pass_id retry_id
1 1
1 2
2 1
2 2
2 3
3 1
3 2
Need to pick up record with MAX(retry_id) within MAX(pass_id).
pass_id retry_id
3 2
Thanks in advance!
The easiest way is with order by and just choosing one row:
select t.pass_id, t.retry_id
from (select t.*
from t
order by pass_id desc, retry_id desc
) t
where rownum = 1
Here is a SQLFiddle.
SELECT *
FROM MyTable
WHERE
retry_id = (Select MAX(retry_id) FROM MyTable) AND
pass_id = (Select MAX(pass_id) FROM MyTable)
Not positive on oracle syntax, but something like
SELECT MAX(retry_ID)
FROM Table
WHERE Pass_ID = (SELECT MAX(Pass_ID)
FROM Table)
Related
Currently my table looks like this; I want to add the count numbers with distinct InstanceId and duplicate values.
Id
InstanceId
Name
1
1
DiscoveryInstance
2
1
DiscoveryInstance
3
2
ETLInstance
4
3
DiscoveryInstance
5
3
DiscoveryInstance
6
2
ETLInstance
7
2
ETLInstance
I want the output to be like this:
Id
InstanceId
Name
1
1
DiscoveryInstance
2
1
DiscoveryInstance_Backup_1
3
2
ETLInstance
4
3
DiscoveryInstance
5
3
DiscoveryInstance_Backup_1
6
2
ETLInstance_Backup_1
7
2
ETLInstance_Backup_2
I don't want to update the first value and update should start with the next duplicate value in the column.
How to update this table to make this output possible in SQL Server query?
EDIT This solution addresses the ORIGINAL question and original output. This is no longer valid because you changed your desired output.
You could use rank() and concat in this manner:
with cte as (select id, name, rank() over (partition by name order by id) as name_rank
from my_table
)
select t.id,
case
when c.name_rank = 1 then t.name
else concat(t.name, '_Backup_', c.name_rank - 1)
end name
from my_table t
join cte c
on t.id = c.id
Output:
id
name
1
DiscoveryInstance
2
DiscoveryInstance_Backup_1
3
ETLInstance
4
DiscoveryInstance_Backup_2
5
DiscoveryInstance_Backup_3
6
ETLInstance_Backup_1
DB-fiddle found here. I see you updated the question after I posted this answer by adding another column, but that does not look important at the moment.
EDIT
This is an updated answer (thanks Guido) that would address your newly updated output:
with cte as (select id, name, rank() over (partition by name, instanceid order by id) as name_rank
from mytable
)
select t.id,
case
when c.name_rank = 1 then t.name
else concat(t.name, '_Backup_', c.name_rank - 1)
end name
from mytable t
join cte c
on t.id = c.id
Another option is using the row_number() like this
This solution uses your new column instanceid to get the correct data
select t.id,
case when rownumber > 1 then t.Name + '_Backup_' + convert(varchar(10), t.rownumber - 1)
else t.Name
end
from ( select t.id,
t.name,
row_number() over (partition by t.Name, t.instanceid order by t.id) as rownumber
from mytable t
) t
order by t.id
See this DBFiddle
output is
id
(No column name)
1
DiscoveryInstance
2
DiscoveryInstance_Backup_1
3
ETLInstance
4
DiscoveryInstance
5
DiscoveryInstance_Backup_1
6
ETLInstance_Backup_1
7
ETLInstance_Backup_2
I have a table as follows:
SampleReq
Group
ID
2
1
_001
2
1
_002
2
1
_003
1
2
_004
1
2
_005
1
2
_006
I want my query to IDs based on the column SampleReq, resulting in the following output:
Group
ID
1
_001
1
_003
2
_006
The query should pick any 2 IDs from group 1, any 1 IDs from group 2 and so on (depending on the column SampleReq).
I tried the query using LIMIT, but this gives me an error saying column names cannot be parsed to a limit.
SELECT Group, ID
FROM Table
LIMIT SampleReq
ORDER BY RAND()
One method is row_number():
select t.*
from (select t.*,
row_number() over (partition by samplereq order by random()) as seqnum
from t
) t
where seqnum <= 2 and id = 1 or
seqnum <= 1 and id = 2;
I've a table that stores the historical data, what i'm trying to do is trying to capture the max seq record. i can do that, but i need to include the tr_type, then i'll use the outupt to join with another table. below is ex of my data
CLM_NO SEQ SUB TR_TYPE
12345 1 1 50
12345 1 2 50
12345 2 1 60
12345 2 2 60
i want to return only the last row
You can try to use exists and correlated subquery
SELECT *
FROM T t1
WHERE exists(
SELECT 1
FROM T tt
GROUP BY tt.CLM_NO
HAVING MAX(tt.SEQ) = t1.SEQ AND MAX(tt.SUB) = t1.SUB
)
EDIT
You can try to use ROW_NUMBER window function.
SELECT * FROM (
SELECT *,ROW_NUMBER() OVER(PARTITION BY CLM_NO ORDER BY TRAN_SEQ DESC,TRAN_SUB DESC) rn
FROM TBL t1
)t1
where rn = 1
I need to select data base upon three conditions
Find the latest date (StorageDate Column) from the table for each record
See if there is more then one entry for date (StorageDate Column) found in first step for same ID (ID Column)
and then see if DuplicateID is = 2
So if table has following data:
ID |StorageDate | DuplicateTypeID
1 |2014-10-22 | 1
1 |2014-10-22 | 2
1 |2014-10-18 | 1
2 |2014-10-12 | 1
3 |2014-10-11 | 1
4 |2014-09-02 | 1
4 |2014-09-02 | 2
Then I should get following results
ID
1
4
I have written following query but it is really slow, I was wondering if anyone has better way to write it.
SELECT DISTINCT(TD.RecordID)
FROM dbo.MyTable TD
JOIN (
SELECT T1.RecordID, T2.MaxDate,COUNT(*) AS RecordCount
FROM MyTable T1 WITH (nolock)
JOIN (
SELECT RecordID, MAX(StorageDate) AS MaxDate
FROM MyTable WITH (nolock)
GROUP BY RecordID)T2
ON T1.RecordID = T2.RecordID AND T1.StorageDate = T2.MaxDate
GROUP BY T1.RecordID, T2.MaxDate
HAVING COUNT(*) > 1
)PT ON TD.RecordID = PT.RecordID AND TD.StorageDate = PT.MaxDate
WHERE TD.DuplicateTypeID = 2
Try this and see how the performance goes:
;WITH
tmp AS
(
SELECT *,
RANK() OVER (PARTITION BY ID ORDER BY StorageDate DESC) AS StorageDateRank,
COUNT(ID) OVER (PARTITION BY ID, StorageDate) AS StorageDateCount
FROM MyTable
)
SELECT DISTINCT ID
FROM tmp
WHERE StorageDateRank = 1 -- latest date for each ID
AND StorageDateCount > 1 -- more than 1 entry for date
AND DuplicateTypeID = 2 -- DuplicateTypeID = 2
You can use analytic function rank , can you try this query ?
Select recordId from
(
select *, rank() over ( partition by recordId order by [StorageDate] desc) as rn
from mytable
) T
where rn =1
group by recordId
having count(*) >1
and sum( case when duplicatetypeid =2 then 1 else 0 end) >=1
I have a table like this.
TABLE-1
id Code
-----------------
1 N188
1 N1Z2
1 N222
2 N189
2 N1Z2
2 N1Z3
3 N188
3 A123
3 B321
4 N188
4 A333
4 B444
I want to select id and code only code has N188.Result should like this:
TABLE-2
id Code
---------------
1 N188
1 N1Z2
1 N222
3 N188
3 A123
3 B321
4 N188
4 A333
4 B444
How can I write sql for this in SQL Server?
Thanks
You can use EXISTS for this:
SELECT id, code
FROM table1 t
WHERE EXISTS (
SELECT 1
FROM table1 t2
WHERE t.id = t2.id
AND t2.Code = 'N188'
)
Condensed SQL Fiddle Demo
Using INNER JOIN
SELECT *
FROM tablename A
JOIN (SELECT id
FROM tablename
WHERE code = 'N188') B
ON a.id = b.id
Here is an alternative method that uses window functions:
select id, code
from (select t.*,
sum(case when code = 'N188' then 1 else 0 end) over (partition by id) as cnt_n188
from table t
) t
where cnt_n188 > 0;