;
end
end
endmodule
First you need to instantiate your adder outside of the always block and connect it to signals:
wire [52:0] b;
reg [5:0] count;
assign b = c[count+7'd52:count];
wire [52:0] sum;
wire c_out;
// Add in x depending on the bits in y
// b has the running result bits that still apply at this point
hans_carlson_adder u0(x, b, 1'b0, sum, c_out);
Now because this is a pipelined adder you are going to need something to kick off the multiplication (I'll call that input start) and something that indicates that the result is available (I'll call that output reg done). You'll want to add them to your mul1 module definition. You can choose a slightly different protocol depending on your needs. It appears that you have something that you've been implementing with the input state. I'm also going to use start to initialize during each calculation so that I don't need a separate reset signal.
reg [52:0] shift;
always #(posedge clk) begin
if (start) begin
done <= 0;
count <= 0;
c <= 106'b0;
shift <= y;
end else if (count < 53) begin
if (shift[0]) begin
c[count+7'd52:count] <= sum;
c[count+7'd53] <= c_out;
end
count <= count + 1;
shift = shift >> 1;
end else begin
done <= 1;
end
end
If you want to make an optimization you could end once the shift signal is equal to 0. In this case the done signal would become high as soon as there were no more bits to add into the result, so multiplying by small values of y would take less cycles.

Iteration limit reached - simple counter in VHDL FSM

I'm having "Iteration limit reached" error in a simple FSM.
This is a part of of a bigger FSM I have to do for a class assignment, and I tracked the problem to this specific part.
The FSM will be controlling a counter, the state IDLE waits for inputs, ZERO sets the counter to zero, and the INCREMENT state increments the counter by one.
When simulating, the error occurs at the first time the input "inc" is high and the clock rises.
If I change the statement "temp := temp + 1;" for "temp := anything" the error stops. I really don't know what can be wrong, as for what I have found this error occurs when changing signals in the process sensitivity list inside the process itself.
I'm using Quartus II for the simulation.
Sorry for english mistakes.
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
use IEEE.NUMERIC_STD.all;
entity fsm is
port
(
clock: in std_logic;
reset: in std_logic;
inc: in std_logic;
count: out std_logic_vector (13 downto 0);
cur_state: out std_logic_vector (1 downto 0)
);
end fsm;
architecture behaviour of fsm is
type state_type is (IDLE, INCREMENT, ZERO);
signal PS, NS: state_type;
begin
sync_proc: process (clock, reset)
begin
if (reset = '1') then
PS <= ZERO;
elsif (rising_edge(clock)) then
PS <= NS;
end if;
end process sync_proc;
comb_proc: process (PS, inc)
variable temp: unsigned (13 downto 0);
begin
case PS is
when IDLE =>
if (inc = '1') then
NS <= INCREMENT;
else
NS <= IDLE;
end if;
when INCREMENT =>
temp := temp + 1;
NS <= IDLE;
when ZERO =>
temp := "00000000000000";
NS <= IDLE;
when others =>
NS <= IDLE;
end case;
count <= std_logic_vector(temp);
end process comb_proc;
with PS select
cur_state <= "00" when IDLE,
"01" when INCREMENT,
"10" when ZERO,
"11" when others;
end behaviour;
You have a very serious CONCEPTUAL mistake in your case statement. Because it produces a combinational circuit (the combinational part of your FSM), it does not have memory, so it can't implement the equation "temp := temp + 1" (because, having no memory, it doesn't know what the value of temp is).
You can see more about this in chapter 11 of "Finite State Machines in Hardware...", by V.Pedroni, published by MIT.

Read file line of unknown size as string in VHDL

I'm trying to make a Test Bench where a file of one single line, where posible characters are "1" and "0". I've to read them all, and use one by one as input in my DUT.
So, in my TB, I've defined a process like the following, in order to read the file an pass it values to my DUT.
stim_proc: process
file input_file: TEXT is in "DatosEntrada.dat";
variable rdline : LINE;
variable line_content : string ( 1 to 4);
variable readed_char : character;
variable j : integer := 0;
begin
while not endfile(input_file) loop
readline(input_file, rdline);
--read(rdline, line_content);
for j in 1 to rdline'length-1 loop
readed_char := line_content(j);
if (readed_char = '1') then
input <= '1';
else
input <= '0';
end if;
wait for clk_period;
end loop;
end loop;
end process;
I'm reading the first (and only) line of my file with the first readline execution. After this, this loop shouldn't execute again.
Then, data from file should be inside rdline. So I've to process it. In order to do it, I've tried to loop over rdline length, but this loop doesn't execute.
for j in 1 to rdline'length-1 loop
So I thought I need to read this line in order to loop over it, and tried to move its data to a string var. The problem is that vector var like string need to have a defined size, and I don't know the file line size.
I've tried reading each time 4 chars from rdline into a string, process it, then repeat. However, I couldn't make it work.
I've found quite lot examples about reading files which have defined line formats, like columns or expected integers.
But how can I read an unknown text of one line?
This readed_char := line_content(j); doesn't work when line_content isn't loaded. Otherwise your attempt to read values is basically sound.
The end of line is not contained in a read LINE buffer, there's no reason to not read the last character of rdline. An end of line is signaled by one or more format effectors other than horizontal tab, and just the line contents are present.
There's also this inference that you have some relationship to a clock edge and not just a clock period. The following example shows that. Note you can also supply an offset from an edge using a wait for time_value.
A loop constant is declared in the loop statement. The variable j you declared is not the same j the loop uses. The loop statement hides the j in the outer declarative region (the variable declaration in the process statement).
Your code treats any other character in the string buffer than '1' as a '0'. I didn't change that, do demonstrate it. You should be aware of the impact.
A LINE is an allocated string of some length dependent on the length of a line in your read file. Every time you call readline the string rdline points to is updated. It doesn't leak memory, the previous buffer rdline pointed to released. You can read the length by using the 'RIGHT attribute or as in this case simply consume all the characters.
There may be line length limits in a VHDL tool implementation. There are none defined in the standard other than the maximum length of a string (POSITIVE'RIGHT).
An MCVE:
library ieee;
use ieee.std_logic_1164.all;
use std.textio.all;
entity foo is
end entity;
architecture fum of foo is
signal input: std_logic ;
signal clk: std_logic := '0';
constant clk_period: time := 10 ns;
begin
stim_proc:
process
file input_file: TEXT is in "DatosEntrada.dat";
variable rdline: LINE;
-- variable line_content : string ( 1 to 4);
-- variable readed_char : character;
-- variable j: integer := 0;
begin
while not endfile(input_file) loop
readline(input_file, rdline);
--read(rdline, line_content);
-- for j in 1 to rdline'length - 1 loop -- EOL not in rdline
for j in rdline'range loop
-- readed_char := line_content(j);
-- if readed_char = '1' then
if rdline(j) = '1' then -- changed
input <= '1';
else
input <= '0';
end if;
-- wait for clk_period; -- sync to edge instead
wait until falling_edge(clk); -- input related to clk edge
end loop;
end loop;
wait; -- added prevents needless loops
end process;
CLOCK:
process
begin
wait for clk_period/2;
clk <= not clk;
if now > 32 * clk_period then
wait;
end if;
end process;
end architecture;
And for DatosEntrada.dat containing:
11011110001HELLO11230000
That produces:
Where you can see all non '1' characters are interpreted as '0'.

Baud Rate Clock VHDL -- floating point exception error and/or style issues

I am trying to build a generic baud rate generator process for a uart transmitter.
The transmitter works fine if I ignore the baud rate divider and pass in the clk signal in the sensitivity list. But I get errors (describe in code comments) if I try to implement the divider. I tried two different methods and both either gave an error, or did not have the expected output. Yes, the exact code posted will not work since I assign fbaud twice, I comment one out to test.
Perhaps I don't understand how the baud generator is supposed to work. From my understanding, the fpga clock runs at 50mHz which is to fast for the rs232 communication. So we need to wait a certain number of clock cycles before we can transmit our character.
In this case, we have a variable baud so we divide the stock clock by the baud generator to get the number of clock cycles we need to wait before sending our 'tick' signal to the transmit state machine.
The baud divider is set in the test bench to x"000008".
-- Universal Asynch Receiver Transmitter
---------------------
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity eds_uart is
generic (width : positive := 16);
port ( clk,reset: in std_logic ;
din_wen: in std_logic; -- state machine sets value thus buffer needed
brd : in std_logic_vector(23 downto 0); -- buad rate dividor
din : in std_logic_vector(7 downto 0); -- input value
txd: out std_logic; -- sent data bit
tx_busy : buffer std_logic -- sent data bit active
);
end entity eds_uart;
architecture behaviour of eds_uart is
type state_type is (idle_s, wait_s, transmit_s); -- three possible states of uat
signal current_s: state_type;
signal tick: std_logic := '0'; -- baud rate clock
signal count: integer := 0; -- count number of characters sent
signal shift: std_logic_vector(9 downto 0); -- intermediate vector to be shifted
signal fbaud: integer := 0;
signal fbaud_counter: integer := 0;
begin
--- process that is causing the issue.
process(clk, brd) begin
fbaud <= (50000000)/to_integer(signed(brd)); -- 50,000,000 is the default clock Hz
------ error message ------
--# ** Warning: NUMERIC_STD.TO_INTEGER: metavalue detected, returning 0
-- # Time: 0 ns Iteration: 0 Instance: /eds_uart_tb/inst_uart
-- # ** Fatal: (SIGFPE) Floating point exception.
--# Time: 0 ns Iteration: 0 Process: /eds_uart_tb/inst_uart/line__29 File:
fbaud <= 50000;
--- error ---
-- this command simply does not work, it compiles and runs though
-- I don't get any transitions in my output wave
-- I don't think it is entering the transmit stage based on a clock signal
if (rising_edge(clk)) then
if (fbaud_counter = fbaud) then -- tick when proper number of counts have appeared
tick <= '1';
elsif (fbaud_counter < fbaud) then
tick <= '0';
fbaud_counter <= fbaud_counter + 1;
end if;
end if;
end process;
process(tick, reset, din) begin
if (reset = '1') then
current_s <= idle_s; -- default state
count <= 0; -- reset character counter
txd <= '1';
tx_busy <= '0';
elsif (current_s = idle_s and din_wen = '1') then -- transition when write enable is high
current_s <= wait_s; -- transition
tx_busy <= '1';
shift <= '1' & din & '0'; -- init shift value
end if;
if(rising_edge(tick)) then
if (current_s = wait_s) then -- transition on clock signal
current_s <= transmit_s;
elsif (current_s = transmit_s) then -- transition on clock signal
if (count < 9) then
txd <= shift(0); -- output value
shift <= '0' & shift(9 downto 1); -- shift to next value
count <= count + 1; -- increment counter
current_s <= transmit_s; -- dont change state
elsif (count = 9) then
txd <= shift(0); -- send last element
count <= 0;
tx_busy <= '0'; -- reset busy signal
current_s <= idle_s; -- start process again
end if;
end if;
end if;
end process;
end architecture behaviour ;
There are a few potential problems with this code, but what seems to be causing your failure is that you're declaring fbaud_counter as an integer but with no range limit specified, and more critically, you're not clearing it when it reached your fbaud count value. Since you never reset the value after the count is reached, it will continue counting through all 2^32 values before it wraps around and matches fbaud again. A range limit is probably a good idea anyway, but either way, if you don't reset it, your baud rate will not be correct. For instance:
if (rising_edge(clk)) then
if (fbaud_counter = fbaud - 1) then
tick <= '1';
fbaud_counter <= 0;
else
tick <= '0';
fbaud_counter <= fbaud_counter + 1;
end if;
end if;
Note that there's really no need for an elsif condition there, as there really isn't a condition where you don't otherwise want to set tick to '0' or increment your count. Note that I'm also counting to fbaud - 1 - If you start at 0, counting all the way to fbaud may put your rate off very slightly.
edit
I simulated the above with the changes I recommended to the process, and I got a response on txd (as well as a steady tick). Are you sure you're simulating long enough? Assuming your clock is set up to be 50 MHz as your code indicates it should be, setting brd to x"000008" will give you an incredibly slow tick rate (8 Hz, oddly enough). I reduced the numerator to 5000 just to speed things up a bit.
I also realize I didn't cover your floating point exception (thanks for pointing that out).
The warning is a hint as to the error. "metavalue detected, returning 0". The warning indicates to_integer is trying to convert a value that it can't resolve to a 1 or 0 (e.g. 'X', or another such std_logic value), and of course you can't divide by 0. This is most likely an initialization problem (note that your fatal error says Time: 0 ns Iteration: 0). In your testbench, how is brd driven initially? Can you give it a default value? If not, you will need to guard against this condition some other way.
When you simulate it it sounds like your brd input is not initialized, so the Us are turning into 0s and you are dividing by zero - hence the exception.
Also, this will synthesise to something very big, resource-wise:
fbaud <= (50000000)/to_integer(signed(brd));
You are asking for this to be calculated every clock cycle, which is a big ask from the hardware.
The usual method is to accept a terminal count (your fbaud) as the input and let the controlling software figure out what the value should be. Or calculate it at compile time as a constant, depending on how flexible you need to be.