I am trying to match the string below but unfortunately it only gives me "nope" as the result. Can anyone help? thanks in advance!
NSMutableAttributedString *text = [NSMutableString stringWithString:#"darn thing suddenly erupted without any warning.";
NSString *findMe = #"suddenly erupted";
[text enumerateSubstringsInRange:NSMakeRange(0, [text length]) options:NSStringEnumerationByWords usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
if ([findMe isEqualToString:substring] ) {
NSLog(#"found it");
}
else {
NSLog(#"nope");
}
}];
Your method is only enumerating separate words. "suddenly erupted" are two words.
Why don't you use -rangeOfSubstring: in order to find whether text contains some substring? For example:
NSLog(#"%#",[[text mutableString] rangeOfString:findMe].location == NSNotFound ? #"nope" : #"found it");
enumerateSubstringsInRange have options like
NSStringEnumerationByLines
NSStringEnumerationBySentences
NSStringEnumerationByParagraphs
NSStringEnumerationByComposedCharacterSequences
NSStringEnumerationByWords
if you have words to compare means it will work
e.g
NSString *text = #"darn thing suddenlyerupted without any warning.";
NSString *findMe = #"suddenlyerupted";
so you cant compare sub string. You need to customize the block or move to some other option.
Related
I have an task where I need to count the occurrences of errors in a log file and I know how to do that. Now Im trying to change the font color of these occurrences. I have it kinda working but it doesn't change the whole word to the wanted color and for the next occurrence of that string it shifts over 3 characters.
See image below.
I searched for the word "Checked" and it gave me these results.
Below is the code that I am using
NSArray * lines = [words componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]];
wordresult = [lines componentsJoinedByString:#""];
if (occS2 == 1)
{
NSString * box2 = [_occSearchTwoTextBox stringValue];
NSUInteger countFatal = 0, length4 = [wordresult length];
NSRange range4 = NSMakeRange(0, length4);
while(range4.location != NSNotFound)
{
range4 = [wordresult rangeOfString: box2 options:NSCaseInsensitiveSearch range:range4];
[self.stringLogTextView setTextColor:[NSColor redColor] range:range4];
NSLog(#"Occurance Edited");
if(range4.location != NSNotFound)
{
range4 = NSMakeRange(range4.location + range4.length, length4 - (range4.location + range4.length));
countFatal++;
}
}
NSString * FatalCount = [NSString stringWithFormat:#"%lu", (unsigned long)countFatal];
[_customSearchTwoTextBox setStringValue:FatalCount];
}
Can anyone please point me to where to why its shifting? I can only assume that it has something to do with my range but I'm not sure what to do to resolve.
Thanks for everyones time!
I'm not sure why your method isn't working correctly, but I would do it a different way. Using enumerateSubstringsInRange:options:usingBlock:, you can enumerate your string by word, and get the range of each word passed in to the method for you. If the word is "Checked", you can increment your count and also set the attributes for that range of a mutable attributed string. Here is an example of how to use that method,
NSString *theText = #"] Tables initialized\n]Database version Checked\n]Got login id-1\n] Tables initialized\n]Database version Checked\n]Got login id-1\n] Tables initialized\n]Database version Checked\n]Got login id-1\n";
NSMutableAttributedString *attrib = [[NSMutableAttributedString alloc] initWithString:theText];
NSDictionary *dict = #{NSForegroundColorAttributeName:[NSColor greenColor]};
__block int count = 0;
[theText enumerateSubstringsInRange:NSMakeRange(0, theText.length) options:NSStringEnumerationByWords usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
if ([substring isEqualToString:#"Checked"]) {
[attrib setAttributes:dict range:substringRange];
count ++;
};
}];
self.textView.textStorage.attributedString = attrib;
NSLog(#"count is: %d",count);
I need to get the word that comes after a certain sign, and remove it.
example :
NSString *me=#" i am going to make !somthing great" ;
I need to remove the word something, together with the ! sign, where ever it will occur in that text.
Is there some method like stringByReplacingOccurrencesOfString: to not only find the sign ,but identify the word that attached to it ?
Thanks.
You want a regular expression. In this case, you want one with the pattern #"!\w*". (An NSScanner would also work, but I think a regular expression is more concise in this case.)
If you have reasons not to use regular expressions (or if you are not familiar with them) you can use following
NSString *me=#" i am going to make !somthing great" ;
NSRange r1 = [me rangeOfString:#"!"];
if (r1.location != NSNotFound) {
NSRange r2 = [me rangeOfCharacterFromSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]
options:0
range:NSMakeRange(r1.location, me.length - r1.location)];
if (r2.location != NSNotFound) {
me = [me stringByReplacingCharactersInRange:NSMakeRange(r1.location, r2.location - r1.location) withString:#""];
}
}
Here's code:
NSMutableString *mutableMe = [me mutableCopy];
NSError *error;
NSRegularExpression *regex = [[NSRegularExpression alloc] initWithPattern:#"!\\w*" options:0 error:&error];
[regex replaceMatchesInString:mutableMe options:0 range:NSMakeRange(0, [mutableMe length]) withTemplate:#""];
If you want to find it first than use
[regex enumerateMatchesInString:mutableMe options:0 range:NSMakeRange(0, [mutableMe length]) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSRange rangeOfString = [result rangeAtIndex:0];
[mutableMe replaceCharactersInRange:rangeOfString withString:#""];
}];
Try following syntax this can help you
NSString *replacedString=[NSString stringByReplacingOccurancesOfString:#"!something" withString:#" "];
I have a block of text (a newspaper article if it's of any relevance) was wondering if there is a way to extract all sentences containing a particular keyword in objective-c? I've been looking a bit at ParseKit but aren't having much luck!
You can enumerate sentences using native NSString methods like this...
NSString *string = #"your text";
NSMutableArray *sentences = [NSMutableArray array];
[string enumerateSubstringsInRange:NSMakeRange(0, string.length)
options:NSStringEnumerationBySentences
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
//check that this sentence has the string you are looking for
NSRange range = [substring rangeOfString:#"The text you are looking for"];
if (range.location != NSNotFound) {
[sentences addObject:substring];
}
}];
for (NSString *sentence in sentences) {
NSLog(#"%#", sentence);
}
At the end you will have an array of sentences all containing the text you were looking for.
Edit: As noted in the comments there are some inherit weaknesses with my solution as it requires a perfectly formatted sentence where period + space is only used when actually ending sentences... I'll leave it in here as it could be viable for people sorting a text with another (known) separator.
Here's another way of achieving what you want:
NSString *wordYouAreLookingFor = #"happy";
NSArray *arrayOfSentences = [aString componentsSeparatedByString:#". "]; // get the single sentences
NSMutableArray *sentencesWithMatchingWord = [[NSMutableArray alloc] init];
for (NSString *singleSentence in arrayOfSentences) {
NSInteger originalSize = [singleSentence length];
NSString *possibleNewString = [singleSentence stringByReplacingOccurrencesOfString:wordYouAreLookingFor withString:#""];
if (originalSize != [possibleNewString length]) {
[sentencesWithMatchingWord addObject:singleSentence];
}
}
I have been trying to use Regular Expression to separate full sentences in a big block of text. I can't use the componentsSeparatedByCharactersInSet because it will obviously fail with sentences ending in ?!, !!, ... I have seen some external classes to do componentSeparateByRegEx but I prefer doing it without adding an external library.
Here is a sample input
Hi, I am testing. How are you? Wow!! this is the best, and I am happy.
The output should be an array
first element: Hi, I am testing.
second element: How are you?
third element: wow!!
forth element: this is the best, and I am happy.
This is what I have but as I mentioned it shouldn't do what I intend. Probably a regular expression will do a much better job here.
-(NSArray *)getArrayOfFullSentencesFromBlockOfText:(NSString *)textBlock{
NSMutableCharacterSet *characterSet = [[NSMutableCharacterSet alloc] init];
[characterSet addCharactersInString:#".?!"];
NSArray * sentenceArray = [textBlock componentsSeparatedByCharactersInSet:characterSet];
return sentenceArray;
}
Thanks for your help,
You want to use -[NSString enumerateSubstringsInRange:options:usingBlock:] with the NSStringEnumerationBySentences option. This will give you every sentence, and it does so in a language-aware manner.
NSArray *fullSentencesFromText(NSString *text) {
NSMutableArray *results = [NSMutableArray array];
[text enumerateSubstringsInRange:NSMakeRange(0, [text length]) options:NSStringEnumerationBySentences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
[results addObject:substring];
}];
return results;
}
Note, in testing, each substring appears to contain the trailing spaces after the punctuation. You may want to strip those out.
Something like this could do the job:
NSString *msg = #"Hi, I am testing. How are you? Wow!! this is the best, and I am happy.";
[msg enumerateSubstringsInRange:NSMakeRange(0, [msg length])
options:NSStringEnumerationBySentences | NSStringEnumerationLocalized
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop)
{
NSLog(#"Sentence:%#", substring);
// Add each sentence into an array
}];
Or use:
[mutstri enumerateSubstringsInRange:NSMakeRange(0, [mutstri length])
options:NSStringEnumerationBySentences
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop){
NSLog(#"%#", substring);
}];
I am trying to write a method:
- (NSDictionary *)wordFrequencyFromString:(NSString *)string {}
where the dictionary returned will have the words and how often they were used in the string provided. Unfortunately, I can't seem to find a way to iterate through words in a string to analyze each one - only each character which seems like a bit more work than necessary. Any suggestions?
NSString has -enumerateSubstringsInRange: method which allows to enumerate all words directly, letting standard api to do all necessary stuff to define word boundaries etc:
[s enumerateSubstringsInRange:NSMakeRange(0, [s length])
options:NSStringEnumerationByWords
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
NSLog(#"%#", substring);
}];
In the enumeration block you can use either NSDictionary with words as keys and NSNumber as their counts, or use NSCountedSet that provides required functionality for counts.
You can use componentsSeparatedByCharactersInSet: to split the string and NSCountedSet will count the words for you.
1) Split the string into words using a combination of the punctuation, whitespace and new line character sets:
NSMutableCharacterSet *separators = [NSMutableCharacterSet punctuationCharacterSet];
[separators formUnionWithCharacterSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
NSArray *words = [myString componentsSeparatedByCharactersInSet:separators];
2) Count the occurrences of the words (if you want to disregard capitalization, you can do NSString *myString = [originalString lowercaseString]; before splitting the string into components):
NSCountedSet *frequencies = [NSCountedSet setWithArray:words];
NSUInteger aWordCount = [frequencies countForObject:#"word"]);
If you are willing to change your method signature, you can just return the counted set.
Split the string into an array of words using -[NSString componentsSeparatedByCharactersInSet:] first. (Use [[NSCharacterSet letterCharacterSet] invertedSet] as the argument to split on all non-letter characters.)
I used following approach for getting most common word from NSString.
-(void)countMostFrequentWordInSpeech:(NSString*)speechString
{
NSString *string = speechString;
NSCountedSet *countedSet = [NSCountedSet new];
[string enumerateSubstringsInRange:NSMakeRange(0, [string length])
options:NSStringEnumerationByWords | NSStringEnumerationLocalized
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop){
[countedSet addObject:substring];
}];
// NSLog(#"%#", countedSet);
//Sort CountedSet & get most frequent common word at 0th index of resultant array
NSMutableArray *dictArray = [NSMutableArray array];
[countedSet enumerateObjectsUsingBlock:^(id obj, BOOL *stop) {
[dictArray addObject:#{#"object": obj,
#"count": #([countedSet countForObject:obj])}];
}];
NSArray *sortedArrayOfWord= [dictArray sortedArrayUsingDescriptors:#[[NSSortDescriptor sortDescriptorWithKey:#"count" ascending:NO]]];
if (sortedArrayOfWord.count>0)
{
self.mostFrequentWordLabel.text=[NSString stringWithFormat:#"Frequent Word: %#", [[sortedArrayOfWord[0] valueForKey:#"object"] capitalizedString]];
}
}
"speechString" is my string from which I have to get most frequent/common words. Object at 0th index of array "sortedArrayOfWord" would be most common word.