I have a table like this.
TABLE-1
id Code
-----------------
1 N188
1 N1Z2
1 N222
2 N189
2 N1Z2
2 N1Z3
3 N188
3 A123
3 B321
4 N188
4 A333
4 B444
I want to select id and code only code has N188.Result should like this:
TABLE-2
id Code
---------------
1 N188
1 N1Z2
1 N222
3 N188
3 A123
3 B321
4 N188
4 A333
4 B444
How can I write sql for this in SQL Server?
Thanks
You can use EXISTS for this:
SELECT id, code
FROM table1 t
WHERE EXISTS (
SELECT 1
FROM table1 t2
WHERE t.id = t2.id
AND t2.Code = 'N188'
)
Condensed SQL Fiddle Demo
Using INNER JOIN
SELECT *
FROM tablename A
JOIN (SELECT id
FROM tablename
WHERE code = 'N188') B
ON a.id = b.id
Here is an alternative method that uses window functions:
select id, code
from (select t.*,
sum(case when code = 'N188' then 1 else 0 end) over (partition by id) as cnt_n188
from table t
) t
where cnt_n188 > 0;
Related
Currently my table looks like this; I want to add the count numbers with distinct InstanceId and duplicate values.
Id
InstanceId
Name
1
1
DiscoveryInstance
2
1
DiscoveryInstance
3
2
ETLInstance
4
3
DiscoveryInstance
5
3
DiscoveryInstance
6
2
ETLInstance
7
2
ETLInstance
I want the output to be like this:
Id
InstanceId
Name
1
1
DiscoveryInstance
2
1
DiscoveryInstance_Backup_1
3
2
ETLInstance
4
3
DiscoveryInstance
5
3
DiscoveryInstance_Backup_1
6
2
ETLInstance_Backup_1
7
2
ETLInstance_Backup_2
I don't want to update the first value and update should start with the next duplicate value in the column.
How to update this table to make this output possible in SQL Server query?
EDIT This solution addresses the ORIGINAL question and original output. This is no longer valid because you changed your desired output.
You could use rank() and concat in this manner:
with cte as (select id, name, rank() over (partition by name order by id) as name_rank
from my_table
)
select t.id,
case
when c.name_rank = 1 then t.name
else concat(t.name, '_Backup_', c.name_rank - 1)
end name
from my_table t
join cte c
on t.id = c.id
Output:
id
name
1
DiscoveryInstance
2
DiscoveryInstance_Backup_1
3
ETLInstance
4
DiscoveryInstance_Backup_2
5
DiscoveryInstance_Backup_3
6
ETLInstance_Backup_1
DB-fiddle found here. I see you updated the question after I posted this answer by adding another column, but that does not look important at the moment.
EDIT
This is an updated answer (thanks Guido) that would address your newly updated output:
with cte as (select id, name, rank() over (partition by name, instanceid order by id) as name_rank
from mytable
)
select t.id,
case
when c.name_rank = 1 then t.name
else concat(t.name, '_Backup_', c.name_rank - 1)
end name
from mytable t
join cte c
on t.id = c.id
Another option is using the row_number() like this
This solution uses your new column instanceid to get the correct data
select t.id,
case when rownumber > 1 then t.Name + '_Backup_' + convert(varchar(10), t.rownumber - 1)
else t.Name
end
from ( select t.id,
t.name,
row_number() over (partition by t.Name, t.instanceid order by t.id) as rownumber
from mytable t
) t
order by t.id
See this DBFiddle
output is
id
(No column name)
1
DiscoveryInstance
2
DiscoveryInstance_Backup_1
3
ETLInstance
4
DiscoveryInstance
5
DiscoveryInstance_Backup_1
6
ETLInstance_Backup_1
7
ETLInstance_Backup_2
I have a table as shown below:
group item rank
1 A 1
1 B 2
1 C 3
2 A 2
2 B 1
3 A 1
3 C 2
I want those groups data only, where item A has rank 1 as shown below:
group item rank
1 A 1
1 B 2
1 C 3
3 A 1
3 C 2
In group 2, A has rank 2, therefore not a part of output.
One way is using an IN clause
select *
from yourTable
where id in (select id from yourtable where item='A' and rank = 1)
you could use a subquery for get the involved id and the join
select * from my_table m
inner join (
select distinct id
from my_table
where item = 'A'
and rank = 1
) t on t.id = m.id
I'm trying to find rows (Name) that does not have ID = 1. For example, if my table looked like this:
Name ID
--------------
A 1
A 0
B 1
B 0
C 0
D 2
D 0
The answer to this query would be:
Name
-----
C
D
Do you have any idea?
SELECT Name
FROM myTable
GROUP BY Name
HAVING SUM(CASE WHEN ID = 1 THEN 1 ELSE 0 END) = 0
Here is one way to do it:
SELECT DISTINCT Name
FROM Table t0
WHERE NOT EXISTS
(
SELECT 1
FROM Table t1
WHERE t0.Name = t1.Name
AND t1.Id = 1
)
Try this query:
SELECT DISTINCT(name)
FROM tbl t1
WHERE
NOT EXISTS (SELECT name FROM tbl t2 WHERE ID=1 AND t1.name=t2.name)
Select Distinct name
From myTable
Where name not in (Select name From myTable Where id= 1)
pass_id retry_id
1 1
1 2
2 1
2 2
2 3
3 1
3 2
Need to pick up record with MAX(retry_id) within MAX(pass_id).
pass_id retry_id
3 2
Thanks in advance!
The easiest way is with order by and just choosing one row:
select t.pass_id, t.retry_id
from (select t.*
from t
order by pass_id desc, retry_id desc
) t
where rownum = 1
Here is a SQLFiddle.
SELECT *
FROM MyTable
WHERE
retry_id = (Select MAX(retry_id) FROM MyTable) AND
pass_id = (Select MAX(pass_id) FROM MyTable)
Not positive on oracle syntax, but something like
SELECT MAX(retry_ID)
FROM Table
WHERE Pass_ID = (SELECT MAX(Pass_ID)
FROM Table)
if I have a table with values like this:
ID SUBID FLAG
-----------------
1 1 1
1 2 (null)
2 3 1
2 3 (null)
3 4 1
4 5 1
4 6 (null)
5 7 0
6 8 (null)
7 9 1
and I would like to get all the ID's where 'FLAG' is only set to 1, so in this case the query would return
ID SUBID FLAG
-----------------
3 4 1
7 9 1
How can I achieve this?
try this:
SELECT * FROM flags where flag=1
and ID NOT in( SELECT ID FROM flags where flag !=1 OR flag IS NULL)
I don't have a db2 instance to test on but this might work:
select t1.id, t1.subid, t1.flag
from yourtable t1
inner join
(
select id
from yourtable
group by id
having count(id) = 1
) t2
on t1.id = t2.id
where t1.flag = 1;