I want to truncate duplicate rows but Qty should be added.
I have a table filled with data,
Item Qty MinQty MaxQty
ABC 10 20 50
XYZ 12 30 40
ABC 15 20 50
I want the result like,
Item Qty MinQty MaxQty
ABC 25 20 50
XYZ 12 30 40
Kindly help me to write the query for the same...
SELECT Item, SUM(Qty), MIN(MinQty), MAX(MaxQty)
FROM tablename
GROUP BY ITem;
The answer above is right, but you would also want to give the derived columns names:
SELECT Item, SUM(Qty) as Qty, MIN(MinQty) as MinQty, MAX(MaxQty) as MaxQty
FROM tablename
GROUP BY ITem;
Related
I am trying to extract itemised sales data for the past 12 months and build a dynamic table with column headers for each month ID. Extracting the data as below works, however when I get to the point of creating a SUM column for each month ID, I get stuck. I have tried to find similar questions but I'm not sure of the best approach.
Select Item, Qty, format(Transaction Date,'MMM-yy')
from Transactions
Data Extract:
Item
Qty
Month ID
A123
50
Apr-22
A123
30
May-22
A123
50
Jun-22
A321
50
Apr-22
A999
25
May-22
A321
10
Jun-22
Desired Output:
Item
Apr-22
May-22
Jun-22
A123
50
30
50
A321
50
Null
10
A999
Null
25
Null
Any advice would be greatly appreciated.
This is a typical case of pivot operation, where you
first filter every value according to your "Month_ID" value
then aggregate on common "Item"
WITH cte AS (
SELECT Item, Qty, FORMAT(Transaction Date,'MMM-yy') AS Month_ID
FROM Transactions
)
SELECT Item,
MAX(CASE WHEN Month_ID = 'Apr-22' THEN Qty END) AS [Apr-22],
MAX(CASE WHEN Month_ID = 'May-22' THEN Qty END) AS [May-22],
MAX(CASE WHEN Month_ID = 'Jun-22' THEN Qty END) AS [Jun-22]
FROM cte
GROUP BY Item
Note: you don't need the SUM as long as there's only one value for each couple <"Item", "Month-Year">.
I have 3 tables.
For simplicity I changed them to these sample tables.
table1: CorporateActionSmmary
RATE Quantity ProductID
--------------------------
56 0 1487
30 0 1871
40 0 8750
table2# ProductMaster
RATEGROSS ISIN ProductID
--------------------------
60 JP0001 1487
33 JP0002 1871
45 JP0003 8750
table3# OpenPosition
Quantity ProductID
-------------------
5 1487
1 1487
5 1487
3 1871
2 1871
4 8750
2 8750
7 8750
3 8750
First I need to add ISIN from table2 to table1
table1: CorporateActionSmmary
RATE Quantity ProductID ISIN
-------------------------------------
56 0 1487 JP0001
30 0 1871 JP0002
40 0 8750 JP0003
So, I used this code
SELECT [dbo].[CorporateActionSummary].*, [dbo].[ProductMaster].[ISIN]
FROM [dbo].[CorporateActionSummary] JOIN [dbo].[ProductMaster] ON CorporateActionSummary.ProductID = ProductMaster.ProductID
Now as you can see the Quantity is missing in Table1 so I have to add-up all the quantities in Table3 for each product ID and add to Table1(as a new column or over-write the Quntity column)
I think I can get the sum of each ProductID's Quantity by the following code, But how can I add it to Table1 that already has ISIN column
SELECT SUM(Qantity),ProductID
FROM [dbo].[OpenPositions]
I am super new to SQL, please explain in detail if it is possible, thank you
I am using Microsoft SQL Server Management Studio
you can sum the quantities and then join with your query like so:
SELECT CA.*, PM.[ISIN],CA.Quantity
FROM [dbo].[CorporateActionSummary] CA
JOIN [dbo].[ProductMaster] PM
ON CA.ProductID = PM.ProductID
JOIN (
SELECT ProductID, SUM(Qantity) Quantity
FROM [dbo].[OpenPositions]
GROUP BY ProductID
) OO
on OO.ProductID = CA.ProductID
you are almost there.. you just need to use the same logic to join to the product master table. However, since you need the total of quantity, you need to group by the other columns you select (but not aggregate).
The query will be something like this :
SELECT
[dbo].[CorporateActionSummary].ProductID
, [dbo].[ProductMaster].[ISIN]
,sum([OpenPosition].Quantity) as quantity
FROM [dbo].[CorporateActionSummary]
JOIN [dbo].[ProductMaster]
ON CorporateActionSummary.ProductID = ProductMaster.ProductID
JOIN [dbo].[OpenPosition]
ON CorporateActionSummary.ProductID = OpenPosition.ProductID
group by
[dbo].[CorporateActionSummary].ProductID
, [dbo].[ProductMaster].[ISIN]
if you want to add more columns to your select, then you need to group by those colums as well
I have a table like this:
empID name amt Date
------------------------------------
1 mark 20 22-10
1 mark 30 22-10
2 kane 50 22-12
2 kane 60 22-12
3 mike 60 22-10
and I want to get an output like that
empID name amt Date TOTAL
-----------------------------------------
1 mark 20 22-10 220
1 mark 30 22-10 220
2 kane 50 22-12 220
2 kane 60 22-12 220
3 mike 60 22-10 220
I have used sum(amt) but it is returning only 1 row; I want other rows as well.
You can use the window function sum() over() without any partition or order by
Example
Select *
,[Total] = sum(amt) over()
From YourTable
You need a windowing function
SELECT
empid
,name
,amt
,[date]
,SUM(amt) OVER(PARTITION BY '') AS Total -- as you show it
,SUM(amt) OVER(PARTITION BY empID) AS Total -- as I think you want it
FROM t
Documentation: https://learn.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql?view=sql-server-ver15
Since you need to display the grand total value for each row you don't need to partition or group by. Therefore, you can use SUM(amt) OVER () .
SELECT *,
SUM(amt) OVER () AS [Total]
FROM tabe_c
I have a table in which has duplicate values. by eliminating these values I want sum of distinct values. but without group by.
My table
--------------------------------------
ID City collection
---------------------------------------
1 xyz 5000
2 xyz 5000
3 abc 2000
4 pqr 3000
5 xyz 5000
6 pqr 3000
7 abc 2000
-----------------------------------
I want result of whole collection column but eliminate city name
ex. Result = 10000
not like
xyz 15000
abc 4000
pqr 6000
or not like 25000
but result should be 10000 by eliminated
Get the Distinct combinations of City and Collection first and then do the SUM
select SUM(Collection) as Collection
from
(
select distinct City, Collection
from table
) data
select sum(collection) as output
from
(
select collection, row_number() over(partition by city order by collection) as RN
from yourtable
) as inside
where RN=1
If you just want the sum of the distinct values of the collections column without the city name (I assume this is what you want from your statement "but eliminate city name") then simply run this:
SELECT SUM(DISTINCT [collection]) FROM tableName
This will return the value 10000 like you are after.
If data is in the following format:
SID TID Tdatetime QID QTotal
----------------------------------------
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 10:00AM 67 110
100 2 01/19/97 9:00AM 66 .
100 2 01/19/97 9:00AM 66 110
100 2 01/19/97 10:00AM 66 110
100 3 01/26/97 9:00AM 68 120
100 3 01/26/97 9:00AM 68 120
110 1 02/03/97 10:00AM 68 110
110 3 02/12/97 9:00AM 64 115
110 3 02/12/97 9:00AM 64 115
120 1 04/05/97 9:00AM 66 105
120 1 04/05/97 10:00AM 66 105
I would like to be able to write a query to sum the QTotal column for all rows and find the count of duplicate rows for the Tdatetime column.
The output would look like:
Year Total Count
97 | 1340 | 4
The third column in the result does not include the count of distinct rows in the table. And the output is grouped by the year in the TDateTime column.
The following query may help:
SELECT
'YEAR ' + CAST(sub.theYear AS VARCHAR(4)),
COUNT(sub.C),
(SELECT SUM(QTotal) FROM MyTable WHERE YEAR(Tdatetime) = sub.theYear) AS total
FROM
(SELECT
YEAR(Tdatetime) AS theYear,
COUNT(Tdatetime) AS C
FROM MyTable
GROUP BY Tdatetime, YEAR(Tdatetime)
HAVING COUNT(Tdatetime) >= 2) AS sub
This will work if you really want to group by the tDateTime column:
SELECT DISTINCT tDateTime, SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY tDateTime
HAVING Count(distinct tDateTime) > 1
But your results look like you want to group by the Year in the tDateTime column. Is this correct?
If so try this:
SELECT DISTINCT YEAR (tDateTime), SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY YEAR (tDateTime)
HAVING Count(distinct tDateTime) > 1
You must do SELECT from this table GROUPing by QTotal, using COUNT(subSELECT from this table WHERE QTotal is the same). If I only I had time I would write you SQL statement, but it'll take some minutes.
Something like:
select Year(Tdatetime) ,sum(QTotal), count(1) from table group by year(Tdatetime )
or full date
select Tdatetime ,sum(QTotal), count(1) from table group by year(Tdatetime)
Or your ugly syntax ( : ) )
select 'Year ' + cast(Year(tdatetime) as varchar(4))
+ '|' + cast(sum(QTotal) as varchar(31))
+ '|' + cast(count(1) as varchar(31))
from table group by year(Tdatetime )
Or do you want just the year? Sum all columns? Or just by year?
SELECT
YEar + year(Tdatetime),
SUM ( QTotal ),
(SELECT COUNT(*) FROM (
SELECT Tdatetime FROM tDateTime GROUP BY Tdatetime
HAVING COUNT(QID) > 1) C
FROM
Tdatetime t
GROUP BY
YEar + year(Tdatetime)
This is the first time I have asked a question on stackoverflow. It looks like I have lost my original ID info. I had to register to login and add comments to the question I posted.
To answer OMG Ponies question, this is a SQL Server 2008 database.
#Abe Miessler , the row with SID 120 does not contain duplicates. the first row for SID 120 shows 9:00AM in the datetime column , and the second row shows 10:00AM.
#Zafer, your query is the accepted answer. I made a few minor tweaks to get it to work. Thanks.
Thanks due to Abe Miessler and the others for your help.