I have a file and I checkout using the command (BZR CHECKOUT ...). Now, I made a lot of commits and found out there are errors in my codes. I want to revert all my files back to its original form after I first checkout. can anybody help me with a step-by-step process/command. thanks!
You can revert your pending (= uncommitted) changes with:
bzr revert
Or if you want to return to the state of a past revision, let's say revision 17, you can do:
bzr update -r 17
Related
The bzr documentation states http://doc.bazaar.canonical.com/bzr-0.10/bzr_man.htm
bzr update: ... If you want to discard your local changes, you can just do a
bzr revert instead of bzr commit after the update.
However this is not what I am getting. I have new files in my repo and all I want is to have the latest revision in my working directory and to have bzr status show anything as being changed.
Is this possible?
First of all, you're looking at an extremely old version of the doc.
As of version 2.6 (current stable),
the description of bzr update is longer, and very different:
Description:
This will perform a merge of the destination revision (the tip of the
branch, or the specified revision) into the working tree, and then make
that revision the basis revision for the working tree.
You can use this to visit an older revision, or to update a working tree
that is out of date from its branch.
If there are any uncommitted changes in the tree, they will be carried
across and remain as uncommitted changes after the update. To discard
these changes, use 'bzr revert'. The uncommitted changes may conflict
with the changes brought in by the change in basis revision.
If the tree's branch is bound to a master branch, bzr will also update
the branch from the master.
You cannot update just a single file or directory, because each Bazaar
working tree has just a single basis revision. If you want to restore a
file that has been removed locally, use 'bzr revert' instead of 'bzr
update'. If you want to restore a file to its state in a previous
revision, use 'bzr revert' with a '-r' option, or use 'bzr cat' to write
out the old content of that file to a new location.
The 'dir' argument, if given, must be the location of the root of a
working tree to update. By default, the working tree that contains the
current working directory is used.
Aliases: up
See also: pull, status-flags, working-trees
Your question is not very clear.
When you're working in centralized mode,
you have a working tree you created with bzr checkout,
the bzr update command will bring in the new revisions that were added in the central repository.
If your working tree was clean (bzr status showing no changes) before bzr update,
then your working tree will be updated to the latest version (as it is on the central server),
and your working tree will be still clean.
If your working tree wasn't clean before bzr update,
then Bazaar will try to merge the new revisions on the server into your working tree,
and conflicts may happen.
If the changes you had were exactly as what the new revisions changed,
then you will end up with a clean working tree, which is extremely rare.
Most commonly,
if your working tree had changes before bzr update,
it will most probably have changes after, and possibly conflicts too.
The bzr status will tell you what they are.
It's best to not have pending changes before running bzr update.
Specifically I have a repository setup in Launchpad. I need to remove this repository but didn't find any link to do that from launchpad website. I am wondering whether I could do it on my local branch using "bzr". Or I am missing something from the launchpad website to remove it.
To have your entire project deleted from Launchpad, you have to post a "question" on this page:
https://answers.launchpad.net/launchpad/+addquestion
Yeah it's weird. But this seems to be the official way. If you search for the keywords "delete project" on this page you will find many many similar requests:
https://answers.launchpad.net/launchpad
Make sure to include a detailed explanation why you want to do this and that you are aware of the consequences. Otherwise you will get a response along the lines "the community might still use the source code you want to delete" and so on.
Of course they are right, and you should carefully consider whether you really want to remove code that other folks might be using and linking to.
If you are sure you want the project gone, then you can reduce the turnaround time with the Launchpad team by first deleting all your branches. You might not be able to delete the trunk, in that case you can try to force-overwrite it with an empty branch, using these steps:
bzr init empty
cd empty
touch empty.txt
bzr add
bzr commit -m 'dummy commit'
bzr push lp:PROJECT --overwrite
Of course, replace PROJECT with the name of your project. All these steps are necessary to empty the branch. You cannot simply push an empty branch, Bazaar will tell you that No new revisions or tags to push. and the branch will be untouched. You need a completely new revision, like the dummy revision in this example.
If your project has no meaningful source code in it, the Launchpad team should not have any objections to delete it, so you can reduce the turnaround time.
Quite often I will start coding a feature on our trunk (AKA HEAD) and after starting to change the code realize that I probably want to do this on a branch. This is fairly easy to do, I simply create the branch with something like:
cvs rtag forkName all
cvs rtag -b branchName -r forkName all
Then from my modified workspace I morph it into the created branch:
cvs up -r branchName
The problem I'm having is that any file that has been added previously is not morphed over to the branch but remains "added" to the trunk.
To fix this, I've gone into the CVS/Entries file and appended the branch tag to the added file entries (don't try this without parental supervision kids).
Is there a better way?
Since your CVS repository does not know about your new files, they keep being added to the trunk. If you would commit them using:
cvs commit -r branchName
they should get the branch tag and any further commits can be normal.
Hit the following situtation a couple of times today:
Myself and another dev both have bazaar local checkouts of a repository.
I make some changes.
The other dev makes and commits some changes.
I update.
The other dev realises their previous changes were broken and uncommits them.
I update.
Now the other dev's uncommitted changes appear as a pending merge in my local checkout, and I can't find a way to separate them from my changes and remove them from my 'local' tree.
Every time this has happened I've had to manually work out which changes are mine and which are not, save my changes, revert, and then re-apply my changes.
I've tried doing a "cherrypicking" reverse merge on my checkout between -r -1..-2, and between -r 0..-1, but neither helped. (0..-1 said "nothing to do", although I might not have done it properly. -1..-2 was the wrong set of changes and thus made things worse.)
How can I fix this situation when it happens (other than going over and smacking the other dev upside the head)?
It is recommended that you don't uncommit in branches that are published somehow, thus avoiding this issue.
Well once you have updated (step 4), the other guy's changes will be merged with yours permanently. Since your changes were uncommitted, they aren't stored anywhere. Therefore, once step 6 has happened, I don't really see a way of automatically separating out your changes from his.
So let's say you manually remove all of his changes so you're just left with yours. You still have this pending merge to deal with. You can fix that by typing
$ bzr revert --forget-merges
That will not change your working tree; it will only remove the pending merge from your "bzr st" so that when you commit it will not look like a merge. This should save you from having to save your changes, revert and re-apply.
To avoid this happening again, you could run bzr update only immediately before you commit. Once merged, to a bzr commit right away, and your changes are locked in. Now he won't be able to uncommit without first updating and seeing your changes, and now it's probably too late for him to do that. If he really wants to go ahead with his uncommit, he's the one that has to deal with the mess, not you.
One final thing you can do -- if you really don't want to deal with it and you don't care too much about having a nice version history. After step 6, just commit. Maybe explain in your log that the other dev uncommitted this change but too late.
This is where the pending merge comes in. If you commit, the uncommitted revision will go back into the repository, as a branch, just as if the other dev had send those changes to you in an email and you merged them. It will look like this:
------------------------------------------------------------
revno: 34 [merge]
committer: You
branch nick: trunk
timestamp: Fri 2010-11-26 15:57:27 +1100
message:
Made my changes to the file.
Note, other guy did some of these changes and uncommitted, but
I already merged.
------------------------------------------------------------
revno: 33.1.1
committer: Other Guy
branch nick: trunk
timestamp: Fri 2010-11-26 15:39:39 +1100
message:
Made some changes to the file.
------------------------------------------------------------
When he runs update again, he'll have his old changes thrown back at him, and probably get a conflict. He'll have to clean it up, then commit his fixes (whatever reason he had to uncommit in the first place). This is probably just as effective as a smack upside the head, and works over a network :)
It looks like bzr pull --overwrite :bound is what you're after.
Is it possible to emulate the behavior of 'git stash' when using fossil/bzr?
Basically I'm interested in handling the following workflow:
at some point the source code tree has state X, it is commited
I proceed to writing new code, I write it for a while and I see the
opportunity of a refactoring
I can't commit at this point, because the change I've started to make is not
completed, it is not atomic yet
at this point I would do 'git stash', would save the current work and would
get back to state X
I would do the refactoring and commit, source code now has state Y
I would merge source code in state Y with code in stash, complete the change
to make it atomic, then commit once again, pushing the source code to state Z
I think that generally it is possible to emulate this scenario when using
another SCM by branching the code in state X instead of doing 'git stash',
doing the refactoring in that branch, then merging the branch back into the
main one. But I'm aware that branching is not always a cheap operation. So are
there any better particular approaches that eventually rely on specific
features of fossil/bzr?
Use bzr shelve and bzr unshelve commands.
You can use the patch command of your system.
First you make a "stash" by storing a generated diff as .patch file:
$scmtool diff > working.patch
then reset your working directory.
later, apply the patch with:
patch -p1 --dry-run < working.patch
and then this works, remove the --dry-run to apply the patch for real.
The stash command was implemented in fossil recently. You got to check out latest fossil executable you will see stash in the available command list.
Here is the link to the web help on its syntax.